In which division will the quotient be a three digit number ?

a) 7620 ÷ 6 b) 612 ÷ 6 c) 498 ÷ 6 d) 348 ÷ 6

Answers

Answer 1

Answer:

b)612÷6

Step-by-step explanation:

6)612(102

-6

01

- 0

12

-12

0

=102


Related Questions

if the age of a tree was predicted to be 800 years old using the regression equation y equals 4.39 x - 6.77 what is the diameter have to be ? this is my 5th time asking a Tudor it does not seem like no one knows how to answer this question

Answers

We can use the equation:

\(age=\text{circumference}+\text{growth rate}\)

Age is given as 800

Circumference is 2*pi*r

Growth rate is the rate of change of growth of the tree. We can find this by looking at the linear equation.

The equation is:

y = 4.39x - 6.77

Matching with y = mx + b, we can say:

m = 4.39 [m is the rate of change. So, this is the growth rate]

Now, we substitute into equation to solve for r:

\(\begin{gathered} 800=2\pi r+4.39 \\ 800-4.39=2\pi r \\ 795.61=2\pi r \\ r=\frac{795.61}{2\pi} \\ r=1249.74 \end{gathered}\)

Diameter is double this radius. So,

Diameter = 1249.74 * 2 = 2499.48

Diameter = 2499.48

Brainliest if u r right
Solve for x and y in the following diagram

Brainliest if u r rightSolve for x and y in the following diagram
Brainliest if u r rightSolve for x and y in the following diagram

Answers

Answer:

x = 2 ; y = 152

Step-by-step explanation:

15x - 2 = 9x + 10

15x - 9x = 10 + 2

6x = 12

6/6 x = 12/6

x = 2 degrees

9 * 2 + 10 + y + 180

18 + 10 + y = 180

28 + y = 180

y = 180 - 28

y = 152 degrees

the traffic flow rate (cars per hour) across an intersection is r(t)=400 900t−150t2, where t is in hours, and t=0 is 6am. how many cars pass through the intersection between 6 am and 9 am? cars

Answers

The number of cars that pass through the intersection between 6 am and 9 am is 10,500 cars.

To find the number of cars passing through the intersection between 6 am and 9 am, we need to integrate the given traffic flow rate function r(t) from t=0 (6 am) to t=3 (9 am). Therefore, we have:

∫(r(t) dt) = ∫(400 + 900t - 150t² dt) [Limits: 0 to 3]

= [400t + 450t² - 50t³/3] from 0 to 3

= [400(3) + 450(3)² - 50(3)³/3] - [400(0) + 450(0)² - 50(0)³/3]

= 1200 + 4050 - 450

= 10,500 cars

Therefore, 10,500 cars pass through the intersection between 6 am and 9 am.

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Joshua’s soup calls for 3 3/4 cups of liquid. Joshua has 2 1/4 cups of both and plans to use water for the rest of the liquid. Joshua wants to know the amount of water he should use

Answers

Answer: 1 cup or 2 cups.

1. Correct to the nearest millimetre, the length of a side of a regular hexagon is 3.6 cm. Calculate the upper bound for the perimeter of the regular hexagon.

2. Kelly runs a distance of 100 metres in a time of 10.52 seconds.
The distance of 100 metres was measured to the nearest metre.

The time of 10.52 seconds was measured to the nearest hundredth of a second.

(d) Calculate the lower bound for Kelly’s average speed. Write down all the figures on your calculator display.

3. Steve measured the length and the width of a rectangle.
He measured the length to be 645 mm correct to the nearest 5 mm.
He measured the width to be 400 mm correct to the nearest 5 mm.

Calculate the lower bound for the area of this rectangle.
Give your answer correct to 3 significant figures.

4. The length of the rectangle is 35 cm correct to the nearest cm.
The width of the rectangle is 26 cm correct to the nearest cm.

Calculate the upper bound for the area of the rectangle.
Write down all the figures on your calculator display.​

Answers

1. The upper bound for the perimeter of the regular hexagon is 21.9 cm.

2. All figures on the calculator display for the calculation of Kelly's average speed is: 99.5 / 10.51 = 9.46717412

3. the lower bound for the area of the rectangle is 2.55 × 10⁵ mm²

4. Upper bound for area = 937.6525 cm²

How to calculate the perimeter of the hexagon

1. The upper bound for the perimeter of the regular hexagon can be calculated by multiplying the length of one side by 6 (the number of sides in a hexagon):

Upper bound for perimeter = 6 × (3.6 + 0.05) = 21.9 cm (rounded to one decimal place)

2. Kelly's average speed can be calculated by dividing the distance she ran by the time she took:

Average speed = distance / time

The lower bound for the distance is 99.5 m (since 100 m was measured to the nearest meter, the actual distance could be as low as 99.5 m).

The lower bound for the time is 10.51 s (since 10.52 s was measured to the nearest hundredth of a second, the actual time could be as low as 10.51 s).

Therefore, the lower bound for Kelly's average speed is:

Average speed = 99.5 / 10.51 = 9.4617 m/s (rounded to 4 decimal places)

3. The length of the rectangle is 645 mm correct to the nearest 5 mm, which means it could be as small as 642.5 mm or as large as 647.5 mm. We can express this as:

645 mm ± 2.5 mm, similarly

400 mm ± 2.5 mm

Lower bound for length = 645 - 2.5 = 642.5 mm

Lower bound for width = 400 - 2.5 = 397.5 mm

Lower bound for area = 642.5 × 397.5 = 255393.75 mm²

Rounded to 3 significant figures, the lower bound for the area of the rectangle is 2.55 × 10⁵ mm².

4. To calculate the upper bound for the area of the rectangle, we need to multiply the upper bounds for the length and width of the rectangle:

Upper bound for length = 35 + 0.45 = 35.45 cm

Upper bound for width = 26 + 0.45 = 26.45 cm

Upper bound for area = 35.45 × 26.45 = 937.6525 cm²

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What is 3 3/4 divided by 5/7?
Pls help me and thank you.

Answers

Answer:

21/4

Step-by-step explanation:

A clerk in a bank engaged in counting one rupee currency note. For the first 10 minutes quickly at
a speed of Rs.150 per minute then he slows down and begins to count at a speed of Rs. 2 less
etery minute than previous minute. Find what time will he take to count a sum of Rs. 4500.​

Answers

Answer:

The time it would take the clerk to count a sum of Rs. 4,500 is 34 minutes

Step-by-step explanation:

The given parameters are;

The rate at which the clerk in the bank counted one rupee currency notes for the first 10 minutes =  Rs. 150/minute

After the first 10 minutes, the rate at which the clerk counted = Rs. 2 less than the previous minute

The time it will take the clerk to count Rs. 4,500 is given as follows;

The number of one rupee currency notes the clerk counts in the first 10 minutes = 10 × Rs. 150 = Rs. 1,500

The amount in one rupee currency notes the clerk counted at a decreasing rate of Rs. 2 less every minute = Rs. 4,500 - Rs. 1,500 = Rs. 3,000

From the 11th minute the number of rupees the clerk counts = Rs. 150 - Rs. 2 = Rs. 148

We have an arithmetic progression with the first term, a = 148, and the common difference, d = -2

The sum of n terms of an AP, \(S_n = \dfrac{n}{2} \times \left [ 2 \cdot a + (n - 1)\cdot d\right ]\)

Which gives;

\(3000 = \dfrac{t}{2} \times \left [ 2 \times 148 + (t - 1)\times (-2)\right ] = 148 \cdot t - t^2 + t\)

3000 = 149·t - t²

Which gives;

t² - 149·t + 3,000 = 0

(t - 24) × (t - 125) = 0, therefore, t = 24 minutes or t = 125 minutes

The time it would take the clerk to count a sum of Rs. 4,500 = 10 + 24 = 34 minutes.

suppose the size of the sample of employees to be selected is greater than 100. would the probability of rejecting the null hypothesis be greater than, less than, or equal to the probability calculated in part (c) ? explain your reasoning.

Answers

If the size of the sample of employees to be selected is greater than 100, the probability of rejecting the null hypothesis would be greater than the probability calculated in part (c) because with a larger sample size, the population mean can be estimated with greater accuracy.

How does sample size affect the estimated population mean?

The determination of the population mean is improved by a larger sample size, in accordance with the Central limit theorem.

In general, it is true that it will be simpler to compute the population mean value if we have a higher sample size (n).

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can the tangent constraint be applied between a line and an arc?

Answers

Yes, the tangent constraint can be applied between a line and an arc in many CAD (Computer-Aided Design) software programs.

In CAD, a tangent constraint is a geometric constraint that forces two entities (lines, arcs, circles, etc.) to share a common tangent at their point of contact. When you apply a tangent constraint between a line and an arc, the software will ensure that the line and the arc are always tangent to each other at their point of intersection.

This constraint is useful for designing mechanical components, such as gears or cams, where you need to ensure that the contact between two parts is smooth and continuous. It is also commonly used in architecture, where a building's curved surfaces may need to be tangent to adjacent straight lines or walls.

In short, the tangent constraint can be applied between a line and an arc, and it is a useful tool in many different fields of design.

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35°
46"
65"
30"
2x
What is the perimeter? This is a little tougher problem,
and to solve it you'll need to know the lengths of the
segments on either side of the perpendicular height
(which is whyt I gave you the numbers in smaller font).
Submit

Answers

The perimeter of the triangle is 170 inches.

How to calculate the value

To solve for the perimeter, we first need to find the length of the perpendicular height. We can do this using the sine function:

sin(35°) = 46/x

x = 46/sin(35°) = 65 inches

Now that we know the length of the perpendicular height, we can find the length of the base of the triangle using the cosine function:

cos(35°) = 65/x

x = 65/cos(35°) = 75 inches

The perimeter of the triangle is the sum of the lengths of the three sides, so the perimeter is:

P = 65 + 75 + 30

= 170 inches

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The area of a circle is 4π cm². What is the circumference, in centimeters? Express your answer in terms of π pie

Answers

Answer:

The formula for the area of a circle is:

A = πr^2

where A is the area and r is the radius.

In this case, we are given that the area is 4π cm². Solving for the radius, we get:

4π = πr^2

r^2 = 4

r = 2

So the radius of the circle is 2 cm.

The formula for the circumference of a circle is:

C = 2πr

Plugging in the value for the radius, we get:

C = 2π(2) = 4π

Therefore, the circumference of the circle is 4π cm.

Suppose a (the word 'a' means starting amount is 1) radioactive substance decays at a rate of 5% per hour, what percent of the substance is left after 10 hours? (make sure you convert your answer from decimal to percent and round to the nearest whole percent)

Answers

Answer:

The percentage of the substance is left after 10 hours is 60%.

Step-by-step explanation:

The expression representing the amount left after a certain period of decay is:

\(y=a(1-r)^{t}\)

Here,

y = final amount

a = initial amount

r = decay rate

t = time taken

It is provided that:

a = 1

r = 5% / hour

t = 10 hours

Compute the percentage of the substance is left after 10 hours as follows:

\(y=a(1-r)^{t}\)

  \(=1\times (1-0.05)^{10}\\\\=0.95^{10}\\\\=0.598737\\\\\approx 0.60\)

The percentage is: 0.60 × 100 = 60%.

Thus, the percentage of the substance is left after 10 hours is 60%.

slope = -1/6; (12, -2)

Answers

Do you need it graphed?

I am offering 50 points to answer this and i will do it again and again

I am offering 50 points to answer this and i will do it again and again

Answers

Answer: Between 2 and 7

Answer:

2 to 5

Step-by-step explanation:

i don't know because of i don't this transmission may not have the completed Questionnaire

in an exponential regression model, the exact percentage of change can be calculated as: (exp(β1) − 1) × 100. if β1 = 0.13, what is the percent increase in e(y)?

Answers

In an exponential regression model, the exact percentage of change can be calculated as: (exp(β1) − 1) × 100. if β1 = 0.13 then the percent increase in e(y) is approximately 13.55%.

To calculate the percent increase in e(y), we use the formula (exp(β1) − 1) × 100, where β1 is the coefficient of the independent variable in the exponential regression model.

Substituting β1 = 0.13 into the formula, we get:

(exp(0.13) − 1) × 100 = 13.55%

Therefore, the percent increase in e(y) is approximately 13.55%.

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Which shows the calculation you need to convert 8 liters to kiloliters?

Answers

Answer: 0.008 kiloliters

Get your calculation units.

\(\frac{1liter}{0.001 kiloliters}\) (1 liter = 0.001 kiloliters)

If we have 8 liters, we must find the amount of kiloliters.

1 liter = 0.001 kiloliters, so 8 liters = 0.008 kiloliters.

The answer to the question is 0.008 kiloliters.

Answer:

B. 8 ÷ 1000

Step-by-step explanation:

Edg. 2021

Ravi makes lemonade by mixing lemon juice and water.
For every 1 cup of lemon juice, he uses 4 cups of water.
Drag the correct number of each ingredient into the box that would make 10 cups of
lemonade

Ravi makes lemonade by mixing lemon juice and water.For every 1 cup of lemon juice, he uses 4 cups of

Answers

We want to find what we need to mix to get 10 cups of lemonade.

We need to use 2 cups of lemon juice and 8 cups of water to get a total of 10 cups of lemonade.

We know that the lemonade recipe is:

1 cup of lemon juice and 4 cups of water.

This gives us a total of:

1 cup + 4 cups =  5 cups of lemonade.

Then if we want 10 cups of lemonade, we just need to use the double of each one of the ingredients.

this is:

2*(1 cup) = 2 cups of lemon juice

2*(4 cups) = 8 cups of water.

We need to use 2 cups of lemon juice and 8 cups of water to get a total of 10 cups of lemonade.

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Answer:

We need to use 2 cups of lemon juice and 8 cups of water to get a total of 10 cups of lemonade.

removed, as shown on the right. The large wheel of a tractor has a radius of 0,67 m. There is a damaged area of rubber on the outside surface of one of the large tractor tyres. How many times will this damaged piece of rubber touch the ground when the farmer drives the tractor home from the fields, over a distance of 1,5 km?​

Answers

Answer:

The damaged area of rubber will touch the ground 834 times. This can be determined by using the formula for circumference, which is 2πr where r is the radius. In this case, the radius is 0.67 meters, so the circumference of the wheel is 4.24 meters. Since the farmer drives 1.5 km, this would be equal to 1500 meters. Therefore, the damaged piece of rubber will touch the ground 1500 meters/4.24 meters = 834 times.

PLSSSS HELP IF YOU TURLY IF YOU TURLY KNOW THISS

PLSSSS HELP IF YOU TURLY IF YOU TURLY KNOW THISS

Answers

X-8=2

Move variable


Solve


Solution

X=10

Answer: yes I will help you the answer is 10

Step-by-step explanation:

you do 9 times X = 9x then do 9 x -8 = -72 then do 18 + 72 = 90 then do 9x/9 = 90/9 then 90/9 = 10 so then 10 is your answer

Idk if someone wants to help to solve this but- it’s worth a try I think it’s 15 points or so and I’ll mark brainliest to first person who answers !

Idk if someone wants to help to solve this but- its worth a try I think its 15 points or so and Ill mark

Answers

Answer:

Part 3: 9 Dogs

Step-by-step explanation:

It says that the ratio they want you to put it in is dogs/students, so dogs are x, and students are y, so if there are 4 students for every dog, 36 students would require 9 dogs

And if the roles were switched it would be students x, dogs y, and there would be 9 students for 36 dogs :D

does anyone know how to do this? find the X,Z,Y

does anyone know how to do this? find the X,Z,Y

Answers

Sorry it’s a bit messy! If you have any questions just ask
does anyone know how to do this? find the X,Z,Y

a quadrilateral with opposite sides both parallel and congruent.​

Answers

The answer is a parallelogram

unit 6 homework 3
help please

unit 6 homework 3 help please

Answers

Part 1: Triangles are similar by Side-Side-Side similarity.

Part 2: Triangles are similar angle-Angle (AA) similarity.

Explain about the similarity of the triangles?The 3 triangle similarity theorems, Side-Angle-Side (SAS), Angle-Angle (AA), and Side-Side-Side (SSS), can also be used to compare two triangles.Triangles are similar if they have two that share a single angle type, or AA (Angle-Angle). Triangles are identical if they have two sets of proportional sides with equal included angles, or SAS (Side-Angle-Side).

Part 1: Ratios must be equal for triangle similarity.

Taking the ratios of the sides:

17/37.4  = 20/44 = 25/55

On solving

0.4545 = 0.4545 = 0.4545

As the ratios are equal, triangles are similar.by Side-Side-Side similarity.

Part 2:

∠F = ∠H (given)

∠EGF = ∠JGH (vertically opposite)

By Angle-Angle (AA) similarity.

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The correct question is 1 and 2.

Select the correct answer from each drop down menu. In the figure, AB=__inches and AC=___
10" inches

Select the correct answer from each drop down menu. In the figure, AB=__inches and AC=___10" inches

Answers

Answer: In the figure AB is about 8.4 inches and AC is about 13.05 inches.

Step-by-step explanation: We can use cosine to find the hypotenuse. \(cos(40)=\frac{10}{x} \\cos(40) (x)=\frac{10}{x}(x)\\cos(40) (x) =10\\\frac{cos(40) (x)}{cos (40)} =\frac{10}{cos (40)} \\x=\frac{10}{cos(40)}\)

Using a calculator x is about 13.05

Using tangent we can find the length opposite of <C

\(tan(40)=\frac{x}{10} \\tan(40) (10)=\frac{x}{10}(10)\\tan(40) (10) = x\)

Using a calculator x would be about 8.4

Answer:

Step-by-step explanation:

Select the correct answer from each drop down menu. In the figure, AB=__inches and AC=___10" inches

What type of
number is -16 rational irrational whole number integer

Answers

The answer is Integer

Answer:

rational, whole number, integer

Step-by-step explanation:

-16 is:

rational

whole number

integer

A 6 mx6 m slab panel serves as a floor for a light storage room, The slab has no ceiling on it but with a 25 mm thick concrete fill finish for the flooring. The slab is an interior slab with adjacent slabs on all of its sides. Determine the required rebar spacing for the top column strip using a diameter 12 rebar. f′c=28MPafy=414MPa​

Answers

Given Data: Width of slab, W = 6mLength of slab, L = 6mThickness of slab, d = 25mm or 0.025m Characteristic compressive strength of concrete, f’c = 28 MPa Yield strength of steel.

fy = 414 MPa Diameter of reinforcement bar, φ = 12 mm Calculation of rebar spacing for top column strip:

First, calculate the effective depth of the slab. Effective depth (d) is given by;d = thickness of slab – cover – diameter of reinforcement bars Consider the cover as 20mm or 0.02mThen effective depth will be;

d = 0.025 – 0.02 – (12/2) × 10^-3= 0.003 m.

Now, calculate the moment of resistance of the slab with a single layer of reinforcement bars. Moment of resistance is given by;

M = f’c × b × d^2 / 6where b is the width of the slab Therefore,

M = 28 × 6 × (0.003)^2 / 6= 0.00168 MN-m.

The maximum moment in the top column strip is given by the relation;

M1 = (M – M2) / 2where M2 is the moment of the support Given that the panel has adjacent slabs on all sides, the slab will be simply supported on all edges Therefore, M2 = W × L^2 / 12= 6 × 6^2 / 12= 18 MN-m Therefore, M1 = (0.00168 – 18) / 2= -8.99916 MN-m.

The tensile force in the top layer of reinforcement bars is given by the relation;T1 = M1 / z where z is the distance of the reinforcement bar from the top layer of the slab.

Assuming that reinforcement bars are provided at 150mm spacing then the number of reinforcement.

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f(x)=5sinx+cosx then f ′
(x)=−5cosx−sinx Select one: True False

Answers

False. The derivative of the function f(x) = 5sin(x) + cos(x) is not equal to -5cos(x) - sin(x). The correct derivative of f(x) can be obtained by applying the rules of differentiation.

To find the derivative, we differentiate each term separately. The derivative of 5sin(x) is obtained using the chain rule, which states that the derivative of sin(u) is cos(u) multiplied by the derivative of u. In this case, u = x, so the derivative of 5sin(x) is 5cos(x).

Similarly, the derivative of cos(x) is obtained as -sin(x) using the chain rule.

Therefore, the derivative of f(x) = 5sin(x) + cos(x) is:

f'(x) = 5cos(x) - sin(x).

This result shows that the derivative of f(x) is not equal to -5cos(x) - sin(x).

In summary, the statement that f'(x) = -5cos(x) - sin(x) is false. The correct derivative of f(x) = 5sin(x) + cos(x) is f'(x) = 5cos(x) - sin(x).

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(Dividing polynomials ick!) Please help I'm failing summer class:)

(Dividing polynomials ick!) Please help I'm failing summer class:)

Answers

Answer:

The answer is 9 (D).

Step-by-step explanation:

Hope this helps!

factorise x2 plus 2x

Answers

Hey there!☺

\(Answer:\boxed{x(x+2)}\)

\(Explanation:\)

\(x2+2x\)

Factor x2+2x by grouping:

\(x2+2x=\\x(x+2)\)

x(x+2) is your answer.

Hope this helps!☺

✨PLEASE HELP✨DUE SOON✨

PLEASE HELPDUE SOON

Answers

Answer:

y=-2

Step-by-step explanation:

Answer:

Do you need 2 answers? If so, it's y=11 & y=-2

If not, it's one of those two.

Step-by-step explanation: