Is -9 terminating, repeating, or neither?

The chi-square statistic is used to determine whether there are differences between two nominally scaled variables. Chi-Square is a statistical test used to compare two nominal variables to determine whether they differ.

The Chi-Square test is used to test for differences between two groups. When you want to compare groups or examine the relationship between two variables, this test is useful. The chi-square test is a method of statistical inference that can be used to compare observed frequencies with expected frequencies, allowing us to determine whether there is a meaningful difference between them. When the p-value obtained from a chi-square test is less than 0.05, it is generally considered statistically significant.

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Answer:

120 is the measure of leog

Step-by-step explanation:

a) PX43.Y=2) = P(X=3 | Y=2) = 4/11.

b) P(X>3, Y≥3) = 0.13.

c) P(X=1, Y=4) = f(1,4) = 0.04

d) P(X+Y = k) = Σxi

(a) We need to find P(X=3, Y=2).

From the given joint probability distribution, we have:

f(3,2) = 0.16

The marginal probability distribution of X is given by:

P(X=x) = Σy f(x,y)

So, we have:

P(X=3) = Σy f(3,y) = f(3,2) + f(3,3) + f(3,4) = 0.16 + 0.12 + 0.08 = 0.36

Now, using the conditional probability formula, we get:

P(X=3 | Y=2) = P(X=3, Y=2) / P(Y=2) = f(3,2) / Σx f(x,2) = 0.16 / (0.16 + 0.12 + 0.04) = 4/11

Therefore, PX43.Y=2) = P(X=3 | Y=2) = 4/11.

(b) We need to find P(X>3, Y≥3).

Using the marginal probability distribution of X and Y as found in part (a), we get:

P(X>3, Y≥3) = P(X=4, Y=3) + P(X=4, Y=4) = f(4,3) + f(4,4) = 0.09 + 0.04 = 0.13

Therefore, P(X>3, Y≥3) = 0.13.

(c) The conditional probability distribution of X given Y=y is given by:

f(x | y) = f(x,y) / Σxf(x,y)

Using the joint probability distribution given in the problem, we get:

Σxf(x,y) = f(1,y) + f(2,y) + f(3,y) + f(4,y) = 0.04 + 0.12 + 0.28 + 0.56 = 1

In light of Y=2, the following is the conditional probability distribution of X:

f(x | 2) = f(x,2) / Σxf(x,2) = 0.16/ (0.16 + 0.12 + 0.08 + 0.04) = 4/10 = 2/5

Similarly, the conditional probability distribution of X given Y=3 and Y=4 are:

f(x | 3) = f(x,3) / Σxf(x,3) = 0.12 / (0.04 + 0.12 + 0.36 + 0.72) = 1/5

f(x | 4) = f(x,4) / Σxf(x,4) = 0.08 / (0.04 + 0.08 + 0.24 + 0.32) = 2/7

Therefore, P(X=1, Y=4) = f(1,4) = 0.04

P(X=2, Y=2) = f(2,2) = 0.12

P(X=3, Y=3) = f(3,3) = 0.28

P(X=4, Y=3) = f(4,3) = 0.09

P(X=4, Y=4) = f(4,4) = 0.04

(d) The marginal probability distribution of X+Y can be found as follows:

P(X+Y = k) = Σxi

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Please add triangle image.

Answer:

i cant answer without a picture or something to see what the missing sides are..

comment the graph and i will answer the question

Step-by-step explanation:

a) The probability that an apple from the tree has a weight greater than 90 grams is of: 0.2514 = 25.14%.

b) i) The p-value of the test is of: 0.0045.

b) ii) The conclusion of the test is given as follows: There is enough evidence to conclude that the mean weight of apples from tree A is greater than the mean weight of apples from tree B, as the p-value of the test is less than the significance level.

The z-score of a measure X of a variable that has mean symbolized by \(\mu\) and standard deviation symbolized by \(\sigma\) is obtained by the rule presented as follows:

\(Z = \frac{X - \mu}{\sigma}\)

The mean and the standard deviation of the weight of the apples are given as follows:

\(\mu = 85, \sigma = 7.5\)

The probability that an apple from the tree has a weight greater than 90 grams is one subtracted by the p-value of Z when X = 90, hence:

Z = (90 - 85)/7.5

Z = 0.67

Z = 0.67 has a p-value of 0.7486.

1 - 0.7486 = 0.2514 = 25.14%.

For each sample, the mean and the standard error are given as follows:

Hence, for the distribution of differences, the mean and the standard error are given as follows:

The test statistic is given by the division of the mean by the standard error of the distribution of differences, hence:

z = 4.2/1.61 = 2.61.

Using the z-table, with z = 2.61, the p-value is of:

0.0045.

As the p-value is less than the significance level, there is enough evidence to conclude that the mean weight of apples from tree A is greater than the mean weight of apples from tree B.

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Answer:

  1/5

Step-by-step explanation:

  1/3 of 3/5 is 1/5

The amount of flour you need is 1/5 cup.

Answer

Step-by-step explanation:

Hope it helps you!

Answer:

a=4, b=5, c=3

=4+5+3/2

=12/2

=s=6

Now,

we have,

√s(s-a)(s-b)(s-c)

√6(6-4)(6-5)(6-3)

√6×2×1×3

√36

=6

The total number of calories from the strawberries in the smoothie is 40 calories.

We are given that 6 strawberries have a total of 24 calories.

This means that, on average, each strawberry has 24/6 = 4 calories.

Next, we are told that the smoothie recipe calls for 0.5 cup of strawberries, which is approximately 10 berries.

This means that we will be using 10 strawberries in the smoothie.

To find the total number of calories from the strawberries in the smoothie, we need to multiply the number of strawberries by the number of calories per strawberry. From our earlier calculation, we know that each strawberry has an average of 4 calories.

So, the total number of calories from the strawberries in the smoothie is:

10 strawberries x 4 calories per strawberry = 40 calories

Therefore, the smoothie contains 40 calories from the strawberries used in the recipe.

It's important to note that the calorie count may vary depending on the other ingredients used in the smoothie. This calculation only accounts for the calories from the strawberries themselves.

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Answer:

8

Step-by-step explanation:

3/5 ×2=8/10

..............

Answer: 9

Step-by-step explanation: The common difference is the difference between each of the terms in an arithmetic sequence.

Let's work backwards.

First, we take the last term we are given and

subtract the second to last term.

So here, we subtract 23 - 14 to get 9.

Now, we take 14 - 5 to get 9.

Notice that 9 is our answer in both problems above.

That means it's our common difference.

A base must be raised to a certain exponent or power, or logarithm, in order to produce a given number. If bx = n, then x is the logarithm of n to the base b, which is expressed mathematically as x = logb n. For instance, 23 = 8; consequently, 3 is the base-2 logarithm of 8 or 3 = log2 8.

When measuring the relative change of a value rather than its absolute difference, logarithmic scales are helpful. Moreover, logarithmic scales are used to compress large-scale scientific data because the logarithmic function log(x) grows very slowly for large x.

\(log_{2} 2=1\\log_{4}4=1\\ log_{100}100=1\\log10=1\)

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The architect's new design for the room increased the volume by 40 ft³ or 50%.

Length is a term used to describe the magnitude of a line segment, arc, or other geometric figure. It is measured in linear units, such as inches, feet, meters, and centimeters. Length is a one-dimensional measurement; it does not include width, height, or depth. Length is also used to describe the amount of time it takes to complete a task, such as a movie's length or the length of a school day.

Original Length: 10 ft
Original Width: 8 ft
Original Volume: 80 ft³

New Length: 12 ft
New Width: 10 ft
New Volume: 120 ft³

Increase in Volume: 40 ft³

The architect's new design added 2 feet to the length and width of the room, which increased the volume by 40 ft³. This increase in volume was calculated by taking the difference between the original volume (80 ft^3) and the new volume (120 ft³). This change in design resulted in a 50% increase in the room's volume.

In conclusion, the architect's new design for the room increased the volume by 40 ft³ or 50%.

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Answer is 180 degree

Hope it helps

A random variable X has a probability distribution as follows:

X = 0, 1, 2, 3

P(X) = 2k, 3k, 13k, 2k

where k is a positive constant. The probability P(X < 2.0) is 0.25.

What is random variable?

A quantity or item that depends on random events is formalised mathematically as a random variable, also known as a random quantity, aleatory variable, or stochastic variable. It is a function or mapping from potential outcomes to a quantifiable space, frequently to real numbers.

We know that probability sum of all events is 1

Therefore here sum of all probability events =P(X=0)+P(X=1)+P(X=2)+PX=3)=1

2k+3k+13k+2k=1

20k=1

k=1/20=0.05

For P(x<2)=P(X=0)+P(X=1)=2k+3k =5k=5*(1/20)=0.25

Hence the correct answer is b, 0.25

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Answer:

Option 2

 x     y

−3     0

−1      3

 0     4

 3     0

4 3

Step-by-step explanation:

For a relation x →  y to be a function, there can be one and only one value of y for a value of x

Looking at the tables we see that option 1 is out since all x values are 2 andthere are multiple values of y

The last option is out because for x = 0 there are two values of y=-2 and y = 2

Correct choice is the second option which has a unique y value for each value of x

Answer:

option 2 im doing it rn

Step-by-step explanation:

Answer:

14.4

Step-by-step explanation:

Cross multiply.

5x = 8 * 9

5x = 72

x = 14.4

Answer:

x= 14.4

Step-by-step explanation:

1. cross multiply

5*x and 8*9

5x=72

2. divide 72 by 5

x= 14.4

Replacing stoplights with roundabouts does not significantly reduce the rate of accidents at intersections based on the given data.

Based on the statistical analysis, replacing stoplights with roundabouts does not significantly reduce the rate of accidents at intersections.

To test this hypothesis, we will use a paired t-test, which compares the means of two sets of paired data. The null hypothesis is that there is no significant difference between the mean accident rates before and after installing roundabouts, while the alternative hypothesis is that the mean accident rate after installing roundabouts is significantly lower than before.

Here are the steps to conduct the paired t-test:

Using the given data, the differences between the accident rates before and after installing roundabouts are:

-0.6, 0.2, 0.6, -0.1, 0

The mean of the differences is 0.02, and the standard deviation is 0.43. There are 5 paired observations, so the degrees of freedom are 4.

Using the formula, we get:

t = 0.02 / (0.43 / √(5)) = 0.14

The critical t-value at a 0.05 level of significance and 4 degrees of freedom is 2.776 from a t-distribution table.

Since the calculated t-value (0.14) is less than the critical t-value (2.776), we fail to reject the null hypothesis. Therefore, we can conclude that replacing stoplights with roundabouts does not significantly reduce the rate of accidents at intersections based on the given data.

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The coordinates of the unit vector, having positive first coordinate and orthogonal to the plane through a given point P(3, -4, 4) = \((\frac{\sqrt{2} }{2}, \frac{-\sqrt{2} }{2},0)\)

Let the coordinates of Q be (6 , -1 , 7) and R be (6, -1 ,9).

Then coordinates of vector(PQ) = < 6 - 3, -1 - (-4), 7 - 4 > = (3, 3, 3)

And coordinates of vector(PR) = < 6 - 3, -1 - (-4), 9 - 4 > = (3, 3, 5)

Thus, vector (n) = vector (PQ) x vector (PR)

=> vector (n) =  \(\left[\begin{array}{ccc}3&3&3\\3&3&5\end{array}\right]\)

Solving for the determinant, we get the coordinates of vector (n)

= (6, -6, 0).

Magnitude of vector (n) = \(\sqrt{6^{2}+{(-6)^{2}+{0^{2} }\) = \(6\sqrt{2}\)

Thus, the unit vector (n) = \(\frac{Coordinates Of Vector (n)}{Magnitude Of Vector(n)}\)

=> Unit vector (n) = \(\frac{(6,-6,0)}{6\sqrt{2} }\) = \((\frac{\sqrt{2} }{2},\frac{-\sqrt{2} }{2},0)\)

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COMPLETE QUESTION:

Find a unit vector with positive first coordinate that is orthogonal to the plane through the points P (3,-4,4).

Answer:

3 and 4

36 and 48

Step-by-step explanation:

you got the 1 wrong

should be 5 and 4

20 and 16

There are approximately 11.25 cups of granulated sugar in a 5 pound bag.

To determine the number of cups of granulated sugar in a 5 pound bag, we can use the conversion factor of 2.25 cups per pound.

First, we multiply the number of pounds (5) by the conversion factor:

5 pounds * 2.25 cups/pound = 11.25 cups

Therefore, there are approximately 11.25 cups of granulated sugar in a 5 pound bag.

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Answer:

4(2x+2)=8(2-3x)

First I am going to distribute the 4 and the 8 on the sides of the equation.

This gets me to

8x + 8 = 16 - 24x

then subtract 8x on both sides to get

8 = 16 - 16x

then subtract 16 on both sides to isolate the -16x

-8 = -16x

then divide by -16 on both sides, to make the x variable positive and isolate the variable even more.

0.5 = x

Step-by-step explanation:

each step is highlighted in bold, and the equation after the step is shown below the bolded line.

Answer:

Im not pretty sure but i think thats the answer ^^

Answer:

(a) 60 cups

(b) 5 cookies, 8 muffins and 4 cupcakes in each container

Step-by-step explanation:

Given

Let:

\(C \to Cookies; M \to Muffins; K \to Cupcakes\)

So:

\(C : M : K = 300 : 480 : 240\)

Solving (a): The greatest number of containers to be used;

To do this, we first reduce the ratio to the lowest

C : M : K = 300 : 480 : 240

Divide by 60

\(C : M : K = 5 : 8 : 4\)

The ratio cannot be further reduced. Hence, he will use 60 cups

Solving (b): The number in each cup

In (a), we have:

\(C : M : K = 5 : 8 : 4\)

This means that;

\(C = 5\) --- Cookies

\(M = 8\) --- Muffins

\(K = 4\) -- - Cupcakes

Answer:

it is 7200 Liters

Step-by-step explanation:

Brainliest?

An urn contains 2 red balls and 2 blue balls. Balls are drawn until all of the balls of one color have been removed. The expected number of balls drawn is 0.6667.

There are two possible outcomes: either all the red balls will be drawn first, or all the blue balls will be drawn first. Let's calculate the probability of each of these outcomes.

If the red balls are drawn first, then the first ball drawn must be red. The probability of this is 2/4. Then the second ball drawn must also be red, with probability 1/3 (since there are now only 3 balls left in the urn, of which 1 is red). Similarly, the third ball drawn must be red with probability 1/2, and the fourth ball must be red with probability 1/1. So the probability of drawing all the red balls first is:

(2/4) * (1/3) * (1/2) * (1/1) = 1/12

If the blue balls are drawn first, then the analysis is the same except we start with the probability of drawing a blue ball first (also 2/4), and then the probabilities are 1/3, 1/2, and 1/1 for the subsequent balls. So the probability of drawing all the blue balls first is:

(2/4) * (1/3) * (1/2) * (1/1) = 1/12

Therefore, the expected number of balls drawn is:

E = (1/12) * 4 + (1/12) * 4 = 2/3

Rounding to four decimal places, we get:

E ≈ 0.6667

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The expected number of balls drawn until all of the balls of one color have been removed is 3.

To find the expected number of balls drawn until all of the balls of one color have been removed, we can consider the possible scenarios:

If the first ball drawn is red:

The probability of drawing a red ball first is 2/4 (since there are 2 red balls and 4 total balls).

In this case, we would need to draw all the remaining blue balls, which is 2.

So the total number of balls drawn in this scenario is 1 (red ball) + 2 (blue balls) = 3.

If the first ball drawn is blue:

The probability of drawing a blue ball first is also 2/4.

In this case, we would need to draw all the remaining red balls, which is 2.

So the total number of balls drawn in this scenario is 1 (blue ball) + 2 (red balls) = 3.

Since both scenarios have the same probability of occurring, we can calculate the expected number of balls drawn as the average of the total number of balls drawn in each scenario:

Expected number of balls drawn = (3 + 3) / 2 = 6 / 2 = 3.

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The number of trees more than 10m tall but not more than 20m tall is 18 trees.

0 < h ≤ 5 = 5

height greater than 0m less than or equal to 5m

5 < h ≤ 10 = 9

height greater than 5m less than or equal to 10m

10 < h ≤ 15 = 13

height greater than 10m less than or equal to 15m

15 < h ≤ 20 = 5

height greater than 15m less than or equal to 20m

20 < h ≤ 25 = 1

height greater than 20m less than or equal to 25m

The number of trees that are more than 10m tall but not more than 20m tall are;

10 < h ≤ 15 = 13

15 < h ≤ 20 = 5

So,

13 + 5 = 18 trees

Therefore, the total number of trees which are 10m tall but not more than 20m tall is 18 trees.

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Answer: 2.) the interquartile range is 10

Step-by-step explanation: see pic

I hope this helps :)