how can the rate of evaporation of a liquid be increased?​

Answers

Answer 1

When air is blown above the surface of liquid, it will take away the liquid carrying air particles from the air above the liquid, resulting in decrease in humidity and increase in rate of evaporation.

Hope that this was helpful :)


Related Questions

If the Sun’s mass increased, how would the gravity between the Sun and Earth change?
Possible Answers :
1. It would increase
2. It would decrease
3. It would not change

Answers

Answer:

1. increase

Explanation:

Mass is proportional to gravity. The bigger two objects are, the stronger the force of gravity between them will be.

to measure the static friction coefficient between a block and a vertical wall, a spring is attached to the block, is pushed on the end in a direction perpendicular to the wall until the block does not slip downward. If the spring is compressed, what is the coefficient of static friction

Answers

Answer:

μ = mg/kx

Explanation:

Since the bock does not slip, the frictional force equals the weight of the block. So, F = mg. Now, the frictional force, F = μN where μ = coefficient of static friction and N = Normal force.

Now, the normal force equals the spring force F' = kx where k = spring constant and x = compression of spring.

N = F' = kx

So, F = μN = μkx

μkx = mg

So, μ = mg/kx

An astronomer is trying to observe two distant stars. The stars are marginally resolved when she looks at them through a filter that passes green light with a wavelength near 550 nm. Which of the following actions would improve the resolution? Assume that the resolution is not limited by the atmosphere.

Required:
a. Changing the filter to a different wavelength? If so, should she use a shorter or a longer wavelength?
b. Using a telescope with an object lens of the same diameter but a different focal length? If so, should she select a shorter or a longer focal length?
c. Using a telescope with an objective lens of the same focal length but a different diameter? If so, should she select a larger or a smaller diameter?
d. Using an eyepiece with a different magnification? If so, should she select an eyepiece with more or less magnification?

Answers

Answer:

a) True. Diffraction decreases with decreasing wavelength

c) True. As the diameter increases the diffraction decreases, we can observe closer stars

Explanation:

To solve two distant stars we must use Rayleygh's criterion that establishes that two objects are separated if the central maximum of one coincides with the first minimum of the other, applying this to the expression for the diffraction of a slit

          a sin θ = m λ

with m = 1

as the telescope has surgical objects, we must solve the problem in polar coordinates, leaving the expression

          a sin θ = 1.22 λ

          sin θ = 1.22 λ/a

now we can analyze the different statements

a) True. Diffraction decreases with decreasing wavelength

b) False. The focal length influences the magnification, the size of the image, but not the resolution of the same

c) True. As the diameter increases the diffraction decreases, we can observe closer stars

d) False. The focal length influences the magnification not the resolution,

(PLEASE HELP ITS DUE SOON ILL MARK BRAINLIEST AND 5 STARS & PLEASE SHOW WORK!!)

(And the answer is not 44 I already tried that and it doesn’t start with 4 either)

(PLEASE HELP ITS DUE SOON ILL MARK BRAINLIEST AND 5 STARS & PLEASE SHOW WORK!!)(And the answer is

Answers

Lol I would help you but I have no clue

What happens to the apperent brightness of a star as you get closer to it

A. It gets brighter.

B. It gets dimmer.

C. It gets larger.

D. It gets smaller


I really the answer Asap thanks!
Im not collage btw lol

Answers

It can either get brighter or even larger depends on the options given also

The thermal energy that causes the ice to melt is transferred from the lemonade as it cools. The loss of this thermal energy causes the temperature of the 300 g of the lemonade to fall by 19 °C. Calculate the specific heat capacity of the lemonade.​

Answers

According to the give value of the mass of lemonade and change in the temperature, the specific heat capacity of the lemonade is 3.81 J/kg/k.

The formula for the specific heat capacity (C) = Q/ m × ΔT

Q is energy added and the value, which is 334J

m is the mass of the lemonade, which is 300g = 0.3 kg

Δ T is the change in temperature, which is 19°C =(273+19)= 292 K

So, C = 334/ 0.3 × 292

         = 3.81 J/kg/k

So the specific heat capacity of the lemonade is 3.81 J/kg/k.

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The NEC states the resistance of 4/0 coated
copper conductors is 0.0626 ohms per 1000
feet. What would be the total resistance of the
three 4/0 conductors installed in parallel, if the
total length for each of the three conductors is
323 feet?

Answers

Answer:

The resistance of 4/0 coated copper conductors is given as 0.0626 ohms per 1000 feet. To find the total resistance of the three 4/0 conductors installed in parallel, we can use the formula for combining resistances in parallel.

Since the total length for each of the three conductors is 323 feet, the resistance of each conductor can be calculated as follows:

Resistance of one conductor = (0.0626 ohms / 1000 feet) * 323 feet

To find the total resistance when the conductors are in parallel, we use the formula:

1/Total Resistance = 1/Resistance of Conductor 1 + 1/Resistance of Conductor 2 + 1/Resistance of Conductor 3

Total Resistance = 1 / (1/Resistance of Conductor 1 + 1/Resistance of Conductor 2 + 1/Resistance of Conductor 3)

Substituting the values, we get:

Total Resistance = 1 / (1/((0.0626 ohms / 1000 feet) * 323 feet) + 1/((0.0626 ohms / 1000 feet) * 323 feet) + 1/((0.0626 ohms / 1000 feet) * 323 feet))

Simplifying the expression will give us the total resistance of the three 4/0 conductors installed in parallel.

Suppose you have a barometer with mercury and a barometer with water. How does the height hwater compare with the height hmercury?.

Answers

The heaviest liquid is mercury. In order to equalize the air pressure, it only climbs 76 cm. Water will rise to a 13.6 because it is 13.6 times lighter than mercury. By a factor of 13.6, mercury is 13.6 times denser than water.

Therefore, the barometer's height would be 13.6 times higher if water were employed in place of mercury. Since water expands when it freezes, the glass tube would be broken.

Because of its high density, mercury is frequently employed in barometers, allowing for a column height that is appropriate for measuring atmospheric pressure. For example, a mercury barometer would need to be 13.6 times taller than a water barometer to measure the same change in pressure.

This is the primary justification for using mercury in thermometers. Mercury will provide accurate readings in comparison to water since it lacks the condensation property that water possesses. Mercury can be used to measure both negative and positive temperatures, whereas water cannot be used to measure either.

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The figure (Figure 1) shows a pV diagram for 4.00×10−3 mole of ideal H2 gas. The temperature of the gas does not change during segment bc. What volume does this gas occupy at point c?

Answers

The volume that the gas will occupy based on the temperature given will be 0.80 liters.

How to calculate the volume?

From the information, it was stated that the figure shows a pV diagram for 4.00×10−3 mole of ideal H2 gas and that the temperature of the gas does not change during segment bc.

Therefore, the volume will be:

= (0.20) × (2.0/0.50)

= 0.20 × 4

= 0.80

In conclusion, the volume is 0.80 liters.

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The toy car in the diagram runs off the edge of the table that is 1.225m high. The car lands 0.400m from the base of the table.

a. How long did it take the car to fall

b. how fast was the car going on the table

Answers

A . 0.5s B. 2.45m/s
Have a great day :)

if the potential difference applied across a particular capacitor is doubled, the stored energy will be doubled. What happens to the energy stored?

Answers

If the potential difference across a capacitor is doubled, the energy stored in it is quadrupled.

The ability difference between any points inside the electric-powered field is defined as the quantity of labor done in transferring a unit of fantastic charge without acceleration from one point to another alongside any route among the 2 factors. The distinction in price between higher capability and lower capacity is known as a voltage or capacity distinction.

The voltage between points can be a result of the build-up of electric rate (e.g., a capacitor), and from an electromotive pressure (e.g., electromagnetic induction in generators, inductors, and transformers).On a macroscopic scale, a potential distinction can be due to electrochemical methods (e.g., cells and batteries), the stress-induced piezoelectric effect, and the thermoelectric effect.

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A rectangular block weighting 320N has dimensions 4metre by 10metre what is the greater pressure and the least pressure it can be exerted on the ground ​

Answers

The pressure exerted by a rectangular block on the ground is 8 Pascal (Pa) when its weight is 320 N and its dimensions are 4 meters by 10 meters. The greatest pressure occurs when the block is vertically placed at 20 Pa, while the least pressure occurs when it is horizontally placed at 8 Pa.

To calculate the pressure exerted by the rectangular block on the ground, we need to consider the formula for pressure:

Pressure = Force / Area

Given that the weight of the block is 320 N and the dimensions of the block are 4 meters by 10 meters, we can calculate the area of the block in contact with the ground. In this case, it is the length multiplied by the width of the block.

Area = length * width

Area = 4 meters * 10 meters

Area = 40 square meters

Now, we can calculate the pressure exerted by the block on the ground:

Pressure = 320 N / 40 square meters

Pressure = 8 N/m^2 (Pascal)

Therefore, the pressure exerted by the rectangular block on the ground is 8 Pascal (Pa).

To determine the greatest pressure and the least pressure that can be exerted on the ground, we need to consider the orientation of the block.

The greatest pressure occurs when the block is placed vertically on one of its smallest faces. In this case, the entire weight of the block (320 N) is concentrated on a smaller area.

The area in contact with the ground is given by the length multiplied by the width of the smallest face.

Area = 4 meters * 4 meters = 16 square meters

Greatest Pressure = 320 N / 16 square meters = 20 \(N/m^2\)(Pascal)

The least pressure occurs when the block is placed horizontally on one of its largest faces. In this case, the weight of the block is distributed over a larger area.

The area in contact with the ground is given by the length multiplied by the width of the largest face.

Area = 4 meters * 10 meters = 40 square meters

Least Pressure = 320 N / 40 square meters = 8 \(N/m^2\)(Pascal)

Therefore, the greatest pressure that can be exerted on the ground is 20 Pascal (Pa), and the least pressure is 8 Pascal (Pa).

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Required
Momentum
The magnitude of the momentum of an object is 64 kg*m/s. If the velocity of the
object is doubled, what will be the magnitude of the momentum of the object? *
32 kg*m/s
64 kg*m/s
128 kg*m/s
256 kg*m/s

Answers

Answer:

C) 128 kg*m/s

Explanation:

When you double something you multiply it by 2 most of the time. 64*2=128 or you can add it 64+64=128. Hope this helps.

what is the acceleration of a 10 kg mass pushed by a 5 N force

Answers

Answer:

The formula is a = F m so in this case a = 5 10 = 0.5 m s 2

Explanation:

Density of iron is 7860 Kg/m^3 what is the mass of iron sphere whose diameter is 0.5 m?

Answers

The mass of the given iron sphere of diameter 0.5 m is 510.9 kg

Density of the iron sphere = 7890 kg/m³

Diameter of the iron sphere = 0.5 m

Radius of the iron sphere = 0.25m

The formula to find the mass of the iron sphere is

                                ρ = m / v

where ρ is the density

          m is the mass

          v is the volume.

So , to find the mass , we need to know the volume of the sphere

Volume of the sphere = 4/3 πr³

Let us substitute the value of r in the above equation,

                    V = 4/3 x 3.14 x (0.25)³

                        = 4/3 x 3.14 x 0.0156

                        = 0.196/3

                  V  = 0.065 m³

So , now let us find the mass of the given sphere

                 ρ = m / v

                m = ρv

                m = 7860 x 0.065

               m = 510.9 kg

Therefore , the mass of the given iron sphere is 510.9 kg

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Which part of a road vehicle must be tested to ensure that there is sufficient friction to stop the vehicle in an emergency?

Answers

The part of a road vehicle which must be tested to ensure that there is sufficient friction to stop the vehicle in an emergency is the tyre.

What is Friction?

This is referred to as a force that resists the motion of one object against another when they roll or slide against each other.

When dealing with braking, the main factor is to have sufficient friction between the road surface and tyre to bring the vehicle to a standstill. If the tyres are wornout there won't be enough friction to make the vehicle stop during emergencies which is therefore the reason why it was chosen as the correct choice.

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Someone who fears their actions or behaviors Will support negative ideas about a group to which they belong is experiencing.
A) cognitive dissonance
B) group polarization
C) misperception
D) stereotypes threat

Answers

D) stereotypes threat

The flu _____.

is caused by bacteria
is noncommunicable
can be prevented by practicing good hygiene
was discovered by Edward Jenner during the 1700s

Answers

can be prevented by practicing good hygiene

Answer:

b and d is wrong because if you sneezing and cough or other things like wiping your nose on your hand and touching things that other people touch can make people have the flu while you have it and edward jenner discovered cowpox and smallpox, not the flu

Explanation:

If a quarterback gets hit by a defensive lineman with a mass of 100 kg and accelerating at a rate of 1m/s2 at what force is the quarterback getting hit? ​

Answers

The quarterback is getting hit with a force of 100 Newtons.

How to calculate the force with which the quarterback is getting hit

We can use Newton's second law of motion:

Force = Mass * Acceleration

Given that the mass of the defensive lineman is 100 kg and the acceleration is 1 m/s², we can substitute these values into the equation:

Force = 100 kg * 1 m/s²

Force = 100 N

Therefore, the quarterback is getting hit with a force of 100 Newtons.

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A rock is dropped from a sea cliff, and the sound of it striking the ocean is heard 3.7 s later.
If the speed of sound is 340 m/s, how high is the cliff?
Neglect all frictional forces.

Answers

The height of the cliff, given that the sound of rock dropped from the cliff was heard 3.7 s later is 629 m

How do I determine the height of the cliff?

We know that echo of sound wave is given by the following formula:

Speed = (2 × distance) / time

Using the above formula, we can determine the height of the cliff. This is illustrated below:

Time = 3.7 secondsSpeed of sound = 340 m/sHeight of cliff =?

Speed = (2 × height) / time

340 = (2 × height) / 3.7

Cross multiply

2 × height = 340 × 3.7

2 × height = 1258

Divide both sides by 2

Height = 1258 / 2

Height = 629 m

Thus, from the above calculation, we can conclude that the height of the cliff is 629 m

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kinetic energy during an object falling

Answers

Answer:

\(kinetic \: energy = \frac{1}{2} m {v}^{2} \\ m = mass \: of \: the \: object \\ v = velocity \: \)

How does the force of the car change as the mass of the car is increased?

Answers

yes

Explanation:

because if a car is 100 pounds then it will have less force than a 250 pound car

When stretched beyond it's elastic limit, a metal rod such as steel​

Answers

Answer:

When an elastic material is stretched, depending on the stress, it might reach a point beyond which it will no longer return to its original size and shape. This point is called the elastic limit.

When the material (such as a metal rod (e.g steel, copper)) is stretched beyond its elastic limit, Hooke's law is no longer obeyed. i.e strain is no longer directly proportional to stress.

The symbol used for a magnetic pole is:

m
M
P
p

Answers

The symbol used for a magnetic pole is option Ana d B:  "m" and "M" , which are used to indicate North and South magnetic poles.

What is the magnetic pole about?

In physics, a magnetic pole is a point on a magnet where the magnetic field is most concentrated. The north pole of a magnet is the pole that points towards the Earth's geographic north pole, while the south pole of a magnet is the pole that points towards the Earth's geographic south pole.

Therefore, These poles are labeled "N" (for north) and "S" (for south) respectively, but it's also common to use the symbols "m" and "M" to indicate magnetic poles.

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The known values are given in the table below them. Find the missing values.

The known values are given in the table below them. Find the missing values.

Answers

The value of  the missing resistance, R₃ = 10.35 ohms.

The value of the missing voltages, V₁ = 6 V, V ₃ = 24 V.

The value of the missing currents, I₁ = 3 A, I₃ = 2.32 A.

What is the value of missing component of the circuit?

The values of the missing component of the circuit is calculated by applying the following formula.

The total resistance of the circuit;

For R₂, R₃, 1/R = 1/R₂ + 1/R₃

1/R = 1/12 +  1/R₃

1/R = (R₃ + 1)/(12R₃)

R = 12R₃ / (R₃ + 1)

For, R₁, R₂ and R₃, total resistance;

R = 12R₃ / (R₃ + 1) + R₁

R = [12R₃ / (R₃ + 1)] + 2

R = (12R₃ + 2(R₃ + 1) ) / (R₃ + 1)

R = (12R₃ + 2R₃ + 2 ) / (R₃ + 1)

R = (14R₃ + 2 ) / (R₃ + 1)

The total current in circuit is calculated as;

I = V/R

I = 30 / R

I = ( 30 ) / (14R₃ + 2 ) / (R₃ + 1)

I = (30R₃ + 30) / (14R₃ + 2) ------- (1)

The voltage in parallel circuit is the same

V₂ = V₃ = 24 V

V₃ = IR₃

24 = IR₃

I = 24/R₃  --------- (2)

Solve (1) and (2) together as follows;

24/R₃ = (30R₃ + 30) / (14R₃ + 2)

30R₃² - 306R - 48 = 0

Solve the quadratic equation, using formula method.

R₃ = 10.35 ohms

I₃ = V₃/R₃

I₃ = 24 V / 10.35

I₃ = 2.32 A

If the voltage drop at R₂ and R₃ = 24 V, the voltage drop at R₁ = 30V - 24 V = 6 V

The current in R₁ = V₁/R₁ = 6 V / 2 V = 3 A

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The work-energy theorem states that the change in the kinetic energy of an object is equal to what?

Answers

The work-energy theorem states that the change in the kinetic energy of an object will be equal to the net work done on the object.

Mathematically, it can be expressed as;

ΔKE = W

Where; ΔKE represents the change in kinetic energy of the object,

W represents the net work done on the object.

This theorem states that when work is done on an object, it results in a change in its kinetic energy. If work is done on an object, its kinetic energy increases, and if work is done by an object, its kinetic energy decreases.

This theorem is a fundamental principle in physics that relates the concepts of work and energy, and it is often used to analyze the motion and behavior of objects in various physical systems.

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an 8.3 kg mass is attached to a string that has a breaking strength of 1500 N. If the mass is whirled in a horizontal circle of radius 80 cm, what maximum speed can it have?

Answers

Answer:

To determine the maximum speed that the 8.3 kg mass can have without breaking the string, we need to consider the tension in the string when it reaches its maximum. At maximum speed, the tension in the string will be equal to the breaking strength of the string.

Given:

Mass (m) = 8.3 kg

Breaking strength of the string (Tension) = 1500 N

Radius of the circle (r) = 80 cm = 0.8 m

The centripetal force required to keep an object moving in a circular path is given by the formula:

F = m * v² / r

Where:

F = Centripetal force

m = Mass

v = Velocity

r = Radius

In this case, the centripetal force is provided by the tension in the string. So we have:

Tension = m * v² / r

Plugging in the values:

1500 N = (8.3 kg) * v² / 0.8 m

To find the maximum speed (v), we can rearrange the equation and solve for it:

v² = (1500 N * 0.8 m) / 8.3 kg

v² ≈ 144.58 m²/s²

v ≈ √(144.58 m²/s²)

v ≈ 12.03 m/s

Therefore, the maximum speed that the 8.3 kg mass can have without breaking the string is approximately 12.03 m/s.

Explanation:

An environmentally conscious physics student 250 N
mows her lawn with a push mower, exerting
a force of 250 N along the handle as shown. 40°
How much force is actually being used to push
the mower along the grou

Answers

The force actually being used to push the mower along the ground is 191 N.

When the physics student exerts a force of 250 N along the handle of the push mower, it's important to consider the components of this force that contribute to the actual force used to push the mower along the ground.

To determine the force used to push the mower along the ground, we need to find the horizontal component of the applied force. The angle of 40° indicates that the applied force can be broken down into two components: the horizontal component and the vertical component. The vertical component of the force is perpendicular to the direction of motion and does not contribute to pushing the mower forward.

To find the horizontal component, we can use trigonometry. The horizontal component is given by the formula:

Horizontal component = Applied force * cos(angle)

Plugging in the values, we get:

Horizontal component = 250 N * cos(40°)

Calculating this value, we find that the horizontal component of the applied force is approximately 191 N.

Therefore, the force actually being used to push the mower along the ground is 191 N. This is the component of the applied force that contributes to the forward motion of the mower, while the remaining vertical component is directed perpendicular to the ground and does not assist in pushing the mower forward.

By exerting a force of 250 N along the handle at a 40° angle, the student effectively applies 191 N of force to push the mower along the ground, ensuring efficient use of their effort while considering the environmental impact.

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Rank the four cases below according to the magnitude of the net electric force on the + q charge. Explain how you determined your ranking.

Rank the four cases below according to the magnitude of the net electric force on the + q charge. Explain

Answers

The order of net coulombic measurement of the amount is (4) > (3) > (1) > (2) .

What kinds of electrostatic charge exist?

The Many Kinds of Electric Forces Electromagnetic forces can be divided into two categories: attractive electromagnetic forces and repellent electrical forces. Related crimes repel each other whereas opposite charges attract one another.

(1)   Net charge density force on charge q: magnitude  = kQq / R2  +  2 kQq cos(theta) / R2

                                                                   = k Q q ( 1 + 2 cos(theta) ) / R2

(2)   Net charge density force on charge q: magnitude = kQq / R2  +  2 kQq cos(theta) / (R/cos(theta))^2

                                                                = k Q q ( 1 + 2 cos3(theta) ) / R2

(3) Net charge density force on charge q: magnitude =  3 kQq / R2

(4)Net charge density force on charge q: magnitude=  kQq / (R/2)^2  = 4 kQq / R2

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2. A crane can lift a 500 kg mass to height of 30 m in 2 minutes. The power at which the crane is operating is
A. 125 Watts
B. 1225 Watts
C.) 7500 Watts
D. 73500 W

Answers

The power at which the crane operates, if it can lift a mass of 500 kg is 1225 Watts.

What is power?

Power is the rate at which work is done.

To calculate the power the crane operates with, we use the formula below

Formula:

P = mgh/t............................... Equation

Where:

P = Powerm = Massg = Acceleration due to gravityh = Heightt = Time

From the question,

Given:

m = 500 kgh = 30 mt = 2 minutes = 2×60 = 120 sg = 9.8 m/s²

Substitute these values into equation 1

P = (500×30×9.8)/120P = 1225 W

Hence, the right option is B. 1225 Watts.

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