What is the isotope for 90 protons and 142 neutrons?

Answer:

Concentration of NH₄⁺ = 6.00 mol/L

Concentration of S²⁻ = 3.00 mol/L

(NH₄)₂S is an ionic compound, with the name Ammonium Sulfide. Ionic compounds are composed of ions held together by electrostatic forces, known as ionic bonding.

The compound is neutral overall, but consists of positively charged ions called cations, and negatively charged ions called anions.

Ions are atoms or molecules that have lost or gained electrons, resulting in a net charge. The cations are attracted to the anions because opposite charges attract.

Ammonium Sulfide is composed of the ammonium cation (NH₄⁺), and the sulfide anion (S²⁻). The following ionic equation represents the dissolution reaction of solid ammonium sulfide into its individual ions upon reaction with water.

\(\boxed{\Large \textsf{$\rm (NH_4)_2S_{\,(s)} \leftrightharpoons 2NH_4^{\ \ +}{}_{(aq)}+S^{2-}_{\ \ \ \ \,(aq)}$}}\)

Since we are not given the volume of the solution, we can provide an arbitrary volume, as the volume will remain constant in the solution. Let us assume the volume of solution is 1 litre.

By this assumption, the reagents will remain in stoichiometric ratios (molar ratio of reactants to products), and therefore 1 mole of (NH₄)₂S will dissolve to produce 2 moles of NH₄⁺ and 1 mole of S²⁻.

Since we have 3.00 moles per litre, and we have 1 litre, therefore there are 3.00 moles of (NH₄)₂S in solution.

By stoichiometry:

Moles of NH₄⁺ = 3.00 × 2 = 6.00 mol

Moles of S²⁻ = 3.00 mol

Therefore, in 1 litre:

Concentration of NH₄⁺ = 6.00 mol/L

Concentration of S²⁻ = 3.00 mol/L

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Answer:

2C2H6(g)+7O2(g)→4CO2(g)+6H2O(l)

Explanation:

When ethane is burned in presence of oxygen, it produces carbon dioxide (CO_2)(CO2) and water (H_2O)(H2O) .

According to law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of reactants must be equal to the mass of products.

In order to get the same mass on both sides, the number of atoms of each element on product side must be same as the number of atoms of each element on reactant side.Thus the equations are balanced.

2C_2H_6(g)+7O2(g)\rightarrow 4CO_2(g)+6H_2O(l)2C2H6(g)+7O2(g)→4CO2(g)+6H2O(l)

Answer:

8 gram

Explanation:

in case of NaOH, normality=molarity

so normality=molarity×acidity or basicity(in case of NaOH it's 1)

then

weight of NaOH required = volume in ml × equivalent weight × normality / 1000

so

1000× 40× 0.2/1000

=8 gram

The total mass of sodium hydroxide (NaOH) needed to make the solution is 8 g (Option 4)

Molarity = mole / Volume

0.2 = mole of NaOH / 1

Mole of NaOH = 0.2 mole

Mass = mole × molar mass

Mass of NaOH = 0.2 × 40

Mass of NaOH = 8 g

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The mass number is the atomic mass rounded to a whole number.

The mass number, can be regarded as the atomic mass number or nucleon number, which can be seen as the total number of protons  as well as neutrons in an atomic nucleus however if it is  approximated , it can be considered to be equal to the atomic mass of the atom expressed in atomic mass units.

It should be noted that the mass number is established by rounding the atomic weight to the nearest whole number.

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They form a new compound with new properties from the original element.

The same components are always present in the same ratios in a compound. Compounds' characteristics differ, sometimes significantly, from the characteristics of the constituent . This is due to the fact that when elements in such a compound combine, a whole new substance with distinct features results.

A compound contains special characteristics that set it apart from the characteristics of its basic elements.

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The given reaction is already balanced, that is to say tha the number of atoms in the reactants matches the number of atoms in the products. In the reaction, we can see the relationship between CaC2 and H2O. For each mole of CaC2 two moles of H2O react.

So, if 4.8 moles of CaC2 are consumed the moles of H2O needed will be:

Mol of H2O = Mol of CaC2 x 2

Mol of H2O = 4.8 x 2 = 9.6 mol of H2O

Now, to calculate the grams of H2O we will use the following equation and the mass molar of H2O.

Mass molar of H2O =18.01 g/mol

So, if 4.8 moles of CaC2 are consumed in this reaction, 172.9 g of H2O are needed

A certain hydroxide salt with the formula M(OH)₃ has a solubility product constant of 9.96 x 10⁻³⁶. The molar solubility of this hydroxide salt in pure water is  7.7 × 10⁻¹⁰ M of  M(OH)₃  

The Ksp of M(OH)₃ = 9.96 x 10⁻³⁶

                           M(OH)₃   ⇄    M³⁺   +   3OH⁻

initial                   ---                    0        10⁻⁷

change                                     + s       +3s

at equ.                                          s          10⁻⁷ + 3s

Ksp = [M³⁺ ] [ OH⁻ ]³

9.96 x 10⁻³⁶ = (s) (10⁻⁷ + 3s)

now assume : (10⁻⁷ + 3s) ≅ 3s

9.96 x 10⁻³⁶ = (s) (3s)³

9.96 x 10⁻³⁶ = 27 s⁴

s⁴ = 9.96 x 10⁻³⁶  / 27

s = ( 0.36 × 10⁻³⁶)^1/4

s = 7.7 × 10⁻¹⁰ M of  M(OH)₃  

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The theoretical yield of aspirin given that 3.52 mL of acetic anhydride reacts with 0.9457 g of salicylic acid would be 1.234 g.

The theoretical yield of a reaction is otherwise known as the stoichiometrical yield of the reaction. It is the amount of product formed from a reaction based on the law of conservation of atoms.

Aspirin is produced when acetic anhydride reacts with salicylic acid according to the following equation:

\(C_4H_6O_3 + C_7H_6O_3--- > C_9H_8O_4 + C_2H_4O_2\)

The mole ratio of acetic anhydride and salicylic acid is 1:1.

Since: mole = mass/molar mass

0.9457 g salicylic acid is equivalent to:

0.9457/138.121 = 0.006847 mol

Thus, the equivalent mol of aspirin that would be formed would also be 0.006847 mol.

Since: mass = mol x molar mass

0.006847 mol aspirin would be:

0.006847 x 180.158 = 1.234 g

Hence, the theoretical yield of aspirin would be 1.234 g.

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Answer:

malleable

Explanation:

The image represent in malleable property of metal.

The image possibly represents the photoelectric effect of a metal, which is when it emits electrons after being exposed to electromagnetic radiation. Metals are also characterized by physical properties such as conductivity, malleability, metallic luster, and metallic bonding.

Based on your question, the image possibly represents the photoelectric effect, a key property of metals. This phenomenon occurs when a metal surface exposed to electromagnetic waves of a certain frequency absorbs radiation and emits electrons. These emitted electrons are called photoelectrons. Metals can also exhibit free electron model behavior, where electrons freely roam within the metal structure.

Metals possess unique physical properties like conductivity, malleability, and metallic luster. Malleability refers to the metal's ability to deform without breaking, while conductivity refers to the metal's ability to transfer heat or electricity. A metallic luster gives metals their characteristic shiny appearance.

Finally, metals are also known for their metallic bonding—a unique force that holds together the atoms within a metallic solid. Metallic bonding gives rise to many useful and varied bulk properties of metals.

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Answer:

no

Explanation:

A NON-polar, totally symmetrical molecule like C2Cl4, known as tetrachloroethene, is used for DRY CLEANING clothes because it attracts to the non-polar grease stains that are NOT effectively removed by polar water molecules. The dry cleaning process is NOT dry at all (C2Cl4 is a liquid).

According to the molecular geometry,as C₂Cl₄ molecule is symmetrical it is non-polar.

Molecular geometry can be defined as a three -dimensional arrangement of atoms which constitute the molecule.It includes parameters like bond length,bond angle and torsional angles.

It influences many properties of molecules like reactivity,polarity color,magnetism .The molecular geometry can be determined by various spectroscopic methods and diffraction methods , some of which are infrared,microwave and Raman spectroscopy.

They provide information about geometry by taking into considerations the vibrational and rotational absorbance of a substance.Neutron and electron diffraction techniques provide information about the distance between nuclei and electron density.

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Answer:

A and F i think

Explanation:

Freezing point depression is a colligative property observed in solutions that results from the introduction of solute molecules to a solvent. The freezing points of solutions are all lower than that of the pure solvent and is directly proportional to the molality of the solute

Molality of the solution and the  Van"t Hoff of the solution affects the  freezing-point depression of a solution.

Recall that the formula for freezing point depression is given by;

ΔT = K m i

Where;

T = freezing-point depression of a solution

K =  freezing-point constant

m = molality of the solution

i = Van't Hoff factor

We can see two important variables in this equation which are;

These two variables affect the  freezing-point depression of a solution.

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The standard enthalpy change for reaction (3) is 117.1 kJ.

The standard enthalpy change for reaction (3) can be calculated by using the enthalpy changes of reactions (1) and (2) and applying Hess's Law.

To do this, we need to manipulate the given equations so that the desired reaction (3) can be obtained.

First, we reverse reaction (1) to get the formation of C2H4(g) from C2H6(g):

C2H4(g)C2H6(g) ΔH° = -52.3 kJ

Next, we multiply reaction (2) by 2 and reverse it to obtain 2 moles of C2H6(g) reacting to form 3 moles of H2(g):

2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

Now, we add the two modified equations together:

C2H4(g)C2H6(g) ΔH° = -52.3 kJ
2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

When adding these equations, the C2H6(g) on the left side cancels out with the C2H6(g) on the right side, leaving us with the desired reaction (3):

C2H4(g) + H2(g)C2H6(g) ΔH° = -52.3 kJ + 169.4 kJ = 117.1 kJ

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Answer:

Engineering is all about solving problems using math, science, and technical knowledge. And engineers have solved a lot of problems in the world by designing and building various technologies. We have everything from machines that can breathe for you in hospitals to suspension bridges to computers we use every day. All of these things were once designed by engineers using the engineering design process.

Explanation:

Answer:

Students will have to use their brains to solve problems and challenges they will face to find a solution to cleaning up oil spills. Students will face failures after completing their solution, lots of research, and problems during the making of their solutions. What will work? What won't?

Explanation:

Hope this helps!

The pH of the solution is 3.059.

To calculate the pH of this solution, we need to use the Henderson-Hasselbalch equation, which relates the pH of a buffer solution to the pKa of the weak acid and the ratio of concentrations of  weak acid and its conjugate base.

First, we need to calculate the concentration of the weak acid and its conjugate base in the solution after the sodium acetate is dissolved.

We know that 1.00 g of sodium acetate is dissolved in 74.5 mL of 0.20 M acetic acid solution. We can use the molar mass of sodium acetate to convert the mass to moles:

1.00 g CH₃COONa × (1 mol CH₃COONa / 82.03 g CH₃COONa) = 0.01219 mol CH₃COONa

Since sodium acetate is a strong electrolyte, it will completely dissociate in water to form sodium ions (Na⁺) and acetate ions (CH₃COO⁻). The acetate ions will react with the acetic acid in the solution to form more acetate ions and hydronium ions (H₃O⁺), which will decrease the pH of the solution.

We can use the stoichiometry of this reaction to calculate the concentration of acetate ions and hydronium ions in the solution:

CH₃COO⁻ + H₃O+ ↔ CH₃COOH + H₂O

Since we started with 0.20 M acetic acid, the initial concentration of hydronium ions is also 0.20 M. Let's call the concentration of acetate ions x. Then, the concentration of acetic acid will be (0.20 - x) M, and the equilibrium constant for this reaction (Ka) is:

Ka = [CH₃COOH][H₂O] / [CH₃COO⁻][H₃O⁺]

Substituting in the known values:

1.75 × 10⁻⁵ = (0.20 - x)(1) / (x)(0.20)

Solving for x:

x = 1.05 × 10⁻³ M

So the concentration of acetate ions is 1.05 × 10⁻³ M, and the concentration of acetic acid is (0.20 - 1.05 × 10⁻³) M.

Now we can use the Henderson-Hasselbalch equation:

pH = pKa + log([A⁻]/[HA])

where pKa is the negative logarithm of the acid dissociation constant (Ka) for acetic acid (pKa = -log(1.75 × 10⁻⁵) = 4.756), [A-] is the concentration of acetate ions (1.05 × 10⁻³ M), and [HA] is the concentration of acetic acid (0.199 M).

Plugging in the values:

pH = 4.756 + log(1.05 × 10⁻³ / 0.199)

pH = 4.756 + (-1.697)

pH = 3.059

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Answer:

The answer to the question is Mercury.

Answer:

Mercury

Explanation:

The planet to the left of A is mercury it is on the 4 row outside the asteroid belt

Step 1 - Understanding the definition of molar concentration

Molar concentration (M or mol/L) is defined as the quotient between the number of moles (n) and the total volume of the solution (V):

Therefore, if the volume of the solution and its final concentration are known, we can use the equation to find the required number of moles.

Step 2 - Finding the required number of moles

The solution's concentration is 0.46 M and its volume is 250 ml. The volume must always be used in L, so:

Therefore, 0.115 moles would be required.

Answer:

the answer is

The atomic number

Answer:

question 2 is false

Explanation:

6 is D

The change in the entropy which will occurs in the system when the 35.0 g of the isopropyl alcohol and condenses from the gas to the liquid is 65.4 JK⁻¹.

The entropy change is as :

ΔS = Q / T

Where,

Q is the total heat energy :

Q = n ΔH

Where,

n is the number of moles

ΔH is the enthalpy of vaporization

The mass of the isopropyl alcohol = 35 g

The moles of the isopropyl alcohol = mass / molar mass

The moles of the isopropyl alcohol = 35 / 60

The moles of the isopropyl alcohol = 0.583 mol

The entropy change = (39.9 × 10³ × 0.583) / 82.30 + 273

The entropy change = 65.4 JK⁻¹

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The organism with the smallest biomass in relation to its trophic level in the given trophic pyramid is likely the hawk, which is the apex/quaternary consumer.

In a trophic pyramid, biomass tends to decrease as we move up the trophic levels.

Producers, such as grass, typically have the highest biomass, as they convert energy from the sun into organic matter through photosynthesis.

Primary consumers, like grasshoppers, feed on producers and have a lower biomass compared to the producers.

Secondary consumers, such as shrews, occupy the next trophic level and have a smaller biomass compared to primary consumers since they obtain energy by consuming primary consumers.

Tertiary consumers, represented by snakes in this scenario, feed on secondary consumers and generally have a smaller biomass than secondary consumers.

At the top of the trophic pyramid, we have apex/quaternary consumers, which include hawks.

These organisms occupy the highest trophic level and have the smallest biomass in relation to their trophic level.

Apex consumers obtain energy by preying on other consumers and have fewer individuals and lower biomass due to the energy loss that occurs throughout the food chain.

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Fluorine (F) Neon (Ne) Phosphorus (P) Potassium (K) Calcium (Ca)

The electron configuration 1s^2 2s^2 2p^5 corresponds to the element fluorine (F) with atomic number 9.

The electron configuration 1s^2 2s^2 2p^6 3s^2 corresponds to the element neon (Ne) with atomic number 10.

The electron configuration 1s^2 2s^2 2p^6 3s^2 3p^3 corresponds to the element phosphorus (P) with atomic number 15.

The electron configuration 1s^2 2s^2 2p^6 3s^2 3p^6 4s^1 corresponds to the element potassium (K) with atomic number 19.

The electron configuration 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d corresponds to the element calcium (Ca) with atomic number 20.

The given electron configurations correspond to the following elements: A) Fluorine (F), B) Neon (Ne), C) Phosphorus (P), D) Potassium (K), and E) Calcium (Ca).

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Answer:

+91.7 KJmol-1

Explanation:

Recall that ∆G= -RTlnK

Since ∆G in this case is ∆Grxn and K is the Ksp

Note that the Ksp is the solubility product (as shown by the reaction equation)

∆Grxn is the change in free energy for the reaction, in this case the ionization of the silver iodide into silver and iodide ions.

R= 8.314JK-1 and T =25°C +273 = 298 K (the centigrade temperature must be appropriately converted to its corresponding absolute absolute before proceeding with the calculation)

Hence we can substitute values accordingly;

∆Grxn = -(8.314 × 298 × ln 8.3×10^-17)

∆Grxn = +91.7 KJmol-1

Resonance is correct answer

What is resonance?

The word "resonance" comes from the Latin word "resonantia," which means "echo," and the verb "resonare," which means "to resound." The term originated in the study of acoustics, specifically the sympathetic resonance seen in musical instruments, such as when one string begins to vibrate and produce sound after another one is struck.

There are many different forms of vibrations or waves that exhibit resonance phenomena, including mechanical, orbital, acoustic, electromagnetic, nuclear magnetic, electron spin, and quantum wave function resonances. Resonant systems can be employed to produce vibrations at a particular frequency (such as those produced by musical instruments) or to isolate particular frequencies from a complicated vibration that contains a range of frequencies (e.g., filters).

When the frequency of an applied periodic force (or one of its Fourier components) is equal to or nearly equal to the natural frequency of the system on which it works, the phenomenon of enhanced amplitude known as resonance results. A dynamic system's oscillations will have a greater amplitude when an oscillating force is applied at its resonant frequency than when the same force is applied at other, non-resonant frequencies

Due to the storage of vibrational energy, small periodic stresses that are close to the system's resonance frequency can cause oscillations in the system with enormous amplitudes.

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The labs in this chemistry class use a green approach, which means they prioritize environmentally friendly practices.

In this chemistry class, the term "green approach" refers to a set of practices and principles that prioritize environmental sustainability and minimize negative impacts on the ecosystem. These labs aim to reduce their carbon footprint, conserve resources, and promote responsible waste management. By adopting a green approach, the class strives to align its scientific pursuits with the goal of environmental stewardship.

One of the key aspects of the green approach in these chemistry labs is the conscious selection and utilization of environmentally friendly materials and chemicals. This includes opting for safer alternatives to hazardous substances whenever possible, such as using non-toxic solvents or reagents. Additionally, the labs may encourage the use of renewable resources and promote the recycling or repurposing of materials to reduce waste generation.

Another important component of the green approach is energy conservation. The labs may employ energy-efficient equipment and lighting systems, as well as implement strategies to minimize energy consumption during experiments. For instance, they may encourage students to turn off equipment when not in use and adopt efficient heating or cooling methods.

Furthermore, the labs may focus on water conservation by promoting responsible water usage and minimizing water wastage during experiments. This could involve using water-efficient techniques, such as microscale experiments that require smaller amounts of water, or implementing recycling systems to capture and reuse water when appropriate.

By embracing a green approach, these chemistry labs aim to instill environmental awareness and responsibility in students while demonstrating that scientific progress can coexist with sustainable practices. Through this approach, students gain valuable knowledge and skills that they can apply in their future scientific endeavors, contributing to a more sustainable and eco-friendly society.

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Based on the given information, Candace can complete the table as follows:

Horizon    Description                    

O             Organic layer                  

A              Topsoil                        

B               Subsoil                        

C               Weathered rock particles      

R               Bedrock                        

This table provides a brief description of each horizon in a soil profile.

- O Horizon (Organic layer): This layer consists of decomposed organic material such as leaves, plant debris, and humus. It is rich in nutrients and contributes to soil fertility.

- A Horizon (Topsoil): The topsoil is the uppermost layer that contains a mixture of organic matter, minerals, and nutrients. It is crucial for plant growth and supports the majority of plant roots.

- B Horizon (Subsoil): The subsoil is located beneath the topsoil and contains less organic matter. It consists of mineral deposits, clay, and dissolved materials leached down from the upper layers.

- C Horizon (Weathered rock particles): The C horizon is composed of weathered rock particles that have undergone some degree of decomposition. It contains broken-down rocks, minerals, and fragments.

- R Horizon (Bedrock): The bedrock is the solid, unweathered layer of rock that underlies all other horizons. It serves as the parent material from which soil is formed through the process of weathering and erosion.

By completing this table, Candace can have a clear understanding of the different horizons in a soil profile and their respective characteristics.

Answer:

...................

.

Answer:results from the attractive force between a hydrogen atom covalently bonded to a electronegative atom

Explanation:

a) The volume of the reactor V0 using the mass balance equation and then use the rate of reaction equation to calculate the reactor size is 66.67 ft³ b) 10 reactors are required for the process to be arranged in series.

Given information:
Rate of feed =100 cfh
Cso=1.5 lbmol/ft³
Forward reaction rate, k=10
Equilibrium constant, Ke=16
Equilibrium conversion= 80%
CT=CU= ½(1.5-CS)
-rS=k[(Cs)² – 0.25(1.5-Cs)²/ke]a) Reactor size calculation:

Let’s use the mass balance equation for the process taking place in the Continuous Stirred Tank Reactor,

Therefore, F = V_0 (C_s)_o

Where, F is the flow rate

V_0 is the volume of the reactor(C_s)_o is the concentration of the reactant initially

This is a reversible reaction that occurs in a Continuous Stirred Tank Reactor or a CSTR. It follows the reaction equation of 2S ⇆ T+U .

Using equilibrium data, we know that the required conversion is 80%. That is, Xeq=0.8Using the equilibrium data equation, we can relate the concentrations of T, U, and S as follows:

[T][U]/[S]²= Ke=16Where,[T], [U] and [S] are the molar concentration of the respective species.

Now, let's use the rate equation for the forward reaction to relate the concentration of S to the rate of the reaction.-r_S=k[(C_S)²-0.25(1.5-C_S)²/Ke]

Now, applying the steady-state assumption, dC_S/dt=0, and considering the fact that CT=CU=0.5(1.5-CS), we can substitute (C_S) with C_T and simplify the rate equation.-r_S=k[((C_T)²-0.25(1.5-C_T)²/Ke)]

Now we can calculate the rate of reaction from the rate equation.

-r_S=k[((C_T)²-0.25(1.5-C_T)²/Ke)]=k[((0.5(1.5-C_T))²-0.25(1.5-0.5(1.5-C_T))²/Ke)]

We can find the volume of the reactor V0 using the mass balance equation and then use the rate of reaction equation to calculate the reactor size.

Therefore,V0=F/(C_S)_o=100/(1.5)=66.67 ft³

So, the reactor size is 66.67 ft³.b) For a given feed rate and the size of the reactors, we can calculate the number of reactors required for the process to be arranged in series using the following equation: N=V1/V2

where, V1 and V2 are the volumes of the reactor in the series.

So, if we want to design an arrangement of vessels having 1/10 the size, we can calculate the size of each reactor in the series.V2=V1/10=6.667 ft³

Now, we can find the number of reactors using the equation: N=V1/V2=66.67/6.667=10

Thus, 10 reactors are required for the process to be arranged in series.

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The inorganic substance with the chemical formula BaSO4 is barium sulfate (or sulphate). It is a tasteless, crystalline white substance that is insoluble in water.

A barium cation and a sulfate anion are the two elements that make up barium sulfate. There are four oxygen atoms joined to the sulfur. A sulfate salt of barium, known as BaSO4, is present in the mineral barite. It is a white crystalline substance that is soluble in strong acids but insoluble in water and alcohol.

Elements include both barium and bromine. Barium is a metal belonging to Group 2 of the modern periodic table, and bromine is a non-metal belonging to Group 17 (halogen).

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