If an object travels along a surface, then the kinetic frictional force does work on the object.
This work is negative because it opposes the direction of motion of the object.
The negative sign indicates that the work done by friction is a loss of mechanical energy of the system, which is converted into heat. Therefore, the kinetic frictional force always opposes the motion of the object and reduces its kinetic energy.
This is why it is important to minimize frictional forces in many applications, such as engineering design and sports equipment, to improve performance and efficiency.
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: Prove that the following paraboloid coordinate system (u, v, ϕ):
x = u.v cosϕ
y = u.v sinϕ
z = 1/2 (u2 - v2)
is orthogonal, and then find the following:
1. The scale factors
2. Gradient
3. Divergent
4. Curl
5. Laplacian
The given paraboloid coordinate system (u, v, ϕ) with x = u.v cosϕ,
y = u.v sinϕ , z = 1/2 (u2 - v2) is orthogonal. The gradient is ∇f = (∂f/∂u) e_u + (∂f/∂v) e_v + (∂f/∂ϕ) e_ϕ ; divergent is ∇²f = ∇ · (∇f) ; curl is (∇ x) and laplacian is (∇²).
We can prove that the paraboloid coordinate system (u, v, ϕ) is orthogonal, by computing the dot products of the basis vectors. The basis vectors in this coordinate system are given by:
e_u = (∂x/∂u, ∂y/∂u, ∂z/∂u) = (v cosϕ, v sinϕ, u)
e_v = (∂x/∂v, ∂y/∂v, ∂z/∂v) = (u cosϕ, u sinϕ, -v)
e_ϕ = (∂x/∂ϕ, ∂y/∂ϕ, ∂z/∂ϕ) = (-u.v sinϕ, u.v cosϕ, 0)
By Taking the dot products, we find that e_u · e_v = 0, e_v · e_ϕ = 0, and e_ϕ · e_u = 0. This proves that the basis vectors are mutually perpendicular, and therefore, the coordinate system is orthogonal.
Next, we can calculate the gradient (∇) in this coordinate system. The gradient of a scalar function f(u, v, ϕ) is given by:
∇f = (∂f/∂u) e_u + (∂f/∂v) e_v + (∂f/∂ϕ) e_ϕ
The divergence (∇ ·) and curl (∇ x) can be computed using the standard formulas in terms of the basis vectors. Finally, the Laplacian (∇²) can be obtained by taking the divergence of the gradient:
∇²f = ∇ · (∇f)
Thus, By evaluating these operations in the given coordinate system using the appropriate partial derivatives, we can determine the gradient, divergent, curl, and Laplacian for any scalar function in the (u, v, ϕ) coordinates.
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Name one benefit and one risk of each biotechnology practice:
Genetic engineering:
Cloning:
Artificial selection:
PLEASE!!!!!!!!!!!!!!!!!!!!!!!
Answer:
Genetic Engineering:
Benefits: More nutritious food, less use of pesticides, increased supply of food with reduced cost and longer shelf life, faster growing plants and animals
Risk: Creating foods that can cause allergic reaction or that are toxic, Unexpected ir harmful genetic changes, genes moving from one GM plant or animal to anotherplant or animal that is not genetically engineered
Cloning:
Benefits: accelerated reproduction of farmers productive livestock to better produce safe and healthy foods, reproduction of the healthiest animals, minimizing the use of antibiotics, growth hormones and chemicals
Risks: Unwantedhealty effects, defects, premature aging and problems with the immune system
Artificial Selection:
Benefits: no safety issues as those brought by genetic engineering, cheap for agricultural businesses, morally accepted, produce crops with higher yield
Risks: Removes variation, makes organism susceptible to diseasesor changes in environment, unable to control genes inherited by offspring
Answer:
Genetic Engineering
Benefits
-Ability to create food that is resistant to pests, cold, and disease.
-Greater food production volume and increased vitamins.
Risks
-Concerns about long-term health risks.
-Lack of regulation.
Cloning
Benefits
-Ability to increase endangered animal populations.
-Possibility of eliminating diseases and defective genes.
Risks
-Shorter lifespan for cloned animals.
-Greater chance of health issues for cloned animals.
Artificial Selection
Benefits
-Allows for selection of desired traits.
-Ability to create better versions of organisms.
Risks
-Loss of genetic diversity.
-Increased chance of diseases that can shorten lifespan.
Explanation:
How are earthquake epicenters active volcanoes and mountain ranges distributed on the map?
Answer:
Volcanoes and earthquakes are not randomly distributed around the globe.
Explanation:
Instead they tend to occur along limited zones or belts. With the understanding of plate tectonics, scientists recognized that these belts occur along plate boundaries.
20.) In an experiment that measures how fast a student reacts, a meter stick dropped
from rest falls 0.20 meter before the student catches it. The reaction time of the student approximately
a)0.30s
b)0.20s
c)0.10s
d)0.40s
The reaction time of the student is approximately 0.2 s (Option B)
How do I determine the reaction time of the student?Considering the question given above, the following formula can be use to obtain the time
h = ½gt²
Where
h is the heightg is the acceleration due to gravityt is the timeNow, let us calculate the reaction time of the student. This is shown below:
Height (h) = 0.20 meterAcceleration due to gravity (g) = 9.8 m/s²Reaction time (t) = ?h = ½gt²
0.20 = ½ × 9.8 × t²
0.20 = 4.9 × t²
Divide both side by 4.9
t² = 0.20 / 4.9
Take the square root of both side
t = √(0.20 / 4.9)
t = 0.2 s
Thus, the reaction time is 0.2 s (Option B)
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what property of earthquakes does the richter scale measure?
The Richter scale measures the magnitude of an earthquake, which is a measure of the energy released by the seismic waves generated by the earthquake.
What is the measures ?Measures are the steps taken to achieve a desired outcome. They can be in the form of legislation, policies, regulations, practices, procedures, and processes. They are used to implement and enforce objectives, goals, and strategies, and can be both proactive and reactive. Measures can be utilized by governments, businesses, and individuals to ensure desired outcomes are achieved in a timely and cost-effective manner. Measures can also be used to monitor progress and evaluate the effectiveness of policies and procedures.
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how would sunspots appear if you could magically remove them from the sun?
If we could magically remove sunspots from the sun, it would appear smoother and more uniform in its brightness. Sunspots are darker, cooler regions on the sun's surface caused by magnetic activity, which creates areas of intense magnetic fields that suppress the movement of heat and gas.
Removing sunspots would affect the sun's overall magnetic field, which could potentially impact the sun's activity and influence space weather. Sunspots are closely related to solar flares and coronal mass ejections, which can cause disruptions in communication and navigation systems on Earth.
However, it is important to note that sunspots are a natural occurrence of the sun and play a significant role in regulating the sun's temperature and energy output. Removing them could have unintended consequences and may not be a practical solution.
Instead, scientists study sunspots to better understand the sun's behavior and predict potential space weather events. They use tools such as the Solar Dynamics Observatory to monitor the sun's activity and gather data that can inform space weather forecasts and help protect our technological infrastructure.
In conclusion, while removing sunspots may seem like a solution, it is important to consider the potential consequences and the valuable role they play in our understanding and management of the sun's behavior.
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the temperature of two bodies differ by 1°c. how much will they differ in Fahrenheit?
Answer:
the answer is 1.8°f...
Answer:
33.8 degrees.
Explanation:
Which of the following is not a factor that is required for the formation of hurricanes?
A: Very high winds in the upper atmosphere
B: Ocean temperatures of atleast 80 degrees F
C: Low winds in the upper atmosphere
D: Warm, moist air
Answer:
Either A or D
Explanation:
Answer:
c
Explanation:
its c because high winds foRM A HURRICAN AND WARM TO AND ESPECIALY IF IT IS 80 DEGRESES
two concentric spherical surfaces enclose a point charge q. the radius of the outer sphere is twice that of the inner one. compare the electric fluxes crossing the two surfaces.
The electric flux crossing the outer sphere is four times greater than the electric flux crossing the inner sphere.
Electric flux is defined as the total number of electric field lines passing through a surface. In this scenario, we have two concentric spherical surfaces encircling a point charge q, with the radius of the outer sphere being twice that of the inner sphere. As we know, the electric field of a point charge decreases with the square of the distance from the point charge. Therefore, the electric field at the outer sphere is four times weaker than the electric field at the inner sphere, as the distance between the point charge and the outer sphere is twice that of the inner sphere.
Now, the electric flux crossing a surface is directly proportional to the strength of the electric field passing through the surface and the area of the surface. As the electric field at the outer sphere is four times weaker than the electric field at the inner sphere, but the surface area of the outer sphere is four times greater than the surface area of the inner sphere, the electric flux crossing the outer sphere is four times greater than the electric flux crossing the inner sphere.
In conclusion, the electric flux crossing the outer sphere is four times greater than the electric flux crossing the inner sphere. This is because the electric field at the outer sphere is four times weaker than the electric field at the inner sphere, but the surface area of the outer sphere is four times greater than the surface area of the inner sphere.
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What is the relationship between the speed of impact and the dropping height?
How is Earth’s outer layer DIFFERENT to a crack hard-boiled egg?
Answer:
no
Explanation:
Suppose that you have left a 200-mL cup of coffee sitting until it has cooled to 30âC , which you find totally unacceptable. Your microwave oven draws 1100 W of electrical power when it is running. If it takes 45 s for this microwave oven to raise the temperature of the coffee to 60âC , what is the efficiency of heating with this oven?
e=(what you get/what you had to pay)
A) Which of the following is the quantity you would label as "what you got"?
B) Which of the following is the quantity you would label as "what you had to pay"?
C) Find the efficiency e of the oven. You will need to use the fact that 4.2 J of energy is required to raise the temperature of 1.0 mL of coffee by 1.0âC .
D) The oven draws 1100 W of power, and you have determined that it heats with an efficiency of 51%. Using this information, determine the time t it would take to bring 240 mL of water from 25âC to 100âC . Note that 4.2 J of energy is required to raise the temperature of 1.0 mL of water by 1.0âC (the same as for the coffee above).
A) The quantity labeled as "what you got" is the increase in thermal energy of the coffee, which is given by the equation:
ΔQ = mcΔT
where m is the mass of the coffee, c is the specific heat capacity of coffee (assumed to be the same as water), and ΔT is the temperature increase.
B) The quantity labeled as "what you had to pay" is the electrical energy consumed by the microwave oven, which is given by the equation:
E = Pt
where P is the power of the microwave oven and t is the heating time.
C) We can first calculate the thermal energy gained by the coffee:
ΔQ = mcΔT = (0.2 kg)(4.2 J/g°C)(60°C - 30°C) = 504 J
Next, we can calculate the electrical energy consumed by the microwave oven:
E = Pt = (1100 W)(45 s) = 49500 J
The efficiency of heating is then:
e = ΔQ/E = 504 J/49500 J = 0.0102 or 1.02%
D) We can use the same equations as above, but solve for the heating time instead of the efficiency:
ΔQ = mcΔT = (0.24 kg)(4.2 J/g°C)(100°C - 25°C) = 2268 J
E = Pt = (1100 W)t
e = ΔQ/E = 0.51 = 2268 J/(1100 W)t
Solving for t, we get:
t = ΔQ/(0.51E) = 2268 J/(0.51)(240 mL)(4.2 J/g°C)(75°C)(1 kg/L)(1100 W/s) = 925 seconds or 15.4 minutes.
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Which one does not affect the gravitational force between the 1 point
earth and the sun? *
The mass of the earth
The mass of the sun
The distance between the earth and the sun
The net electrical charge of the earth
Answer:
D. The net electrical charge of the Earth.
Explanation:
All the other three choices affect the gravitational force. I remember from middle school.
Two coils A and B are wound side by side. Coil A has 8120 turns and coil B has 11842 turns. 54% of flux produced by coil A links coil B. A current of 6 A in coil A produces 0.02 mWb, while the same current in coil B produces 0.078 mWb. a) Calculate the mutual inductance and the coupling coefficient. b) Calculate the emf induced in coil B when the current is reversed in 0.015 seconds.
a) Mutual inductance = 0.108 H; Coupling coefficient = 0.482. b) - 4.95 V.
a) Mutual inductance, M between coil A and coil B can be given as:
M = k√(L_AL_B) here, k is the coupling coefficient, L_A and L_B are the inductances of the coil A and coil B respectively. Since 54% of flux produced by coil A links coil B,
So, K = 0.54
L_A = N_A Φ/I_AL_A
= 8120 × 0.02/6
= 27.07 mH
L_B = N_B Φ/I_BL_B
= 11842 × 0.078/6
= 154.63 mH
M = k√(LALB) = 0.482 × √(27.07 × 0.15463) = 0.108 H
b) The emf induced in coil B can be given as:-
ε = M (dI_B/dt)/L_B
ε = 0.108 × (-6/0.015) / 0.15463 = -4.95 V
Thus, the emf induced in coil B when the current is reversed in 0.015 seconds is -4.95 V.
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a 5.00 kg mass is at the origin. a 7.00 kg mass is located at x = 0.600 m, and a 4.00 kg mass is at x = 0.900 m. What is the net gravitational force on the 5.00 kg mass?
Answer:
Given,
A 5 kg mass is at the origin. A 7 kg mass is located at x = 0.6 m and a 4 kg mass is at x = 0.9 m.
To find,
the net gravitational force on the 5 kg mass.
we know, from Newton's gravitational law, two massive bodies attract each other by a force , F = Gm₁m₂/r²
so, 7 kg mass attracts 5kg mass by the force, F₁ = G(7kg)(5kg)/(0.6)²
= 35G/0.36 = 97.22G
similarly, 4kg mass attracts 5kg mass by the force, F₂ = G(4kg)(5kg)/(0.9)²
= 20G/0.81 = 24.69G
net gravitational force = F₁ + F₂
= 97.22G + 24.69G
= 121.91G
we know, G = 6.67 × 10¯¹¹ Nm²/Kg²
F = 121.91 × 6.67 × 10¯¹¹
= 813.1397 × 10¯¹¹ N
= 8.131397 × 10^-9 N ≈ 8.13 × 10^-9 N
Therefore net gravitational force acting on mass 5kg is 8.13 × 10^-9 N
Please correct answers only, if you don’t know, ignore. Please answer this or am I correct?
Answer:
C is correct.
Explanation:
Some drops a ball off of the top of a 125-m-tall building. In this prob-lem, you will be solving for the time it takes the ball to hit the ground.(a)Define your coordinate system, be thorough.(b)Write down the given infor-mation, be sure to include hidden information.(c)State what physics principleis at play here. How do you know this?(d)Select an equation.(e)Solve forthe time it takes for the ball to hit the ground.
Answer:
t = 5.05 s
Explanation:
This is a kinetic problem.
a) to solve it we must fix a reference system, let's use a fixed system on the floor where the height is 0 m
b) in this system the equations of motion are
y = v₀ t + ½ g t²
where v₀ is the initial velocity that is v₀ = 0 and g is the acceleration of gravity that always points towards the center of the Earth
e) y = 0 + ½ g t²
t = √ (2y / g)
t = √(2 125 / 9.8)
t = 5.05 s
A pitcher throws a ball toward a player holding a softball bat. The bat applies a 10-Newton force to the ball. Which statement correctly describes the reaction force between the bat and the ball?
Answer:
The reaction force is the force that causes the ball to move toward the bat.
Explanation:
Answer:
D; the reaction force is the force of the ball on the bat.
Explanation:
In the process of making a rainbow, light enters the water droplet at location 1 and exits at location 3. Which
of the following choices correctly identifies the sequence of interactions that produce the rainbow?
Answer: D, Refraction, Reflection, Refraction.
Explanation: Refraction is a rainbow. See image for info.
A series circuit consists of a 0.55 h inductor with internal resistance of 8.0 ω connected in series with a 4.0 ω resistor, an open switch, and an ideal 12 v batterya. When the switch is closed, what is the initial current through the 4.0-ohm resistor? b. What is the current through the 4.0-ohm resistor a very long time after the switch is closed?
Part a) When the switch is closed, the initial current through the 4.0-ohm resistor is 0 A.
Part b) The current through the 4.0-ohm resistor a very long time after the switch is closed is 1 A.
What is the best way to define a series circuit?A series circuit has each load in a separate row. The flow of electricity has only ONE path. If this circuit were a row of light bulbs, the others would all go out if one of the bulbs blew.
What drawbacks come with using a series circuit?The first drawback of a series circuit is that if one component fails, the entire circuit will fail because the circuit is broken. The second drawback is that the resistance of a series circuit increases with the number of components in the circuit.
Part a)
We know that the inductor in a series circuit resists the abrupt change in current according to Lenz's law.
Additionally, if the flux in the circuit changes, it will create a reverse EMF to create the opposite current in the circuit.
When the switch is shut off at time t = 0,
then initially it will generate the opposing EMF so that the circuit's net EMF is zero.
therefore, the current is zero.
Part b).
The induced EMF in the circuit will eventually reach zero because the flow will stay constant,
Therefore, we may state
\(EMF= i(R_1+R_2)\)
\(12= i(8+4)\)
\(i= \frac{12}{12}\)
\(i=1A\)
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on bode's advice, herschel named his newly discovered planet after:
Answer:
On Bode's advice, Herschel named his newly discovered planet after: the Greek god Uranus.
Explanation:
Herschel named his newly discovered planet Uranus on Bode's advice for a couple of reasons:
Mythological Naming Convention: During that time, it was a common practice to name celestial objects after mythological figures, particularly gods from Greek and Roman mythology. Bode suggested following this convention and recommended that Herschel choose a name from Greek mythology for the newly discovered planet.
Connection to the Sky: Uranus was chosen as the name for the planet because it was the name of the Greek god of the sky. Given that Herschel had discovered a celestial object in the sky, naming it after the god associated with the sky seemed fitting.
By naming the planet Uranus, Herschel paid homage to the mythological tradition of naming celestial bodies while also establishing a connection between his discovery and the vastness of the sky.
Hope this helps!
How long does it take a earth to rotate on its axis?
Answer:
23 hours, 56 minutes about 24 hours
Explanation:
(Im sorry if this is wrong please correct me if so. Good Luck)
The average distance between Earth and its moon is 384,000,000 meters. Express this distance in kilometers.
Answer: 384 400 km.
Explanation: The awnser is 384 400 kilometers
10C of charge flow through a resistor in 4 seconds. What is the current?
Answer:
Very simple. The charge Q= 20 C. the formula for Q= I* t. now I= Q/t = 20/1s = 20 Amps.
Explanation:
The current given that the charge is 10C and the time is 4 seconds is gotten as Current = 2.5 Amps
Given Data
Charge = 10 Columbs
Time = 4 seconds
Current = ?
Current, charge and time RelationshipElectrical current is defined by how much electric charge has been transferred per second, giving the following relationship:
Charge = Current*Time
Rearranging this we get:
Current = Charge/Time
The symbol for charge is Q , it is measured in coulombs (C).
The symbol for current is I , it is measured in amperes (A).
The symbol for time is T, it is measured in seconds (s).
Substituting our given Data into the expression we have
Current = 10/4
Current = 2.5 Amps
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A position versus time graph is shown:
Position vs. Time
1 15
10
10
Time (seconds) ->
Which statement accurately describes the motion of the object in the graph above?
O It is at rest for 3 seconds before moving at constant speed for 10 seconds.
It is at rest for 3 seconds before moving at constant speed for 4 seconds.
Olt is moving from 0 cm to 5 cm at constant speed of 7 cm/s.
O it is moving from 0 cm to 3 cm at a constant speed of 3 cm/s.
Answer: Answer: The object moves forward at 5 m/s, stops, and then changes velocity.
Explanation:
With the information given in the question we can graph the points (image attached).
As we can observe, in the first segment of the graph the velocity is increasing linearly (at a constant rate) and is 5 m/s, then in the second segment we can see the position of the object remains the same from second 2 to second 4, which means the object is stopped.
Finally, in the third and last segment, we can observe a change in velocity (at a negative constant rate, because is decreasing), which is decreasing until the object stops.
Explanation:
please help A 10 kg box initially at rest is pulled with a 50 N horizontal force for 4 m across a level surface. The force of friction acting on the box is a constant 20 N. How much work is done by the gravitational force?
A. 100 J
B. 0 J
C. 10 J
D. 50 J
The box is being pulled horizontally, so any work done on the box must be done by forces that are parallel to the ground. But gravity always points downward, which is perpendicular to the surface in this case, so the gravitational force performs B. 0 J of work.
A 0.50 kilogram ball is held at a height of 20 meters. What is the kinetic energy of the ball when it reaches halfway after being released?
A.
49 joules
B.
98 joules
C.
1.0 × 102 joules
D.
1.1 × 102 joules
Answer:
A
Explanation:
Use the conservation of energy formula to calculate the velocity of the ball when it reaches the halfway point (10m down). Then, use your calculated value to obtain the kinetic energy.
Answer:
A. 49 on Plato
Explanation:
Its the right one trust me .
adrienne (50kg) and bo (90 kg) are playing on a 100 kg rigid plank resting on supports. if adrienne stands on the left end, can bo walk all the way to the right end without the plank tipping over? if not, how far can he get past the support on the right?
The distance from the left support is greater than 49/9 meters, then the plank will tip over.
When responding to questions on the Brainly platform as a question-answering bot, it is important to be factually accurate, professional, friendly, and concise. Irrelevant parts of the question or typos should not be ignored.
Additionally, using relevant terms from the question in the answer is important to ensure that the answer is clear and specific.Here is a possible answer to the student question: Adrienne (50 kg) and Bo (90 kg) are playing on a 100 kg rigid plank resting on supports.
If Adrienne stands on the left end, can Bo walk all the way to the right end without the plank tipping over? If not, how far can he get past the support on the right?Assuming that the plank is uniform and mass is distributed uniformly,
the weight of the plank can be taken to be halfway between Adrienne and Bo, which is 70 kg. Using the principle of moments, the torque due to Adrienne is equal to the torque due to Bo when the plank is balanced. Thus,
the product of the weight and distance of Adrienne from the pivot point (left support) is equal to the product of the weight and distance of Bo from the pivot point. Therefore,50 kg × d1 = 90 kg × d2where d1 and d2 are the distances of Adrienne and Bo from the left support, respectively.
The total distance of the plank from left to right is L, which is the sum of the distances from the left support to the right support, and is 2d2. Thus, L = 2d2.
When the plank is about to tip over, the torque due to Bo is equal to the maximum torque that the plank can withstand before tipping over, which is the product of half the weight of the plank and half the length of the plank, that is,70 kg × L/2.
Therefore,90 kg × d2 = 70 kg × L/2.
Substituting L = 2d2,
we obtain90 kg × d2 = 70 kg × 2d2/2= 70 kg × d2Bo can walk all the way to the right end without the plank tipping over if his distance from the left support, d2, is less than or equal to 49/9 meters (approximately 5.44 meters).
This means that he can walk 50/9 meters (approximately 5.56 meters) past the right support before the plank tips over.
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ocean acidification impacts corals in what major way?
A student with a body mass of 74.0 kilograms climbed several flights of stairs to a final height 7.0 meters from the bottom. A second
student, using a stopwatch, determined that the climb was completed in 13.0 seconds. The body mass, time, and vertical height
reached by the student is given in the table. (Estimate g as 10 m/s2)
How many watts of power were generated by the student during the climb?
Answer:398.5 watts
Explanation: