Pointing towards a person, a man said to a woman, "his mother is the only daughter of your father." How is woman related to that person?

Answer:

the first one

Step-by-step explanation:

absolute value is a number's distance from zero, so distance from zero can not possibly be negative. Therefore, |4x-2|=-6 has no solution.

Answer:

It would be the first one because there is no value of x that makes the equation be true since an absolute value can never be negative.

Step-by-step explanation:

Hope this helps:)....if don't help then sorry for wasting your time and may God bless you:)

To use the geometric series to give a series for 1/1 x, we can start with the formula for a geometric series:

S = a/(1-r)

where S is the sum of the series, a is the first term, and r is the common ratio.

In this case, we can let a = 1 and r = -1/x. Then, we have:

S = 1/(1-(-1/x)) = x/(x+1)

So, we have a series for 1/1 x:

1/1 x = x/(x+1)

To differentiate this series to give a series for \(1/(1 x)^2\), we can use the power rule for differentiation. If we let y = 1/1 x, then:

dy/dx = \(x/(x+1)^2\)

This gives us a series for \(1/(1 x)^2\):

\(1/(1 x)^2 = -x/(x+1)^2\)
Given the terms "geometric series" and "differentiate," here's the solution to your question:

To find a series for 1/(1-x), we can use a geometric series with the formula:

Sum = a * \((1 - r^n) / (1 - r)\)

In this case, the first term a is 1, and the common ratio r is x. Therefore, the geometric series becomes:

1/(1-x) = 1 * \((1 - x^n) / (1 - x) = 1 + x + x^2 + x^3 + ...\)

Now, differentiate the series term by term to find the series for \(/(1-x)^2\):

d(1)/(dx) = 0, \(d(x^n)/(dx) = nx^(n-1)\)

The differentiated series is:

\(0 + 1 + 2x + 3x^2 + 4x^3 + ...\)

This is the series for \(1/(1-x)^2\), as requested.

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The probability that the student makes it to the second class before it starts is very close to 0.

To find the probability that the student makes it to the second class before it starts, we can use the concept of linear combinations of random variables and the properties of normal distributions.

Let's define the random variable X as the total time it takes for the student to transition from the end of the first class to the start of the second class. Since X is a linear combination of independent normally distributed random variables (X1, X2, X3), we can use their means and variances to calculate the mean and variance of X.

The mean of X is the sum of the means of X1, X2, and X3:

μX = μ1 + μ2 + μ3 = 9:02 + 9:15 + 10 = 28:17 minutes.

The variance of X is the sum of the variances of X1, X2, and X3:

σX^2 = σ1^2 + σ2^2 + σ3^2 = (2.5)^2 + (3)^2 + (2.5)^2 = 15.25 minutes^2.

Now, we need to calculate the probability that X is less than or equal to 0, meaning the student arrives before the second lecture starts. Since X follows a normal distribution, we can standardize the variable and calculate the probability using the standard normal distribution table.

Z = (0 - μX) / σX = (0 - 28:17) / √15.25 ≈ -9.43.

Using the standard normal distribution table or a calculator, we can find the probability corresponding to Z = -9.43. The probability is essentially 0, as the value is significantly far in the left tail of the standard normal distribution.

Therefore, the probability that the student makes it to the second class before it starts is very close to 0.

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Answer:

area = 288.62 mm²

Step-by-step explanation:

To find the area we divide the complex shape into simple shapes whose areas we can find.

There is a rectangle in the center.

There are 2 congruent triangles on the sides.

We have the lengths of 2 perpendicular sides of the triangles, so they are the base and height.

For the rectangle, we only have the width. We need to find the length.

The length of the rectangle is the hypotenuse of the triangles.

We use the Pythagorean theorem to find the length of the hypotenuse of the right triangle. That is the length of the rectangle.

a² + b² = c²

(10.4 mm)² + (15.3 mm)² = c²

c² = 342.25 mm²

c = 18.5 mm

area = area of triangles + area of rectangle

area = 2 × (1/2)bh + LW

area = 2 × (1/2) × 15.3 mm × 10.4 mm + 18.5 mm × 7 mm

area = 159.12 mm² + 129.5 mm²

area = 288.62 mm²

Answer:

x^2 - 10x + 25

Step-by-step explanation:

Hope it helps.

Answer:

Set your calculator to degree mode.

x/sin(34°) = 21/sin(71°)

x = 21sin(34°)/sin(71°) = about 12.42

The required answer would be the sum of 5, and 4 is divided by 2 as per the PEMDAS rule which is the correct answer would be option (A)

PEMDAS rule states that the order of operation starts with the calculation enclosed in brackets or the parentheses first. Exponents (degrees or square roots) are then operated on, followed by multiplication and division operations, and then addition and subtraction.

We have been given that expression as

⇒ 5 + 4 ÷ 2

As per the PEMDAS rule,

We have to apply the division operation to terms 4 and 2,

⇒ 5 + 4 /2

⇒ 5 + 2

Apply the addition operation, and we get

⇒ 7

Therefore, the required answer would be the sum of 5, and 4 is divided by 2.

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In summary, given a simple dataset with 30 points, the following steps were performed: (a) OLS estimation was used to calculate the coefficients β^0 and β^1 for the regression of Y on X.

(b) the predicted value of Y was calculated for each observation; (c) the residuals were calculated for each observation; (d) the Explained Sum of Squares (ESS), Total Sum of Squares (TSS), and Residual Sum of Squares (RSS) were calculated separately; (e) the coefficient of determination R^2 was calculated; (f) the predicted value of Y was determined when X equals the last digit of the CUNY ID plus one; and (g) the interpretation of β^0 and β^1 was provided.

In detail, to calculate the OLS estimates of coefficients β^0 and β^1, a regression model of Y on X was fitted using the given dataset. β^0 represents the intercept term, which indicates the value of Y when X is zero. β^1 represents the slope of the regression line, indicating the change in Y corresponding to a unit change in X.

The predicted value of Y for each observation was obtained by plugging the corresponding X value into the regression equation. The residuals were then calculated as the difference between the observed Y values and the predicted Y values. ESS represents the sum of squared differences between the predicted Y values and the mean of Y, indicating the variation explained by the regression model.

TSS represents the total sum of squared differences between the observed Y values and the mean of Y, representing the total variation in Y. RSS represents the sum of squared residuals, indicating the unexplained variation in Y by the regression model. R^2, also known as the coefficient of determination, was calculated as ESS divided by TSS, indicating the proportion of total variation in Y explained by the regression model. Finally, the predicted value of Y was determined when X equals the last digit of the CUNY ID plus one, allowing for an estimation of Y based on the given information.

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A Type II Error, also known as a "false negative," is a statistical term used in hypothesis testing. In hypothesis testing, we start with two competing hypotheses: the null hypothesis (H0) and the alternative hypothesis (Ha).

The goal of hypothesis testing is to determine which hypothesis is more likely to be true given the data. A Type II Error occurs when we fail to reject the null hypothesis when it is actually false. In other words, we incorrectly conclude that the null hypothesis is true when it is actually false.

For example, consider a medical test for a certain disease. The null hypothesis is that the patient does not have the disease, and the alternative hypothesis is that the patient does have the disease.

If the test results are negative (i.e., the patient does not have the disease), and the patient actually does have the disease, then we have made a Type II Error.

The probability of making a Type II Error is represented by the Greek letter β (beta). A common goal in hypothesis testing is to keep the probability of making a Type II Error as low as possible, while also keeping the probability of making a Type I Error (false positive) low as well.

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Answer:

\(\huge\boxed{2}\)

Step-by-step explanation:

Given Polynomial is:

\(3x^2 + 6x = 0\)

Degree of polynomial is the highest power on the variable.

Here 2 is the highest power on the variable, So, it is the degree of polynomial.

Answer:

Move right 6 units and up 4 units

Step-by-step explanation:

Quadratic Equation: f(x) = a(bx - h)² + k

a = vertical stretch/shrink

b = horizontal stretch/shrink

h = horizontal movement left/right

k = vertical movement up/down

Answer:

15

Step-by-step explanation:

f(x) = 3x -12 for x = 9

f(9) = 3(9) -12

27-12

15

Answer:

667/45 or 14 37/45

Step-by-step explanation:

you have to convert 5 4/5 x 2 5/9 then you multiply those numbers but simply them which would be 29/5 x 23/9 then you get 667/45 or 14 37/45 as an alternative form

hope this helps

Answer:

3) The value of k is 8. 5) The slope of the line y=-17x+47/3 is -17.

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(k-5)/(2-1)

m=(k-5)/1

m=k-5

k-5=3

k=3+5

k=8

----------------------

5) y=mx+b where m=slope and b=y-intercept.

The proportion of scores in a standard Normal Distribution that are greater than 1.25 is closest to a. a is 0.1056.

The proportion of scores in a standard Normal Distribution that are greater than 1.25 is:

\(P(Z > 1.25) = 1 - P(Z < 1.25)\)

Using a standard normal distribution table or a calculator.

The area to the left of 1.25 is 0.8944, so:

\(P(Z > 1.25) = 1 - P(Z < 1.25) = 1 - 0.8944 = 0.1056\)

The closest answer choice is (a) 0.1056.

The percentage of scores in a normal distribution with a standard deviation larger than 1.25 is:

either a calculator or a normal distribution standard table.

0.8944 is the region to the left of 1.25, so:

The nearest possible response is (a) 0.1056.

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Answer:

Pretty much everything, my dude

Step-by-step explanation:

May I have brainliest please? :)

Answer:

you fine

Step-by-step explanation:

Answer:

  11.4

Step-by-step explanation:

You want the distance between C(-5, 5) and D(4, -2).

The distance formula is ...

  d = √((x2 -x1)² +(y2 -y1)²)

For the given points, the distance is computed to be ...

  d = √((4 -(-5))² +(-2 -5)²) = √(81 +49) = √130

  d ≈ 11.4

The length of CD is about 11.4 units.

__

Additional comment

The distance formula is an application of the Pythagorean theorem. It computes the hypotenuse of a right triangle whose legs are the differences in x- and y-coordinates.

The total surface area of the prism will be 290.125 Square units.

The surface area of a rectangular prism is the measure of how much-exposed area a prism has. Surface area is expressed in square units.

The surface area of a rectangular prism is given by:

SA = 2 (lh +wh + lw )

where

l = 3

w = 4.25

h = 18.25

SA = 2 (3x18.25 + 4.25x18.25 + 3x4.25)

SA = 2 (54.75 + 77.5625 + 12.75)

SA = 2 (146.0625)

SA = 290.125 square units

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For Question 22:
To calculate the Page Rank of node B after 2 iterations, we need to use the formula:
PR(x) = (1-d) + d(Σ PR(y)/O(y))
where PR(y) is the Page Rank of node y and O(y) is the number of outgoing links from node y.

After the first iteration, the Page Rank of each node is:
PR(A) = 0.16, PR(B) = 0.29, PR(C) = 0.26, PR(D) = 0.29

So, for node B:
PR(B) = (1-0.9) + 0.9((PR(A)/1) + (PR(C)/2) + (PR(D)/1))
= 0.1 + 0.9(0.16/1 + 0.26/2 + 0.29/1)
= 0.1 + 0.9(0.16 + 0.13 + 0.29)
= 0.1 + 0.9(0.58)
= 0.52

After the second iteration, we need to use the updated Page Rank values to calculate the new values. So, after the first iteration, the Page Rank of each node is:
PR(A) = 0.11, PR(B) = 0.52, PR(C) = 0.28, PR(D) = 0.29

So, for node B:
PR(B) = (1-0.9) + 0.9((PR(A)/1) + (PR(C)/2) + (PR(D)/1))
= 0.1 + 0.9(0.11/1 + 0.28/2 + 0.29/1)
= 0.1 + 0.9(0.11 + 0.14 + 0.29)
= 0.1 + 0.9(0.54)
= 0.55

Therefore, the Page Rank of node B after 2 iterations is 0.55.

For Question 23:
To calculate the authoritativeness and hubness scores for node A, we need to use the formulas:
a(x) = Σh(y) and h(x) = Σa(y)
where h(y) is the hubness score of node y and a(y) is the authoritativeness score of node y.

In the very beginning, all nodes have an equal score of 1. So, for node A:
a(A) = h(A) = 1

Therefore, the authoritativeness and hubness scores for node A in the very beginning are both 1.

For Question 24:
To calculate the hubness score of node D after 2 iterations, we need to use the formula:
h(x) = Σa(y)*z(y,x)
where a(y) is the authoritativeness score of node y and z(y,x) is 1 if there is a link from node y to node x, otherwise it is 0.

After the first iteration, the authoritativeness scores are:
a(A) = 0.11, a(B) = 0.52, a(C) = 0.28, a(D) = 0.09

And the hubness scores are:
h(A) = 0.11, h(B) = 0.28, h(C) = 0.52, h(D) = 0.09

So, for node D:
h(D) = (a(A)*z(A,D)) + (a(B)*z(B,D)) + (a(C)*z(C,D)) + (a(D)*z(D,D))
= (0.11*0) + (0.52*1) + (0.28*0) + (0.09*1)
= 0.61

After the second iteration, the updated authoritativeness scores are:
a(A) = 0.07, a(B) = 0.38, a(C) = 0.27, a(D) = 0.28

And the updated hubness scores are:
h(A) = 0.07, h(B) = 0.29, h(C) = 0.45, h(D) = 0.19

So, for node D:
h(D) = (a(A)*z(A,D)) + (a(B)*z(B,D)) + (a(C)*z(C,D)) + (a(D)*z(D,D))
= (0.07*0) + (0.38*1) + (0.27*0) + (0.28*1)
= 0.66

Therefore, the hubness score of node D after 2 iterations is 0.66.
Question 22:
For the Page Rank of node B after 2 iterations, we use the formula: PR(x) = (1-d) + d * Σ(PR(y)/O(y)), where d=0.9, and O(y) is the number of outgoing links from y.

Without knowing the specific network structure and initial Page Rank values, I cannot provide the exact Page Rank for node B after 2 iterations.

Question 23:
In the beginning, the authoritativeness (a) and hubness (h) scores for node A are initialized. Generally, they are initialized as 1 for each node.

So, for node A:
a(A) = 1
h(A) = 1

Question 24:
For the hubness score of node D after 2 iterations, we need to update the initial hubness score twice using the formula: h(x) = Σ(a(y)), where x has a link to y.

Similar to Question 22, without knowing the specific network structure and initial authoritativeness values, I cannot provide the exact hubness score for node D after 2 iterations.

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MEAN: =29.42

THE MEDIAN:

\((29 + 36) \times \frac{1}{2} = 32.5\)

that's my answer hope it helps

Answer:

46878954575

Step-by-step explanation:

Answer:

I believe it will be 5.16.

Step-by-step explanation:

18% of 28.65 is 5.157, but rounded to the nearest cent will be 5.16. So 5.16 will be your answer. If this is wrong forgive me :3

Answer: C

Step-by-step explanation:

\(75=\frac{d+94}{2}\\ \\ 150=d+94 \\ \\ d=56\)

The area of each tile is 1 sq ft, No of tiles required is 176 sq ft /1 sq ft = 176

What is the area of the rectangle?

The area a rectangle occupies is the space it takes up inside the limitations of its four sides. The dimensions of a rectangle determine its area. In essence, the area of a rectangle is equal to the sum of its length and breadth.

Here, we have

Given: The pool is designed to be a 60 ft by 26 ft rectangle, and the deck around the pool is going to be lined with slate tiles that are 1 ft squares.

We have to find out how many tiles are needed.

The internal Length of the rectangle is 60ft

Internal Breadth of the rectangle is 26 ft

External Length of the rectangle is 60+ 2*1 = 62ft

External Breadth of the rectangle is 26+ 2*1 = 28ft

Area of the deck to be tiled = Outer Area - Inner area

  = (62×28 ) - (60×26)

  = 1736 - 1560

 =  176 Sq ft

Hence, the area of each tile is 1 sq ft, No of tiles required is 176 sq ft /1 sq ft = 176

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Answer:

  = 2^(3·1/4·1/2) = 2^(3/8)

Step-by-step explanation:

You want to simplify ...

  \(\sqrt{\sqrt[4]{8}}\)

The useful rules of exponents are ...

  \(\sqrt[n]{a}=a^{\frac{1}{n}}\\\\(a^b)^c=a^{bc}\)

Recognizing 8 = 2³, you can use fractional exponents to represent the roots, then simplify the exponent of the result.

  \(\sqrt{\sqrt[4]{8}} = ((2^3)^{\frac{1}{4}})^{\frac{1}{2}}=2^{3\cdot\frac{1}{4}\cdot\frac{1}{2}}=2^{\frac{3}{4\cdot2}}=\boxed{2^{\frac{3}{8}}}\)

__

Additional comment

In plain text, this is written 2^(3/8). Both the caret and the parentheses are required.

Answer:

the last one .

Step-by-step explanation:

like my answer and brainliest please

The solution to the equation "5*2-3^2 / (3^2-(-2))^2" after solving it is 1/121

To solve the equation 5*2-3^2 / (3^2-(-2))^2, we need to simplify the numerator and the denominator. This will give us this:

5*2-3^2 / (3^2-(-2))^2 =

= 10 - 9 / (9 - (-2))^2

Simplify further to make the number reduced

10 - 9 / (9 - (-2))^2

After the subtraction at the numerator level, the denominator figures have two minus signs which becomes a plus. As a result, we realize the value below

= 1 / (11)^2

In order to remove the bracket in the denominator, it implies that the number in bracket will be multiplied by itself since it is in the superscript of 2 which means 11 multiply by 11 or (11 x 11)

= 1/121

Therefore, to solve the equation 5*2-3^2 / (3^2-(-2))^2, one needs to simplify the equation and do the subtraction and addition from the numerator and the denominator respectively to realize the answer which is 1/121

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Answer: 1/121

Step-by-step explanation:

( 5 * 2 - 3^2 )/[ 3^2 - (-2)] ^ 2

= (10 - 9)/(9+2)^2

= 1 / 11^2

= 1/121

First, locate any two point from the line.

(15, 150) and (25, 130)

x₁ = 15 y₁= 150

x₂ = 25 y₂ = 130

Next, is to find the intercept.

Substitute x=15 y=150 and m=-2 into y=mx + b and solve for b

That is;

150 = 15(-2) + b

150 = -30 + b

Add 30 to both-side of he equation

150 + 30 = b

180 = b

Form the equation by substituting m=-2 and b=180 into y=mx + b

y = -2x + 180

Hence, the line function is y = -2x + 180