Solve this inequality:
5W – 4 > 59 – 2w

Answer:

6;

\( {50}^{o} \)

Step-by-step explanation:

AB=DE=6

m∠F=m∠C=

\( {50}^{o} \)

Answer:

93%

Step-by-step explanation:

Answer: 9 + 10 = 19

-129 x 5 =  -645

232 exponent of 2 = 53,824

32 x 400  = 12,800

400 / 23 = 17

53,824 + 12,800 + -645 + 19 + 17 = 66015

Step-by-step explanation:

Answer: 19

Step-by-step explanation:

2+1+1+12+3=19

Yes, because in a geometric sequence, we multiply or divide to get to the next term.

I hope it helps!

\(*RosalindCordelia*\)

Hi!

I can help you with joy! :-)

Of course we can multiply by 4 because in a geometric sequence, we multiply or divide to get to the next term.

\(*GentleGirlie*\)

Answer:

x=1.75

Step-by-step explanation:

5x+4=x+11

5x-x=11-4

4x=7

divide both sides by 4

4x/4=7/4

x=1.75

90% of the observations lie above 0.2 in this uniform distribution.

To find the percent of observations that lie above 0.2 in a uniform distribution, we need to calculate the area under the density curve above 0.2.

Since the density curve represents a uniform distribution, the probability density function (PDF) is a constant value between 0 and 2. The area under the density curve represents the probability of an observation falling within that range.

In a uniform distribution, the PDF is given by:

f(x) = 1 / (b - a)

Where a is the lower bound and b is the upper bound of the distribution.

Since the lower bound is 0 and the upper bound is 2, the PDF for this uniform distribution is:

f(x) = 1 / (2 - 0) = 1 / 2

To find the percent of observations above 0.2, we need to find the area under the density curve above 0.2.

Since the PDF is constant for this distribution, the area above 0.2 is equal to:

(2 - 0.2) * (1 / 2) = 1.8 / 2 = 0.9 = 90%

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An example of a rational expression is 2x+3/x-2.

The complete question wasn't found. Therefore, a overview will be given. It should be noted that a rational expression simply means quotient of two polynomials.

A rational expression is a fraction whose numerator and denominator are polynomials.

In this case, an example of a rational expression is 2x+3/x-2

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The parametric form can be written as -

\(x = x_2 \left[ \begin{array}{c} -3 \\ 1 \\ 0 \\ 0 \\ \end{array} \right] + x_3 \left[ \begin{array}{c} 0 \\ 0 \\ 1 \\ 0 \\ \end{array} \right] + x_4 \left[ \begin{array}{c} 4 \\ 0 \\ 0 \\ 1 \\ \end{array} \right]\)

A matrix equation of the form \($A\overrightarrow x=0\) is called homogeneous matrix equation.

A matrix equation of the form  \($A\overrightarrow x=\overrightarrow b\) is called non - homogeneous matrix equation.

Given is to find the solution in parametric vector form.

If there are {m} free variables in the homogeneous equation, the solution set can be expressed as the span of {m} vectors :

\($\overrightarrow x=s_{1} \overrightarrow v_{1} + s_{2} \overrightarrow v_{2}+......+s_{m} \overrightarrow v_{m}\)

We have a matrix where {A} is the row equivalent to that matrix -

\(\begin{bmatrix} 1&3&0&-4 \\ 2&6&0&-8 \end{bmatrix}\)

Given matrix can be written in Augmented form as -

\(\left[ \begin{array}{cccc|c} 1&3&0&-4 & 0\\2&6&0&-8&0\\ \end{array} \right]\)

Row Reduced Echelon Form can be obtained using the following steps -

{ 1 } - Interchanging the rows R{1} and R{2}.

\(\left[ \begin{array}{cccc|c} 2&6&0&-8&0 \\ 1&3&0 &-4 & 0 \\ \end{array} \right]\)

{ 2 } - Applying the operation R{2} -> 2R{2} - R{1}, to make the second 0.

\(\left[ \begin{array}{cccc|c} 2&6&0&-8&0\\1&3&0&-4&0 \\ \end{array} \right] \;\;\;\;\;\;R_2 \rightarrow 2R_2 - R_1\)

\(\left[ \begin{array}{cccc|c} 2 & 6 & 0 & -8 & 0 \\ 0 & 0 & 0 & 0 & 0 \\ \end{array} \right]\)

{ 3 } - Using R{1} -> R{1}/2

\(\left[ \begin{array}{cccc|c} 2&6&0&-8&0\\0&0&0&0&0\\ \end{array} \right]  \;\;R_1 \rightarrow \dfrac{1}{2} R_1\)

{ 4 } - Following equation can be deducted as

\(x_1 + 3x_2 - 4x_4 =0\)

{ 5 } - We can write the parametric form as -

\(x = x_2 \left[ \begin{array}{c} -3 \\ 1 \\ 0 \\ 0 \\ \end{array} \right] + x_3 \left[ \begin{array}{c} 0 \\ 0 \\ 1 \\ 0 \\ \end{array} \right] + x_4 \left[ \begin{array}{c} 4 \\ 0 \\ 0 \\ 1 \\ \end{array} \right]\)

Therefore, the parametric form can be written as -

\(x = x_2 \left[ \begin{array}{c} -3 \\ 1 \\ 0 \\ 0 \\ \end{array} \right] + x_3 \left[ \begin{array}{c} 0 \\ 0 \\ 1 \\ 0 \\ \end{array} \right] + x_4 \left[ \begin{array}{c} 4 \\ 0 \\ 0 \\ 1 \\ \end{array} \right]\)

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When calculating a nation’s digital power, the term that is used to refer to the demonstrated capabilities of a nation-state in cyber offense or defense is Cyberwarfare.

Cyberwarfare  can be regarded as the use of cyber attacks against a nation-state so as to produce significant harm.

It should be noted that Cyber Warfare is set of actions  which is been carried out by  nation or organization so as to be able to launch an attack on institutions' computer network systems.

The interests or reasons for cyberwarfares based on the Cybersecurity as well as Infrastructure Security Agency are;

In order to achieve the goals behind the cyberwarfare programs, it is usually designed to focus on spectrum of objectives which will bring harm to national interests.

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Answer:

if y = 2x then

-3x+8y=26

-3x + 8·2x= 26

-3x+16x=26

13x=26

x = 26/13= 2

Answer: B. θ = 36°

Step-by-step explanation:

Concept:

Here, we need to know the idea of the Law of sines.

In trigonometry, the law of sines, sine law, sine formula, or sine rule is an equation relating the lengths of the sides of a triangle (any shape) to the sines of its angles.

The Law of sines: a / sinA = b / sinB = c / sinC

If you are still confused, please refer to the attachment below for a graphical explanation.

Solve:

a = 10 m

c = 11.2 m

C = 41°

Given formula

a / sinA = c / sinC

Substitute the value into the formula

10 / sinA = 11.1 / sin (41)

Cross-multiply to simplify the equation

sinA × 11.1 = 10 · sin (41)

Divide 11.1 on both sides

sinA × 11.1 / 11.1 = 10 · sin (41) / 11.1

sinA = 10 · sin (41) / 11.1

Apply arcsine or the inverse of sine (basically representing the division of sine)

A = sin⁻¹ (10 · sin (41) / 11.1)

A = 36°

Hope this helps!! :)

Please let me know if you have any questions

The  equation Px+6=3(x+q) of p and q are:p = 0, q = 3orp = 3, q = 2

We know that if x = -1 is the only solution, then the equation should have only one root, i.e.,

discriminant = 0.

Discriminant of the equation: D = b² - 4ac

Given equation can be written as: Px - 3x + 6 - 3q = 0

Comparing it with the general equation ax² + bx + c = 0,

we get a = p, b = -3, and c = 6 - 3q

Discriminant = (-3)² - 4p(6 - 3q)

For x = -1, the equation becomes:

P(-1) - 3(-1) + 6 - 3q = 0

or, -P + 3 + 6 - 3q = 0

or, -P - 3q + 9 = 0

or, -3q = P - 9

or, q = (9 - P)/3

or, q = (3 - P/3)

If x = -1 is the only solution,

then the discriminant should be equal to 0.

(-3)² - 4p(6 - 3q) = 0

We know that q = (3 - P/3)

On substituting the value of q in the above equation, we get:

9 - 4p(6 - 3(3 - P/3)) = 0

or, 9 - 4p(6 - 9 + P) = 0

or, 9 - 4p(P - 3) = 0

or, 0 = 4p² - 12p

Substituting the value of p, we get:

0 = 4p² - 12p

or, 0 = 4p(p - 3)

Either 4p = 0 or p - 3 = 0

p = 0 or p = 3

If p = 0, then q = 3, and

if p = 3, then q = 2

Therefore, the values of p and q are:p = 0, q = 3orp = 3, q = 2

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Answer:

100

Step-by-step explanation:

6 seconds to select + 14 seconds to complete check out

to complete transaction order of 5 products equal 100 second

Answer: x=3.75   y=1.25

Step-by-step explanation:

Let the numbers we are looking for be x and y

Hence,

x=3y

x+y=5

x=3y

x=5-y

Thus,

3y=5-y

3y+y=5

4y=5

Divide both parts of the equation by 4:

y=1.25

Hence,

x=3(1.25)

x=3.75

Evaluating the integral-  \(\int_0^1 (u+2)(u-3) du\) we get the simplified answer = -37/6.

Let's evaluate the integral as follows -

\(\int_0^1 (u+2)(u-3) du\)

now lets multiply the expression and we will get,  

\(= \int_0^1 u^2-u-6 d u\)

Distributing the integrals to each expression.

\(= \int_0^1 u^2 d u+\int_0^1-u d u+\int_0^1-6 d u\)

By the Power Rule, the integral of \($u^2$\) with respect to u is  \($\frac{1}{3} u^3$\).

\(= \left.\frac{1}{3} u^3\right]_0^1+\int_0^1-u d u+\int_0^1-6 d u\)

Since -1 is constant w.r.t u, move -1 out of the integral of the second term.

\(= \left.\frac{1}{3} u^3\right]_0^1 -\int_0^1u d u+\int_0^1-6 d u\)

By using the power rule, the integral of \($u^2$\) w.r.t to u is \($\frac{1}{2} u^2$\)

\(= \left.\left.\frac{1}{3} u^3\right]_0^1-\left(\frac{1}{2} u^2\right]_0^1\right)+\int_0^1-6 d u\)

Let's Combine \($\frac{1}{2}$\) and \($u^2$\).

\(= $$\left.\left.\frac{1}{3} u^3\right]_0^1-\left(\frac{u^2}{2}\right]_0^1\right)+\int_0^1-6 d u$$\)

Now, apply the constant rule,

\(= $$\left.\left.\left.\frac{1}{3} u^3\right]_0^1-\left(\frac{u^2}{2}\right]_0^1\right)+-6 u\right]_0^1$$\)

Substituting the limits and simplifying we get,

= -37/6

Hence, the simplified answer for the given integral \(\int_0^1 (u+2)(u-3) du\) is -37/6.

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The complete question is-

Evaluate the integral-  \(\int_0^1 (u+2)(u-3) du\).

The consumption bundle that will not be the consumer's choice, given the assumptions of choosing the optimal bundle, is option B) 30 snacks and 12 meals. To determine the optimal consumption bundle, we need to consider the consumer's budget constraint and maximize their utility.

Given that the price of snacks is $4 and the price of meals is $10, and the consumer has $240 remaining on their meal card, we can calculate the maximum number of snacks and meals that can be purchased within the budget constraint.

For option A) 5 snacks and 20 meals, the total cost would be $4 × 5 + $10 × 20 = $200. Since the consumer has $240 remaining, this bundle is feasible.

For option B) 30 snacks and 12 meals, the total cost would be $4 × 30 + $10 × 12 = $240. This bundle is on budget constraint, but it may not be the optimal choice since the consumer could potentially consume more meals for the same cost.

For option C) 20 snacks and 16 meals, the total cost would be $4 × 20 + $10 × 16 = $240. This bundle is also on budget constraint.

Since options A, C, and D are all feasible within the budget constraint, the only bundle that will not be the consumer's choice is option B) 30 snacks and 12 meals. The consumer could achieve a higher level of utility by reallocating some snacks to meals while staying within the budget constraint. Therefore, the correct answer is option B.

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The x intercept of the function the quantity of 5 x squared minus 25 x, all over x is 5

we have given a function the quantity  f(x) = (x² - 25x)/x

Firstly, we will take the common factor out from numerator and denominator  which is x and it  will get cancel from the fraction  we will get

5x - 25

Now we will take again the common factor out which is 5 we will get

5(x - 5)

Here, we will equate the expression to zero we will have

5(x - 5) = 0

x - 5 = 0

x = 5

We will get value of x

x=5

Therefore, the x intercept of the function the quantity of 5 x squared minus 25 x, all over x is 5

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Answer: 0.4 Inches

Step-by-step explanation:

Someone said it in the comments, give credit to them.

There are 20 combinations of boxes that can be used for the customer's 15 chocolate pieces.

In mathematics, a coefficient is a multiplicative factor in some term of a polynomial, a series, or an expression; it is usually a number, but may be any expression. When the coefficients are themselves variables, they may also be called parameters.

It is given that a customer ordered 15 pieces of gourmet chocolate. The order can be packaged in small boxes that contain 1, 2 or 4 pieces of chocolate. Any box that is used must be full.

The coefficient of \(x^{15}\) from the steps shown in the image is 20.

Hence, there are 20 possibilities.

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The optimal values of these parameters are:

a. β₁ = 0

b. β₂ = 0

The linear regression y = β1 + β2x + e, assuming that the sum of squared errors (SSE) takes the following form:

SSE = 382 + 681 + 382 + 18β1β2

Derive the partial derivatives of SSE with respect to β1 and β2 and solve the optimal values of these parameters.

Given that SSE = 382 + 681 + 382 + 18β1β2 ∂SSE/∂β1 = 0 ∂SSE/∂β2 = 0

Now, we need to find the partial derivative of SSE with respect to β1.

∂SSE/∂β1 = 0 + 0 + 0 + 18β2 ⇒ 18β2 = 0 ⇒ β2 = 0

Therefore, we obtain the optimal value of β2 as 0.

Now, we need to find the partial derivative of SSE with respect to β2. ∂SSE/∂β2 = 0 + 0 + 0 + 18β1 ⇒ 18β1 = 0 ⇒ β1 = 0

Therefore, we obtain the optimal value of β1 as 0. Hence, the partial derivative of SSE with respect to β1 is 18β2 and the partial derivative of SSE with respect to β2 is 18β1.

Thus, the optimal values of β1 and β2 are 0 and 0, respectively.

Therefore, the answers are: a. β₁ = 0 b. β₂ = 0

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Padma rented the kayak for 3 hours.

We are given the following system of equations:

X6 + Y10 = 60 --- (1)

X and Y are the number of hours Padma rented the bike and kayak respectively.

We want to find the value of Y, which represents the number of hours Padma rented the kayak.

To solve for Y, we can isolate Y in equation (1) as follows:

Y10 = 60 - X6

Y = (60 - X6)/10

Now, we can substitute the given information that Padma rented the bike for 3 hours (X = 3) and solve for Y:

Y = (60 - 3*6)/10 = 3

Therefore, Padma rented the kayak for 3 hours.

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Answer:

3.07meters

Step-by-step explanation:

9-5.93=3.07

Answer:

Their are many other answers to this question this is one of the ones that are correct.

The least sample size needed to assure with 90% confidence that the sample mean will not differ from the population mean by more than 5 minutes will be 416.16.

A normal distribution is a data set design in which the majority of values cluster around the middle of the range and the remainder taper off symmetrically toward either end. Data in a normal distribution are symmetrically distributed and have no skew. The majority of values cluster around a central location, with values decreasing as one moves out from the center. In a normal distribution, the measures of central tendency (mean, mode, and median) are all the same. The normal distribution, like any other probability distribution, defines how the values of a variable are distributed. Because it properly captures the distribution of values for many natural occurrences, it is the most important probability distribution in statistics.

Here,

The z value at the 90 percent confidence interval is 1.645.

t ≥ z*s/√n

5≥1.645*62/√n

√n≥20.398

√n≥20.4

n≥416.16

The smallest sample size required to ensure that the sample mean does not deviate from the population mean by more than 5 minutes with 90% confidence is 416.16.

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Answer:

In this algebraic expression, "Negative x" represents a term with a coefficient of -1, and "x" represents a variable. "10.2" represents a constant term. The "+" sign represents addition.

Step-by-step explanation:

"minus one-half x" represents a term with a coefficient of -0.5 and variable "x". "+ y" represents a term with variable "y" and a coefficient of 1.

Simplifying the expression by combining like terms:

-x - 0.5x = -1.5x

Negative x + 10.2 - one-half x + y = 10.2 - 1.5x + y

Answer:

what do you need help with?

Answer:

x=2 and y=−3

Step-by-step explanation:

Use math papa's systems of equations calculator that shows work!

:)

Answer:

I'm doing this now in school. its a pain

Step-by-step explanation:

x=2

y=-3