Please help!
Write the equation of the graphed line.

y=3x-2
y=4/3x-2
y=3/4x+2
y=3/4x-2
y=-2/3x+4
y=-3/4x-2

Since x = 8, you would need to plug in 8 into the x.

f(x) = 6x - 4

f(x) = 6(8) - 4

f(x) = 48 - 4

f(x) = 44

So, the correct answer would be C. 44

Answer:

C

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

hope this helps lovely! <3

Answer:

76 degrees

Step-by-step explanation:

Let the angles be x, y and z

As per given:

Considering the first 2 equations in the third one:

So the third angle is:

Answer:

If gas costs $3.75 per gallon and Berto has $12, then he can purchase 12/3.75 gallons. This is approximately 3.2 gallons. So the coordinate on this line would be (3.2, 12).

Actually... It's from web

Answer: D.25

see in the picture, we have:

2x + 70 = 120

⇔ 2x = 50

⇔ x = 50/2

⇔ x = 25

Step-by-step explanation:

Answer:

$325.02

Step-by-step explanation:

What is 2% administrative fee on $16,251?

2% = 0.02

We Take

16251 x 0.02 = $325.02

So, 2% administrative fee on $16251 is $325.02

Answer:

4.75 liters of punch

Step-by-step explanation:

2.8 + 0.75 = 3.55

3.55 + 1.2 = 4.75 liters of punch

Answer:

21

Step-by-step explanation:

20+1=21

Answer:

your answer is 12>2

Step-by-step explanation:

you basically do 3 x 4 = 12

The time vector for a 2-second signal with a sampling rate of 1000 Hz can be created using the formula t = [0:1/fs:2], where fs is the sampling rate (1000 Hz).

The formula for creating a time vector based on a sampling rate of 1000 Hz for a 2-second signal is t = [0:1/fs:2], where fs is the sampling rate (1000 Hz) and t is the time vector. The calculation is as follows: t = [0:1/1000:2] = [0, 0.001, 0.002, 0.003, 0.004, ..., 1.999, 2.000]. So, the time vector for a 2 second signal at 1000 Hz sampling rate is [0, 0.001, 0.002, 0.003, 0.004, ..., 1.999, 2.000].

The formula for creating a time vector based on a sampling rate of 1000 Hz for a 2-second signal is t = [0:1/fs:2], where fs is the sampling rate (1000 Hz) and t is the time vector. The resulting time vector is [0, 0.001, 0.002, 0.003, 0.004, ..., 1.999, 2.000], which can be used to create a 2-second signal with a sampling rate of 1000 Hz.

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The range of the function g(x) is [300, ∞)

In this question, we have been given that we have deposited $300 into a savings account that earns interest annually.

The function g(x) = 300(1.04)^x used to find the amount of money in the savings account, g(x), after x years.

We need to find the range of the function.

Since a savings account earns interest annually, x can have take values from 0 to infinity.

For x = 0 year,

g(0) = 300(1.04)^0

g = 300 * 1

g = 300

For x tends to ∞, the value of function would be ∞

Therefore, the range of the function g(x) is [300, ∞)

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It is true that Δ ABD and Δ DCA congruent by RHS by the given explanation.

Triangle congruence refers to all corresponding angles being equal. It is equal on all corresponding sides.

RHS stands for Right Angle -Hypotenuse-Side. According to the RHS congruence theorem, two right-angled triangles are congruent if their respective hypotenuses and sides are the same as those of another right-angled triangle.

Here we have

AOC and BOD are diameters of a circle, center O

We can represent the above picture as given below

From figure

Δ ABD and Δ DCA are two right-angle triangles

=> ∠AOD = ∠BOC   [ Vertically opposite Right angle ]  

=> AD = BC  [Chords formed by Two diameters (Hypotenuse of triangles)]

=> AO = OB     [ Radius of the circles i.e side of triangles ]    

By the above observations

Δ ABD and Δ DCA congruent by RHS.

Therefore,

It is true that Δ ABD and Δ DCA congruent by RHS by the given explanation.

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To solve the system of equations using Gaussian elimination, we can represent the given system in an augmented matrix form:

[ 3 -7 -2 | 46 ]

[ 1 -3 0 | 18 ]

To perform Gaussian elimination, we'll apply row operations to the augmented matrix to obtain row-echelon form.

First, let's perform the row operation R2 = R2 - (1/3)R1:

[ 3 -7 -2 | 46 ]

[ 0 2 (2/3) | 2 ]

Next, we'll perform the row operation R2 = (1/2)R2:

[ 3 -7 -2 | 46 ]

[ 0 1 (1/3) | 1 ]

Now, let's perform the row operation R1 = R1 + 7R2:

[ 3 0 1 | 53 ]

[ 0 1 (1/3) | 1 ]

Finally, let's perform the row operation R1 = R1 - (1/3)R2:

[ 3 0 0 | 52 ]

[ 0 1 (1/3) | 1 ]

The resulting row-echelon form gives us the following system of equations:

3x₁ + 0x₂ + 0x₃ = 52

0x₁ + 1x₂ + (1/3)x₃ = 1

From the row-echelon form, we can see that the system has a unique solution.

Therefore, the correct choice is A. The unique solution is x₁ = 52, x₂ = 1, and x₃ = 0.

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Answer:

A dilation stretches or shrinks the original figure. A description of a dilation includes the scale factor (or ratio) and the center of the dilation. The center of dilation is a fixed point in the plane. If the scale factor is greater than 1, the image is an enlargement (a stretch).

Step-by-step explanation:

To find the coordinates of point B, we can use the section formula which states that the coordinates of the point that divides a segment with endpoints (x1, y1) and (x2, y2) in the ratio of m:n are given by:

((mx2 + nx1)/(m+n), (my2 + ny1)/(m+n))

The coordinates of point B are (4.25, 8.25), and the answer is (D).

Here, A (2, 6) and C (5, 9) are the endpoints of the segment, and we want to partition the segment in the ratio of 3:1. So, we have:

m:n = 3:1

m+n = 4

Solving for m and n, we get:

m = 3, n = 1

Now, substituting  values in the section formula, we get:

((35 + 12)/(3+1), (39 + 16)/(3+1)) = (4.25, 8.25)

Therefore, the coordinates of point B are (4.25, 8.25), and the answer is (D).

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Answer:

(4.25, 8.25)

Step-by-step explanation:

i took the quiz

You would use the CHARINDEX string function to locate the index of the first character of the first occurrence of a substring within another string.

The CHARINDEX() function is defined as returning the substring's location within the given string. Like the SUBSTRING function, it operates in reverse.

⇒ Syntax of CHARINDEX() function is CHARINDEX (substring, input_string)

Substring: Here, we specify the substring within the input string that we wish to look for. A maximum of 8000 characters may be used in this argument.

Input_string: The input string is defined in this argument.

Therefore, You would use the CHARINDEX string function to locate the index of the first character of the first occurrence of a substring within another string.

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The mass of the chemicals at the end of the experiment is between 54.7 g and 54.71 g.

The lower bound for the mass of the chemicals at the end of the experiment is

            = 62 - 7.3

            =54.7 g.

The upper bound for the mass of the chemicals at the end of the experiment is 62 - 7.3 + 0.01 = 54.71 g.

Therefore, the mass of the chemicals at the end of the experiment is between 54.7 g and 54.71 g.

Note: The rounding to 2 significant figures means that the mass of the chemicals could be slightly different from the values given, but the difference would be less than 0.01 g.

What is lower bound?

The lowest number that can be rounded to obtain an estimated value is referred to as the lower bound (LB).

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The new design has better performance.In the old design, the CPI was 0.052, while in the new design, the CPI was 0.046 As a result, the new design is the winner here since the CPI is lower in the new design.

Given data,

Length of Embedded Program = 1

Let the multiply instruction  = 12 cycles

All other instruction  = 4 cycles

Percentage of multiply instructions in embedded program = 15%

Let's calculate the CPI (Cycles Per Instruction) of the old design.

CPI of the old design

\(CPI = (no. of cycles for multiply instruction × % of multiply instruction + no. of cycles for all other instructions × % of all other instructions)/100\)

We know no. of cycles for multiply instruction = 12 cycles

No. of cycles for all other instructions = 4 cycles

\(Percentage of all other instructions = 100% - Percentage of multiply instructions= 100% - 15% = 85%\)

Putting all the values,

\(CPI of the old design= (12 × 15% + 4 × 85%)/100= (1.8 + 3.4)/100= 5.2/100= 0.052\)

CPI of the old design = 0.052

Let's calculate the CPI (Cycles Per Instruction) of the new design.

Cycle time of new design is increased by 20%, it means

the new cycle time will be = 1.2 Old cycle time

New cycle time = 1.2 × Old cycle time

New cycle time / Old cycle time = 1.2

Let's calculate the new cycle time,

Cycle time of new design = 1.2 × 4= 4.8 cycles

The number of cycles for multiply instruction is reduced to 8 cycles

Let's calculate the CPI of the new design.

CPI of the new design

\(CPI = (no. of cycles for multiply instruction × % of multiply instruction + no. of cycles for all other instructions × % of all other instructions)/100\)

We know no. of cycles for multiply instruction = 8 cycles

No. of cycles for all other instructions = 4 cycles

\(Percentage of multiply instructions = 15%Percentage of all other instructions = 100% - Percentage of multiply instructions= 100% - 15% = 85%\)

Putting all the values,

\(CPI of the new design= (8 × 15% + 4 × 85%)/100= (1.2 + 3.4)/100= 4.6/100= 0.046\)

CPI of the new design = 0.046

In terms of performance, a lower CPI means better performance.

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The simplified form of the given coordinate is (0,7/4) and the points in the coordinate plane given below:

In the given question we have to represent in given point in the coordinate plane.

The given coordinate is (0, 1 3/4).

In the given coordinate we firstly simplify the given coordinate.

We solve 1 3/4 this mixed fraction in the improper fraction.

To convert into improper fraction we multiply 1 with 4 then add with 3.

So simplified form is;

1 3/4 = 7/4

So the simplified form is (0, 7/4).

The point on the coordinate plane is given below:

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a)  The critical point is (-1/2, 7/16).

b)  The discriminant is negative, the critical points (0, -1) and (1, 1) do not have extrema.

c)   all the critical points (nπ, 0) are saddle points.

a) To find the critical points, we need to find the points where the partial derivatives of f(x, y) with respect to x and y are equal to zero.

Partial derivative with respect to x:

∂f/∂x = 3x^2 + 1 - 4y

Partial derivative with respect to y:

∂f/∂y = -4x - 2

Setting these partial derivatives equal to zero and solving the resulting system of equations, we can find the critical points:

3x^2 + 1 - 4y = 0 ...(1)

-4x - 2 = 0 ...(2)

From equation (2), we have -4x - 2 = 0, which gives x = -1/2. Substituting this value of x into equation (1), we get:

3(-1/2)^2 + 1 - 4y = 0

3/4 + 1 - 4y = 0

7/4 - 4y = 0

-4y = -7/4

y = 7/16

Therefore, the critical point is (-1/2, 7/16).

To determine the nature of this critical point, we can calculate the second partial derivatives:

∂²f/∂x² = 6x

∂²f/∂y² = 0

∂²f/∂x∂y = -4

The discriminant for this point is D = (∂²f/∂x²)(∂²f/∂y²) - (∂²f/∂x∂y)² = (6x)(0) - (-4)² = 16.

Since the discriminant is positive and ∂²f/∂x² = 6x, the critical point (-1/2, 7/16) is a relative minimum.

(b) To find the critical points for f(x, y) = x(y + 1) - x²y, we need to find where the partial derivatives with respect to x and y are equal to zero.

Partial derivative with respect to x:

∂f/∂x = y + 1 - 2xy

Partial derivative with respect to y:

∂f/∂y = x - x²

Setting these partial derivatives equal to zero, we get:

y + 1 - 2xy = 0 ...(1)

x - x² = 0 ...(2)

From equation (2), we have x - x² = 0, which gives x(x - 1) = 0. This implies that x = 0 or x = 1.

Case 1: x = 0

Substituting x = 0 into equation (1), we have:

y + 1 = 0

y = -1

Therefore, one critical point is (0, -1).

Case 2: x = 1

Substituting x = 1 into equation (1), we have:

y + 1 - 2y = 0

-y + 1 = 0

y = 1

Therefore, another critical point is (1, 1).

To determine the nature of these critical points, we calculate the second partial derivatives:

∂²f/∂x² = -2

∂²f/∂y² = 0

∂²f/∂x∂y = -2

The discriminant for both critical points is D = (∂²f/∂x²)(∂²f/∂y²) - (∂²f/∂x∂y)² = (-2)(0) - (-2)² = -4.

Since the discriminant is negative, the critical points (0, -1) and (1, 1) do not have extrema.

(c) To find the critical points for f(x, y) = cos(x) cosh(y), we need to find where the partial derivatives with respect to x and y are equal to zero.

Partial derivative with respect to x:

∂f/∂x = -sin(x) cosh(y)

Partial derivative with respect to y:

∂f/∂y = cos(x) sinh(y)

Setting these partial derivatives equal to zero, we get:

-sin(x) cosh(y) = 0 ...(1)

cos(x) sinh(y) = 0 ...(2)

Equation (1) implies that sin(x) = 0, which occurs when x = nπ for n being an integer.

Equation (2) implies that sinh(y) = 0, which occurs when y = 0.

Therefore, the critical points are of the form (nπ, 0), where n is an integer.

To determine the nature of these critical points, we can calculate the second partial derivatives:

∂²f/∂x² = -cos(x) cosh(y)

∂²f/∂y² = cos(x) cosh(y)

∂²f/∂x∂y = -sin(x) sinh(y)

The discriminant for these critical points is D = (∂²f/∂x²)(∂²f/∂y²) - (∂²f/∂x∂y)² = (-cos(x) cosh(y))(cos(x) cosh(y)) - (-sin(x) sinh(y))² = cos²(x) cosh²(y) - sin²(x) sinh²(y).

Since cos²(x) and cosh²(y) are always positive, and sin²(x) and sinh²(y) are always non-negative, the discriminant D will always be non-negative.

Therefore, all the critical points (nπ, 0) are saddle points.

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The answer to the question is C, which is integers 4,5 or -4,-3.

Let's call the first integer x and the second integer x+1 (since they are consecutive).
According to the problem, we can set up the following equation:
x(x+1) = x + (x+1) + 19
We can simplify this equation by expanding the left side and combining like terms on the right side:
x^2 + x = 2x + 20
Now we can move all the terms to one side and get a quadratic equation:
x^2 - x - 20 = 0
We can factor this equation as (x-5)(x+4) = 0, which means the solutions for x are 5 and -4.
Therefore, the two consecutive integers are either 4,5 or -4,-3.
The long answer includes all the steps of solving the quadratic equation:
x^2 - x - 20 = 0
We can use the quadratic formula to solve for x:
x = (-b ± √(b^2 - 4ac)) / 2a
In this case, a=1, b=-1, and c=-20.
x = (1 ± √(1 - 4(1)(-20))) / 2(1)
x = (1 ± √81) / 2
x = (1 ± 9) / 2

The two solutions for x are 5 and -4.
Therefore, the two consecutive integers are either 4,5 or -4,-3.
The product of two consecutive integers is 19 more than their sum. To find the integers, let's represent them as x and x+1.

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Answer:

The final balance is $4,353.56.

The total compound interest is $1,153.56.

Step-by-step explanation:

Answer:

It’s depends on how much of your grade the assignment was worth

Step-by-step explanation:

Answer: Im pretty sure it will effect your grade by 24% if thats the answer your looking for. It also depends on how much the assignment was actually worth

The y-coordinate for the solution to the system of equations is -3.

What is a system of equations?

A finite set of equations for which common solutions are sought is referred to in mathematics as a set of simultaneous equations, often known as a system of equations. The intersection of two lines represents the system of equations' solution.

Given system of equations are,

6x + 11y = -3

4x + y = 17

To solve these equations, we must first remove x or y terms.

To do this we must make the removing term's coefficients the same.

In this case, let's remove y.

We are multiplying the second equation by 11. Then,

6x + 11y = -3

44x + 11y = 187

Now we will subtract the second equation from the first.

- 38x  = -190

x = 5

Now to find y, substitute x in any one of the equations.

6 * 5 + 11y = -3

11y = -33

y = -3

Hence the y-coordinate for the solution to the system of equations is -3.

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If the resulting F-statistic is less than the critical value, we fail to reject the null hypothesis and conclude that there is not enough evidence to suggest that the variances are significantly different.

The F-test is a statistical test used to compare the variances of two groups.

In this problem, we will use it to compare the variance of the value added by the manufacturer and the variance of the cost of materials in manufacturing. The F-test is performed by dividing the larger variance by the smaller variance. The resulting F-statistic is then compared to the critical value of an F-distribution with degrees of freedom equal to the sample size minus one for each group.

Before we can perform the F-test, we need to determine which variable will be group 1. Typically, the variable with the smaller mean is designated as group 1. This is because we want to minimize the chance of making a type II error, which is failing to reject the null hypothesis when it is false. If we designated the variable with the larger mean as group 1, we might not detect a significant difference between the groups, even if one exists.

Once we have designated which variable will be group 1, we can perform the F-test. If the resulting F-statistic is greater than the critical value of the F-distribution, we reject the null hypothesis and conclude that the variances are significantly different.

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Answer:

34 sq cm

Step-by-step explanation:

4x4 = 16

9x2 = 18

16+18= 34

Answer:

A: 6

B: 16

C: 2

D: -12

Step-by-step explanation:

They are asking you to multiply the equations:

(3x^2 + 2x - 3)(2x + 4)

Distribute and you should get:

6x^3 + 16x^2 + 2x - 12

The Coefficients A,B,C, and D are 6, 16, 2, and -12.

We can use Coulomb's law to calculate the magnitude of the electric field at a distance r away from a point charge Q:

E = k * Q / r^2

where k is Coulomb's constant, Q is the charge of the point charge, and r is the distance from the point charge.

In this problem, we have a point charge Q of -10 nC located at (1.2 cm, 0 cm), and we want to find the x-component of the electric field at a distance r = 5.3 cm away at position (-4.1 cm, 0 cm).

To find the x-component of the electric field, we need to use the cosine of the angle between the electric field vector and the x-axis, which is cos(180°) = -1.

So, the x-component of the electric field at position (-4.1 cm, 0 cm) is:

E_x = - E * cos(180°) = - (k * Q / r^2) * (-1)

where k = 9 x 10^9 N*m^2/C^2 is Coulomb's constant.

Substituting the given values, we get:

E_x = - (9 x 10^9 N*m^2/C^2) * (-10 x 10^-9 C) / (0.053 m)^2

E_x ≈ -30,566.04 N/C

Rounding this to two significant figures and including the appropriate units, we get:

The x-component of the electric field is about -3.1 x 10^4 N/C (to the left).

The value of c so that cx-d=2x+4 has No Solution is c=2.

In the given question ,

we have

cx-d=2x+4       ....(i)

Given that d = 2 ,

We substitute the value of d=2 in equation (i)

On substituting we get

cx-2=2x+4

Simplifying further we get

cx=2x+4+2

cx=2x+6

cx-2x=6

x(c-2)=6

x=6/(c-2)

For x to have NO SOLUTION the denominator should be 0.

because when denominator becomes 0 the value becomes not defined , hence will have no solution.

Substituting the denominator = 0

we get c-2=0

c=2.

Therefore , the value of c so that cx-d=2x+4 has No Solution is c=2.

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