what is [(4×2)÷(4÷2)]×3

Answer:

Long solution

Step-by-step explanation:

(a) Let the height of the cone be h cm. The volume of the hemisphere is given by (1/2)(4/3)πr³ = (2/3)πr³. The volume of the solid is the sum of the volumes of the hemisphere and the cone, which is (2/3)πr³ + (1/3)πr²h. Since the volume of the hemisphere is one third of the volume of the solid, we have:

(2/3)πr³ = (1/3)πr²h

Simplifying, we get:

2r = h

Therefore, h is expressed in terms of r as h = 2r.

(b) The slant height of the cone can be found using the Pythagorean theorem. Let l be the slant height, then we have:

l² = r² + h²

Substituting h = 2r, we get:

l² = r² + (2r)² = 5r²

Taking the square root of both sides, we get:

l = r√5

Since k is an integer, we can write:

l = Vk cm, where k is an integer

Comparing the two expressions, we get:

Vk = r√5

Therefore, the value of k is k = ⌊r√5⌋, where ⌊x⌋ denotes the largest integer less than or equal to x.

(c) The total surface area of the solid is the sum of the curved surface area of the cone, the curved surface area of the hemisphere, and the area of the circular base of the cone. We have:

Curved surface area of the cone = πr l = πr(r√5) = πr²√5

Curved surface area of the hemisphere = 2πr²

Area of the circular base of the cone = πr²

Therefore, the total surface area of the solid, in cm², is given by:

πr²√5 + 2πr² + πr² = (πr²)(√5 + 3)

A type I error takes place if a given null hypothesis is rejected but is said to be true in the population such as the forecast shows it is snowing outside but actually it is isn't.

A type II error is known to be a statistical term that tells the error that takes place when one fails not to accept a null hypothesis that is said to be really false. A type II error create a false negative.

Note that:

The power of the test shows that:

See full question below

Suppose you have the following null and alternative hypothesis:

H o: it is snowing.

H a: It is not snowing

(A) in the context of this problem, describe a Type-1 error

(B) Describe Type II error

(C)Describe power of the test

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Answer: Yes, after 7 weeks, they will have the same amount of money

Step-by-step explanation: So let’s say Joyce will be equation 1, so it would be - T = 13 + 6x, where T represents the total money, and x represents the number of weeks. And let’s say Enrique will be equation 2, which will be - T = 80 - 5x, where once again, T represents the total money, and x represents the number of weeks.

So, let’s start going off numbers, we will start at 5 weeks, when we put that in, Joyce will have $43 and Enrique will have $65, so we know it will be more than 5 weeks, so let’s try 8 weeks, Joyce will have $61 and Enrique will have $40, so it’s below 8, so how about we try 7, at 7 weeks, Joyce will have $55, and Enrique will have $55 too. So this means, after 7 weeks, Joyce and Enrique will have the same amount of money

Answer:

\( \frac{1}{2} \times 9 \times 6 = 27 \\\)

You have to count the units then put the rule

\( \frac{1}{2} \times base \: \times hight\)

The polynomial function are \(x^{2}\) and \(\frac{1}{x}\).

A polynomial function is a function that involves only non-negative integer powers or only positive integer exponents of a variable in an equation like the quadratic equation, cubic equation, etc.

Christi should know the "zeros" of the polynomial function for sketching the graph of it (where the graph intersects with the x an y - axises, (if it does). Also, she needs to know the vertical and horizontal stretches/shrinks for that. Finally, she should know the basic function of the polynomial function such as , \(x^{2}\) and \(\frac{1}{x}\) , etc.

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Answer:

Step-by-step explanation:

\(\angle 2,\angle AEG, \angle GEB\)

For this problem we know that David worked 7 173 hours today and planted 11 trees. And we want to find How long did it take him to plant each tree?

So we can set up the following equation:

And solving for x we got:

It took him 1.5 hour to plant each tree.

​

\(The given function is: $f(x, y) = e^{x + y + 4}$.The partial derivative of f(x, y) with respect to x is given by, $f_{x}(x, y) = \frac{\partial}{\partial x}e^{x + y + 4} = e^{x + y + 4}$\)

\(Similarly, the partial derivative of f(x, y) with respect to y is given by,$f_{y}(x, y) = \frac{\partial}{\partial y}e^{x + y + 4} = e^{x + y + 4}$\)

\(Now, let's calculate the value of $f_{x}(2,-1)$.\)

\(We have,$f_{x}(2,-1) = e^{2 - 1 + 4} = e^{5}$\)

\(Similarly, the value of $f_{y}(-4,3)$ is given by,$f_{y}(-4,3) = e^{-4 + 3 + 4} = e^{3}$\)

Hence, $f_{x}(x, y) = e^{x + y + 4}$ and $f_{y}(x, y) = e^{x + y + 4}$.

\(The values of $f_{x}(2,-1)$ and $f_{y}(-4,3)$ are $e^{5}$ and $e^{3}$ respectively.\)

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Answer:

Step-by-step explanation:

Not a function

In order for an equation to represent a function any single value of x must have at most one corresponding value of y which satisfies the equation.

For

x2+y2=9

(for example)

x=0

there are two values for y (namely +3 and −3) which satisfy the equation

If you plug this graph into a calculator, you will find that it is a graph of a circle.

Circles have the formula x2+y2=r2 if they are centered at the origin.

From that, we can find that the radius is 3, and it is centered at the origin.

To find the domain and range, we just find the largest and smallest x and y values.

Since the radius is 3, and the graph is centered at the origin, the largest x value is 3. Similarly, the smallest x value is -3.

The domain is −3≤x≤3

We can use the same thing for the range. The radius is 3, so the largest and smallest values of the y will be 3 and -3.

The range is -3≤y≤3

Answer:

See below

Step-by-step explanation:

6. Look at the graph of the equation x^2+y^2=8. Give its domain and range.

7. Use algebraic means to show that x^2+y^2=8 is not a function. Explain your process.

8. Is there any value(s) of the domain of x^2+y^2=8 that passes the vertical line test? If so, name the value(s) and state whether or not the existence of this value makes this relation a function. You can use Desmos to help you explore this idea, if needed.

Each strength training exercise should be performed for 2 to 6 sets with no more than 6 repetitions. To encourage the greatest outcomes, the training intensity for each set should be 85% or greater.

In essence, percentages are fractions with a 100 as the denominator. We place the percent sign (%) next to the number to indicate that the number is a percentage. For instance, you would have received a 75% grade if you answered 75 out of 100 questions correctly on a test (75/100). %, which is a relative figure used to denote hundredths of any amount. Since one percent (symbolized as 1%) is equal to one tenth of anything, 100 percent stands for everything, while 200 percent refers to double the amount specified.

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Answer:

hypotenuse 2 is the answer

The regular expression is ^(a(aa)*b)$.

To create a regular expression for the language L = {w = {a,b}* | w has an odd number of 'a's and ends with 'b'}, we can use the following expression:

^(b|(a(aa)*b))$

Breaking it down:

^ indicates the start of the string.

(b|(a(aa)*b)) matches either 'b' or a sequence of 'a's followed by an odd number of 'a's and 'b'.

(aa)* matches zero or more pairs of 'a's.

$ indicates the end of the string.

This regular expression ensures that the string starts with 'b' or a sequence of 'a's, followed by an odd number of 'a's, and ends with 'b'. Any additional characters or sequences in between are not allowed.

Please note that regular expressions can have different notations and conventions depending on the context or programming language you're using. The expression provided here follows a general pattern that should work in most cases.

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19 + X > 26

X > 7

To break your record you need more than 7 digs

Answer:

256.4

Step-by-step explanation:

This is Rylan from yesterday

The solution set to the given inequalities from the graph in the form (x,y) is (-1, 2)

In mathematics, inequality arises when two mathematical expressions or two numbers are compared that are not equal. Generally, inequalities may be either numerical or algebraic, or a mixture of both.

Linear inequalities require at least one linear algebraic expression, here the polynomial is of one degree and is compared with another algebraic expression of a degree less than or equal to 1.

In the given question, we are to graph the following linear inequalities

x + y > 1

-x + y < 3

The solution set to the given inequalities by plotting their graph shows that (x,y) is (-1, 2)

The points in each shaded region of the graph are:

(0, 3)  The point is a solution to either inequality

(0, 1)   The point is a solution to one of the inequality

(-3, 0)  The point is  not a solution to either inequality

(-1, 2)   The point is a solution to either inequality

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Answer:

Ffggf

Step-by-step explanation:

The 50% value is 13.

The longest hours studied is 20.

The shortest hours studied is 5.

The 75% number is 17.

The five number summary is the summary of a dataset that contains information on the minimum number, the 25th percentile, the median, the 75th percentile and the maximum number.

The median is the number at the center of the dataset. The median is 13. The maximum number provides information on the longest number of hours studies. The  minimum  number is the shortest number studied by anyone. The minimum number is 5. The 75th percentile is 17.

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Answer:

0.31

Step-by-step explanation:

Prime number (a+b) ≡ a+b (mod p).

To prove the given statements, we will use some number theory properties.

Statement 1: If (x, y) = 1, then (x+y, xy) = 1.

Proof:

Let's assume (x+y, xy) = d, where d is a common divisor of (x+y) and xy.

Since d divides (x+y), we can express x+y = dm, where m is an integer.

Similarly, d divides xy, so we can express xy = dn, where n is an integer.

Expanding xy = dn, we get x(dm-y) = dn.

Since (x, y) = 1, x cannot divide d. Thus, x must divide n, which means n = xk, where k is an integer.

Substituting n = xk in xy = dn, we get x(dm-y) = dxk.

Cancelling x, we have dm-y = dk.

Rearranging the equation, we get y = dm-dk = d(m-k).

This implies that d divides y, which contradicts the assumption that (x+y, xy) = d. Hence, (x+y, xy) = 1.

Statement 2: If (a, b) = 1, then a² = ab + b².

Proof:

Expanding (a+b)², we have (a+b)² = a² + 2ab + b².

Now, let's subtract 2ab from both sides of the equation:

(a+b)² - 2ab = a² + b².

Simplifying, we get a² + 2ab + b² - 2ab = a² + b².

Cancelling like terms, we have a² = ab + b², which proves the statement.

Statement 3: If (a, b) = 1, then (a+b, 2) = 1.

Proof:

Let's assume (a+b, 2) = d, where d is a common divisor of (a+b) and 2.

Since 2 is a prime number, its only divisors are 1 and 2.

If d = 1, then (a+b, 2) = 1, which proves the statement.

If d = 2, then (a+b) is even because it is divisible by 2. However, since (a, b) = 1, both a and b cannot be odd. Thus, either a or b must be even, making (a+b) even. This contradicts the assumption that d = 2. Hence, (a+b, 2) cannot be 2, and it must be 1.

Statement 4: (a+b) ≡ a+b (mod p), where p is a prime number.

Proof:

To prove this congruence, we need to show that (a+b) - (a+b) is divisible by p, which means (a+b) - (a+b) = kp for some integer k.

Simplifying, we get 0 = kp, which is true since any number multiplied by 0 is 0.

Therefore, (a+b) ≡ a+b (mod p).

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The independent variable x ,represents minutes and dependent variable is the number of candies eating by Levi because the eating of candies depends on the minutes.

A function relating these variable is Z(x)=4x

So Z(7)=28 meaning In 7 minutes Levi ate 28 candies and number of candies left in the bag is 22.

As given,

Independent variable=x

Dependent variable=Z(x)

Function Z(x)=4x

So, Z(7)=4×7

            =28

Candies left in bag =50 -28

                              =22

Therefore, function relating independent variable x with Z(x)=4x  and Z(7)=28 represents number of candies ate by Levi in 7 minutes ,number of candies left in the bag is 22.

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The solution to the initial value problem 64y'' - y = 0, with y(-8) = 1 and y'(-8) = -1, is approximately:

y(t) ≈ -4.038e^(t/8) + 5.038e^(-t/8)

To solve the initial value problem 64y'' - y = 0, with initial conditions y(-8) = 1 and y'(-8) = -1, use the method of solving second-order linear homogeneous differential equations.

First, let's find the characteristic equation:

64r^2 - 1 = 0

Solving the characteristic equation, we have:

r^2 = 1/64

r = ±1/8

The general solution of the homogeneous equation is given by:

y(t) = c1e^(t/8) + c2e^(-t/8)

Now, let's apply the initial conditions to find the particular solution.

1. Using the condition y(-8) = 1:

y(-8) = c1e^(-1) + c2e = 1

2. Using the condition y'(-8) = -1:

y'(-8) = (c1/8)e^(-1) - (c2/8)e = -1

system of two equations:

c1e^(-1) + c2e = 1

(c1/8)e^(-1) - (c2/8)e = -1

Solving this system of equations, we find:

c1 ≈ -4.038

c2 ≈ 5.038

Therefore, the particular solution is:

y(t) ≈ -4.038e^(t/8) + 5.038e^(-t/8)

Hence, the solution to the initial value problem 64y'' - y = 0, with y(-8) = 1 and y'(-8) = -1, is approximately:

y(t) ≈ -4.038e^(t/8) + 5.038e^(-t/8)

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Answer:

7/20

Step-by-step explanation:

To add fractions, the first step is to get a common denominator

1/4 + 1/10

The common denominator is 20

1/4 *5/5 = 5/20

1/10 *2/2 = 2/20

5/20 + 2/20 = 7/20

Answer:

It is D 128.67

Solution:

Opposite=60

Angle=25degrees

Adjacent=?

Hypotenuse=?

We need to solve for the adjacent so don't worry about hypotenuse value.

Equation to solve for Adj.

tan(x)=Op./Hyp.

tan(25)=60/adj.

You then flip it

Adj.=60/tan(25)

Adj.=60/0.46630765815

Adj.=128.67 feet

Whallah!

Ask any questions that you have in the comments!

Answer:

D 128.67

Step-by-step explanation:

took the test and got it right. 100% correct

The minimum value of the function f(x) =0. 9x2+3. 4x-2. 4 is -3.77 and its parabolic curve is upward because of its minimum value.

Let's consider the equation of a function.

f(x) = \(0.9x^{2} + 3.4x -2.4\)

Now, divide each and every element and assume that a, b, and c are coefficients of the function given.

a: 0.9

b: 3.4

c: -2.4

The sign of the coefficient of a determines the exposure of the parabola. Since a >  0, the parabola is open upwards and has a minimum value.

We can find the "x" of the vertex using the following expression.

x(v) = -b/2a = -3.4/(0.9)

x(v) = -3.77

We can find the "y" of the vertex by replacing this x in the equation

y(v) = 0.9(-3.77)² + 3.4(-3.77) -2.4

y(v)  = -2.42

The minimum value of the function is -3.77

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The rules AAS, ASA, SSS and SAS are congruence rule of triangle  and the each rules has been explained

The rules AAS, ASA, SSS and SAS are congruence rule of triangle

SSS rule is side-side-side rule, it states that if three sides of the one triangle and three sides of the other triangles are equal, then both triangles are congruent

SAS rule is side-angle-side rule, it states that if two sides and one included angles between the sides of the one triangle is equal to  the two sides and one included angles between the sides of the other triangle, then both triangles are congruent

ASA rule is angle-side-angle rule, it states that if two angles and one included side between the angle of the one triangle is equal to the two angles and one included sides between the angles of the other triangle, then both triangles are congruent

AAS rules is angle-angle-side rule, it states that if two angles and one non included sides of the one triangle is equal to the two angles and one non included sides of the another triangle, then both triangles are congruent

Therefore, the AAS, ASA, SSS and SAS are the rules of congruence of the triangle

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The sum of the 3 inside angles equal 180

To find the missing angle subtract the 2 known angles from 180.

R = 180 - 114 - 32 = 34

R = 34 degrees

Answer:

1 . is a function

2. is not a function