a skydiver falls from rest through air and reaches teminal velocity

what is the acceleration of the skydiver during his fall

a) constant at 0m/s²
b) constant at 10m/s²
c) starting at 0m/s² and increasing to 10m/s²
d) starting at 10m/s² and decreasing at 0m/s²
​

Answer:

4.186 m/s^2

Explanation:

First, convert km/hr to m/s:

(75 km/hr)(1000m/1km)(1hr/60min)(1min/60s) = 20.83 m/s

Then, divide 20.93 m/s by 5.0s

(20.93 m/s) / (5.0s) = 4.186 m/s^2

Answer: An object with a greater mass requires a greater force to accelerate.

Explanation:

Answer:

An object with a greater mass requires a greater force to accelerate.

Explanation:

I took the test.

\(\boxed{\boxed{\sf CH_4+2O_2}\longrightarrow \boxed{\sf CO_2+2H_2O}}\)

Different measurement scales, such as ratio scale, equal-interval, rank-order, and nominal, are used in many disciplines, including statistics and the social sciences.

A. Letters of the alphabet:

Nominal: Without any intrinsic order or numerical value, the letters of the alphabet indicate categories or labels.

Discrete: Each letter is unique and cannot be divided into more compact parts.

B. Time of day:

Equal-Interval: A continuous scale with equal gaps between each unit (such as minutes or seconds) is what the term "time of day" represents.

Continuous: Any fractional value between units is possible when measuring time as a continuous variable (for example, 12:15, 12:30, or 12:45).

C. Medals Won in the Olympics:

Rank-Order: Olympic medals can be rated according to level of accomplishment (for example, gold, silver, and bronze).

Discrete: The total number of medals earned cannot be divided further because it is a whole number.

D. Percent score from a memory test:

Ratio Scale: A score of 50% is half of a score of 100%, for example, and percentage scores from memory tests can be compared using ratios because they have a meaningful zero point.

Continuous: Percent scores allow for fractional values and can range from 0 to 100.

E. Number of teen pregnancies in San Clemente:

Ratio Scale: A scale with a meaningful zero point and the capacity to compare ratios can be used to calculate the number of teen pregnancies.

Discrete: Pregnancies are counted as a whole; they cannot be subdivided into smaller numbers.

F. G.P.A.:

Equal-Interval: A continuous scale with equal distances between each unit is represented by the GPA (for example, 2.0, 2.5, and 3.0).

Continuous: Any value within a range, including fractional values (like 3.75), can be used for G.P.A.

G. Food Grades at Restaurants:

Rank-Order: Restaurants may rate their food using a letter grading system (A, B, C, etc.).

Discrete: There is no more subdividing the grades because they are separate groups.

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Answer:

156.8 Joules

Explanation:

Work = Force x Displacement

Displacement = 2m

Force (force of gravity) = mass x acceleration due to gravity =  8Kg x 9.8m/s^2

= 78.4N

Work = FxD

Work = 78.4 N x 2m

Work = 156.8 N·m  OR 156.8 Joules

The amount of work done in lifting this box is equal to 156.8 Joules.

Given the following data:

Scientific data:

To calculate the amount of work that is done in lifting this box:

Mathematically, the work done by a person is calculated by using this formula:

\(Work\;done = Fd = mgd\)

Where:

Substituting the given parameters into the formula, we have;

\(Work\;done = 8 \times 9.8 \times 2\)

Work done = 156.8 Joules.

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Answer:

Explanation:

The density of a substance can be found by using the formula

\(density = \frac{mass}{volume} \\\)

From the question

mass = 250 g

volume = 100 cm³

So we have

\(density = \frac{250}{100} = \frac{5}{2} \\ \)

We have the final answer as

Hope this helps you

Answer:

I’d say the air outside the hemisphere is more free than from the inside of the hemisphere.

Explanation:

hope this help!

Answer:

The three agents of sediment transport, which result in deposition as energy decreases, are ice, wind, and water.

Answer:

the second option

Explanation:

an object vibrating at a second objects natural frequency forces the second object to vibrate

The correct answer is D. Shortening the pendulum.

Changing the mass of the pendulum bob or the block-spring system will not affect the period of oscillation, as the period of both systems depends only on the length of the pendulum and the spring constant, respectively. Similarly, increasing the angle through which the pendulum swings will not change the period of oscillation, as long as the angle remains small.

Shortening the pendulum will decrease the length of the pendulum, which in turn decreases the period of oscillation. If the pendulum is shortened by the right amount, its period of oscillation can become equal to that of the block-spring system, thereby making the two systems oscillate with the same period.

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Explanation:

Note that resonance can only occur when the natural frequency is greater than the damping rate, multiplied by the square root of 2. If the damping is too large, then resonance cannot occur.

Answer: All elements in the same group (column) on the periodic table will have the same number of valence electrons.

Explanation:

Explanation:

a) i) Calculation of the friction force:

The friction force can be determined using the equation:

friction force = coefficient of friction * normal force

The normal force is equal to the weight of the object, which can be calculated as:

normal force = mass * gravitational acceleration

where the gravitational acceleration is approximately 9.8 m/s².

normal force = 75 kg * 9.8 m/s² = 735 N

friction force = 0.4 * 735 N = 294 N

ii) Calculation of the acceleration of the body:

Now, we can calculate the acceleration using Newton's second law:

net force = mass * acceleration

Since the applied force and the friction force act in opposite directions, the net force can be calculated as:

net force = applied force - friction force

net force = 300 N - 294 N = 6 N

mass = 75 kg

6 N = 75 kg * acceleration

acceleration = 6 N / 75 kg = 0.08 m/s²

b) Explanation:

In part (a), we calculated the friction force to be 294 N and the acceleration of the body to be 0.08 m/s². The positive acceleration indicates that the body is moving in the direction of the applied force.

The friction force opposes the motion of the body and acts in the opposite direction to the applied force. In this case, the applied force of 300 N is greater than the friction force of 294 N. As a result, the net force acting on the body is 6 N in the direction of the applied force.

The small net force of 6 N, compared to the body's mass of 75 kg, results in a relatively low acceleration of 0.08 m/s². This indicates that the body will accelerate slowly in the direction of the applied force due to the presence of friction.

Overall, the friction force and the resulting acceleration of the body are determined by the coefficient of friction (μ) and the mass of the object. In this case, the body experiences a relatively high friction force, leading to a small acceleration.

planets

Explanation:

Answer:

Friction is defined as the force that opposes the motion of a solid object over another. There are mainly four types of friction: static friction, sliding friction, rolling friction, and fluid friction. Friction and normal force are directly proportional to the contacting surfaces and it doesn’t depend on the hardness of the contacting surface. With the increase in relative speeds, the sliding friction reduces whereas fluid friction increases with the increase in the relative speed, also fluid friction is dependent on the viscosity of the fluid.

In sliding motion, each point on the body has only translational or linear motion. But in case of rolling motion, different points have a combination of linear as well as rotational motion.

Types Of Friction

Static Friction

Sliding Friction

Rolling Friction

Fluid Friction

Static Friction

Answer:

Its d 3.74 x 10-8N

Explanation:

Answer: 3.74 x 10-8 N

Explanation:

Answer:

anywhere the tornado goes debri goes except for the more heavier pieces they just go in random places but the lighter pieces stay with the tornado until the tornado is gone or disinegrated

Explanation:

around and around

The following are some examples of the functional dependencies that can be held:

PX, PY, and PZ →VX

PX, PY, and PZ →VY

PX, PY, and PZ →VZ

Functional dependency is a term that describes a constraint that is usually used to explain the link between two (2) different sets of attributes, where one set may predict the true value of the other attributes accurately and uniquely.

The coordinates of the molecule in this example would be PX, PY, and PZ, while the velocities of those coordinates would be VX, VY, and VZ. Functional dependencies can so be illustrated by the following examples:

PX, PY, and PZ → VX

PX, PY, and PZ → VY

PX, PY, and PZ → VZ

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Answer:

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 75 × 1.2

We have the final answer as

Hope this helps you

Answer:

\(\boxed {\boxed {\sf 90 \ Joules}}\)

Explanation:

Work can be found by multiplying the force by the distance.

\(W=f*d\)

The force of the package is 75 newtons.

The distance the package is lifted off the ground is 1.2 meters.

\(f= 75 \ N \\d=1.2 \ m\)

Substitute the values in and multiply.

\(W= 75 \ N *1.2 \ m\)

\(W=90 \ N*m\)

1 Newton meter (N*m) is equal to 1 Joule (J).

Therefore, our answer of 90 Newton meters is equal to 90 Joules.

\(W= 90 \ J\)

The work done is 90 Joules.

There are two d-block elements that exhibit electron configuration exceptions: chromium (Cr) and copper (Cu). Let's explore each of them individually:

1. Chromium (Cr):

Chromium has an electron configuration of [Ar] 3d^5 4s^1 instead of the expected [Ar] 3d^4 4s^2.

  In the case of chromium, one electron from the 4s orbital is promoted to the 3d orbital, resulting in a half-filled 3d orbital and a more stable configuration. This arrangement lowers the overall energy of the atom, making it more favorable.

Chromium's electron configuration exception allows it to have greater stability and is consistent with the observed properties of the element.

2. Copper (Cu):

Copper has an electron configuration of [Ar] 3d^10 4s^1 instead of the expected [Ar] 3d^9 4s^2.

Copper also exhibits an electron configuration exception by promoting one electron from the 4s orbital to the 3d orbital, resulting in a completely filled 3d orbital and increased stability.

Copper's electron configuration exception provides additional stability, which influences its chemical and physical properties.

These electron configuration exceptions in chromium and copper result from the desire to achieve a more stable configuration by filling or half-filling the d orbitals, leading to observed anomalies in their electron configurations.

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Answer:

30 ml

Explanation:

it is very easy

Answer: It would be yards

Explanation:

Answer:

I suppose you are talking about American football, so the answer would be yards.

Explanation:

The field is measured using yards.

Answer:

sdf

Explanation:

The electric force between two point charges is 1/6 N.

Given data:

Initial distance between the charges (r1) = 2.0 cm

The new distance between the charges (r2) = 8.0 cm

Initial electric force between the charges - F1 = 1.0 N

Solution:

Lets' say the two charges are q and q2. The formula to calculate electric force between the two charges is given below

F = K |q1| |q2| / r^2

K is a constant.

New electric force can be expressed as

F2/F1 = K |q1| |q2| / r2^2 ÷  K |q1| |q2| / r1^2

F2/F1 = r2^2 / r1^2

After substituting the values we will get

F2 = 1.0 N ( 2.0 / 8.0)^2

F2 = 4/64 N

F2 = 1/16N

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Answer:

Her linear velocity on the outer edge is 3 m/s

Her rotational velocity, is constant at 2 RPM

Explanation:

The given parameters are;

The radius of the rotating platform = r

The linear velocity  v(t) = 1 m/s

The position Emily is riding = 1/3 the distance from the center

The rotational velocity = 2 RPM = 2 Revolutions per minute

The formula for angular velocity, ω is given as follows;

ω = θ/t

Where;

θ = The angle rotated

t = The time taken for the rotation

Given that the rotational velocity = 2 RPM

1 revolution = 2·π radians

The angular velocity, ω = 2×π×(2 RPM) = 4·π rad/min = 4·π/60 rad/seconds

ω = 4·π/60 rad/seconds

The linear velocity, v = r₁×θ/t = r₁×ω

Where;

r₁ = 1/3 × r

v = 1 m/s = 1/3 × r  × 4·π/60 rad/seconds

∴ r = 1/(1/3 × 4·π/60) = 45/π meters

r = 45/π meters

Therefore her linear velocity, v₂ and her rotational velocity if she moves to the outer edge will be given as follows;

v₂ = r × ω = 45/π × 4·π/60 = 3 m/s

Her linear velocity on the outer edge, v₂ = 3 m/s

Her rotational velocity, remains at 2 RPM.

The current leaving the battery is the magnitude of current flowing out of the battery, which can be measured using an ammeter. Measuring the current at three different places around the circuit will give an indication of how much the current is changing, or not, as it moves around the circuit.

For the first measurement, the current leaving the battery can be measured directly using the ammeter. To measure the current at the other two points, the ammeter needs to be connected in series with the components, such as resistors, at those points.

If the circuit is a simple series circuit, the current should be constant at all points around the circuit, as the same current flows through all components in the same direction. However, if the circuit is more complex, the current can change at different points. For example, if the circuit contains a parallel connection, then current will split at that point and different currents will flow through each parallel path.

By measuring the current at three different points around the circuit, you can see whether or not the current is constant and draw conclusions about the circuit structure and components.

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In figure.4, the forward resistance is 2Ω. To calculate the current, we use Ohm's law, which states that the current (I) flowing through a conductor is directly proportional to the voltage (V) across its ends and inversely proportional to the resistance (R) of the conductor.

I = V/RThe voltage across the resistor can be found by subtracting the voltage across the diode from the voltage of the source. The voltage across the diode is 0.7V

when it is forward biased. Therefore, the voltage across the resistor is:

V = 12V - 0.7V = 11.3VNow we can calculate the current: I = V/R = 11.3V/2Ω = 5.65A

Please note that since the resistance is given in Ω, the unit of voltage should also be in volts (V) and not millivolts (mV), which is shown in the diagram.

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Answer:

The question of analog vs. digital audio is one of the more hotly debated questions in the world of music, film and media today. Does digital sound better? Does analog sound better? Is there even a noticeable difference?

It’s impossible to understand the difference completely without understanding what distinguishes analog audio from digital audio. A full discussion of these terms is best left to your curriculum and discussions with your mentor in the studio. For now, though, here’s a brief explanation of what these two words mean, and the differences between them.

Analog refers to a continuously changing representation of a continuously variable quantity. Digital, however, refers to representing these variable quantities in terms of actual numbers, or digits. The last two sentences seem a bit complex, but let’s try to simplify them with an example. If you consider the numbers 1 and 2 on a number line, there are actually an infinite number of points between 1 and 2. This is what analog represents—the infinite number of possibilities between 1 and 2. Digital, on the other hand, only looks at certain number of fixed points along the line between 1 and 2 (for example, 1 ¼, 1 ½, 1 ¾, and 2).

Can you see the difference? Digital takes a few “snapshots” of the number line, while analog takes the whole line into account.

As another example, think of analog vs. digital as the difference between seeing something in real life and watching it on film. When we see something happen in real life, there are no “spaces” between what we see, so we’re watching it happen in analog. Film, however, is actually a series of still photographs that are taken in rapid-fire intervals, and when we see them in succession, it tricks our minds into thinking we’re seeing a continuous flow of movement. So in a manner of speaking, when we watch the event happen on film, we’re watching it digitally, because we’re watching increments of the event, rather than the whole thing in fluid motion. (Not to be confused with digital video vs. film, which is another discussion completely!)

Let’s bring this idea into audio, music, and the studio. Sound occurs naturally in analog–that is to say, sound occurs in a continuous set of waves that we hear with the human ear. (Think of it as a “wavy” line with an infinite number of points along it.) When we capture that sound in a way that represents all the possible frequencies, we’re recording in analog; when we use computers to translate the sound into a series of numbers that approximate what we’re hearing, we’re recording in digital.

Thus, a purely analog recording would be something that was recorded on tape and produced using manual equipment to mix, master and press into a vinyl LP. A purely digital recording would be recorded on a computer program such as Pro Tools, mixed, mastered and produced digitally, and eventually burned onto a CD as an MP3 or audio file.

The most ironic aspect of the debate about digital vs. analog recording is that nowadays a lot of music is a combination of the two.  For example, you might record a song onto analog tape, but mix and master it digitally, or release it on the Internet as an MP3.

So what’s the difference in quality between analog and digital? The idea between digital recording is that our ears and brains technically can’t determine the spaces between the digital values, just like our brains interpret film as continuous motion. However, to many people, analog sound tends to be warmer, has more texture and is thought to capture a truer representation of the actual sound. Digital is felt to be somewhat cold, technical and perhaps lacking in analog’s nuance.

However digital is much cheaper. Recording an album with analog technology can require a whole studio full of equipment, but with digital recording technology, it’s possible to record a whole album in a bedroom on a laptop. And whereas analog technology can wear out or be damaged, digital media can last for an indefinite length of time.

Today many recording artists, both major and independent, record using a mixture of digital and analog techniques. While analog audio does give warmth and a truer sound quality, digital is cheaper to work with and offers more control over the finished product.