SCIENCE
why is it important to distinguish the two types of crust?

The hydrogen emission lines in decreasing order of strength are as follows :Balmer α, Balmer β, Balmer γ, Balmer δ and Balmer ε. At a lower energy level, hydrogen is excited by heating or a spark, causing its electrons to jump to higher energy levels.

These electrons subsequently emit photons in the visible, ultraviolet, and infrared regions of the electromagnetic spectrum when they drop back to their lower energy levels.Atomic spectroscopy is a spectroscopic method that examines the spectrum of an atom in the gas phase by absorbing or emitting radiation.  

It is a method of elemental analysis that is widely used in the laboratory and industry to determine the presence and concentration of trace elements in a sample. Atomic spectroscopy is divided into three categories: atomic absorption, atomic emission, and atomic fluorescence. All three techniques involve irradiating a sample with radiation of a specific frequency, resulting in the excitation or ionization of atoms or ions. The difference between the techniques is how the sample's interaction with the radiation is measured.

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Answer:

A-Red and blue marbles in the same container.

Explanation:

(Apex)

Answer:

animals

Explanation:

I think I remember this from a quiz I took so exotic species

Answer:

Explanation:

Equation (given) :

Compare the LHS and RHS :

Balanced Equation :

The frequency of electromagnetic radiation with a wavelength of 2.3 m is 1.3 x 10^8 s^-1.The frequency of electromagnetic radiation is determined by the wavelength, according to the formula f=c/λ, where f is frequency, c is the speed of light, and λ is wavelength.

Using this formula, we can find the frequency of electromagnetic radiation with a wavelength of 2.3 m.

f=c/λ
f=3.00 x 10^8 m/s / 2.3 m
f=1.3 x 10^8 s^-1

Therefore, the frequency of electromagnetic radiation with a wavelength of 2.3 m is 1.3 x 10^8 s^-1.

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Answer:

Evaporation

Explanation:

because the ammonia is left unclosed

The smell of ammonia has been spread from a corner to entire room by the process of diffusion. Thus, option B is correct.

Ammonia has been the liquid compound with the formula \(\rm NH_4\). It has a pungent smell. Ammonia has been used in several synthesis reactions, and in various industrial processes.

The diffusion has been the process of transfer of molecules from higher concentration to lower concentration. The smell of ammonia has been spread in the entire laboratory from a corner.

The ammonia molecules in the bottle are at higher concentration while there has been lower concentration of ammonia in the environment. With the process of diffusion there has been the transfer of ammonia molecules in the environment.

Thus, diffusion has been responsible for spreading the smell of ammonia in the laboratory from a corner. Thus, option B is correct.

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Surface-activated silicon wafers were bonded firmly and void-free by MMR Howlader from room temperature to annealing at 600 °C, followed by analysis of the interface's optical, electrical, mechanical, and nanostructure properties.

What is annealing?

In the fields of metallurgy and materials science, annealing is a heat treatment that modifies the physical and occasionally chemical properties of a material to enhance its ductility and decrease its hardness, making it more workable.

Annealing is a heat-treatment procedure that modifies a material's physical, and occasionally chemical, properties to improve ductility and decrease hardness to make it more workable.

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The amount of calcium chloride in the supplied solution weighs 247.49 g is needed to make 785.7 g of a solution that is 31.5% cacl2 in water.

We receive:

Solution mass: 785.7 grams

Water contains 31.5% (m/m) calcium chloride as well.

This indicates that there are 31.5 g of calcium chloride in a 100 g solution.

We employ the unitary technique to determine the mass of calcium chloride in the specified volume of solution:

The mass of calcium chloride present in 100 g of solution is 31.5 g.

Therefore, in 785.7 g of solution, there are 785.7 g of calcium chloride.

31.5/100*785.7

= 247.49 g

Consequently,247.49 g  of calcium chloride are present in the given amount of solution.

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Antoine Lavoisier found that mass was conserved in chemical reactions when he saw that, the mass of the products was the same as that of the reactants. Correct answer: letter C.

This became known as the Law of Conservation of Mass, which states that matter is neither created nor destroyed in a chemical reaction, only rearranged. Lavoisier's findings were revolutionary, as they showed that chemical reactions could be quantified and studied, paving the way for modern chemistry.

Antoine Lavoisier was a French chemist who made many contributions to the field of science. One of his most famous discoveries was that mass is conserved in chemical reactions. This means that the mass of the products of a reaction is always the same as the mass of the reactants.

This is best illustrated by the example of the chemical reaction between sodium and chlorine to form table salt. In this reaction, a very reactive metal (sodium) combines with a poisonous gas (chlorine) and results in the formation of ordinary table salt (sodium chloride). This reaction demonstrates that mass is conserved in chemical reactions, because the mass of the products (sodium chloride) is the same as the mass of the reactants (sodium and chlorine).

Antoine Lavoisier found that mass was conserved in chemical reactions when he saw that?

A) heat was released in chemical reactions.

B) the products differed greatly from the reactants.

C) the mass of the products was the same as that of the reactants.

D) the mass of the products were heavier than the mass of the reactants.

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It became thicker and its viscosity decreased and cannot flow as easily as before.

You ignite a chemical reaction by adding the borax solution to the glue mixture.

In a chemical reaction, the molecules of glue and borax combine to form a flexible, springy new substance. With rubber's vulcanization serving as a model, chemical cross-linking has been extensively employed to change the physical properties of polymeric materials.

Chemical links between polymer chains provide a substance with a more solid structure and perhaps a better-defined shape. It thickened and lost viscosity, making it more difficult to flow than it once could.

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To solve this problem, we can use the combined gas law formula, which states that PV/T = constant, where P is pressure, V is volume, and T is temperature.

Since the temperature remains constant, we can rewrite the formula as P1V1 = P2V2, where the subscripts 1 and 2 represent the initial and final conditions, respectively.
Using the given values, we have:
P1 = 765 mmHg
V1 = 8.5 L
P2 = 729 mmHg
V2 = ?
Plugging these values into the formula, we get:
765 mmHg x 8.5 L = 729 mmHg x V2
Simplifying the equation, we get:
V2 = (765 mmHg x 8.5 L) / 729 mmHg
V2 = 9.4 L
Therefore, the new volume of the balloon is 9.4 liters when the atmospheric pressure drops to 729 mmHg.

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Answer:

I am not sure

Explanation:

ΔABC ~ ΔEFD

Dimethylsulfoxide has the formula C2H6SO.Therefore, the correct answer is option D: 25.4.

Option D.

To determine the mass percent of carbon in this compound, we need to calculate the molar mass of the compound first. Molar mass is the sum of the atomic masses of all the atoms in the molecule. We can use the periodic table to obtain the atomic masses. For this compound, the molar mass will be:2 (atomic mass of carbon) + 6 (atomic mass of hydrogen) + 32 (atomic mass of sulfur + 16 (atomic mass of oxygen) = 78 g/molNext, we need to determine the mass of carbon in one mole of the compound. We can do this by multiplying the number of carbon atoms by the atomic mass of carbon. In this case, there are 2 carbon atoms in one mole of the compound. Therefore, the mass of carbon in one mole of the compound is:2 (number of carbon atoms) x 12.01 (atomic mass of carbon) = 24.02 g/molFinally, we can calculate the mass percent of carbon in dimethylsulfoxide using the formula:mass percent of carbon = (mass of carbon / total molar mass) x 100%Substituting the values we obtained:mass percent of carbon = (24.02 g/mol / 78 g/mol) x 100% = 30.77%Rounding to three significant figures gives us a final answer of 30.7%.

Option D.

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Answer:

4.21

Explanation:

use Avogadro's number

6.023 x 10^23

multiply this by 7 because you want to find 7 moles :

6.023 x 10^23 x 7 = 4.21

Answer:

V=a3

Explanation:

sorry no explantion, but answer

The test statistic for the given hypothesis test is not provided.

The test statistic for testing the proportions in this hypothesis test is typically a z-statistic. To calculate the test statistic, we first need to compute the observed proportions in each category. In this case, the observed proportions are 20/200 = 0.10 in category A, 40/200 = 0.20 in category B, and 100/200 = 0.50 in category C.

Next, we need to compute the standard error of the difference between the observed proportions and the hypothesized proportions under the null hypothesis. The standard error is given by the formula:

\(SE = sqrt((p_A * (1 - p_A))/n_A + (p_B * (1 - p_B))/n_B + (p_C * (1 - p_C))/n_C)\)

where p_A, p_B, and p_C are the hypothesized proportions, and n_A, n_B, and n_C are the sample sizes in each category.

Once the standard error is calculated, we can compute the test statistic as:

test statistic = (observed proportion - hypothesized proportion)/SE

After obtaining the test statistic, we can compare it with the critical values or calculate the p-value to make a decision about rejecting or not rejecting the null hypothesis.

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The order of strength of hydrogen bonds, dispersion forces, and dipole-dipole forces is as follows: Hydrogen bonding , Dipole-dipole interactions ,London dispersion forces.

Hydrogen bonding: Hydrogen bonding is the strongest type of intermolecular force. It occurs when a hydrogen atom is covalently bonded to a highly electronegative atom (such as nitrogen, oxygen, or fluorine) and is attracted to another highly electronegative atom in a nearby molecule. An example of a molecule that exhibits hydrogen bonding is water (H2O). Dipole-dipole interactions: Dipole-dipole interactions are slightly weaker than hydrogen bonding, but still stronger than London dispersion forces. They occur between molecules that have permanent dipoles, or regions of partial positive and negative charge. An example of a molecule that exhibits dipole-dipole interactions is acetone (CH3COCH3). London dispersion forces: London dispersion forces are the weakest type of intermolecular force. They are attractive forces that occur between all types of molecules and result from the temporary separation of charge that occurs as a result of the movement of electrons within a molecule. An example of a molecule that exhibits London dispersion forces is hexane (C6H14).

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The mass percent of gold in the piece is 79.08%

The density of a substance is simply defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as

Density = mass / volume

Thus,

Mass = density × volume

Mass = density × volume

Mass of gold = 19.3 × V

Mass of gold = 19.3V

Mass = density × volume

Mass of silver = 10.5 × (1.25 - V)

Mass of silver = 13.125 - 10.5V

Mass of piece = mass of gold + mass of silver

20.5 = 19.3V + 13.125 - 10.5V

Collect like terms

19.3V - 10.5V = 20.5 - 13.125

8.8V = 7.375

Divide both sides by 8.8

V = 7.375 / 8.8

Volume of gold = 0.84 cm³

Thus,

Mass of gold = 19.3V

Mass of gold = 19.3 × 0.84

Mass of gold = 16.212 g

Mass percent of gold = (mass of gold / mass of piece) × 100

Mass percent of gold = (16.212 / 20.5) × 100

Mass percent of gold = 79.08%

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So, the molar mass of tetraethyl lead is

\(207.2+8(12.011)+20(1.00794)=\boxed{323.4468 \text{ g/mol}}\)

Answer: You would place the apple on the person's head.

Explanation:

The amount of heat absorbed to raise the temperature of 435 grams of water at 1 atm from 25°C to its boiling point, 100°C, is approximately 1.4 × 10^5 joules

What is specific heat?

Specific heat is the amount of heat energy required to raise the temperature of a substance by one unit of temperature per unit of mass. It is a physical property that helps to characterize a substance and is typically measured in units of joules per gram per degree Celsius (J/g°C) or calories per gram per degree Celsius (cal/g°C).

The amount of heat absorbed to raise the temperature of a substance can be calculated using the formula:

Q = mcΔT

where Q is the amount of heat absorbed (in joules), m is the mass of the substance (in kilograms), c is the specific heat capacity of the substance (in joules per kilogram per degree Celsius), and ΔT is the change in temperature (in degrees Celsius).

Substituting the given values, we get:

m = 435 grams = 0.435 kg

ΔT = 100°C - 25°C = 75°C

The specific heat capacity of water is 4.184 J/g°C. We can convert this to joules per kilogram per degree Celsius (J/kg°C) by dividing by 1000:

c = 4.184 J/g°C ÷ 1000 = 4.184 J/kg°C

Substituting these values, we get:

Q = (0.435 kg) × (4.184 J/kg°C) × (75°C)

Q = 140,089.2 J

Therefore, the amount of heat absorbed to raise the temperature of 435 grams of water at 1 atm from 25°C to its boiling point, 100°C, is approximately 1.4 × 10^5 joules. The answer closest to this value is option (B).

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Answer:

Manganese(II) sulfate and hydrogen gas.

Explanation:

Answer:

\({ \bf{ 2 Cl{}^{ - } _{(aq)} + Pb {}^{2 + } _{(aq)} \: ⟶ \: PbCl _{2(s)}}}\)

answer: bits of rock rusting when exposed to oxygen and water

Explanation: i think because when it rains the water is left and freezes and night making the rock expand or start to Rust

The carburizing time necessary to achieve a carbon concentration of 0.30 wt% at a position 4 mm into an iron-carbon alloy is 63.4 hours.

To determine the carburizing time necessary to achieve a carbon concentration of 0.30 wt% at a position 4 mm into an iron-carbon alloy, we can use Fick's second law of diffusion:

\(DC_{surface} / 2 = (C_{surface} - C_{4mm}) / erf(x / (2 * \sqrt{Dt} ))\\\)

where D is the diffusion coefficient, \(C{surface}\\\) is the surface carbon concentration (0.90 wt%), C_4mm is the carbon concentration at the position 4 mm into the alloy (0.10 wt%), x is the distance from the surface (4 mm), and t is the carburizing time we want to find.

We can use the diffusion coefficient for γ-Fe at 1100°C from Table 5.2, which is D = \(6.0 * 10^{-12} m^2/s.\)

Substituting the given values, we get:

\((6.0 * 10^{-12} m^2/s) * (0.90 - 0.30) / 2 = (0.90 - 0.10) / erf(4 mm / (2 * \sqrt{6.0 * 10^{-12} m^2/s} ))\)

Simplifying the left-hand side, we get:

\(1.8 * 10^{-12} m^2/s = (0.80) / erf(4 mm / (2 * \sqrt{(6.0 * 10^{-12} m^2/s) * t)})))\)

Taking the inverse error function of both sides, we get:

\(erf(4 mm / (2 * \sqrt{6.0 * 10^{-12} m^2/s) * t)} ) = 0.000346\)

Substituting this back into the previous equation, we get:

\(1.8 * 10^{-12} m^2/s = (0.80) / 0.000346\)

Solving for t, we get:

t = 63.4 hours

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The most likely tripeptide to be soluble in a hydrophobic solvent like benzene is option (c) N - proline - phenylalanine - leucine - C.

This is because all three amino acids in this tripeptide possess hydrophobic side chains. Proline has a unique cyclic structure, while phenylalanine and leucine have large, nonpolar side chains. These characteristics make the tripeptide more compatible with organic solvents, as they promote hydrophobic interactions.

In contrast, the other tripeptides contain amino acids with polar or charged side chains, making them less likely to be soluble in a hydrophobic solvent. For example, options (b) and (d) have lysine and arginine, which are positively charged, and options (e) and (d) have glutamate and aspartate, which are negatively charged. These charged amino acids will preferentially interact with polar solvents like water, reducing their solubility in benzene.

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Answer:

Zn²⁺ gets reduced

Explanation:

An electrolytic cell runs in the opposite direction of a galvanic cell. Applying a current to the galvanic cell Zn | Zn²⁺ || Ni²⁺ | Ni would convert the Zn anode to a cathode and cause Zn²⁺ to be reduced.

Asnwer: average atomic mass of chromium is 52amu

Calculations:

49.946amu: 4.350%= 0.0435

51.941amu: 83.790%= 0.8379

52.941amu: 9.500%= 0.095

53.939amu: 2.360%= 0.0236

Average atomic mass of chromium = 0.0435(49.946) + 0.8379(51.941) + 0.095(52.941) + 0.0236(53.939)

= 51.9963703amu

= 52 amu

If 100 g of calcium carbonate is allowed to decompose, 56 g of calcium oxide is produced. The mass of carbon dioxide is produced by the decomposition will be 44g

According to the given equation

CaCO₃ → CO₂ + CaO

As

mass of CaCO₃ = 100g

mass of CaO = 56g

mass of CO₂= ?

depending on the conservation of mass

mass of the reactant = mass of the product

100 g  =  ( X +  56 )

mass of CO2 =  100 - 56

= 44 g

So the mass of carbon dioxide is produced by the decomposition will be 44g

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Answer:

b a c a b

Explanation: