Answer:
are they talking about the form classification or..?
Apply Newton's first law to music playing on the radio.
Answer: Find the answer in the explanation
Explanation:
The music playing on the radio will be heard through the sound waves coming from the radio.
The travelling wave will obey Newton's first law of motion which state that:
An object or particle will remain at rest or continue its linear motion in a straight line except an external force is applied.
The external force through wind could affect the travelling of the sound waves. Since the wave is longitudinal wave. That is, it needs a medium (air) for its propagation.
. a 30 newton stone is dropped from a height of 10 m and strikes the ground with a speed of 13 m/s. what average force of air friction acted on the stone as it fell?
The average force of air friction that acted on the stone as it fell is 8.72 N.
The resistance experienced by an object when passing through the air is known as air friction. The force of air resistance is proportional to the speed of the object moving through the air. The faster an object travels, the greater the resistance it experiences. It can be computed using the following formula:
F = 1/2pv²CdA,
Where F is the force of air resistance, p is the density of the air, v is the velocity of the object, Cd is the drag coefficient, and A is the surface area of the object.
The formula for gravitational potential energy is:
PE = mgh
where m is the mass of the object, g is the acceleration due to gravity (9.8 m/s²), h is the height the object was dropped from
Let us determine the velocity of the object upon impact. The formula for finding the velocity of an object that falls from a height is:
v² = u² + 2gh
where v is the final velocity, u is the initial velocity (which is zero in this case), g is the acceleration due to gravity (9.8 m/s²), h is the height the object was dropped from
Substitute the values into the formula:
v² = 0 + 2(9.8)(10)
v² = 196
v = √196
v = 14 m/s
Therefore, the final velocity of the object is 14 m/s.
Let us now calculate the force of air resistance using the formula:
F = 1/2pv²CdA
where F is the force of air resistance, p is the density of the air (1.2 kg/m³ at sea level), v is the velocity of the object (14 m/s), Cd is the drag coefficient (for a sphere it is 0.47), A is the surface area of the object (for a sphere it is πr²)
Substitute the values into the formula:
F = 1/2 × 1.2 × 14² × 0.47 × π(0.5²)
F = 8.72 N
Therefore, the average force of air friction that acted on the stone as it fell is 8.72 N.
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How could you know that a chemical change has taken place?
Which of the following hypothetical stars would appear the brightest? Star Madolarian of magnitude 2 Star Naboo of magnitue 6 Star Sorgan of magnitude 1 Star Versio of magnitude 3 QUESTION 4 If you use the highest daily position of the Sun to mark the noon time of a day, then which of the following timing system you are using? 1. Apparant Solar Times 2. Mean Solar Times 3. The Equation of Times 4. None of These QUESTION 5 Who constructed the star magnitude system that goes from 1 to 6 ? 1. Tycho Brahe 2. Hipparchus 3. Galieo 4. Copernicus
Star Sorgan of magnitude 1 would appear the brightest out of the following hypothetical stars. If you use the highest daily position of the Sun to mark the noon time of a day, then you are using Apparant Solar Times. The star magnitude system that goes from 1 to 6 was constructed by Hipparchus. Option 2 is correct.
The apparent brightness of a celestial object in the sky is called its magnitude. The scale is inverted; lower numbers denote greater brightness. The stars are classified using their magnitudes, which is denoted by 'm. 'A star's apparent magnitude is how bright it appears in the sky as seen from Earth. A star's absolute magnitude is how bright it would be if it were a distance of 10 parsecs (32.6 light-years) from Earth.
The highest daily position of the Sun is used to mark the noon time of a day in the Apparent Solar Times timing system. The star magnitude system that goes from 1 to 6 was created by Hipparchus.
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a space traveler weighs 682 n on earth. what will the traveler weigh on another planet whose radius is 3 times that of earth and whose mass is 2 times that of earth?
The traveler's weight on another planet whose radius is 3 times that of Earth and whose mass is 2 times that of Earth is 21.647 N
The following is the solution to the given problem:
Mass and gravity are related to one another. Gravity is generated by the planet's mass, and the magnitude of the gravitational force is determined by the mass of the planet on which the object is situated, as well as the mass of the object.
Mass, distance, and gravity are all factors that influence the gravitational force. Mass is directly proportional to the gravitational force and inversely proportional to the square of the distance from the gravitational force's center.
Here is the formula: Force of gravity = G(M1M2)/d²where, G is the gravitational constant 6.67 x 10^{-11} N(m/kg)^2, M1 is the mass of the first body, M2 is the mass of the second body, d is the distance between the centers of two bodies.
On earth, the traveler weighs 682 N. On another planet whose radius is 3 times that of Earth and whose mass is 2 times that of Earth, we have to calculate the traveler's weight.
Mass of Earth is 5.972 × 10^24 kg2,
Radius of Earth is 6.371 x 10^63.
The mass of the planet whose radius is 3 times that of Earth and whose mass is 2 times that of Earth.
Mass of the planet = 2 x mass of Earth = 2 x 5.972 × 10^24 kg = 1.1944 × 10^25 kg4.
The radius of the planet whose radius is 3 times that of Earth,
Radius of the planet = 3 x radius of Earth = 3 x 6.371 x 10^6 m = 1.9113 × 10^7 m5.
The distance between the two planets.
Distance between two planets = radius of planet + radius of Earth
= 1.9113 × 10^7 m + 6.371 x 10^6 m
= 2.54813 x 10^7 m
= 2.54813 x 10^10 cm.
Putting all the values in the formula.
Force of gravity = G (M1 M2) / d²
Where, Mass of the traveler on the other planet is m.
Mass of the Earth is M1 = 5.972 × 10^24 kg.
Mass of the other planet is M2 = 2 x 5.972 × 10^24 kg = 1.1944 × 10^25 kg.
Radius of the Earth is r1 = 6.371 x 10^6 m.
Radius of the other planet is r2 = 3 x 6.371 x 10^6 m = 1.9113 × 10^7 m.
Distance between the two planets is d = 2.54813 x 10^10 cm.682
= G (M1 M2)/d²
G = 6.674 × 10^-11 N m² / kg²
Force of gravity on other planet = G(mM2)/r² where m is the mass of the traveler on the other planet
= 6.674 × 10^-11 × (m × 1.1944 × 10^25)/(1.9113 × 10^7)²
Weight on another planet = force of gravity on another planet × mass of the traveler on another planet
= (6.674 × 10^-11 × (m × 1.1944 × 10^25)/(1.9113 × 10^7)²) × m
= 21.647 N (approximately)
Therefore, the traveler's weight on another planet whose radius is 3 times that of Earth and whose mass is 2 times that of Earth is 21.647 N (approximately).
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8. (a) a spherical mirror is cut in half horizontally and the top half removed. will an image be formed by the bottom half of the mirror? how does the image formed by the half mirror compare to the image formed before cutting the mirror in half?
As the radius of curvature and focal length of the mirror is bottom half of the mirror is same as earlier, so the image formation by this mirror will not change. As a result, the bottom half of the spherical mirror will reflect an image that is an exact replica of the image it projected prior to being chopped.
Only the aperture area will be cut in half when a mirror is cut in half horizontally; the radius of curvature remains unchanged.
The spherical mirror has a radius of curvature that is twice its focal length. Because the radius of curvature remains unchanged when the mirror is cut horizontally, the focal length of the bottom portion will be the same as in the initial situation.
The location of the image created by the lower portion of the mirror is therefore the same as in the preceding situation according to the mirror equation.
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The gravitational force on the moon is only 1/6 that on earth. What is the weight of a 10 kg object on the earth and on the moon? what is the mass of the object on the earth and the moon?.
Answer:
10 kg
Explanation:
The mass of the object is always constant and does not depend on the gravitational force of the Earth or the Moon.
which two criteria are least important for engineers to consider when developing a process to produce an important chemical
Answer:
Chemical engineering is a multi-disciplinary branch of engineering that combines natural and experimental sciences such as chemistry and physics, along with life sciences such as biology, microbiology and biochemistryplus mathematics and economics to design, develop, produce, transform, transport, operate
Explanation:
Answer:
A. the process needs to produce significant amounts of ammonia
C. the process needs to be able to be performed safely
Explanation:
a p e x
how far must the mirror m2 (see the figure (figure 1)) of the michelson interferometer be moved so that 1910 fringes of he-ne laser light (633 nm ) move across a line in the field of view?
The Michelson interferometer is a device that uses the interference of light waves to measure distances and wavelengths.
In this question, we are asked to determine how far mirror M2 needs to be moved so that 1910 fringes of He-Ne laser light (with a wavelength of 633 nm) move across a line in the field of view.
To find the distance M2 needs to be moved, we can use the formula:
Δx = (N * λ) / 2
Where Δx is the distance M2 needs to be moved, N is the number of fringes, and λ is the wavelength of the light.
Plugging in the given values, we have:
Δx = (1910 * 633 nm) / 2
To calculate this, we need to convert the wavelength from nm to meters:
Δx = (1910 * 633 * 10⁻⁹m) / 2
Simplifying this equation gives us the distance M2 needs to be moved.
Δx = 0.6068 m
Therefore, mirror M2 must be moved approximately 0.6068 meters so that 1910 fringes of the He-Ne laser light (with a wavelength of 633 nm) move across a line in the field of view.
To find the distance M2 needs to be moved, we use the formula Δx = (N * λ) / 2, where Δx is the distance M2 needs to be moved, N is the number of fringes, and λ is the wavelength of the light. In this case, N is given as 1910 fringes, and λ is given as 633 nm.
First, we need to convert the wavelength from nm to meters by multiplying it by 10⁻⁹. Then, we substitute the values into the formula: Δx = (1910 * 633 * 10⁻⁹ m) / 2. By simplifying the equation, we find that Δx is approximately 0.6068 meters. Therefore, mirror M2 must be moved approximately 0.6068 meters so that 1910 fringes of the He-Ne laser light (with a wavelength of 633 nm) move across a line in the field of view.
The mirror M2 of the Michelson interferometer needs to be moved approximately 0.6068 meters so that 1910 fringes of the He-Ne laser light with a wavelength of 633 nm move across a line in the field of view.
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A solid cube of mass 87 kg and edge length 0.95 m rests on a horizontal floor as shown below. A person then pushes on the upper edge of the cube with a horizontal force of magnitude F. At what value of F will the cube start to tip? Assume the frictional force from the floor is large enough to prevent the cube from sliding.
The force required to tip the cube is equal to the coefficient of static friction times the weight of the cube.
fx=μs * 87 kg * 9.8 m/s^2
What is the force required to tip the cube?Generally, The cube will start to tip when the net torque about the point of contact between the cube and the floor is equal to zero. The torque is given by:
torque = force x distance from axis of rotation
The distance from the axis of rotation is half the edge length of the cube (0.475m), and the force is the force applied by the person (). Therefore, the torque is:
torque = fx x 0.475
For the cube to tip, the torque due to the person's force must be greater than the maximum torque the friction can provide, which is the friction force times the distance from the axis of rotation.
The maximum torque provided by friction is:
friction torque = friction force x 0.475
Since the friction force is equal to the normal force (mg) multiplied by the coefficient of static friction (μs), the maximum torque provided by friction is:
friction torque = μs * mg * 0.475
where m is the mass of the cube, g is the acceleration due to gravity and μs is the coefficient of static friction between the cube and the floor.
So, we can find the force needed to tip the cube by equating the torque due to the force with that of the friction torque.
Fx*0.475 = μs * m * g * 0.475
Fx= μs * m * g
Fx= μs * 87 kg * 9.8 m/s^2
Note: The coefficient of static friction (μs) is a dimensionless quantity between 0 and 1, it varies depending on the surfaces in contact.
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Calculate the force in lb, required to accelerate a mass of 7 kg at a rate of 17 m/s²?
Therefore, the force required to accelerate a mass of 7 kg at a rate of 17 m/s² is approximately 26.78 lb.
To calculate the force required to accelerate a mass of 7 kg at a rate of 17 m/s², you can use the formula F = ma, where F is the force in newtons, m is the mass in kilograms, and a is the acceleration in meters per second squared. Since the question asks for the force in lb, we will need to convert the result from newtons to pounds.
First, we can calculate the force in newtons by multiplying the mass by the acceleration: F = 7 kg x 17 m/s² = 119 N.
To convert newtons to pounds, we can use the conversion factor 1 N = 0.2248 lb. Therefore, the force required to accelerate a mass of 7 kg at a rate of 17 m/s² is:
F = 119 N x 0.2248 lb/N = 26.78 lb.
Therefore, the force required to accelerate a mass of 7 kg at a rate of 17 m/s² is approximately 26.78 lb.
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PLEASE HELPP I NEED TO PASS THIS !!
A sprinter runs 200 m in 25 s. Calculate his average speed
Answer:
Explanation:
speed=distance/time = 200/25=8m/s^2
Help!!
I'm not sure my answer is correct.
The problem is attached!
Answer:
where's ur answer?
Explanation:
hihi
most thermodynamic calculations are performed under standard conditions. which set of conditions (temperature, concentration, and pressure) is associated with standard conditions?
Standard conditions refer to a specific set of temperature, concentration, and pressure values, which are commonly used in scientific experiments and calculations to provide a consistent basis for comparison.
In most thermodynamic calculations, standard conditions are defined as a temperature of 298.15 K (25°C), a concentration of 1 mol/L (1 M) for solutions, and a pressure of 1 atm (101.325 kPa) for gases. These conditions are important because they serve as a reference point, allowing scientists to easily compare the properties and behavior of various substances under the same set of conditions.
The use of standard conditions simplifies calculations and ensures that the results are consistent across different studies. By providing a uniform reference point, researchers can focus on the effects of specific variables, such as the type of substance, its structure, or its interactions with other substances, without having to account for variations in temperature, concentration, or pressure.
To summarize, standard conditions for most thermodynamic calculations involve a temperature of 298.15 K (25°C), a concentration of 1 mol/L (1 M) for solutions, and a pressure of 1 atm (101.325 kPa) for gases. These conditions provide a consistent basis for comparison, enabling scientists to examine the properties and behavior of various substances under the same set of conditions.
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Two cars bump going the same direction and stick together. Car A has a mass of 1000kg car B has a mass of 2000kg. What the speed of the cars after the collision?
Answer:
I belive that the 2000 kg will be going faster then the 1000kg
Explanation:
Because it is 2x as heavy as the other car which means it most likely would hit the car and keep going because it can hit it so hard that the car dosent hit effected
Salt dissolves in water to form saltwater. Is this considered a chemical change or a physical change
Salt dissolves in water to form saltwater. This kind of change is regarded as a chemical change.
A physical change is a kind of change in which only the physical properties of matter change. In a physical change, neither the composition nor the chemical nature of matter is changed.
A chemical change involves a chemical process that results in the production of new substances. When you dissolve salt in water the sodium chloride dissociates in Na+ and Cl- ions which can be written in the form of a chemical reaction as,
NaCl → Na+(aq) + Cl-(aq)
Thus, dissolving salt in water is an example of a chemical change.
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why a person feel weightlessness in a spacecraft orbiting around a heavenly body
Answer:
The orbital velocity an aircraft orbiting around a heavenly body is found as follows;
At the orbital velocity, \(F_G\) = \(F_C\)
Where;
\(F_G\) = The gravitational force = \(\dfrac{G \cdot M \cdot m}{R_E^2}\)
\(F_C\) = The centripetal force = \(\dfrac{m \cdot v_0^2}{R_E}\)
Therefore
\(v_0 = \sqrt{\dfrac{G \cdot M}{R_E} }\)
Therefore, at the orbital velocity of the spacecraft, the centripetal force attracting the person away from the central region heavenly body is equal to the gravitational force pulling the person towards the center of the heavenly body (which was felt as her or his weight), and the person feels weightless while inside the orbiting spacecraft
Explanation:
A red cart has a mass of 4 kg and a velocity of 5 m/s. There is a 2-kg blue cart that is parked and not moving, thus its velocity is 0 m/s.
The red cart hits the blue cart.
The blue cart starts to move forward with a velocity of 6 m/s. The red cart bounces off of the blue cart and moves backwards, at a velocity of 2 m/s.
Name the TYPE of collision that occurred.
Calculate the BEFORE momentum of the red cart. Use correct units.
Calculate the BEFORE momentum of the blue cart. Use correct units.
Calculate the AFTER momentum of the red cart. Use correct units.
Calculate the AFTER momentum of the blue cart. Use correct units.
Calculate the SYSTEM’S TOTAL MOMENTUM before the collision. Use correct units.
Calculate the SYSTEM’S TOTAL MOMENTUM after the collision. Use correct units.
EXPLAIN how this example supports the Law of Conservation of Momentum. Use the evidence to support your answer of how this example supports the Law of Conservation of Momentum. Use correct units. Be specific.
Answer:dam hold up
Explanation:
Predict how network modifiers affect the Tg of a ceramic glass.
Network modifiers are elements or compounds that can alter the network structure of a ceramic glass by breaking the covalent bonds and introducing ionic bonds. The addition of network modifiers can decrease the glass transition temperature (Tg) of a ceramic glass.
Network modifiers are elements or compounds that can alter the network structure of a ceramic glass by breaking the covalent bonds and introducing ionic bonds. The addition of network modifiers can decrease the glass transition temperature (Tg) of a ceramic glass. This is because the introduction of ionic bonds disrupts the continuous network of covalent bonds, which lowers the energy required for the molecules to move and transition from a solid-like state to a liquid-like state. Therefore, the more network modifiers added to a ceramic glass, the lower the Tg will be. Conversely, the removal of network modifiers or the addition of network formers (elements or compounds that enhance the network structure) will increase the Tg of a ceramic glass.
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can someone please help me answer this question ?
Answer:
b 60 N force
Explanation:
The change in the momentum is given by the force•distance from the attached point. We don't have any distance, but apparently, the stick forces are being applied in each quarter of the stick, so let's use fractions of 4 to solve it:
150 N:
150•1/4 = 37.5
30 N:
30•2/4 = 30•1/2 = 15
60 N:
60•3/4 = 45
40 N:
40•4/4 = 40•1 = 40
What would be the likeliest effect of moving the pitchers mound in the MLB closer so that it’s 50 feet from home plate?
The guilty batter will often be removed from the game after charging the mound, though depending on the situation, there may also be a fine or suspension. Discipline for throwing a beanball may also be applied to the pitcher.
Pitchers There were worries that the game was unfairly rigged in favor of the pitcher and was therefore no longer entertaining to watch. In order to assist the batters, the pitching mound was dropped from 15 inches to 10 inches, and the strike zone was restored to its 1961 dimensions.Simple logic underlies the decision to relocate the mound: Pitchers in the modern day stand significantly taller and throw much harder than pitchers in the nineteenth century. As a result, today's batters have less time to react to pitches that are released closer to home plate and move faster toward their targets.For more information on MLB pitchers kindly visit to
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what will happen to the gravition force between two bodies if the distance between them is halved keeping their masses constant
Answer:
The new force will be 4times the original
Express 48 m/s in terms of
1.km/h
2.m/min
3.km/s
4.km/minutes
48 m/s in terms of km/h is 720.8 km/h. In terms of m/min is 2880 m/min, in terms of km/s is 0.048 km/s and in terms of km/min is 2.88 km/min.
To solve this question, we need to understand some terms. The unit of velocity is measured in m/s. It can be expressed in different units of velocity.
1 km (kilometer) = 1000 meter
1 h (hour) = 3600 seconds
1 minutes = 60 seconds
To convert m/s into km/h,
48 m/s * 3600/1000 = 172.8 km/h
To convert m/s into m/min,
48 m/s * 60 = 2880 m/min
To convert m/s into km/s,
48 m/s ÷ 1000 = 0.048 km/s
To convert m/s into km/minutes,
48 m/s * 60 / 1000 = 2.88 km/min
Therefore, the 48 m/s expressed is 172.8 km/h, 2880 m/min, 0.048 km/s and 2.88 km/min.
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48 m/s is equivalent to 172.8 km/h, 2880 m/min, 0.048 km/s, and 2.88 km/minute.
To express 48 m/s in different units of velocity:
km/h (kilometers per hour):
To convert m/s to km/h, we can use the conversion factor of 3.6 since 1 m/s is equal to 3.6 km/h.
48 m/s * (3.6 km/h / 1 m/s) = 172.8 km/h
Therefore, 48 m/s is equivalent to 172.8 km/h.
m/min (meters per minute):
To convert m/s to m/min, we can use the conversion factor of 60 since there are 60 seconds in a minute.
48 m/s * (60 m/min / 1 s) = 2880 m/min
Therefore, 48 m/s is equivalent to 2880 m/min.
km/s (kilometers per second):
Since 1 kilometer is equal to 1000 meters, to convert m/s to km/s, we divide the value by 1000.
48 m/s / 1000 = 0.048 km/s
Therefore, 48 m/s is equivalent to 0.048 km/s.
km/minute (kilometers per minute):
To convert m/s to km/minute, we first need to convert m/s to km/s (as calculated in the previous step) and then multiply by 60 to convert seconds to minutes.
0.048 km/s * 60 = 2.88 km/minute
So, 48 m/s is equivalent to 2.88 km/minute.
Hence, 48 m/s is equivalent to approximately 172.8 km/h, 2880 m/min, 0.048 km/s, and 2.88 km/minute.
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letter “c” is pointing to the force variable in the graph . What letter in physics is used to represent force
Answer:
Explanation:
Newton
The critical temperature the core must reach for a star to shine by fusion is a. 5,800 K b. 11,000 K c. 127,000 K d. 10 million K e. 100 million K.
The critical temperature the core must reach for a star to shine by fusion is 10 million K.
The process by which stars produce energy is through nuclear fusion, in which hydrogen atoms combine to form helium, releasing energy in the process. The temperature and pressure at the star's core must be high enough to initiate and sustain this fusion process.
The minimum temperature required for hydrogen fusion to occur is approximately 10 million K. At this temperature, the hydrogen atoms have enough thermal energy to overcome their electrostatic repulsion and come close enough together for the strong nuclear force to bind them into helium.
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Imagine you want to create a model of Solar system (and beyond) with the Sun
represented by a beach ball of diameter 60 cm = 0.60 m. (i.e. of radius 30 cm = 0.30m). On that same scale:
What is the diameter of the Milky Way?
And the diameter or Radius of Earth
Using the scale model of the Sun given;
The diameter of the Milky Way = 4.28 × 10¹¹ mThe diameter of the Earth = 5.44 × 10⁻³ mWhat is the diameter of the Milky Way?The diameter of the Milky Way is about 1 × 10¹⁸ km.
The diameter of the Sun is about 1.4 × 10⁶ km
The diameter of the Earth is about 1.27 × 10⁴ km.
Using the scale model of the Sun given, the diameter of the Milky Way = (1 × 10¹⁸ km/1.4 × 10⁶ km) × 0.6 m
The diameter of the Milky Way = 4.28 × 10¹¹ m
Using the scale model of the Sun given, the diameter of the Milky Way = (1.27 × 10⁴ km/1.4 × 10⁶ km) × 0.6 m
The diameter of the Earth = 5.44 × 10⁻³ m
In conclusion, the diameter of the Milky Way is far bigger than the Sun while the diameter of the Sun is about 5400 times bigger than the Earth.
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Convert 55 miles into inches
Answer:
3.485e+6 inches. hope this helps
Answer:
What I got was a big number but it got around 3.485e+6
Explanation:
A spring with a spring constant of 100 N/m completes one oscillation in 2.4 seconds. What is the mass attached to the spring?
a. 9.7 kg
b. 14.6 kg
c. 13.3 kg
d. 5.2 kg
e. 12.3 kg
To solve this problem, we can use the formula for the period of oscillation of a spring-mass system:
T = 2π√(m/k)
where T is the period of oscillation, m is the mass attached to the spring, and k is the spring constant.
We are given that T = 2.4 seconds and k = 100 N/m. Substituting these values into the formula, we get:
2.4 = 2π√(m/100)
Squaring both sides and rearranging, we get:
m = (100/4π²) × (2.4²) = 12.3 kg (rounded to one decimal place)
Therefore, the mass attached to the spring is 12.3 kg.
Hi! I'd be happy to help you with your question. To find the mass attached to the spring, we need to use the formula for the period of a spring-mass system: T = 2π√(m/k), where T is the period (time for one oscillation), m is the mass, and k is the spring constant.
In this case, the spring constant (k) is 100 N/m, and the period (T) is 2.4 seconds. We can rearrange the formula to solve for the mass (m):
m = (T^2 * k) / (4π^2)
Substitute the given values into the formula:
m = (2.4^2 * 100) / (4π^2)
m ≈ (5.76 * 100) / (39.48)
m ≈ 14.61
The mass attached to the spring is approximately 14.61 kg.
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Given a force of 100 N and an acceleration of 5 m/s2, what is the mass
Answer:
20 kg
Explanation:
Mass equals force divided by acceleration, so divide 100 N by 5 m/s2 and you get your mass: 20 kg
Answer: m= 20 kg
Explanation: Use the formula
F = m a
to solve this.
100 N = m (5 m/s²)
100 N / (5 m/s²) = m
20 kg = m
(N is also kgm/s², so when you divide by m/s², you are left with kg.)