speed of sound is 332 MS and frequency of sound is 10 Hz what is the wavelength of the sound
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Answer:

Control groups let the one who is expermenting compare  the effect of the varibles in the expermental group.

Explanation:

Answer:

a

Explanation:

after the universe reach the limit, gravity does its thing

To find the mass in kilograms, you need to know the object's weight in newtons and the acceleration due to gravity. The formula for finding mass is mass = weight / acceleration due to gravity. So if you have an object with a weight of 100 N and the acceleration due to gravity is 9.8 m/s^2, the mass would be 10.204 kg.

The mass of the block is 0.025 kg or 25 g, when the spring has k = 28 N/m, and compresses 0.11 m before bringing the block to rest.

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The pressure of the cube that exerts the most pressure while resting on a floor is mathematically given as

P=16.6pascal, Option D is correct

Generally, the equation for the Pressure   is mathematically given as

P=force/Area

Therefore, In considering the one with the most pressure we look at the one with the most force/Area

In conclusion, the one with the most Force/Area is a 25 N cube with 1.5 m sides

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Answer:

Explanation:

When a ball is at its highest point, its acceleration is 0. The only thing pulling it down, is gravity so, the correct option is D. Downwards.

I'm not sure however due to the fact that the arrows on the other options are facing backwards meaning the ball would go backwards; and for the one option the ball is going up. However, the ball isn't going backwards nor up, so it must be D. If I am wrong I greatly apologize.

The East/West component of SuperPointParticleDog's force on the ball is -115.7 N. (Westward).

Isaac's force:

Magnitude: 255 N

Angle: 13 degrees North of East

x-component: 255*cos(13) = 245.1 N (Eastward)

y-component: 255*sin(13) = 58.1 N (Northward)

Newton's force:

Magnitude: 156 N

Angle: 34 degrees South of East

x-component: 156*cos(34) = 129.4 N (Westward)

y-component: 156*sin(34) = 86.5 N (Southward)

Now we can add the x- and y-components of the forces to find the net force:

Net force:

x-component: 245.1 N - 129.4 N = 115.7 N (Eastward)

y-component: 58.1 N - 86.5 N = -28.4 N (Southward)

The net force has an Eastward component of 115.7 N. Therefore, the East/West component of SuperPointParticleDog's force on the ball is -115.7 N. (Westward).

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The impulses and changes in momentum are identical because equal forces are applied over equal periods of time.

The momenta of the two carts are identical since they both begin at rest and experience equal changes in momentum. We are aware that force is the same as mass multiplied by acceleration. Due to the initial resting state of both carts, u = 0 m/s, and the plastic cart moves 1 m. Newton's second law states that when the same force is applied to the two carts, the plastic cart will have more final momentum than the lead cart because of the momentum principle. Newton's third law states that every object feels the same force for the same length of time, which results in the same impulse and consequent change in momentum.

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Due to equivalent forces being delivered over equal times, the impulses and changes in momentum are identical.

The acceleration is determined by dividing the net force by the mass. An object's acceleration doubles if the net force exerted on it also doubles. Increased mass will result in a halving of acceleration.

Second Law of Motion: Force In accordance with his second law, a force is defined as the change in momentum (mass times velocity) per change in time. The definition of momentum is the product of the mass m and the velocity V of an object.

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Answer:

Electromagnetic waves differ in their wavelengths and frequencies. The higher the frequency of an electromagnetic wave, the greater its energy. The speed of an electromagnetic wave is the product of its wavelength and frequency, so a wave with a shorter wavelength has a higher frequency, and vice versa.

Explanation:

Answer:

PE = 137.2931 J

Explanation:

PE = 137.2931 J

Answer:

The speed of the particle is proportional to:

c. t²

Explanation:

Given;

initial velocity of the particle, u = 0

let the net force on the object = F

Work done on the particle is given by;

W = F x d

W ∝ t

\(Fd \ \alpha \ t\\\\\frac{mv}{t}d \ \ \alpha \ t\\\\mvd \ \ \alpha \ t^2\\\\v \ \ \alpha \ t^2\)

Therefore, the speed of the particle is proportional to t²

The speed of the particle is proportional to t.

It should be noted that work is a change in kinetic energy. Therefore, power will be calculated as:

Power = Work / Time = force × velocity

Power is proportional to t. Since force is a constant, then the velocity will be proportional to t. Therefore, the speed of the particle is proportional to t.

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QUESTION 1: What conclusion can you make on whether any of the liquids are the same. Explain based on the information in the table.

         Sample 2 & 4 are the same, but in different amounts. We can tell this because, looking at the table, the boiling points and the densitities are the same. The mass and volume may be different, but this is because they are in different amounts as said earlier.

QUESTION 2: Describe what is good and what might be improved about Carl's models in explaining how the three states of water are different in the arrangement of their water molecules.

         Carl's models have a good start. They state how ice is a solid, water is a liquid, and vapor is a gas. It also states how ice has more structure than water and how water has more structure than vapor.

         Some things that could be improved upon is how ice (a solid) will keep it's shape, a liquid (water) will change shape to fit the "bottom" of the container, and how vapor (a gas) will change shape to fill the whole conatiner and will need a lid. His models somewhat show this, but he could add onto it to make it improved.

         I hope this helps, have a nice day! :D

1.5 grams  of Iodine-131 is left after 32 days

The half life of a substance is given by:

No (1/2 ) ^ t / (t*1/2)

Where No is the substance remaining after the period

t(1/2) is the half life

t(1/2) = 8 days

t = 32 days

No =  24 grams

N = 24 x (1/2)^ 32/ 8

N = 1.5 grams

Half-life is  described as the length of time it takes for half of the radioactive atoms of a specific radionuclide to decay.

A good rule of thumb is that, after seven half-lives, you will have less than one percent of the original amount of radiation.

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Answer:

USB-6000

Explanation:

For this strange exercise, you must take into account two fundamental aspects of the data acquisition cards;

* The resolution of the cards, which for a 12-bit card is 2.24mV =2.24 10⁻³V , for which a card of this resolution is sufficient

    In your case, the amplitude is 50 mv, which is why it is much higher than the resolution of the card.

* The sampling rate or the frequency in which the card can acquire the data, the typical frequencies go from 200 Khz to the MHz, in general a card that has more than double the frequency to be measured should be selected.

In this case the frequency of your wave is

           f = 1 / T

           f = 1/100 10⁻³

            f = 10 Hz

therefore a low frequency card is suitable.

- The third point is the requirement that it has a USB interface, most of the card do not have it

If you check the National Instruments catalog, there are low-cost cards for example: USB-6000 of 12bits and 10KS / s the latter is the samples taken per second

The horizontal force applied to the lower block is approximately 1,420.85 Newtons

The known parameters are;

The mass of the block, m₁ = 400 kg, weight, W₁ = 3,924 N

The mass of the block resting on the first block, m₂ = 100 kg, weight, W₂ = 981 N

The length of the string attached to the block, W₂, l = 6 m

The horizontal distance from the point of attachment of the second block to the block W₂, x = 5 m

The coefficient of friction between the surfaces, μ = 0.25

Let T represent the tension in the string

The upward force on W₂ due to the string = T × sin(θ)

The normal force of W₁ on W₂, N₂ = W₂ - T × sin(θ)

The tension in the string, T = N₂ × μ × cos(θ)

∴ T = (W₂ - T × sin(θ)) × μ × cos(θ)

sin(θ) = √(6² - 5²)/6

cos(θ) = 5/6

∴ T = (981 - T × √(6² - 5²)/6) × 0.25 × 5/6

Solving, we get;

T ≈ 183.27 N

The normal reaction on W₂, N₂ = T/(μ × cos(θ))

∴ N₂ = 183.27/(0.25 × 5/6) = 879.7

N₂ ≈ 879.7 N

The friction force, \(F_{f2}\) = N₂ × μ

∴ \(F_{f2}\) = 879.7 N × 0.25 = 219.925 N

The total normal reaction on the ground, \(\mathbf{N_T}\) = W₁ + N₂

\(N_T\) = 3,924 N + 879.7 N = 4,803.7 N

The friction force, on the ground \(\mathbf{F_T}\) = \(\mathbf{N_T}\) × μ

∴  \(F_T\) = 4,803.7 N × 0.25 = 1,200.925 N

The horizontal force applied to the lower block, P = \(\mathbf{F_T}\) + \(\mathbf{F_{f2}}\)

Therefore;

P = 1,200.925 N + 219.925 N = 1,420.85 N

The horizontal force applied to the lower block, P ≈ 1,420.85 N

The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J

First, we shall list out the given parameters from the question. This is shown below:

The quantity of heat energy that must be transferred can be obtained as follow:

Q = MCΔT

= 2.25 × 394 × 220

= 195030 J

Thus, we can conclude quantity of heat energy that must be transferred is 195030 J

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Answer:

0

Explanation:

it takes 84 years for Uranus to orbit the Sun. It only takes 12 years for Jupiter to orbit the Sun. So technically by the time that Jupiter finishes it's one, Uranus will not be able to even finish half of its orbit.

At the highest attitude, the  velocity of  the ball is 0 m/s, so the kinetic energy is 0 as well.

Hence the answer is potential energy because it doesn't depend on velocity .

The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.

To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.

The force between two charged particles can be calculated using Coulomb's law:

F = k * |q₁ * q₂| / r²

Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.

First, let's calculate the force exerted on q₂ by q₁:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²

F₁₂ ≈ 252000 N

The force is positive because q₁ and q₂ have opposite charges.

Next, let's calculate the force exerted on q₂ by q₃:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²

F₂₃ ≈ -63000 N

The force is negative because q₂ and q₃ have the same charge.

Finally, we can find the net force on q₂ by summing the individual forces:

Net force = F₁₂ + F₂₃

Net force = 252000 N + (-63000 N)

Net force ≈ 189000 N

The net force on particle q₂ is approximately 189000 N.

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An electric motor is used to convert electrical energy to mechanical energy; therefore, the answer is B.

Explanation:

You would think it should. But remember the Force is also determined by mass. The mass of the earth markes our mass like the smallest part of a mosquito leg. The earth will go on it its merry way without cosidering us at all.

Answer:

The linear velocity of blood in the aorta can be calculated using the equation:

v = Q / A

where v is the linear velocity, Q is the volume flow rate, and A is the cross-sectional area of the vessel.

The volume flow rate Q can be calculated using the equation:

Q = SV / t

where SV is the stroke volume and t is the duration of systole.

The cross-sectional area of the aorta can be calculated using the equation:

A = πr^2

where r is the radius of the aorta.

Given that the radius of the aorta is 1.5 cm, the stroke volume is 60 ml, and the duration of systole is 0.25 s, we can calculate the volume flow rate Q:

Q = SV / t = 60 ml / 0.25 s = 240 ml/s

Converting the units of Q to cm^3/s:

Q = 240 ml/s × 1 cm^3/1 ml = 240 cm^3/s

We can then calculate the cross-sectional area of the aorta:

A = πr^2 = π × (1.5 cm)^2 = 7.07 cm^2

Finally, we can calculate the linear velocity of blood in the aorta:

v = Q / A = 240 cm^3/s / 7.07 cm^2 = 33.9 cm/s

Therefore, the linear velocity of blood in the aorta is 33.9 cm/s.

Answer:

I = 15,645. kg*m/s or 15,645 N*s

Explanation:

I = m(^v)

I = 1050kg((26.2m/s-11.3m/s)

I = 15,645. kg*m/s

Answer:

Proving LHS=RHS

Explanation:

Given

p=dgh

Multiplying by 0 on both sides of the equations

p×0=dgh×0

0=0

:- Hence proved

Answer:

0.83 m/s

Explanation:

25-0÷30=0.83 m/s

1).

Time = (distance) / (speed)

Time = (1000 meters) / (331 m/s)

Time = 3.02 seconds

2).

Acceleration = (change in speed) / (time for the change)

Change in speed = (second speed) - (first speed)

Change in speed = (50 m/s) - (20 m/s) = 30 m/s

Acceleration = (30 m/s) / (5 seconds)

Acceleration = 6 m/s²

Answer: the answer is (C)

Explanation: Bar graphs show comparisons using number comparisons

Answer: The answer is a because that's where it would be after it bounced