In the following problem, which is the unknown quantity?
A sample of helium gas has a volume of 546 mL at a pressure of 1.60 atm and a temperature of 137
°C. What is the pressure of the gas in atm when the volume is 657 mL and the temperature is 158°C?
A) P2
B) P1
C) V1
D) V2

The Microscope part and their right descriptions are as follows

Iris Diaphragm: A. Increases or decreases the light intensity

Objective Lens System: B. After light passes through the specimen, it next enters this lens system

Stage: C. Platform that supports a microscope slide

Adjustment Knob: D. Causes stage (or objective lens) to move upward or downward

Condenser: E. Concentrates light onto the specimen

Other parts of a microscope and their description that you should know about includes;

Eyepiece - The lens that you look through to see the image of the specimen.

Body tube - The tube that connects the eyepiece to the objective lenses.

Arm - The part of the microscope that supports the body tube and connects it to the base.

Base - The part of the microscope that supports the arm and provides stability.

Illuminator - The light source that provides light for the microscope.

Stage clips - The clips that hold the microscope slide in place on the stage.

Revolving nosepiece - The part of the microscope that holds the objective lenses and allows them to be rotated into place.

The above answer is in response to the full question below;

Match the names of the microscope parts in column A with the descriptions in column B. Place the letter of your choice in the space provided.

1. Iris diaphram

2. Objective lens system

3. Stage

4. Adjustment knob

5. Condenser

Increases or decreases the light intensity

2. After light passes through the specimen, it next enters this lens system

3. Platform that supports a microscope slide

4. Causes stage (or objective lens) to move upward or downward

5. Concentrates light onto the specimen

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The center of gravity is the same for all passenger vehicles no it is different

The center gravity is the point through which the force of gravity acts on an object or system then in the mechanics problem the gravitational field is assumed to be uniform and the center of gravity is then in exactly the same position as the center of mass and the the center of gravity is the same for all passenger vehicles no it is different because the thermotical point where the sum of all of the masses of each of its individual components effectively act and the center of gravity is low then the stability of vehicle and passenger are more

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Answer:

A ---->gamma ray

Explanation:

Gamma rays have the highest frequencies among all electromagnetic waves and therefore have the shortest wavelengths.

Answer:

protons = atomic numbermass number = protons + neutronsatomic number = mass number - neutrons = 78-38 = 40

Explanation:

The atomic number of an element represents the number of protons in its nucleus.

To determine the atomic number, subtract the number of neutrons from the mass number.

In this case, the mass number is 78, and there are 30 neutrons per atom. So, atomic number = mass number - number of neutrons = 78 - 30 = 48.

Therefore, the element with a mass number of 78 and 30 neutrons per atom has an atomic number of 48. The element with atomic number 48 is cadmium (Cd), which means it has 48 protons in its nucleus.

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To solve this problem, we need to use stoichiometry and the balanced equation for the reaction. From the balanced equation, we see that 4 moles of H2 are required to react with 1 mole of O2 to produce 2 moles of H2O.

1 mole O2 = 32 g O2

8.75 g O2 = 8.75 g / 32 g/mol = 0.2734 moles O2

Using the stoichiometry of the balanced equation, we can determine the moles of H2 needed to react with the given moles of O2:

0.2734 moles O2 × 4 moles H2 / 1 mole O2 = 1.0936 moles H2

Finally, we can convert the moles of H2 to grams using the molar mass of H2:

1.0936 moles H2 × 2 g/mol H2 = 2.1872 g H2

Therefore, the mass of H2 needed to react with 8.75 g of O2 is approximately 2.19 g H2 (to two significant figures).

So, the closest option is O 2.21 g H₂.

Answer:

Explanation:

The balanced chemical equation for the reaction between FeCl and Cl2 is:

2FeCl + Cl2 → 2FeCl3

From the equation, we can see that 1 mole of Cl2 reacts with 2 moles of FeCl. To find the amount of FeCl that reacted when 175.98 grams of Cl2 reacted, we need to follow a few steps:

Calculate the number of moles of Cl2 that reacted:

mass of Cl2 / molar mass of Cl2 = 175.98 g / 70.906 g/mol = 2.479 mol Cl2

Use the mole ratio from the balanced equation to find the number of moles of FeCl that reacted:

2 moles FeCl / 1 mole Cl2 = x moles FeCl / 2.479 moles Cl2

x moles FeCl = 2 moles FeCl / 1 mole Cl2 x 2.479 moles Cl2 = 4.958 moles FeCl

Calculate the mass of FeCl that reacted:

mass of FeCl = moles of FeCl x molar mass of FeCl = 4.958 moles x (55.845 + 35.453) g/mol = 340.3 g

Therefore, 340.3 grams of FeCl reacted when 175.98 grams of Cl2 reacted.

Answer:

100,000

Explanation:

1 kilometer equals 100,000 centimeters

You multiply the length value by 100,000

Answer:

One kilometre is 100,000 centimeters

Explanation:

Answer

Pressure is decreased

Explanation

As the pressure on a gas increases, the volume of the gas decreases because the gas particles are forced closer together. Conversely, as the pressure on a gas decreases, the gas volume increases because the gas particles can now move farther apart.

The following nucleophiles would be considered basic for reaction with an epoxide: NaOH, H2O, CH3ONa, CH3OH, LiAlH4, RMgBr and CH3CC- (alkynyl anion).

Basic nucleophiles are typically more reactive towards epoxides than acidic nucleophiles due to their electron-rich nature, which allows them to attack the highly electrophilic carbon centre of the epoxide ring. Acidic nucleophiles are species that can donate electrons to form a new bond with an electron-deficient center, such as a carbocation or an electrophilic carbon atom.

These nucleophiles can attack the carbon centre of the epoxide and open the ring to form a new alkoxide or alkyne product, depending on the specific conditions and reagents used.

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Answer: Atoms are the smallest particles of an element.

Forest is a habitat for many plants and animals because it provides a suitable environment for them.

Forest is a habitat for many plant life and animals as it offers a appropriate environment for them. As an instance, neem, Sheesham, Palash, tiger, porcupine, elephants, jackal and so forth. The ground beneath the tree of the forest is the forest floor.

It causes habitat destruction, accelerated chance of predation, reduced food availability, and lots greater. As a result, some animals lose their homes, others lose meals assets – and ultimately, many lose their lives. In reality, deforestation is one of the essential causes of extinction.

Weather trade also alters the life cycles of flora and animals. as an instance, as temperatures get warmer, many plant life are starting to develop and bloom earlier inside the spring and live to tell the tale longer into the fall. A few animals are waking from hibernation sooner or migrating at different instances, too.

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Answer:

283.211

Explanation:

Answer:

648.68 mg

Explanation:

The reaction that takes place is:

First we calculate how many moles of each reactant were added, using the given volumes and concentrations:

24 mmol of FeCl₃ would react completely with (24 * 3) 72 mmol of NaOH. There are not as many NaOH mmoles, so NaOH is the limiting reactant.

Now we calculate how many moles of Fe(OH)₃ are formed, using the moles of the limiting reactant:

Finally we convert 6.07 mmol Fe(OH)₃ to grams, using its molar mass:

The 129.6 g mass of Fe(OH)₃ will be obtained.

Weight or mass of any substance can be calculated from mole as:

n = W/M.

Given chemical reaction is:

FeCl₃ + 3NaOH → Fe(OH)₃ + 3NaCl

According to the question:

Concentration of FeCl₃ = 0.240 M

Volume of FeCl₃ = 100 mL

Concentration of NaOH = 0.182 M

Volume of NaOH = 200 mL

Moles can be calculated by using the formula M = n/V mole/L 0r M = n×1000/V g/mL,

Moles of FeCl₃ = 0.240 × 100 = 0.024 mole

Moles of NaOH = 0.182 × 200 = 3.64 mole

From the stoichiometry of the reaction, it is clear that 3 mole of NaOH i.e. 109.2 moles of NaOH reacts with 1 mole of FeCl₃ to form product. So here NaOH is the limiting agent and responsible for the formation of product. Now we calculate how many moles of Fe(OH)₃ are formed, using the moles of the limiting reactant as follow:

Moles of Fe(OH)₃ = 1/3 × ( 3.64) = 1.21 mole

Finally we convert 12.1 mole Fe(OH)₃ to grams, using its molar mass:

W = 1.21 mole × 106.87 g/mole = 129.6 g

Hence, 129.6 gram of Fe(OH)₃ will be obtained.

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Answer:

83

Explanation:

3X + 2Y → 5C + 4D

2 moles of Y will produce 5 moles of C

33.0 moles of Y will produce: 33.0 x 5/2 = 82.5 or 83 moles of C

Answer:

C.) protons and neutrons

Explanation:

Most atoms contain proton(s), neutron(s), and electron(s). Within the nucleus of an atom, there are protons and neutrons. Electrons are located outside of the nucleus.

The true statement  for the quantum mechanical atomic model is that Electrons give off electromagnetic radiation when they jump from a high to a low energy level.

Option c is correct.

The quantum mechanical atomic model, also known as the wave mechanical model, describes the behavior of electrons in atoms as waves.

This model described that only electrons can exist only in certain discrete energy levels around the nucleus. When an electron absorbs energy, it moves to a higher energy level.

In other words, when it loses energy, it moves to a lower energy level.

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Explanation:

add HCl to it.

it will become 1,1-dichloro ethane which is a monomer.

hope this helps.

Answer:

Sulphur + oxygen gives ➙ Sulphur oxide

Explanation:

Sulfur oxide is a compound that consists of sulfur and oxygen molecules. I hope this helps!

Answer:

F⁻(aq) + H₂O(l) ⇄ HF(aq) + OH⁻(aq)

Explanation:

According to Brönsted-Lowry acid-base theory, an acid is a substance that donates H⁺ ions. In this sense, hydrofluoric acid is an acid according to the following equation.

HF(aq) + H₂O(l) ⇄ F⁻(aq) + H₃O⁺(aq)

According to Brönsted-Lowry acid-base theory, a base is a substance that accepts H⁺ ions. In this sense, the fluoride ion is a base according to the following equation.

F⁻(aq) + H₂O(l) ⇄ HF(aq) + OH⁻(aq)

The equilibrium constant for this reaction is Kb = 1.39 × 10⁻¹¹.

1) Volume of oxygen gas produced is 3.19 L ; 2) Volume of gaseous HF produced is 4.92 L ; 3) Pressure of gaseous O₂ produced is 10.0 atm. ; 4) Pressure of gaseous B₂H₆ produced is 6292 mm Hg.5) 34.6 grams of phosphoric acid reacted.

Molar mass can be defined the mass of one mole of substance.

1.) Molar mass of potassium chlorate (KClO₃) is: 39.098 g/mol + 35.453 g/mol + 3 * 15.999 g/mol = 122.549 g/mol

10.5 g KClO₃ * (1 mol KClO₃ / 122.549 g KClO₃) * (3 mol O₂ / 2 mol KClO₃) = 0.1281 mol O₂

As V = (nRT) / P

= (0.1281 * 0.08206 * (25.0 + 273.15) ) / 1.05

So V = 3.19 L

Therefore, the volume of oxygen gas produced is 3.19 L.

2.) Molar mass of calcium fluoride (CaF₂) is: 40.078 g/mol + 2 * 18.998 g/mol = 78.076 g/mol

8.5 g CaF₂ * (1 mol CaF₂ / 78.076 g CaF₂) * (2 mol HF / 1 mol CaF₂) = 0.2171 mol HF

V = (0.2171  * 0.08206 / * 292.15 ) / 1.124

V = 4.92 L

Therefore, volume of gaseous HF produced is 4.92 L.

3.) Molar mass of HgO = 200.59 g/mol

125 g HgO = 125/200.59 = 0.623 mol HgO

From the balanced equation, 2 moles of HgO produces 1 mole of O₂

Therefore, 0.623 mol HgO produces 0.3115 mol O₂

As P = nRT/V

= (0.3115 mol)(0.08206 )(394.15 )/(9.61 )

P = 10.0 atm

Therefore, pressure of gaseous O₂ produced is 10.0 atm.

4. Molar mass of NaBH₄ = 37.83 g/mol

25.0 g NaBH₄ = 25.0/37.83 = 0.661 mol NaBH4

From the balanced equation, 2 moles of NaBH₄ produces 1 mole of B₂H₆

Therefore, 0.661 mol NaBH₄ produces 0.3305 mol  B₂H₆

As P = nRT/V

= (0.3305 )(0.08206 )(289.15 )/(8.10 )

P = 8.29 atm

8.29 atm = 6292 mm Hg

Therefore, pressure of gaseous  B₂H₆ produced is 6292 mm Hg.

5.) As n = PV/RT

n = (1.00 )(24.3 )/(0.0821 )(273 ) = 1.06 mol CO₂

1.06 mol CO₂ × (1 mol H₃PO₄/3 mol CO2) = 0.353 mol H₃PO₄

Molar mass of H₃PO₄ is 98.0 g/mol; so 0.353 mol H₃PO₄ × (98.0 g H₃PO₄/mol) = 34.6 g H₃PO₄

Therefore, 34.6 grams of phosphoric acid reacted.

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Answer:

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

\(n = \frac{N}{L} \\ \)

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

\(n = \frac{3.01 \times {10}^{23} }{6.02 \times {10}^{23} } = \frac{3.01}{6.02} \\ \)

We have the final answer as

Hope this helps you

Answer:

A Intrusive

Explanation:

I go to K12 and they say that's the answer

Hope it is Helpful to you

The number of atoms in the 0.940 grams P₂O₅ is equal to 3.4 × 10²¹ atoms.

Avogadro’s number is the number of particles in one mole of any substance or element. Generally, these entities can be atoms, molecules, ions, protons, or electrons, depending upon the kind of chemical reaction or reactant and product.

The Avogadro’s constant is experimentally found approximately equal to 6.022 × 10²³ mol⁻¹.

Given, the amount of phosphorous oxide, P₂O₅ = 0.940 g

The molecular mass of the phosphorous oxide, P₂O₅ = 141.95 g/mol

It means that 141.95 g of  P₂O₅ contains atoms = 6.022 × 10²³

Then 0.940 g of P₂O₅ will contain atoms = (0.940/141.95) × 6.022 × 10²³

= 0.034 × 10²³ atoms

= 3.4 × 10²¹ atoms

Therefore, the atoms in the 0.940 grams P₂O₅ are 3.4 × 10²¹ atoms.

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The element nitrogen exists as a gas  and is  obtained from air on a large scale​ by fractional distillation of air.

An element is defined as a substance which cannot be broken down further into any other substance. Each element is made up of its own type of atom. Due to this reason all elements are different from one another.

Elements can be classified as metals and non-metals. Metals are shiny and conduct electricity and are all solids at room temperature except mercury. Non-metals do not conduct electricity and are mostly gases at room temperature except carbon and sulfur.

The number of protons in the nucleus is the defining property of an element and is related to the atomic number.All atoms with same atomic number are atoms of same element.

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Answer

1.88 grams

Explanation

Given:

3H2(g) + N2(g) ----> 2NH3(g)

Volume of NH3(g) = 3 L

What to find:

The grams of N2(g) required.

Step-by-step solution:

From this balanced equation, 3 moles of H2(g) react with 1 mole N2(g) to produce 2 moles NH3(g).

That can also mean 3 liters of H2(g) reacts with 1 liter N2(g) to produce 2 liters of NH3(g).

Thus, if it takes 1 liter of N2(g) to produce 2 liters of NH3(g),

Then it will take x liters of N2(g) to produce 3 liters of NH3(g)

To get x, cross multiply and divide both sides by 2 liters NH3(g):

1.5 liters of N2(g) are required to produce 3 L of NH3(g).

The final step is to convert 1.5 liters of N2(g) to grams.

1 mole of N2(g) occupies 22.4 L at STP

Note: 1 mole of N2(g) = 28.01 g

Thus, if 28.01 grams N2(g) occupies 22.4 L at STP

Then the mass of N2(g) in 1.5 L of N2(g) is:

Therefore, the grams of N2(g) required to 3L of NH3(g) is 1.88 grams

Answer: The half-reactions represents reduction are as follows.

Explanation:

A half-reaction where addition of electrons take place or a reaction where decrease in oxidation state of an element  takes place is called reduction-half reaction.

For example, the oxidation state of Cr in \(Cr_{2}O^{2-}_{7}\) is +6 which is getting converted into +3, that is, decrease in oxidation state is taking place as follows.

\(Cr_{2}O^{2-}_{7} + 3 e^{-} \rightarrow Cr^{3+}\)

Similarly, oxidation state of Mn in \(MnO^{-}_{4}\) is +7 which is getting converted into +2, that is, decrease in oxidation state is taking place as follows.

\(MnO^{2-}_{4} + 5 e^{-} \rightarrow Mn^{2+}\)

Thus, we can conclude that half-reactions represents reduction are as follows.

At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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Answer:

Attached picture.

Explanation:

(1) Ksp equals the product of [Co 2+][CO3 2-]. CoCO3 is excluded from the equilibrium expression because it is a pure solid. The mole ratio of Co 2+ and CO3 2- is 1:1 so their molar solubilities are the same.

(2) There is an initial concentration of 0.10 M Co 2+ so write that in the "I" row for Co 2+ on the ICE table. When you find the zeros of the quadratic when solving for "s", take the positive value rather than the negative value because concentration cannot be negative.

(3) Extra products will cause the equilibrium to consume products and form reactants. So the reverse reaction will occur faster than the forward reaction. More products mean an increased Q value compared to K, since the numerator of \(K = \frac{[products]}{[reactants]}\) increases.

Answer:

The three primary colors used when mixing dyes or paints are red, yellow, and blue. Other colors are often a mixture of these three colors. Try running a chromatography test again with non-primary-color markers, like purple, brown, and orange.

Explanation: