draw the mirror image of the following compound. label the molecule as chiral or achiral. be sure to answer all parts.

Answer: C

infrared rays

Explanation:

A thermogram is an image produced by a special camera that, instead of visible light, records infrared rays. Hence option C is correct.

Thermogram is defined as the process using an infrared camera to search for unusually warm or cold spots on a component that is otherwise functioning correctly.  Thermograms, also known as thermal pictures, are really visual representations of an object's infrared radiation emission, transmission, and reflection. The fact that there are numerous infrared energy sources makes it challenging to determine an object's temperature precisely using this method.

Infrared rays are defined as a region of the electromagnetic spectrum that stretches from the microwave range to the long wavelength, or red, end of the visible light range. Transmission of infrared ray energy is the term used to describe electromagnetic radiation with wavelengths greater than visible light but shorter than radio waves.

Thus, a thermogram is an image produced by a special camera that, instead of visible light, records infrared rays. Hence option C is correct.

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Answer:

Electrons, Protons, and Neutrons. ... Protons are another type of subatomic particle found in atoms. They have a positive charge so they are attracted to negative objects and repelled from positive objects. Again, this means that protons repel each other

Answer:

Answer to A. helium, neon, argon, krypton, xenon, and radon, B. Elemental hydrogen (H, element 1), nitrogen (N, element 7), oxygen (O, element 8), fluorine (F, element 9), and chlorine (Cl, element 17) are all gases at room temperature, and are found as diatomic molecules (H2, N2, O2, F2, Cl2). C. Elements Compounds

Ar (argon) HBr (hydrogen bromide) C 3H 8 (propane)

Kr (krypton) HI (hydrogen iodide) C 4H 10 (butane)

Xe (xenon) HCN (hydrogen cyanide)* CO (carbon monoxide)

Rn (radon) H 2S (hydrogen sulfide) CO 2 (carbon dioxide)

Explanation:

Answer:

B) They will react because X and Y can share two pairs of electrons to become stable

Explanation:

The electron configurations of two elements x and y are given :

X: 1s2 2s2 2p6

Y: 1s2 2s2 2p6 3s2 3p6

The statement that is true for both the elements is that, they both will react as they both can share two pairs of electrons to become stable.

To become stable the outermost shell or p orbital should have 8 electrons, so element X  can gain 2 atoms to become stable.

Element Y can also react as it can also share two atoms to fulfill its 3p orbital and will stable.

Hence, the correct option is "B".

Answer:

i think it c

Explanation:

The formula for the time (t) it will take for perfume molecules to diffuse a distance (l) into the room can be derived as follows: t = (l^2) / (6D), where D is the diffusion coefficient.

Diffusion is the process by which molecules spread out from an area of high concentration to an area of low concentration. In this case, we are considering the diffusion of perfume molecules into the room. To derive a formula for the time it takes for diffusion to occur, we need to consider the factors that affect the rate of diffusion.

The time it takes for molecules to diffuse a distance (l) can be related to the diffusion coefficient (D), which is a measure of how quickly molecules move and spread out. The formula for the time (t) can be derived using the equation t = (l^2) / (6D), where (l^2) represents the squared distance traveled and 6D represents the diffusion coefficient.

The diffusion coefficient depends on various factors, including the mass (m) and collision cross-section (σ) of the perfume molecules, as well as the pressure (p) and temperature (t) of the environment. By assuming that the mass and collision cross-section of the perfume molecules are similar to air molecules, we can consider them to be constant in the formula.

It's important to note that this derived formula is a simplification and assumes ideal conditions. Real-world diffusion processes may involve additional factors and complexities. However, the derived formula provides a starting point for understanding the relationship between diffusion time, distance, and the diffusion coefficient.

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The statement is FALSE. Non-ferrous metals can be hardened by heat treatment, although the mechanisms and processes involved may differ from ferrous metals.

Heat treatment techniques such as precipitation hardening can be used to increase the strength of non-ferrous metals. Non-ferrous metals are metals or alloys that do not include iron (or iron allotropes, such as ferrite, etc.) in significant quantities. Non-ferrous metals are employed because they have desired qualities like reduced weight (for example, aluminium), greater conductivity (for example, copper), non-magnetic characteristics, or corrosion resistance (for example, zinc), even though they are often more expensive than ferrous metals. In the iron and steel sectors, several non-ferrous materials are also employed. Bauxite, for instance, is used as a flux in blast furnaces, whereas wolframite, pyrolusite, and chromite are utilised to create ferrous alloys.

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In general, the arming time of a munition refers to the time required for the munition's fuse to become active and enable the explosive charge to detonate. The arming time can vary depending on several factors, including the type of fuse used, the specific munition model.

Tail fuzes like the M905 tail fuze are designed to be used with certain types of munitions, such as bombs, and are typically armed by the motion or rotation of the munition during its descent or trajectory. The arming time of a tail fuze can depend on several factors, including the munition's velocity, the altitude of the munition, and the specific settings on the fuze.

It's important to note that discussing specific arming times of military munitions is not recommended, as it can be considered sensitive information that should only be handled by authorized personnel with the proper clearance and training to ensure public safety and security.

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the formulae of the hydrogen carbonates of metals X, Y, and Z are X(HCO3), Y(HCO3)2, and Z(HCO3)3, respectively.  The valencies of metals X, Y, and Z are 1, 2, and 3 respectively.

The formula for hydrogen carbonate is HCO3-, which consists of one hydrogen ion, one carbonate ion, and two oxygen atoms.To determine the formula for the hydrogen carbonates of metals X, Y, and Z, we need to consider the charges of the metal cations and the carbonate anion. For X with a valency of 1, the formula for its hydrogen carbonate is X(HCO3), where X is the metal cation with a charge of +1. For Y with a valency of 2, the formula for its hydrogen carbonate is Y(HCO3)2, where Y is the metal cation with a charge of +2. For Z with a valency of 3, the formula for its hydrogen carbonate is Z(HCO3)3, where Z is the metal cation with a charge of +3.

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NaOH is a base and addition of NaOH will cause the left reaction to proceed and the solution turns yellow.

Chemical equilibrium refers to a dynamic stare in which the forward and reverse reactions are occurring at the same time at the same rate.

Any change in the reaction conditions will cause equilibrium to shift either to the left or right.

In the given equation, addition of acid will result in the forward reaction proceeding and the solution turns orange.

The left reaction is favoured on addition of base.

Since NaOH is a base, addition of NaOH will cause the left reaction to proceed.

The solution turns yellow

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The change to the solution is that the addition of NaOH will cause the left reaction to proceed and the solution turns yellow.

A solution means a special type of homogeneous mixture that is composed of two or more substances.

It should be noted that a change in the reaction conditions will cause the equilibrium to shift either to the left or right.

In this case, the addition of NaOH will cause the left reaction to proceed and the solution turns yellow.

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Answer:

Because looking at the reactivity series of both elements Calcium is more reactive than hydrogen.

The situation is an example of chemical weathering is acid rain.

When the droplets of water during the rain become acidic because of atmospheric pollution is known as acid rain due to the presence of acid in the environment like sulfur and nitrogen.

This affects the respiratory system of both humans and animals as well as damage the originality of soil and affects the growth of plants and other microorganisms in the environment.

Therefore, the situation is an example of chemical weathering is acid rain as it also increases corrosion.

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We can use the ideal gas model and the adiabatic compression process to determine the rate of entropy production and the isentropic compressor efficiency.

(a) Rate of Entropy Production:

The rate of entropy production, denoted as ΔS/Δt, can be calculated using the following equation:

ΔS/Δt = Power Input / (T1 - T2)

where:

Power Input is the power input per kg of air flowing (42 kJ/kg),

T1 is the initial temperature (300 K),

T2 is the final temperature after compression.

Since the compression process is adiabatic, there is no heat exchange, and the temperature change is related to the pressure change using the adiabatic equation:

P1 * V1^k = P2 * V2^k

where:

P1 and P2 are the initial and final pressures,

V1 and V2 are the initial and final volumes,

k is the specific heat ratio (1.4 for air).

From the given data, the initial pressure P1 is 1 bar (100 kPa), and the final pressure P2 is 1.5 bar (150 kPa). Since the process is adiabatic, the volume ratio V1/V2 can be expressed as the pressure ratio P2/P1 raised to the power of 1/k:

V1/V2 = (P2/P1)^(1/k)

Calculating V1/V2:

V1/V2 = (150 kPa / 100 kPa)^(1/1.4) = 1.1214

Now we can calculate the final temperature T2 using the ideal gas law:

P2 * V2 = m * R * T2

where:

m is the mass of air flowing per unit time,

R is te specific gas constant for air (287 J/(kg·K)).

Since we are interested in the rate of entropy production per unit mass, we can assume a unit mass of air flowing (m = 1 kg).

Calculating T2:

T2 = (P2 * V2) / (m * R)

  = (150 kPa * 1.1214) / (1 kg * 287 J/(kg·K))

  = 0.5851 K

Now we can calculate the rate of entropy production:

ΔS/Δt = Power Input / (T1 - T2)

      = 42 kJ/kg / (300 K - 0.5851 K)

      ≈ 0.142 kJ/K per kg of air flowing

Therefore, the rate of entropy production for the compressor is approximately 0.142 kJ/K per kg of air flowing.

(b) Isentropic Compressor Efficiency:

The isentropic compressor efficiency (η) is defined as the ratio of the actual work done by the compressor (W_act) to the work done in an isentropic (reversible adiabatic) process (W_isentropic):

η = W_act / W_isentropic

For an adiabatic process, the work done is given by:

W = C_v * (T2 - T1)

where C_v is the specific heat capacity at constant volume. For air, C_v = R / (k - 1).

Calculating W_isentropic:

W_isentropic = C_v * (T2_isentropic - T1)

           = (R / (k - 1)) * (T2_isentropic - T1)

For an isentropic process, the final and initial temperatures are related by:

T2_isentropic / T1 = (P2 / P1

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Answer:

13.6 g

Explanation:

The mass of BeF₂ present in 655 ml of a solution that is 0.442 M is equal to 13.82 g.

We can calculate the concentration of a solute in a solution in terms of molarity, molality, and normality.

The molarity of a particular solution can be determined from the number of moles of a solute per unit volume of the solution.

The Molarity of the particular solution can be determined from the mathematical formula mentioned below:

Molarity = Moles/Volume of the Solution

Given, the molarity of BeF₂ solution = 0.442 M

The volume of the BeF₂ solution, V = 655 ml = 0.655 L

The molar mass of the BeF₂, M = 47.01 g/mol

Molarity of BeF₂ solution = m/(M × V)

0.442 = m/ (47.01 × 0.655)

m = 13.82 g

Therefore, 13.82 g of BeF₂ is required for the given solution.

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The synthesis of gaseous hydrogen iodide from hydrogen gas and iodine vapor at the given temperature and equilibrium constant results in a partial pressure of 0.25 atm for iodine vapor.

To solve this problem, we first need to write the balanced chemical equation for the synthesis of hydrogen iodide:
H_{2}(g) + I_{2}(g) ⇌ 2HI(g)
Next, we'll use the given equilibrium constant (K = 100) and the partial pressures of H2 (1.000 * 10^{-2} atm) and HI (5.000 x 10^-1 atm) to calculate the partial pressure of I2 at equilibrium. The equilibrium expression for the reaction is:
K = \frac{[HI]^2 }{ ([H_{2}] * [I_{2}])}
We can plug in the given values and solve for the partial pressure of I2:
100 =\frac{ (5.000 * 10^{-1})^2 }{ (1.000 * 10^{-2} * [I2])}
Now, we'll solve for [I_{2}]:
[I_{2}] = \frac{(5.000 * 10^{-1})^2 }{ (1.000 * 10^{-2} * 100)}
[I_{2}] = \frac{0.25 }{ 1}
[I_{2}] = 0.25 atm
In conclusion, the synthesis of gaseous hydrogen iodide from hydrogen gas and iodine vapor at the given temperature and equilibrium constant results in a partial pressure of 0.25 atm for iodine vapor.

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The reaction has synthesized hydrogen iodide from hydrogen gas and iodine vapor. The partial pressure of iodine vapor is \(2\)×\(10^{-5}\)atm.

The reaction between hydrogen gas and iodine vapor to form hydrogen iodide is as follows:
\(H_{2} (g) +I_{2} (g)\) ⇌\(2HI (g)\)
At a temperature where the equilibrium constant is \(100\), we know that the reaction favors the formation of hydrogen iodide. This means that at equilibrium, there will be a higher concentration of hydrogen iodide compared to hydrogen gas and iodine vapor.
The given partial pressures of \(HI\) and \(H_{2}\) are \(5.000\)× \(10^{-1}\) atm and \(1.000\) × \(10^{-2}\) atm, respectively.  The partial pressure of iodine vapor is given by equilibrium constant expression:
\(k_{c} =\frac{[HI]^{2} }{[H_{2}] [I_2]}\)
Since we know that \(k_{c}\) = 100, on rearranging
\([I_{2}]= \frac{[H_{2}][HI]^{2}}{k_{c} }\)
Substituting the given partial pressures:
\([I_{2}]\) = (\(1.000\)× \(10^{-2}\) atm) (\(5.000\) × \(10^{-2}\) atm\()^{2}\) ÷ \(100\)
\([I_{2}]\)= \(2.5\)× \(10^{-5}\) atm
Therefore, the partial pressure of iodine vapor is \(2.5\) × \(10^{-5}\) atm.
Overall, the reaction has reached equilibrium with a higher concentration of hydrogen iodide. This means that the reaction has synthesized hydrogen iodide from hydrogen gas and iodine vapor.

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The ionic radius is the distance between the nucleus of the ion up to the electron cloud that overlays the ion.  

The ionic radius is the distance between the nucleus of the ion up to the electron cloud that overlays the ion.  We know that for a metal, the ionic radii  decreases as the  magnitude of charge on the ion increases  while in the case of the negative ion, the ionic radii increases as the magnitude of charge on the ion increases.

Let us now look at the ions as shown;

a)  I^->I> I^+ - This is because the negative ion leads to an expansion of the electron cloud which decreases in the atom and the positive ion.

b) Ca²+ > Mg2+ > Be²+ - Ionic radius increases down the group as more shells are added.

c)  Fe>Fe²+ > Fe³+ - This is because, for a metal, the ionic radii  decreases as the magnitude of charge on the ion increases

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Cohesion;

Adhesion;

We know that the forces of adhesion are the forces that hold molecules to the surface of the vessel that contains it while the forces of cohesion is the force that holds the molecules of the water together.

Let us now try to see the properties individually;

Cohesion;

Adhesion;

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To find the number of moles represented by a certain number of particles, you can use Avogadro's number and the concept of molar mass.

Avogadro's number (symbolized as N_A) is a fundamental constant that represents the number of particles (atoms, molecules, ions, etc.) in one mole of a substance. It is approximately equal to 6.022 × 10²³ particles/mole.

Molar mass is the mass of one mole of a substance and is expressed in grams/mole. It represents the sum of the atomic masses or molecular masses of the constituent particles in a substance.

To calculate the number of moles, you can follow these steps;

Determine the number of particles you have (atoms, molecules, ions, etc.).

Identify the molar mass of the substance or the average molar mass if it's a mixture.

Divide the number of particles by Avogadro's number to convert them into moles. The formula is:

Moles = Number of Particles / Avogadro's number

Moles = Number of Particles / (6.022 ×10²³ particles/mole)

The result will give you the number of moles represented by the given number of particles.

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--The given question is incorrect, the correct question is

"Explain how you would find the number of moles that are represented by a certain number of representative particles."--

The ideal monatomic molecule has three degrees of freedom, thus let N=the total number of molecules in each gas maintained at temperature T.

Hence, the monatomic gas's typical kinetic energy  E₁=(3/2) Nkt

, then its heat capacity at constant volume,

\(e1=\frac{3}{2} nKt\)

. [k= Boltzman constant]

Similarly, for the diatomic gas

Cv₂=5/2Nk

as 5 degrees of freedom are available to a diatomic molecule.

Now, each of the gases receives a certain quantity of energy E in the form of heat. If T₁ and T₂ are the corresponding temperature increases, then

E=Cv₁T₁=Cv₂T₂,

or,

T₁/T₂=Cv₂/Cv₁ = 5/3

So,

T1>T2

this monatomic gas will be more heated.

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The ratio of the final volumes is 1:1

The ratio of the final volume of the diatomic gas to that of the monatomic gas can be found using the ideal gas law, which relates pressure, volume, number of moles, and temperature:

PV = nRT

Where:

P = pressure

V = volume

n = number of moles

R = the gas constant

T = temperature

Since the gases are at the same temperature and have the same number of moles, their ratio of volumes will depend only on the ratio of their pressures.

Let's consider the monatomic gas first. Since the pressure is constant during heating, we can write:

P₁V₁ = nRT₁

After doubling the volume, the new volume is 2V₁, and we can write:

P₂(2V₁) = nRT₂

where P₂ is the new pressure and T₂ is the final temperature of the gas.

Dividing the second equation by the first equation, we get:

P₂(2V₁) / (P₁V₁) = nRT₂ / nRT₁

Canceling out n and rearranging the terms, we get:

P₂ / P₁ = (2V₁ / V₁) * (T₂ / T₁)

P₂ / P₁ = 2(T₂ / T₁)

Similarly, for the diatomic gas, we have:

P₃V₃ = nRT₁

P₄(2V₃) = nRT₂

Dividing the second equation by the first equation, we get:

P₄ / P₃ = (2V₃ / V₃) * (T₂ / T₁)

P₄ / P₃ = 2(T₂ / T₁)

Since both gases have the same number of moles and are heated at constant pressure, their initial pressures are the same (P₁ = P₃). Therefore, the ratio of the final pressures is:

P₂ / P₄ = (P₂ / P₁) * (P₃ / P₄) = 1 * (P₃ / P₄) = P₃ / P₄

Substituting the expressions we found for P₂ / P₁ and P₄ / P₃, we get:

P₃ / P₄ = (2(T₂ / T₁)) / (2(T₂ / T₁)) = 1

Therefore, the ratio of the final volumes of the diatomic gas to the monatomic gas is:

(2V₃) / (2V₁) = V₃ / V₁ = P₃ / P₁ = 1

So the ratio of the final volumes is 1:1. This means that both gases will occupy the same volume after being heated at constant pressure until their volume doubles, as long as they have the same number of moles and the same initial temperature.

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The volume to which you should dilute the 50 mL of a 5.0 M KI solution in order for 25 mL of the diluted solution to contain 3.05 g of KI is approximately 0.00122 g/mL.

To calculate the volume to which you should dilute 50 mL of a 5.0 M KI solution so that 25 mL of the diluted solution contains 3.05 g of KI, we can use the formula:

C1V1 = C2V2

Where:

C1 = Initial concentration of the solution

V1 = Initial volume of the solution

C2 = Final concentration of the solution

V2 = Final volume of the solution

Let's assign the values:

C1 = 5.0 M

V1 = 50 mL

C2 = ? (unknown)

V2 = 25 mL

We need to calculate the final concentration (C2) first. We can use the formula:

C = m/V

Where:

C = Concentration

m = Mass of solute

V = Volume of solution

For the diluted solution containing 3.05 g of KI in 25 mL:

C2 = m/V2

C2 = 3.05 g / 25 mL

Next, we substitute the values into the dilution equation and solve for V2:

C1V1 = C2V2

(5.0 M)(50 mL) = (C2)(25 mL)

250 mL·M = (C2)(25 mL)

M = (C2)(25 mL) / 250 mL

Finally, we substitute the value of C2 and solve for V2:

M = (3.05 g / 25 mL)(25 mL) / 250 mL

M = 0.305 g / 250 mL

M = 0.00122 g/mL

Therefore, to dilute 50 mL of a 5.0 M KI solution so that 25 mL of the diluted solution contains 3.05 g of KI, you need to dilute it to a concentration of approximately 0.00122 g/mL.

The volume to which you should dilute the 50 mL of a 5.0 M KI solution in order for 25 mL of the diluted solution to contain 3.05 g of KI is approximately 0.00122 g/mL.

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From 22 moles of hydrogen gas 328.53 liters of ammonia are formed.

What is Mole concept?

The mole concept is a convenient method of expressing the amount of a substance.

Avogadro's number is the number of units in one mole of any substance and equals to 6 .02214076 × 1023. The units can be electrons, atoms, ions, or molecules.

No. of moles is defined as a particular no. of particles that we can calculate with the help of Avogadro’s number.

Given,

moles of hydrogen gas = 22

According to reaction given,

3 moles H2 forms - 2 moles NH3

1 mole forms - 2/3 moles NH3 = 0.666 moles

22 moles H2 forms - 14.66 moles

1 mole of any gas at STP has- 22.4 litres volume

14.66 moles of NH3 has = 328.53 litres

Therefore, from 22 moles of hydrogen gas 328.53 liters of ammonia are formed.

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0.65L of ammonia are formed.

The mole is an amount unit similar to familiar units like pair, dozen, gross, etc. It provides a specific measure of the number of atoms or molecules in a bulk sample of matter.

A mole is defined as the amount of substance containing the same number of atoms, molecules, ions, etc. as the number of atoms in a sample of pure 12C weighing exactly 12 g.

Given,

Moles of hydrogen gas = 22 moles

From the reaction,

                                         N₂ + 3H₂ = 2NH₃

3 moles of hydrogen will give 2 moles of ammonia

1 mole of hydrogen gives 2 ÷ 3 moles of ammonia

Thus, 22 moles of hydrogen gives = (2 ÷ 3 ) × 22

                                                         = 14.67 moles of ammonia

We know that, 1 mole of a gas occupies 22.4 L of volume

So, 14.67 moles will occupy 14.67 ÷ 22.4 L

                                             = 0.65 L

Therefore, 0.65L of ammonia are formed.

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Answer:

B

Explanation:

Condensation happen when water is warmed up in room temperature against a cold surface like water vapor

Answer:

# of electron shells

Explanation:

Elements in the same periodic group have the same number of electron shells.

Answer:

I'm sorry, I cannot provide exact temperature, salinity, or density values for specific ocean locations without further information. The values of these properties can vary greatly depending on many factors such as water depth, water circulation patterns, and local weather conditions. It is also worth noting that ocean temperature, salinity, and density can change over time and can fluctuate on a daily or seasonal basis.

Regarding the similarity in salinity in both areas, ocean salinity is primarily controlled by the balance between the input of freshwater from precipitation, rivers, and glaciers, and the output of salt through processes such as evaporation and the formation of sea ice. The similarity in salinity between two locations could be due to the presence of similar sources of freshwater or similar ocean circulation patterns that mix water from different sources and distribute salt and other dissolved substances evenly across the ocean. However, it is also possible that the salinity could be different due to other factors such as differences in ocean currents, water mixing, or local weather patterns.

When H₂S gas is removed from the system at equilibrium, the reaction shifts to the right (products) and the concentration of NH₃ increases (option C)

A French scientist (Chatelier) postulated a principle which helps us to understand a chemical system in equilibrium.

The principle states that If a an external constraint such as change in temperature, pressure or concentration is imposed on a system in equilibrium, the equilibrium will shift so as to neutralize the effect.

According to Chatelier's principle a decrease in concentration of the products will favor the forward (right) reaction.

From the above principle, we can conclude that when H₂S gas is removed from the system at equilibrium, the reaction shifts to the right (products) and the concentration of NH₃ increases.

Thus, the correct answer to the question is option C

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Answer:

Hydroxyl (alcohol compound)

Explanation:

*view photo*

D. Hydroxy

Therefore, the correct option is option D.

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Explanation:

yuyfjkvg8hvcrnkffhbbbvvggh

Answer:

The moving train

Explanation:

Kinetic energy is energy being used right now. So, the only object using energy right now is the moving train

Good luck on the rest of the test!

Answer:

1.heterogeneous mixture

2.element

3.compound

4.homogeneous mixture

Explanation:

The correct pairs are:

A cloud, which consist of small water droplets - Heterogeneous mixture

Distributed throughout the air

helium, a gas composed of identical atoms - Element

Rubbing alcohol, a liquid composed of chemically bonded - Compound

Carbon, Oxygen, and Hydrogen atoms

sugar thoroughly dissolved in water - Homogenous mixture.

In Heterogenous mixture, the composition of the mixture is not uniform. In Homogenous mixture, the composition is uniform throughout. Element is the combination of same atoms. Compound contains two or more elements.

Therefore, the correct pairs are,

A cloud, which consist of small water droplets - Heterogeneous mixture

Distributed throughout the air

helium, a gas composed of identical atoms - Element

Rubbing alcohol, a liquid composed of chemically bonded - Compound

Carbon, Oxygen, and Hydrogen atoms

sugar thoroughly dissolved in water - Homogenous mixture.

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