The wavelength of the emitted photon is approximately 3.80 nm.
The energy levels of an electron in a one-dimensional box are given by the formula;
En = (n² × h²) / (8 × m × L²)
where n is the quantum number of the energy level, h is Planck's constant, m is the mass of the electron, and L is the length of the box.
In this case, the electron jumps from the n = 2 level to the ground state, which corresponds to n = 1. We can calculate the energy difference between these two levels;
ΔE = E₂ - E₁ = (2² × h²) / (8 × m × L²) - (1² × h²) / (8 × m × L²)
ΔE = (3 × h²) / (8 × m × L²)
Now, we can use the energy-wavelength relationship for a photon;
E = hc / λ
where c is the speed of light and λ is the wavelength of the photon.
Rearranging the equation to solve for λ, we get;
λ = hc / ΔE
Substituting the expression for ΔE, we get;
λ = hc / [(3 × h²) / (8 × m × L²)]
λ = (8 × m × L² × c) / (3 × h)
Plugging in the values for the given parameters;
m = mass of electron = 9.10938356 × 10⁻³¹ kg
L = length of the box = 0.70 nm = 0.70 × 10⁻⁹ m
c = speed of light = 2.998 × 10⁸ m/s
h = Planck's constant = 6.62607015 × 10⁻³⁴ J·s
Now we can calculate the value of λ;
λ = (8 × 9.10938356 × 10⁻³¹ kg × (0.70 × 10⁻⁹ m)² × 2.998 × 10⁸ m/s) / (3 × 6.62607015 × 10⁻³⁴ J·s)
λ ≈ 3.80 nm
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I was hoping you could help me with this question?
In order to determine the angle between the given vectors, use the following formula:
\(\vec{u}\cdot\vec{v}=uv\cos \theta\)where the left hand side of the equation is the dot product of u and v vectors, u and v are the magnitude of the vectors and θ is the angle between the vectors.
Then, by solving for θ, you obtain:
\(\begin{gathered} \cos \theta=\frac{\vec{u}\cdot\vec{v}}{uv} \\ \theta=\cos ^{-1}(\frac{\vec{u}\cdot\vec{v}}{uv}) \end{gathered}\)Then, first calculate the dot product:
\(\begin{gathered} \vec{u}\cdot\vec{v}=(u_x)(v_x)+(u_y)(v_y) \\ \vec{u}\cdot\vec{v}=(0)(11)+(-10)(-12)=120 \end{gathered}\)The magnitudes of the vectors are:
\(\begin{gathered} u=\sqrt[]{u^2_x+u^2_y}=\sqrt[]{(0)^{}+(-10)^2}=\sqrt[]{100}=10.00 \\ v=\sqrt[]{v^2_x+v^2_y}=\sqrt[]{(11)^2+(-12)^2}=\sqrt[]{265}\approx16.28 \end{gathered}\)Then, by replacing the dot product and the valued of u and v into the expression for θ, you obtain:
\(\theta=\cos ^{-1}(\frac{120}{10.00\cdot16.28})\approx42.51\)Hence, the angle between u and v vectors is approximately 42.51 degrees.
A dog drags a 1-kg bone across the floor for 2 meters with an applied
force of 10N. How long did it take him if he used 40 Watts of power?
seconds
Answer:
0.5 seconds
Explanation:
Work = Fdcos(theta) = 10*2*cos(0) = 20 J
Power = W/t
40 = 20/t
t = 0.5s
Respond to all of the following in a minimum of 175 words
- Visualization is a powerful tool to have in your motivation toolbox. For this week’s My Vision Board and Reflection Worksheet assignment, you will take time to visualize your goals, not just the outcome, but each step to get there. Do you see a relationship between the process and practice of visualizing and maintaining motivation? Explain how you perceive the relationship or lack of it.
-Self-discipline is taking personal responsibility of your willingness and desire to finish tasks and reach your goals. The readings discussed several ways to increase your level of self-discipline. Which of the strategies discussed this week do you think you will use to increase your level of self-discipline in your life? Share a bit about why you think those strategies will work best for you.
Visualizing your objectives aids in sustaining inspiration by making your ambitions more perceptible and attainable.
Why is this important?By contemplating the actions required to reach a desired outcome, individuals can foster lucidity and guidance, thereby pleasing them with determination for moving forward. Additionally, focusing on the process of accomplishment through visualization helps divide the steps needed to attain those objectives, thus reducing their complexity, making it less menacing, and rendering them easier to achieve.
Various strategies towards increasing self-discipline were also proposed: setting apparent goals, creating schedules, sidestepping enticement, and practicing mindfulness amongst others.
Personally, I find that determining clear-cut aims and scheduling activities are the most productive tactics to pursue. This approach establishes definite targets and creates an environment that favors concentration whereby dedicating time for working towards set purposes becomes convenient.
This system constructs accountability while instilling discipline as daily progression is made toward target achievements during scheduled times - this encourages further motivation and commitment.
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Note that this prompt has to do with Vision Setting, motivation and Self Discipline.
What is the explanation for the above?
The connection between maintaining motivation and visualization is undeniable. Visualization involves the creation of a mental image that represents your desired outcome, allowing you to keep your eyes on the prize, which helps increase motivation levels.
Note that, breaking down the steps needed to achieve your goals through visualization can make the process less daunting while ensuring consistent progress towards success. Mental checkpoints where achievements are recognized further strengthen one's resolve, thus fueling motivation for even greater accomplishments.
Developing self-discipline is crucial and comes with various techniques for improving it. Optimizing productivity can sometimes be challenging for individuals like myself who struggle with distractions while working.
Fortunately, creating a detailed schedule has always been an effective solution for managing such situations. By factoring-in designated time slots within this timetable per individual tasks, focusing intently can be achieved without succumbing to environmental disturbances experienced in regular work environments.
To additionally promote personal drive during these sessions of focus-creation we should endeavor attainable objectives which will boost our overarching mission amid these intentional work segments.
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How are the characteristic x ray spectrum formed
Answer:
Explanation:.
•What is the gravitational potential energy of a girl
who has a mass of 40 kg and is standing on the
edge of a diving board that is 5 m above the water?
Answer:
1960 joule
Explanation:
A 12.5-µF capacitor is connected to a power supply that keeps a constant potential difference of 24.0 V across the plates. A piece of material having a dielectric constant of 3.75 is placed between the plates, completely filling the space between them.
(a) How much energy is stored in the capacitor before and after the dielectric is inserted?
(b) By how much did the energy change during the insertion? Did it increase or decrease?
Answer:
a) 0.0036 J & 0.0135 J
b) 0.0099 J
Explanation:
Given that
Capacitance of a capacitor, C(i) = 12.5*10^-6 F
Potential difference across the capacitor, V = 24 V
Dielectric constant, k = 3.75
Energy in a capacitor is given by the formula
U = ½ CV²
Now, applying this to our solution, we have.
a, the energy stored before the dielectric was inserted is 0.0036. After inserting the dielectric, we then take cognizance into it, essentially multiplying by the constant of the dielectric, we got 0.0135 J
b) Now, Change in energy is gotten by subtracting the two energies, and we have
ΔU = U - U(1)
ΔU = 0.0036 - 0.0135
ΔU = 00099 J
See attachment for calculation
if i am changing velocity, i must also have _______ and a net _________
if i am changing velocity, i must also have acceleration and a net force
Newton's first law of motionNewton's first law of motion states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.According to Newton's first law of motion, without a force acting on an object, its velocity does not change. The net force acts on an object to change its velocity and cause acceleration.
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a 20 ft shipping container on a cargo ship has a mass of 24000 kg and a volume of 33.2m3. what is the density of the shipping container
Answer:
722.89
Explanation:
mass=24000kg
volume=33•2
density=?
now,
density=mass/volume
=24000/33•2
=722•89
density=722•89 kg/m^3
Determine the MASS of the object in kg. (use g=10 m/s/s
Explanation:
Sorry but the question is incomplete
Shown below is a box of mass m1 that sits on a frictionless incline at an angle above the horizontal θ=30°. This box is connected by a relatively massless string, over a frictionless pulley, and finally connected to a box at rest over the ledge, labeled m2. If m1 and m2 are a height h above the ground and m2>>m1: (a) What is the initial gravitational potential energy of the system? (b) What is the final kinetic energy of the system?
(a) The initial gravitational potential energy of the system is 0.5 (m₁ + m₂)gL.
(b) The final kinetic energy of the system is 0.5 (m₁ + m₂)gL .
Initial gravitational potential energy of the system
P.E = mgh
where;
h is height of the inclineLet the length of the incline = L
h = L sinθ
P.E = mg(L sinθ)
P.E = (m₁ + m₂)g (L sinθ)
P.E = 0.5 (m₁ + m₂)gL
Final kinetic energy of the systemThe final kinetic energy of the system is equal to the initial potential energy since the inclined plane is frictionless.
K.E(f) = (m₁ + m₂)g (L sin30)
K.E(f) = 0.5 (m₁ + m₂)gL
Thus, the initial gravitational potential energy of the system is 0.5 (m₁ + m₂)gL and the final kinetic energy of the system is0.5 (m₁ + m₂)gL .
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10. A plane is flying through very dense clouds with no visibility. The pilot's
instruments tell her that she is flying at a heading of 54 knots West by
103 knots South. What is the pilot's total velocity?
The pilot's total velocity is 116.3 knots in the direction of 62.3⁰.
What is the pilot's total velocity?The pilot's total velocity is calculated by applying the principle of relative velocity.
The total velocity is also the resultant velocity and the magnitude of the pilot's total velocity is calculated by applying Pythagoras theorem as follows;
R = √ (V₁² + V₂²)
R = √ (54² + 103²)
R = 116.3 knots
The direction of the velocity vector is calculated as follows;
tan θ = (103 knots) / (54 knots)
θ = tan⁻¹ (103/54)
θ = 62.3⁰
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dentify the number of significant digits in 472000 g.
3
4
5
6
Answer:
3
Explanation:
An increase in voltage results in
If the current is held constant, an increase in voltage will result in an increase in resistance.
hope it helps...!!!
in a periscope, what is the nature of the reflected image? is it a virtual image or a real one?
Answer:
mirrors set parallel to each other at 45 degree angle.
real
Determine the magnitude as well as direction of the electric field at point A, shown in the above figure. Given the value of k = 8.99 × 1012N/C.
Answer:
Electric field at A = 9.28 x 10¹² N/C
Explanation:
Given:
K = 8.99 x 10¹² N/C
Missing information:
Length = 11 cm = 11 x 10⁻² m
q = 12.5 C
Find:
Electric field at A
Computation:
Electric field = Kq / r²
Electric field at A = [(8.99 x 10¹²)(12.5)] / [11 x 10⁻²]²
Electric field at A = 9.28 x 10¹² N/C
Find the magnitude and direction of the resultant velocity vector for the following perpendicular velocities:
a. a surfer traveling at 1.5 m/s relative to the water across a wave that is traveling at 5.5 m/s.
b. a fish swimming at 2.5 m/s relative to the water across a river that moves at 4.5 m/s.
a) Resultant velocity is 15.63 m/s.
b) Resultant velocity is 12.97m/s.
What is velocity?The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
a) A surfer traveling at 1.5 m/s relative to the water across a wave that is traveling at 5.5 m/s.
Resultant velocity = √(1.5²+5.5²) m/s = 15.63 m/s.
b) A fish swimming at 2.5 m/s relative to the water across a river that moves at 4.5 m/s.
Resultant velocity = √(2.5²+4.5²) m/s = 12.97m/s.
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suppose a hiker is on a mountain ridge 1200 meters above sea level. approximately what air pressure will she experience
Assuming standard atmospheric conditions, the air pressure at sea level is approximately 1013.25 hectopascals (hPa) or 1 atmosphere (atm). The air pressure decreases with altitude following the barometric formula, which states that pressure decreases by about 1 hPa for every 8 meters of ascent.
Using this formula, we can estimate the air pressure at 1200 meters above sea level as follows:
1200 m / 8 m per hPa = 150 hPa
Therefore, the hiker on a mountain ridge 1200 meters above sea level would experience an air pressure of approximately 863.25 hPa (1013.25 hPa - 150 hPa) or about 0.85 atm.
A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm,find the emf of the cell.
A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.
To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.
Given:
Resistance of the coil, R1 = 4 ohm
Resistance of the other resistor, R2 = 8 ohm
Current passing through the 8-ohm resistor, I = 2A
First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.
The total resistance of two resistors in parallel can be calculated using the formula:
1/Rp = 1/R1 + 1/R2
Substituting the given values, we have:
1/Rp = 1/4 + 1/8
1/Rp = 2/8 + 1/8
1/Rp = 3/8
Rp = 8/3 ohm
Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).
R_total = R_internal + Rp
R_total = 0.5 + 8/3
R_total = 1.833 ohm
Now, we can find the emf of the cell using Ohm's Law:
emf = I * R_total
emf = 2 * 1.833
emf ≈ 3.667 volts
Therefore, the emf of the cell is approximately 3.667 volts.
However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.
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A pendulum of mass 12 kg is released from rest at some height, as shown by
point A in the image below. At the bottom of its arc at point B, it is traveling at
a speed of 19 m/s. What is the approximate amount of energy that has been
lost due to friction and air resistance? (Recall that: g = 9.8 m/s²)
20 m
A35
B186
C78
D112
The energy lost to friction and air resistance is 186 J.
option B.
What is the energy lost to friction and air resistance?The energy lost to friction and air resistance is calculated from the change in the mechanical energy of the pendulum.
The initial potential energy of the pendulum at the initial position is calculated as;
PEi = mghi
where;
m is the massg is gravityh is the initial heightP.Ei = 12 kg x 9.8 m/s² x 20 m
P.Ei = 2,352 J
The final kinetic energy of the pendulum is calculated as follows;
K.Ef = 0.5 x 12 kg x (19 m/s)²
K.Ef = 2,166 J
ΔE = 2,166 J - 2,352 J
ΔE = -186 J
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When a ball is thrown straight up with no air Resistance, the acceleration is in what direction ?
Answer:
The ball has a velocity upwards but the acceleration is downwards. Gravity is giving the ball a downwards acceleration from the moment the ball leaves the hands.
Please help 3. What is the best explanation of the image shown below?
O A. The ball was pitched at orbital velocity.
O B. The ball was pitched at more than orbital velocity but less than escape velocity.
O c. The ball was pitched at escape velocity.
D. The ball was pitched at more than escape velocity
Answer:
A
Explanation: took the test
A train travels 8.81 m/s in a -51.0° direction.
The train accelerates for 2.23 s, changing its
velocity to 9.66 m/s in a 37.0° direction.
What is [delta]x?
The displacement of the train after 2.23 seconds is 25.4 m.
Resultant velocity of the trainThe resultant velocity of the train is calculated as follows;
R² = vi² + vf² - 2vivf cos(θ)
where;
θ is the angle between the velocity = (90 - 51) + 37 = 76⁰R² = 8.81² + 9.66² - 2(8.81 x 9.66) cos(76)
R² = 129.75
R = √129.75
R = 11.39 m/s
Displacement of the trainThe displacement is calculated as follows;
Δx = vt
Δx = 11.39 m/s x 2.23 s
Δx = 25.4 m
Thus, the displacement of the train after 2.23 seconds is 25.4 m.
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what exercises most beneficial for your overall health
Answer:
Endurance, or aerobic
Strength, or resistance training
Balance
Flexibility
Explanation:
Answer:
Walking. Walking is simple, yet powerful. It can help you stay trim, improve cholesterol levels, strengthen bones, keep blood pressure in check, lift your mood, and lower your risk for a number of diseases (diabetes and heart disease, for example).
A catapult launches a rock with an initial speed of 35 m/s at an initial angle of 22o above the ground from a height of 0.0 m. After the rock has traveled 10 m horizontally along the ground from its starting point, what is its height above the ground
Answer:
h = 3.6 m
Explanation:
This is the case of a projectile motion. We assume the air resistance to be negligible. So the speed of the rock remains constant in x-direction. Therefore,
s = V₀ₓ t
where,
V₀ₓ = x - component of launching velocity = V Cos θ = (35 m/s)(Cos 22°) V₀ₓ = 32.45 m/s
s = distance traveled horizontally by the rock = 10 m
t = time taken to cover the distance = ?
Therefore,
10 m = (32.45 m/s)(t)
t = (10 m)/(32.45 m/s)
t = 0.31 s
Now, we consider the vertical motion. The vertical motion is taking place under the action of gravity. So it is uniformly accelerated motion. Applying 2nd equation of motion to the vertical motion:
h = (Vi₀)(t) + (0.5)gt²
where,
h = height of rock = ?
Vi₀ = Vertical Component of Launching Velocity = V₀Sinθ = (35 m/s)(Sin 22°)
Vi₀ = 13.11 m/s
g = - 9.8 m/s² (negative for upward motion)
Therefore,
h = (13.11 m/s)(0.31 s) + (0.5)(-9.8 m/s²)(0.31 s)²
h = 4.06 m - 0.47 m
h = 3.6 m
SP1. A railroad engine moves forward along a straight section of track for a distance of 70 m due west at a constant speed of 5 m/s . It then reverses its direction and travels 32 m due east at a constant speed of 4 m/s . The time required for this deceleration and reversal is very short due to the small speeds involved. a. What is the time required for the entire process? b. Sketch a graph of average speed versus time for this process . Show the deceleration and acceleration upon reversal as occurring over a very short time interval . c. Using negative values of velocity to represent reversed motion, sketch a graph of velocity versus time for the engine ( see fig. 2.15 ). d. Sketch a graph of acceleration versus time for the engine (see fig . 2.16).
The relationships between average speed (s), velocity (v), and acceleration can be shown shown graphically by plotting their values with time
a. The time required for the entire process is 22 seconds
The required graphs to question b, c, and d are attached
The reasons the above value for time and the attached graph are correct are given as follows:
The given parameters are;
The distance due west travelled by the train = 70 m
The speed in the western direction = 5 m/s
The distance due east the train then travelled = 32 m
The speed of the train while travelling east = 4 m/s
a. The time required for the entire process, t, is given as follows;
\(Time = \dfrac{Distance}{Velocity}\)
Therefore, the total time, t = (70 m/(5 m/s)) + (32 m/(4 m/s)) = 22 s
The time required for the entire process is 22 seconds
b. The table of values (obtained with MS Excel) are as follows;
Time: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22
Avg. Speed: 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 4.9, 4.875, 4.8, 4.78, 4.74, 4.7, 4.67, 4.64
Please find attached the required graph of average speed versus time
c. The table of values are as follows;
Time: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22
Velocity: 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, -4, -4, -4, -4, -4, -4, -4, -4
Please find attached the required graph of velocity versus time
d. The table of values are as follows;
Time: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22
Acceleration: DNE, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, -9, 0, 0, 0, 0, 0, 0, 0
Please find attached the required graph of acceleration versus time
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Our sun is 2.3×10 4ly (light- years) from the center of our Milky Way galaxy and is moving in a circle around that center at a speed of 250 km/s. (a) How long does it take the Sun to make one revolution about the galactic center (b) How many revolutions has the sun completed since it was formed about 4.5×10 9years ago
It takes the Sun 5.5*10¹⁵ seconds to complete one rotation around the galactic center. Since it was formed around 4.5*10⁹ years ago, the sun has made 26 full revolutions.
(a) T=2πR/V;
R=2.3*10⁴ly(9.46*10¹²Km/1 ly)
R=2.18*10¹⁷ km
T=2π(2.18*10¹⁷)/250 km
T=5.5*10¹⁵s
(b)N=t/T
=(4.5×10⁹ y)(3.6*10⁷ s/y)/5.5*10¹⁵s
=26 revolutions
The revolving center of the Milky Way galaxy, also known as the Galactic Center or Galactic Center, is known as the barycenter. Sagittarius A*, a compact radio source almost exactly in the galactic rotational center, is the galaxy's central massive object and is a supermassive black hole with a mass of around 4 million solar masses. The Milky Way's brightest spots, the Butterfly Cluster (M6) or the star Shaula, are very close to the Galactic Center, which is around 8 kiloparsecs (26,000 ly) from Earth in that direction. The Pipe Nebula is located south of the Butterfly Cluster.
There are over 10 million stars within one parsec of the Galactic Center, mostly red giants but also including a sizeable number of huge supergiants and Wolf-Rayet stars.
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What happens to the mechanical advantage of a machine if the output force is less than the input force? What must happen to output distance? Give an example of a machine that does this?
anyone solve this for mw urgently please.
Decrease.
What is the weight on the equator than at the Poles?Yes, You weigh less on the equator than at the North or South Pole, but the difference is small.
Note that your body itself does not change.
Rather it is the force of gravity and other forces that change as you approach the poles. These forces change right back when you return to your original latitude.
In short, a trip to the equator is not a viable long-term weight-loss program.
Your weight is the combination of all the large-scale, long-term forces on your body. While the earth's gravity is by far the strongest large-scale force, it is not the only one.
We experience as "something pulling you down" is actually the total of all the forces and not just gravity.
The four dominant large-scale, long-term forces are:
The earth's gravity
The sun's gravity
The moon's gravity
The earth's centrifugal force
Hence, the weight of a body at the equator will be less than at the Poles.
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Why is a valve placed before the rotameter?
a.To measure the flow of liquid entering the extraction bed
b.To regulate the flow of fluid leaving the extraction bed
c.To regulate the flow of liquid entering the extraction bed
d.None of the above.
A valve placed is before the rotameter to regulate the flow of liquid entering the extraction bed. The correct option is c.
What is control valve?Control valves are generally used to maintain a flow as close as possible to the desired value.
Valves positioned before the rotameter for throttling purposes. A control valve will regulates the rate of fluid flow. Control valves control typically flow rate, pressure, and temperature.
Thus, the correct option is c.
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Which correctly describes latent heat?
A. The heat of molecules that are under pressure
B. The heat held inside of ice crystals colder than -2°C
C. The heat absorbed or lost by a substance while it's changing state
D. The heat used to change the temperature of a liquid
Option C. The heat absorbed or lost by a substance while it's changing state correctly describes latent heat
Latent heat is the heat absorbed or lost by a substance while it is changing state.
The latent heat is a type of heat that is transferred during phase change, i.e., while a substance undergoes a change of state.
For example, when ice melts into liquid water, or when liquid water evaporates into water vapor, heat is absorbed from the surroundings.
Latent heat is not associated with a temperature change; rather, it's associated with a change of state.
For instance, the temperature of water remains at 100°C while boiling.
When water is boiling, the latent heat of vaporization is absorbed and utilized to break the hydrogen bonds holding water molecules together to change water from the liquid phase to the gaseous phase.
When the water is boiling, adding more heat won't increase the water's temperature, instead, the extra heat will be absorbed to change the phase of water molecules.
Therefore, the correct answer to the given question is option C: The heat absorbed or lost by a substance while it is changing state.
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