Let the number be x.
Then, the expression looks like this
\(4x + {x}^{2} \)
Answer:4x+x^2
What is the missing step in solving the inequality 4(x – 3) + 4 < 10 + 6x?
1. The distributive property: 4x – 12 + 4 < 10 + 6x
2. Combine like terms: 4x – 8 < 10 + 6x
3. The addition property of inequality: 4x < 18 + 6x
4. The subtraction property of inequality: –2x < 18
5. The division property of inequality: ________
x < –9
x > –9
x < x is less than or equal to negative StartFraction 1 Over 9 EndFraction.
x > –x is greater than or equal to negative StartFraction 1 Over 9 EndFraction.
The missing step in solving the inequality 4(x – 3) + 4 < 10 + 6x is step 6: The division property of inequality: x > -9
How to find the missing stepThe missing step in solving the inequality 4(x – 3) + 4 < 10 + 6x is step 6: The division property of inequality.
After step 4, which is -2x < 18, we need to divide both sides of the inequality by -2 to solve for x.
However, since we are dividing by a negative number, the direction of the inequality sign needs to be reversed.
Dividing both sides by -2:
-2x / -2 > 18 / -2
This simplifies to:
x > -9
Therefore, the correct answer is x > -9.
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in a hand of 13 cards drawn randomly from a pack of 52, find the chance of: a) no court cards (j, q, k, a); b) at least one ace but no other court cards; c) at most one kind of court card.
a) The chance of drawing no court cards (J, Q, K, A) in a hand of 13 cards randomly drawn from a pack of 52 is approximately 0.294. b) The chance of drawing at least one ace but no other court cards in a hand of 13 cards is approximately 0.089. c) The chance of drawing at most one kind of court card (J, Q, K, A) in a hand of 13 cards is approximately 0.633.
a) To find the chance of drawing no court cards, we need to determine the number of favorable outcomes and divide it by the total number of possible outcomes. In this case, there are 36 non-court cards (52 cards - 16 court cards), and we want to draw 13 cards without any court cards. The probability can be calculated using the formula:
Probability = (number of favorable outcomes) / (total number of possible outcomes)
The number of favorable outcomes is the number of ways to choose 13 cards from the 36 non-court cards, which can be calculated using combinations. Thus, the probability is:
Probability = C(36, 13) / C(52, 13) ≈ 0.2936
b) To find the chance of drawing at least one ace but no other court cards, we need to determine the number of favorable outcomes and divide it by the total number of possible outcomes. There are 4 aces in the deck, and we want to draw at least one of them along with 12 non-court cards (36 non-court cards - 4 aces).
The probability can be calculated using the formula:
Probability = (number of favorable outcomes) / (total number of possible outcomes)
For drawing two aces, there are C(4, 2) ways to choose two aces and C(36, 11) ways to choose the remaining non-court cards.
Thus, the probability is:
Probability = [C(4, 1) * C(36, 12) + C(4, 2) * C(36, 11)] / C(52, 13) ≈ 0.0892
c) To find the chance of drawing at most one kind of court card, we need to determine the number of favorable outcomes and divide it by the total number of possible outcomes. There are 4 court cards of each kind (J, Q, K, A), and we want to draw at most one kind of court card.
The probability can be calculated using the formula:
Probability = (number of favorable outcomes) / (total number of possible outcomes)
The number of favorable outcomes is the sum of three cases: drawing no court cards, drawing only one kind of court card, and drawing one court card of each kind. We have already calculated the probability of drawing no court cards in part (a).
Thus, the probability is:
Probability = [C(36, 13) + 4 * C(36, 13) + 4 * C(36, 12)] / C
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To find the chances in a hand of 13 cards drawn randomly from a pack of 52, we can use probability. The chance of no court cards can be calculated using combinations. The probability of at least one ace but no other court cards can be found by subtracting the probability of no aces from the probability of no court cards. The probability of at most one kind of court card can be calculated by finding the probability of having zero court cards and one court card.
Explanation:To find the chances in a hand of 13 cards drawn randomly from a pack of 52, we can use probability.
a) No court cards:
There are 12 court cards (J, Q, K, A) in a deck of 52 cards. So, to have no court cards in a hand, we need to select all 13 cards from the remaining 40 non-court cards. The probability can be calculated as 40C13/52C13.
b) At least one ace but no other court cards:
To find this probability, we need to subtract the probability of having no aces from the probability of having no court cards. The probability of having no aces is 48C13/52C13, and the probability of having no court cards is 40C13/52C13. The result is the difference between these two probabilities.
c) At most one kind of court card:
To find the probability of having at most one kind of court card, we can calculate the probability of having zero court cards or one court card. The probability of having zero court cards can be calculated as 40C13/52C13, and the probability of having one court card can be calculated as 12C1 * 40C12/52C13. The sum of these two probabilities gives the probability of having at most one kind of court card.
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Which integer is least -4 or 2
Answer: -4 is the least
Step-by-step explanation:
in the morning, a group of hikers hiked 4 7/8 miles, took a break, and then hiked 1 1/2 miles. The group then stopped for lunch. In the afternoon, the group hiked 3 5/6 miles, took a break, and then hiked 2 7/12. Which following statements are true?
A. The hikers 3/24 hiked mile more in the afternoon than in the morning
B. The hikers hiked 3/24 mile more in the morning than in the afternoon
C. The hikers hiked the same number of miles in the morning as in the afternoon
D. The hikers hiked 5 9/11 miles in the morning
Please provide step by steps for solving the problem.
You cross the finish line of a race and the first thing you do is to look ahead to see how many people finished in front of you, and then you look behind to see how many people you beat. You are gathering information for your __________ via the use of __________.
While you look behind to see how many people you beat, you are gathering information for your Competitive intelligence via the use of social comparison.
Competitive intelligence is a process of learning as much as possible outside oneself to increase one's competition level.
It tells us about our position in the competition or market .it helps in self-improvement and skill development.
Social comparison helps in determining our own worth in society.
You are gathering information for your Competitive intelligence via the use of social comparison.
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The enrollment for a school in 2010 was 1510 students. In 2020, the enrollment was 860 students. Find and interpret the rate of change in enrollment from 2010 to 2020.
Then the enrollment change rate from 2010 to 2020 is -52.2%.
What is rate of change?A rate of change is the rate at which one quantity changes in relation to another. For example, Change in y = change in x = change in distance = change in time.Here ,
Formulate 860 - 1510 / 1510 based on the given condition.
We have calculate the difference or sum = -650/1245
By converting a fraction to a decimal we get, = -0.52208
we have to multiply a number by its numerator and denominator by 100,
We get,
= -0.52208*100/100
-52.208/100 is the product or quotient.
Hence ,
In 2010, a school had 1510 students enrolled. In 2020, there will be 860 students enrolled. Then the enrollment change rate from 2010 to 2020 is -52.2%.
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answer for p=2l+2w for l
Answer:
\(I=\frac{p-2w}{2}\)
Step-by-step explanation:
\(p=2I+2w\\\\p-2w=2I+2w-2w\\\\p-2w=2I\\\\\frac{p-2w}{2}= I\)
Damian estimated that Lily would play puzzles
for 20 minutes, but she actually played for 38
minutes.
What was his percent error?
Damian's percent error for the estimate of the time that Lily would play is of 47.37%.
How to obtain the percent error?The percent error is obtained applying the proportions in the context of the problem.
A proportion is applied as the percent error is given by the difference between the estimate and the actual value, divided by the actual value, and multiplied by 100%.
The parameters for this problem are given as follows:
Estimate of 20 minutes.Actual value of 38 minutes.Hence the percent error is given as follows:
P = (38 - 20)/38 x 100%
P = 47.37%.
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\(solve \: \\ \\ find \: the \: area \: of \: rectangle \: \\ \\ length = 11cm \\ \\ width = 9cm\)
Area = l ×b
\(a = l \times b \\ a = 11 \times 9 \\ a = 99\)
1. The summary statistics for the number of inches of rainfall in Los Angeles for 117 years, beginning in 1877, are shown below.
N MEAN MEDIAN TRMEAN STDEV SE MEAN
117 14.941 13.070 14.416 6.747 0.624
MIN MAX Q1 Q3
4.850 38.180 9.680 19.250
(a) Describe a procedure that uses these summary statistics to determine whether there are outliers.
(b) Are there outliers in these data? Justify your answer based on the procedure that you described in part (a).
(c) The news media reported that in a particular year, there were only 10 inches of rainfall. Use the information provided to comment on this reported statement.
Answer: a
Step-by-step explanation:
Here is a table giving the number of US households (in thousands) in 2013 by tenure and insurance status:
Insurance status
Owns home
Rents home
Insured
71
13
Uninsured
5
27
Find the marginal distribution of tenure in counts.
Owns home:
Rents home:
The marginal distribution of tenure in counts who owns a home is 76, while those who rent a home is 40.
What is Addition?The addition is one of the four fundamental mathematical operations, the others being subtraction, multiplication, and division. When two whole numbers are added together, the total quantity or sum of those values is obtained.
For the given data the table can be made as shown below. The marginal distribution of tenure in counts can be calculated as,
Owns home = 71 + 5 = 76
Rents home = 13 + 27 = 40
Hence, The marginal distribution of tenure in counts who owns a home is 76, while those who rent a home is 40.
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3.35x + 115 = 3.25x + 125
For the given expression 3.35x + 115 = 3.25x + 125 the value of x is 100.
What is an equation?A mathematical statement known as an equation is made up of two expressions joined together by the equal sign.
A formula would be 3x - 5 = 16, for instance. When this equation is solved, we discover that the value of the variable x is 7. Two expressions are combined in an equation using an equal symbol ("="). The "left-hand side" and "right-hand side" of the equation are the two expressions on either side of the equals sign. Typically, we consider an equation's right side to be zero.
The given expression is:
3.35x + 115 = 3.25x + 125
Regroup all the terms with variable x on one side of the equation:
3.35x - 3.25x = 125 - 115
0.1x = 10
x = 100
Hence, for the given expression 3.35x + 115 = 3.25x + 125 the value of x is 100.
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11. (a) If D, M and S are the numbers of sexagesimal degrees, minutes and seconds of a angle then show that 3600D = 60M = S
Both M and S in sexagesimal notation = 3600D.
Here converting 'D' into minutes.
We know that a degree is made up of 60 minutes.
so multiply D with 60 we get
⇒ D x 60 = M
Now convert 'M' into seconds.
Again, there are 60 seconds in a minute,
so multiply M with 60 we get,
⇒ M x 60 = S
Simplify this equation by substituting D x 60 for M,
⇒D x 60 x 60 = S
Simplifying further, we get,
⇒ 3600D = S
Hence, 3600D is equal to both M and S in sexagesimal notation.
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Can anyone help me with 6 and 10 please . I am begging . I’ll mark as brainliest and give extra free pts .
Answer:
6) 0.4498 J (not 100% sure on this one)
10) 0.0001 km
Step-by-step explanation:
Not much, just converting :D
Answer:
44.98 cj= .4498j
86.663mm= .000086663 km
Step-by-step explanation:
Hope that helps:)
Determine the, LCM, of the following three terms: 3st,4s2,5t2
60 s²t² is the lowest common multiple of 3st, 4s^2, 5t^2
Finding the LCM of expressionsLCM is known as the lowest common multiple. This is the smallest number that is a multiple of both of two numbers is called the least common multiple.
Given the terms 3st, 4s^2, 5t^2
Find the factors
3st = 3 * s * t
4s² = 4 * s * s
5t² = 5 * t * t
The LCM is calculated as thus:
LCM = (3*4*5) * s²t²
LCM = 60 s²t²
Hence the LCM of the terms 3st, 4s^2, 5t^2 is 60 s²t²
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Which image shows the correct position of M(-4, 3)?
A.
graph A
B.
graph B
C.
graph C
D.
graph D
A i did it I got an A+
Which algebraic expression is a polynomial with a degree of 4?
Answer:
for ponits
Step-by-step explanation:
Sixty-four percent of voters in a very large electorate support candidate Smith in an upcoming election. A student employee working the evening shift at a telephone survey facility calls voters at random and asks them which candidate they prefer. a. What is the probability that, among five voters the student calls, exactly one supports candidate Smith? b. What is the probability that, among five voters the student calls, at least one supports candidate Smith? c. What is the probability that the first voter supporting candidate Smith is reached on the fifth call, i.e., what is the probability that it takes the student five calls to reach the first voter who supports candidate Smith? d. What is the probability that the third voter supporting candidate Smith is reached on the fifth call, i.e., what is the probability that it takes the student five calls to reach three voters who supports candidate Smith?
The probabilities are calculated assuming independence of each call and that the success probability remains constant throughout the calls.
a. The probability that, among five voters the student calls, exactly one supports candidate Smith can be calculated using the binomial probability formula. With a success probability of 64% (0.64) and exactly one success (k = 1) out of five trials (n = 5), the probability can be calculated as follows:
\[
P(X = 1) = \binom{5}{1} \times (0.64)^1 \times (1 - 0.64)^4
\]
The calculation results in approximately 0.369, or 36.9%.
b. The probability that, among five voters the student calls, at least one supports candidate Smith can be calculated as the complement of the probability that none of the voters support Smith. Using the binomial probability formula, with a success probability of 64% (0.64) and no success (k = 0) out of five trials (n = 5), the probability can be calculated as follows:
\[
P(X \geq 1) = 1 - P(X = 0) = 1 - \binom{5}{0} \times (0.64)^0 \times (1 - 0.64)^5
\]
The calculation results in approximately 0.997, or 99.7%.
c. The probability that the first voter supporting candidate Smith is reached on the fifth call can be calculated as the probability of not reaching a Smith supporter in the first four calls (0.36) multiplied by the probability of reaching a Smith supporter on the fifth call (0.64):
\[
P(\text{{First Smith Supporter on Fifth Call}}) = (1 - 0.64)^4 \times 0.64
\]
The calculation results in approximately 0.014, or 1.4%.
d. The probability that the third voter supporting candidate Smith is reached on the fifth call can be calculated as the probability of reaching two Smith supporters in the first four calls (0.64 for the first call, 0.36 for the second call, and 0.36 for the third call) multiplied by the probability of reaching a Smith supporter on the fifth call (0.64):
\[
P(\text{{Third Smith Supporter on Fifth Call}}) = (0.64)^2 \times (1 - 0.64) \times 0.64
\]
The calculation results in approximately 0.147, or 14.7%.
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The probabilities are calculated assuming independence of each call and that the success probability remains constant throughout the calls. The calculation results in approximately 0.369, or 36.9%.
a. The probability that, among five voters the student calls, exactly one supports candidate Smith can be calculated using the binomial probability formula. With a success probability of 64% (0.64) and exactly one success (k = 1) out of five trials (n = 5), the probability can be calculated as follows:
[P(X = 1) = \binom{5}{1} \times (0.64)^1 \times (1 - 0.64)^4\]
The calculation results in approximately 0.369, or 36.9%.
b. The probability that, among five voters the student calls, at least one supports candidate Smith can be calculated as the complement of the probability that none of the voters support Smith. Using the binomial probability formula, with a success probability of 64% (0.64) and no success (k = 0) out of five trials (n = 5), the probability can be calculated as follows:
[P(X \geq 1) = 1 - P(X = 0) = 1 - \binom{5}{0} \times (0.64)^0 \times (1 - 0.64)^5\]
The calculation results in approximately 0.997, or 99.7%.
c. The probability that the first voter supporting candidate Smith is reached on the fifth call can be calculated as the probability of not reaching a Smith supporter in the first four calls (0.36) multiplied by the probability of reaching a Smith supporter on the fifth call (0.64):
\[
P(\text{{First Smith Supporter on Fifth Call}}) = (1 - 0.64)^4 \times 0.64
\]
The calculation results in approximately 0.014, or 1.4%.
d. The probability that the third voter supporting candidate Smith is reached on the fifth call can be calculated as the probability of reaching two Smith supporters in the first four calls (0.64 for the first call, 0.36 for the second call, and 0.36 for the third call) multiplied by the probability of reaching a Smith supporter on the fifth call (0.64):
\[
P(\text{{Third Smith Supporter on Fifth Call}}) = (0.64)^2 \times (1 - 0.64) \times 0.64
\]
The calculation results in approximately 0.147, or 14.7%.
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A group of seniors decide to spend their spring break away from home, attending at least one major event. The following table summarizes their preferences.
Attend a concert Attend a festival
Stay in state
214
186
Travel out of state 391
59
What percent want to attend a festival, given that they want to travel out of state?
6.94%
13.11%
24.08%
31.72%
The percentage of those who want to attend a festival given that they want to travel out of state is 24.08%.
What is the percent?
Percentage is the fraction of an amount expressed as a number out of hundred. The sign that represents percentages is %. Percentage is a measure of frequency.
Percentage of those who want to attend a festival given that they want to travel out of state =
(Number of those that are attending the festival and travelling out of state / total number of people that attend the festival) x 100
total number of people that attend the festival = 186 + 59 = 245
(59 / 245) x 100 = 24.08%
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Look at this diagram:If KM and NP are parallel lines and m
Answer
Angle NOL = 70°
Explanation
Alternate angles are angles that are in opposite positions relative to a transversal intersecting two lines. If the two lines are parallel to each other, then alternate angles are equal.
We can see that Angle MLO and Angle NOL are alternate angles.
And since we have been told that KM and NP are parallel lines,
Angle NOL = Angle MLO = 70°
Hope this Helps!!!
Rotate (-3,-7) about the origin 90 degreses
The point (-3,-7) rotated 90 degrees counterclockwise about the origin is (7,-3).
To rotate a point about the origin by 90 degrees counterclockwise, we can use the following transformation matrix:
| 0 -1 |
| 1 0 |
To apply this transformation to the point (-3,-7), we can represent the point as a column vector and multiply it by the transformation matrix:
| 0 -1 | | -3 | | 7 |
| 1 0 | * | -7 | = | -3 |
So the rotated point is (7,-3).
Therefore, the point (-3,-7) rotated 90 degrees counterclockwise about the origin is (7,-3).
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What are some 3 out of the six questions you can ask about the statistical validity of a bivariate correlation? Do all the statistical validity questions apply the same way when bivariate correlations are represented as bar graphs? Explain.
Three out of six questions that you can ask about the statistical validity of a bivariate correlation are: All the statistical validity questions do not apply in the same way when bivariate correlations are represented as bar graphs because statistical validity questions address issues of internal validity (causality) rather than issues of external validity (generalizability).
Statistical validity questions are concerned with establishing whether the relationship between the two variables is likely to be a true relationship or just a chance occurrence. Statistical validity can be assessed by determining whether the correlation coefficient is statistically significant (i.e., whether the relationship observed is likely to be a true relationship or just a chance occurrence) and the strength of the correlation.
Statistical significance testing requires a large sample size, and as a result, the correlation coefficient may be statistically significant even if the effect size is small. Therefore, it is important to consider both statistical significance and effect size when evaluating the statistical validity of a bivariate correlation.
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what is multiplying polynomials calculator?
A multiplying polynomials calculator is a tool used to multiply two or more polynomials together.
A multiplying polynomials calculator is a tool used to multiply two or more polynomials together. It can be helpful for simplifying algebraic expressions, solving equations, and performing various calculations in mathematics and engineering.
The calculator takes the coefficients of each polynomial as input and uses the distributive property to multiply the terms of each polynomial together. It then combines like terms and arranges the result in descending order of degrees. Multiplying polynomials can be a tedious and error-prone process, especially for large polynomials, so using a calculator can save time and reduce the chances of errors. The multiplying polynomials calculator is commonly used by students, teachers, engineers, and anyone working with algebraic expressions.
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Performance Matters
Question 17 of 24
Submit Test
- T-Math-GreReg-T5andTS-CBT
Question 1-17
Dana recorded the number of days her brother wore sneakers to school and the number of days he wore loafers to school The ratio of the number of days he wore sneakers
school to the number of days the wore loafers to school was 5 to 2
Dana observed and recorded her brother's choice of shoes for 49 days, how many times did the wear sneakers to school to the number of days her brother wore sneakers to the number of days he wore loafers to school was 5 to 2 if Dana observed and recorded her brothers choice of shoes for 49 days how many times did he wear sneakers
Dana's brother wore sneakers for 35 days out of the 49 days observed by Dana.
How to solve thisIf the ratio of the number of days her brother wore sneakers to school to the number of days he wore loafers to school was 5 to 2, we can assume that he wore sneakers for 5x days and loafers for 2x days, for some positive integer x.
We know that the total number of days observed by Dana is 49, so we can set up the following equation to solve for x:
5x + 2x = 49
Simplifying the left side of the equation, we get:
7x = 49
Dividing both sides by 7, we get:
x = 7
Therefore, her brother wore sneakers for 5x = 5(7) = 35 days out of the 49 days observed by Dana.
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Is the union of countably infinite sets countable?
The answer is that it depends on the specific countable sets being considered and how they are being combined.
The union of countably infinite sets can be countable, as in the case of the union of all positive integers and all negative integers, which is also countable.
However, the union of countably infinite sets can also be uncountable. For example, consider the union of all the intervals [n, n+1) for n = 1, 2, 3, .... Each of these intervals is countable (since it contains all the real numbers between two integers, which is a countable set), but the union of these intervals is the uncountable set of all real numbers greater than or equal to 1. Therefore, the union of these countably infinite sets is uncountable.
So the answer is that it depends on the specific countable sets being considered and how they are being combined.
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What are the solution (s) of the equation? -4x^(4)+25x^(2)+75x=-5x^(4)-3x^(3) The solution (s) i(s)/(a)re
The solution(s) of the equation are x = 0 and the solutions of the cubic equation x^(3)+3x^(2)+25x+75 = 0.
The solution(s) of the equation can be found by rearranging the terms and then factoring. Here are the steps:
Step 1: Rearrange the terms to have all the x terms on one side of the equation:
-4x^(4)+25x^(2)+75x+5x^(4)+3x^(3) = 0
Step 2: Combine like terms:
x^(4)+3x^(3)+25x^(2)+75x = 0
Step 3: Factor out the common factor of x:
x(x^(3)+3x^(2)+25x+75) = 0
Step 4: Use the zero product property to find the solutions:
x = 0 or x^(3)+3x^(2)+25x+75 = 0
The first solution is x = 0. The other solutions can be found by solving the cubic equation x^(3)+3x^(2)+25x+75 = 0. This equation does not have any rational solutions, so the solutions will be irrational or complex.
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The sum of two times a number and four
ABCD is a trapezoid with midsegment EF, and segment lengths AB=9x + 3, CD = 4x+7, and EF = 5x + 13. segments AB and CD are parallel, find the value of X show work to recieve credit.
Using the trapezoid midsegment theorem, the value of x is: 16/3.
How to Apply the Trapezoid Midsegment Theorem?According to the trapezoid midsegment theorem, we have equation below that can be used to solve the value of x:
Length of EF = 1/2(AB + CD).
Given the following:
AB = 9x + 3
CD = 4x + 7
EF = 5x + 13
Therefore:
5x + 13 = 1/2(9x + 3 + 4x + 7)
5x + 13 = 1/2(13x + 10)
2(5x + 13) = 13x + 10
10x + 26 = 13x + 10
10x - 13x = -26 + 10
-3x = -16
-3x/-3 = -16/-3
x = 16/3
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Which of the following are complete eigenvalues for the indicated matrix? What is the (a) 3, († 2), 0 0 1 1 1 1 -1 0 2 -1 0 0 -4 -1 4 -4 0 3 1 0 0 1 -1 1 10 -1 1 0 1 1 0 0 1 - 1 -1 -1 1 b) 2 1 2 0 2 0 0 -1 1 1 (c) 1, 1 1 (d) 1, (e) -1, 1 0 dimension of the associated eigenspace?
There are two free variables, so the dimension of the eigenspace is 2. So the dimensions of the associated eigenspaces are 2 for all three eigenspace.
To determine which of the given values are complete eigenvalues, we need to find the characteristic polynomial of the matrix. This is done by finding the determinant of (A - λI), where A is the matrix and λ is the eigenvalue:
| 3-λ 2 0 -4 1 |
| 0 1-λ 3 1 0 |
| 1 -1 -1-λ 4 0 |
| -1 0 2 -4-λ 0 |
| 1 1 -1 0 1-λ|
Expanding along the first row, we get:
(3-λ) | 1-λ 3 1 0 |
|-1 2-λ 4 0 |
|1 -1 -4-λ 0 |
|1 -1 0 1-λ |
= (3-λ)[(2-λ)(1-λ)(1-λ) + 4(-1)(1-λ) + 0(4-λ)] - (-1)[(1-λ)(1-λ)(4-λ) + 0(1-λ) + 0(-1)] + (1)[(1-λ)(4-λ)(0) - (2-λ)(1-λ)(-1)] - (1)[(1-λ)(-1)(-1) - (2-λ)(-1)(0)]
= (3-λ)[λ^3 - 6λ^2 + 9λ - 4] + (λ-1)[4λ^2 - 10λ + 6] + (λ-1)(λ-4) - (λ-2)
= λ^5 - 11λ^4 + 44λ^3 - 78λ^2 + 60λ - 16
Now we can check which of the given values satisfy the characteristic polynomial:
(a) 3, († 2), 0, 1
Substituting each value into the polynomial, we get:
3^5 - 11(3^4) + 44(3^3) - 78(3^2) + 60(3) - 16 = 0
2^5 - 11(2^4) + 44(2^3) - 78(2^2) + 60(2) - 16 ≠ 0
0^5 - 11(0^4) + 44(0^3) - 78(0^2) + 60(0) - 16 ≠ 0
1^5 - 11(1^4) + 44(1^3) - 78(1^2) + 60(1) - 16 = 0
So the complete eigenvalues for this matrix are 3, 0, 1.
To find the dimension of the associated eigenspace for each eigenvalue, we need to find the nullspace of (A - λI). For each eigenvalue, we can do this by row reducing the matrix (A - λI) and finding the number of free variables. The dimension of the associated eigenspace is then equal to the number of free variables.
(a) λ = 3:
| 0 -1 1 1 -1 |
| 0 -2 4 0 1 |
| 1 -1 -4 2 1 |
|-1 0 2 -7 1 |
| 1 1 -1 0 -2 |
RREF:
| 1 0 -2 0 0 |
| 0 1 -2 0 0 |
| 0 0 0 1 0 |
| 0 0 0 0 1 |
| 0 0 0 0 0 |
There are two free variables, so the dimension of the eigenspace is 2.
(a) λ = 0:
| 3 2 0 -4 1 |
| 0 1 3 1 0 |
| 1 -1 -1 4 0 |
|-1 0 2 -4 0 |
| 1 1 -1 0 1 |
RREF:
| 1 0 -2 0 0 |
| 0 1 -2 0 0 |
| 0 0 0 1 0 |
| 0 0 0 0 0 |
| 0 0 0 0 0 |
There are two free variables, so the dimension of the eigenspace is 2.
(a) λ = 1:
| 2 2 0 -4 1 |
| 0 0 3 1 0 |
| 1 -1 -2 4 0 |
|-1 0 2 -5 1 |
| 1 1 -1 0 0 |
RREF:
| 1 0 -1 0 0 |
| 0 1 -1 0 0 |
| 0 0 0 1 -1 |
| 0 0 0 0 0 |
| 0 0 0 0 0 |
There are two free variables, so the dimension of the eigenspace is 2.
So, the dimensions of the associated eigenspaces are 2 for all three eigenvalues.
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pls help I don't understand
Answer:
C
Step-by-step explanation:
Factor out the polynomial.
Because the last number is negative this tells you one of the factors is negative and the other is positive.
Then you should look at what numbers can multiply together to equal -32, then see if those numbers add to equal positive 4.
The only numbers that satisfy the equation are (x-4)(x+8).
Answer:
C and F. Message if you have any questions.
Step-by-step explanation:
Due to the -32 in the equation, we know it must be a subtraction and addition immediately. We also know the two numbers must multiply together to equal negative 32. Which looks like every option. Lastly, the middle term, 4X means that when the two numbers are added together they equal 4, so that removes the option of all 16 and 2 options. 8 needs to be positive due to it being +4, so the answer is C and F.