Which of the following factors is not a distribution intermediary?

a.
Agent and broker

b.
Retailer

c.
Consumer

d.
Wholesaler

(a) The errors made by the student are:

Incorrectly expanding 49(2) as 24 instead of 98.

Mistakenly factoring the quadratic equation as (y - 8)(y - 1) instead of

\(y^{2} - 9y + 8.\)

(b) The exact solution to the equation is x = 7/11.

(a) The student made two errors in their solution:

Error 1: In the step \("22x + 49(2) = 0,"\) the student incorrectly expanded 49(2) as 24 instead of 98. The correct expansion should be 49(2) = 98.

Error 2: In the step \("y^{2} - 9y + 8 = 0,"\) the student mistakenly factored the quadratic equation as (y - 8)(y - 1) = 0. The correct factorization should be \((y - 8)(y - 1) = y^{2} - 9y + 8.\)

(b) To find the exact solution to the equation, let's correct the errors made by the student and solve the equation:

Starting with the original equation: \(22x + 4 - 9(2) = 0\)

Simplifying: 22x + 4 - 18 = 0

Combining like terms: 22x - 14 = 0

Adding 14 to both sides: 22x = 14

Dividing both sides by 22: x = 14/22

Simplifying the fraction: x = 7/11

Therefore, the exact solution to the equation is x = 7/11.

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Answer:

4.24 inches

Step-by-step explanation:

212/50

Answer:

4.24 inches

Step-by-step explanation:

To get the answer you divide 212 miles by 50 miles.

The units digit of the double factorial notation is the units digit of the product of all the even integers from 2 to 8, which is 8! The units digit of 8! is 8, so the answer is 8.

Factorials are mathematical operations symbolized by an exclamation point following a number. To find the factorial of a number, such as 5, write it down as 5! then multiply it by all the positive integers less than 5, including 1. Therefore, 5! is equivalent to 5 x 4 x 3 x 2 x 1, or 120. Factorials are frequently employed in mathematical equations and computations, especially in probability and statistics, where they are used to calculate the number of combinations or permutations that may be made from a given collection of numbers or variables. For example, if you had 5 distinct objects and want to determine how many various combinations , you used the factorial of 5.

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Answer:

09kikgjj78nmi

:

Answer:

Domain: [-1, 3)
Range: (-5, 4]

Step-by-step explanation:

\(\begin{array}{c|ccc}\cline {2-4} 2 & 9 ,& 18 ,& 99 \\ \cline {2-4} 3 & 9 & ,9 & ,11 \\ \cline {2-4} 3 & 3 ,& 3, & 11 \\ & 1, & 1 , & 11 \end {array}\)

Answer:

about 14 chairs

Step-by-step explanation:

All you do is do 95 divided by 7, which is 13.57142857142857.... If your teacher would want you to round, then answer with 14, but if they wouldn't, I would just do 14

Explanation

We are given the following:

We are required to solve the simultaneous equation given using substitution method.

This can be achieved as follows:

Now, we get the value of x as follows:

Hence, the answer is:

Answer:

16

Step-by-step explanation:

Subtract DE from CE and you will get the value of CD

27 - 11 = 16

Answer:

1 = - 4 - 14 √3

2 = 9 - 11 √3

Step-by-step explanation:

Question 1

(-4√3 + 2)(√3 + 4)

Apply FOIL method

= (-4√3) √3 + (-4√3) . 4 + 2 √3 + 2 . 4

Apply minus-plus rules: + (-a) = -a

= -4 √3 √3 - 4 . 4 √3 + 2 √3 + 2 . 4

Simplify

= - 4 - 14 √3

Question 2

(-3 + √3)(1 + 4 √3)

Apply FOIL method

= (-3) . 1 + (-3) . 4 √3 + √3 . 1 + √3 . 4 √3

Apply minus-plus rules: + (-a) = -a

= -3 . 1 - 3 . 4 √3 + 1 . √3 + 4 √3 √3

Simplify

= 9 - 11 √3

The coupon rate of the bonds by King of Diamonds Industries would be 7 %.

The formula for the bond price shows the coupon payment and so can be used to find the coupon rate:

= (Coupon payment  x ( 1 - ( 1 + r ) ^ ( - number of years till maturity ) ) ) / r + Face value /  (1  + rate )^ number of years

1,482.01 = (C x (1 - (1 + 0.07 )^ (- 14) ) ) / 0.07 + F / (1 + 0.07 ) ^ 14

103.7407 - 0.07 x (F / (1 + 0.07) ^14 ) = C x  (1 - ( 1 + 0.07) ^ ( - 14) )

Using a calculator, C is $ 70.

This means that the coupon rate is:

= 70 / 1, 000

= 7 %

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Answer:

The Range = 72

Step-by-step explanation:

Definition ==================================

The Range of data set is is the difference between the smallest and largest values

……………………………………………………………

The Range = 78 - 6 = 72

To get system B, the second equation in system A was replaced by the sum of that equation and the first equation multiplied by -3. The solution to system B will be the same as the solution to system A.

What is Linear equation ?

Linear equation can be defined as the equation in which the highest degree is one.

First equation of system A multiplied by -3:

(-3)(x+6y=5)

(-3)(x)+(-3)(6)=(-3)(5)

-3x-18=-15

Sum of the second equation of system A and the first equation multiplied by -3:

(-3x-18)+(3x-7y)=(-15)+(-35)

-3x-18+3x-7y=-15-35

-25y=-50

System B

x+6y=5

-25y=-50

Hence,  To get system B, the second equation in system A was replaced by the sum of that equation and the first equation multiplied by -3. The solution to system B will be the same as the solution to system A.

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Answer:

3840

Step-by-step explanation:

Using the fundamental counting principle

The restaurant is offering five kinds of soup, three kinds of salad, four kinds of appetizers, six entrees, five desserts, and four beverages.

There are 5 independent events happening (5 prixe dinners)

(1) soup or salad (not both)

We have five kinds of soup, three kinds of salad

soup or salad (not both), = 5 + 3

= 8

(2) appetizer = 4

(3) entrees = 6

(4) dessert = 5

(5) Beverage = 4

Hence,

8 × 4 × 6 × 5 × 4

= 3840

The number of different prix fixe dinners are possible is 3840

Given statement solution is :- The correct answer is: The frequency is 3 more than expected.

To determine the expected frequency of landing on an even number when rolling a fair six-sided number cube, we need to calculate the probability of landing on an even number and multiply it by the total number of rolls.

The number cube has six possible outcomes: 1, 2, 3, 4, 5, and 6. Of these, three are even numbers: 2, 4, and 6. Therefore, the probability of rolling an even number is 3/6, which simplifies to 1/2 or 0.5.

The expected frequency can be found by multiplying the probability by the total number of rolls:

Expected frequency = Probability of landing on an even number × Total number of rolls

Expected frequency = 0.5 × 30 = 15

Now, we can compare the expected frequency (15) to the actual frequency (18) given in the problem statement.

The actual frequency is 18, and it is 3 more than the expected frequency (18 - 15 = 3).

Therefore, the correct answer is: The frequency is 3 more than expected.

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An angle is produced at the point where two or more lines meet. Thus the value of LP required in the question is approximately 14.

Two lines are said to be perpendicular when a measure of the angle between them is a right angle. While parallel lines are lines that do not meet even when extended to infinity.

From the question, let the length of LP be represented by x.

Thus, from the given question, it can be deduced that;

LM ≅ PN = 20

KP = KN - PN

    = 30 - 20

KP = 10

LP = x

Also,

<MLP is a right angle, so that;

< KLP = < KLM - <PLM

         = 126 - 90

<KLP = \(36^{o}\)

So that applying the Pythagoras theorem to triangle KLP, we have;

Tan θ = \(\frac{opposite}{adjacent}\)

Tan 36 = \(\frac{10}{x}\)

x = \(\frac{10}{Tan 36}\)

  = \(\frac{10}{0.7265}\)

x = 13.765

Therefore the side LP ≅ 14.

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Answer:

Step-by-step explanation:

You want to identify the graphs that go with each of these functions, along with a particular point on the curve.

The equations are written here in standard form, factored form, and vertex form. (The "factored form" is sometimes called "intercept form.") Each of these forms can be analyzed for characteristics relevant to identifying the corresponding graph.

In general, we can readily identify the opening direction, based on the sign of the leading coefficient. Depending on the form, we can also identify zeros, the vertex, and the y-intercept.

The line of symmetry (x-coordinate of the vertex) of the equation in the form ax² +bx +c is x = -b/(2a). That is, it will be left of the y-axis when the coefficients 'a' and 'b' have the same sign.

The graph of equation A will be graph 4, the only one with its vertex left of the y-axis. The y-intercept is the constant: point S = (0, 9).

Equation B has a positive leading coefficient, so opens upward. The zeros of the factors are -3 and +9, so identify the places where the graph crosses the x-axis. Graph 3 is the only one that opens upward and has x-intercepts. Point R is (9, 0).

The vertex form of a quadratic is ...

  y = a(x -h)² +k . . . . . . . vertex (h, k); leading coefficient 'a'

Equation C has its vertex at (h, k) = (3, 9) and opens upward (a>0). Graph 1 is the only one matching those characteristics. Point P is the vertex, so point P is (3, 9).

Equation D is the same as equation B, but with a negative leading coefficient. That is, it opens downward and crosses the x-axis in two places, at x = -3 and x = 9. Graph 2 is matches this description. The left zero is point Q, (-3, 0).

<95141404393>

The area of the circle circumscribed about the right triangle with legs 6 and 8 is approximately 78.54 square units.

To find the area of the circle circumscribed about a right triangle, we can use the fact that the diameter of the circle is equal to the hypotenuse of the right triangle. In this case, the legs of the right triangle are given as 6 and 8.

Using the Pythagorean theorem, we can find the length of the hypotenuse:

\(c^2 = a^2 + b^2\)

where c is the length of the hypotenuse, and a and b are the lengths of the legs.

Substituting the values:

\(c^2 = 6^2 + 8^2\)

\(c^2 = 36 + 64\\ c^2 = 100\)

Taking the square root of both sides:

\(c = \sqrt{100} \\ c = 10\)

Therefore, the length of the hypotenuse is 10 units.

Since the diameter of the circumscribed circle is equal to the hypotenuse, the radius of the circle is half the length of the hypotenuse, which is 10/2 = 5 units.

Now we can calculate the area of the circle using the formula:

Area = π \(r^2\)

where r is the radius of the circle.

Area = π \(5^2\)

Area = π × 25

Area = 78.54 square units

Hence, the area of the circle circumscribed about the right triangle with legs 6 and 8 is approximately 78.54 square units.

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Answer:

C infinite solutions

Step-by-step explanation:

First put both equations in the form of y=mx+b then you will get the same equation in both. Since both equations are the same they intersect at all the points which means this system has infinite solutions.

Answer: 2a < 2b

Step-by-step explanation:

We are given a statement:

a < b and b < c, then 2a ____ 2b

We can use simple numbers that make the statement true.

Where,

a = 2

b = 3

c = 4

Now lets plug it in.

2 < 3 and 3 < 4, then 2(2) ____ 2(3)

and lets simplify:

2 < 3 and 3 < 4, then 4 ____ 6

We can see that 4 is less than 6,

so as a is less than b, 2a is less than 2b.

The only thing changing is the coefficient being multiplied by the variables a and b.

See below for the appropriate and correct question.

Suppose that, next month, the technology group will receive 24 requests for help with computer problems. Among, these, 19 are software related and 5 are hardware problems. If a novice in the group is randomly assigned to 3 problems, what are the probabilities that she will address:

a. none of the hardware problems?

b. only one of the hardware problems?

Answer:

a. the probabilities that she will address none of the hardware problems 0.4788

b. the probabilities that she will address only one of the hardware problems 0.4224

Step-by-step explanation:

From the information given:

Let represent R to be the total number of request received.

i.e. R = 24

Let the number of hardware problems be p = 5

Let the number of the randomly assigned problem be m = 3

Then, we can compute the probability mass function of a hypergeometric distribution by using the formula:

\(h(x,m,p,R) = \dfrac{ (^p_x) (^{R-p}_{m-x}) }{^R_m}\)  where x can be 0,1,2,3...

Thus;

\(h(x,3,5,24) = \dfrac{ (^5_x) (^{24-5}_{3-x}) }{(^{24}_3)}\)

(a). To find the probability that she will address none of the hardware problems; we have:

x = 0

Then:

\(h(0;3,5,24) = \dfrac{ (^5_0) (^{24-5}_{3-0}) }{(^{24}_3)}\)

\(h(0;3,5,24) = \dfrac{ (^5_0) (^{19}_{3}) }{(^{24}_3)}\)

\(h(0;3,5,24) = \dfrac{ \dfrac{5!}{0!(5-0)!} \times \dfrac{19!}{3!(19-3)!} }{\dfrac{24!}{3!(24-3)!}}\)

\(h(0;3,5,24) = \dfrac{ 1 \times 969 }{2024}\)

\(h(0;3,5,24) = 0.4788\)

b) To find the probability that she will address only one of the hardware problems; we have:

x = 1

Then:

\(h(1;3,5,24) = \dfrac{ (^5_1) (^{24-5}_{3-1}) }{(^{24}_3)}\)

\(h(1;3,5,24) = \dfrac{ (^5_1) (^{19}_{2}) }{(^{24}_3)}\)

\(h(1;3,5,24) = \dfrac{ \dfrac{5!}{1!(5-1)!} \times \dfrac{19!}{2!(19-2)!} }{\dfrac{24!}{3!(24-3)!}}\)

\(h(1;3,5,24) = \dfrac{ 5 \times 171 }{2024}\)

\(h(1;3,5,24) = 0.4424\)

Answer:

67 cents

Step-by-step explanation:

Answer:

67 cents

Step-by-step explanation:

im smart

Answer:

y = -12x -77

Step-by-step explanation:

-5 - -7/-6 - -7 = -12

slope = -12

y = mx + b

Subsutitue

7 = -12 ⋅ -7 + b

b = -77

good luck, i hope this helps :)

The equation of the regression line is y = 4 + x and the regression analysis of the given data need not be done.

Straight line equation is y = a + bx.

The normal equations are

∑y = a·n + b ∑x ∑ xy = a ∑x + b∑x² Hence the regression analysis of the data :

The values are calculated using the following table

x y x²             x⋅y

58 62 3364 3596

47 51 2209 2397

84 88 7056 7392

62 66 3844 4092

57 61 3249 3477

72 76 5184 5472

69 73 4761 5037

hence :

∑x = 449

∑y = 477

∑x² = 29667

∑x⋅y = 31463

Substituting these values in the normal equations

7a+449b=477

449a+29667b=31463

Solving these two equations using Elimination method,

7a+449b=477

and 449a+29667b=31463

7a+449b=477→(1)

449a+29667b=31463→(2)

equation(1)×449

⇒3143a+201601b=214173

equation(2)×7

⇒3143a+207669b=220241

Substracting

⇒-6068b = -6068

⇒6068b = 6068

⇒b = 1

Putting b = 1 in equation (1), we have

7a+449(1) = 477

⇒7a = 477  - 449

⇒7a = 28 or a  = 4.

Now Estimate y for x=50

y = a + bx , we get

y = 4 + 1×50

y = 4 + 50

y = 54

At x equals 50 we get the value of y as 54 .

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Answer:

oi mate

for the 1st one its "it means that there are 36 cookies in 3 dozen"

for the 2nd one its"(1,12) since 1 is the start and 12 is the beginning

Step-by-step explanation:

Answer:

  t ≈ 0.0664731

Step-by-step explanation:

Use the inverse sine function.

  sin(12t) = 141/197

  12t = arcsin(141/197)

  t = arcsin(141/197)/12

  t ≈ 0.0664731 . . . . . . . radians

__

This is the principal value. There are other solutions at values of t that have integer multiples of π/6 added to this. There are also solutions where any of those values is subtracted from π.

_____

In general, angles in math are assumed to be in radians, unless specified otherwise. This angle corresponds to about 3.81°. (In geometry, the usual assumption is that angles are measured in degrees.)

The probability that Isaiah will make both penalty kicks, as simulated by flipping two fair coins 20 times, is 25%.

Since Isaiah scores with a 50% success rate on penalty kicks, the probability of him scoring a goal on any given penalty kick is 0.5 or 50%.

If he flips two fair coins to simulate 20 trials, there are four possible outcomes: HH (two goals), HT (one goal and one miss), TH (one goal and one miss), and TT (two misses).

Out of the 20 trials, there are two possible ways for Isaiah to score both of his penalty kicks: HH and HH. The probability of getting HH on two coin flips is (0.5) x (0.5) = 0.25 or 25%.

Therefore, the probability that Isaiah will make both penalty kicks, as simulated by flipping two fair coins 20 times, is 25%.

Expressed as a percentage, this is:

P(two goals) = 25%

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Answer:

A

Step-by-step explanation:

For a right triangle

\(A=\frac{ab}{2} \\\frac{(10.4)(15.3)}{2} =79.56\)

This is the same as the other triangle because they are the same size because of congruency

Area of the rectangle

\(a^2+b^2=c^2\\\)

\(\sqrt{(10.4^2+15.3^2} =c\)

\(c= 18.5\)

18.5 x 7 = 129.5

Add them all up

129.5+79.56+79.56= 288.62

The probability that a defective component will be detected only by the first inspector is 0.19

The probability that a defective component will be detected by exactly one of the two inspectors is 0.38

The probability that all three defective components in a batch escape detection by both inspectors is 0.

It is given that The first inspector detects 81% of all defectives that are present, and the second inspector does likewise.

Therefore P(A)=P(B)=81%=0.81

At least one inspector does not detect a defect on 38% of all defective components.

Therefore, bar P(A∩B)=0.38

As we know:

bar P(A∩B)=1-P(A∩B)=0.38

P(A∩B)=1-0.38=0.62

A defective component will be detected only by the first inspector.

P(A∩barB)=P(A)-P(A∩B)

=0.81-0.62

P(A∩barB)=0.19

The probability that a defective component will be detected only by the first inspector is 0.19

Part (B) A defective component will be detected by exactly one of the two inspectors.

This can be written as: P(A∩barB)+P(barA∩B)

As we know:

P(barA∩B)=P(B)-P(A∩B) and P(A∩bar B)=P(A)-P(A∩B)

Substitute the respective values we get:

P(A∩ barB)+P(bar A∩B)=P(A)+P(B)-2P(A∩B)

=0.81+0.81-2(0.62)

=1.62-1.24

P(A∩ barB)+P(bar A∩B)=0.38

The probability that a defective component will be detected by exactly one of the two inspectors is 0.38

Part (C) All three defective components in a batch escape detection by both inspectors

This can be written as: P(bar A∪ bar B)-P(bar A∩B)-P(A∩ barB)

As we know bar P(A∩B)=P(bar A∪ bar B)=0.38

From part (B): P(bar A∩B)+P(A∩bar B)=0.38

This can be written as:

P(bar A∪ bar B)-P(bar A∩B)-P(A∩bar B)=0.38-0.38=0

The probability that all three defective components in a batch escape detection by both inspectors is 0

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