how is this possible?​

Answer:

battery pack is transferring its energy to Mila's phone. The potential energy of the battery converts to electrical energy for Mila's phone

Explanation:

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The spinning tube of air created by winds moving in opposite directions to tip upwards and become vertical because of the updraft of wind in a supercell. Hence, option (A) is correct.

As a deep, continuously revolving updraft known as a mesocyclone, a supercell is a type of thunderstorm. This causes these storms to occasionally be called spinning thunderstorms.

Supercells, which are the least frequent and have the potential to be the most severe of the four types of thunderstorms (supercell, squall line, multi-cell, and single-cell), are the least common overall.

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The statement "The effective length of an open globe valve in a 12-inch nominal pipe is 100 ft" is false because it cannot be measured in feet, as it refers to the length attributed to the valve for calculating pressure drop and flow characteristics in the piping system. Instead, it is measured in equivalent length, which is a multiple of the pipe diameter.

Globe valves are designed to control the flow of fluids in a piping system. They have a spherical body and consist of a movable disc or plug that regulates the flow by adjusting the size of the valve's opening. The effective length of a valve, expressed as equivalent length, represents the added resistance it introduces to the fluid flow, comparable to an additional length of straight pipe.

In a piping system, equivalent lengths of valves and fittings are added to the actual pipe lengths to estimate the total resistance to fluid flow, enabling accurate calculations of pressure drop and flow rates. The equivalent length of an open globe valve is typically much greater than that of other valve types, like gate or ball valves, due to its more significant flow resistance. However, it is essential to note that the effective length of a globe valve is not measured in feet but in equivalent length based on the pipe diameter.

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Answer: Speed of light in air is more than speed of light in water, which means water is optically denser than air.

Answer:

There

Explanation:

A medium is denser when the speed of light gets reduced when light travels through that medium. When water travels through water, its speed gets reduced. Hence, it is a optically denser medium. Speed of light in air is more than speed of light in water, which means water is optically denser than air.

Answer:

natural is the answer

Friction is a natural force which exist

The correct option is D, The process that was added to our theory of planet formation to explain the surprising extrasolar planets is migration.

A planet is a celestial body that orbits around a star, is spherical in shape due to its own gravity, and has cleared its orbit of other debris. The eight planets in our solar system are Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune.

Planets are formed from the same gas and dust that surrounds a young star, called a protoplanetary disk. Over time, this material comes together due to gravitational attraction and forms into larger and larger bodies, eventually creating planets. Planets can have various features such as atmospheres, moons, and rings. They also have different characteristics such as size, composition, and temperature, which can affect their ability to support life.

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Answer:

1st question c part

2nd question c part

The measurement of 13.2 ounces is 0.375 kg in SI units.

To convert 13.2 ounces to SI units, we need to convert it to kilograms since the SI unit for mass is kilograms (kg).

Given:

1 lb = 16 oz

1 kg = 2.2 lbs

First, let's convert 13.2 ounces to pounds:

13.2 oz * (1 lb / 16 oz) = 0.825 lbs

Now, let's convert pounds to kilograms:

0.825 lbs * (1 kg / 2.2 lbs) ≈ 0.375 kg

Therefore, the measurement of 13.2 ounces is approximately 0.375 kg in SI units.

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check the pictures(2 pictures)check the pictures(2 pictures)check the pictures(2 pictures)

The vector sum of the two forces is 20  and the magnitude of the resultant is 20 towards positive x-axis.

A vector is a quantity or phenomena with magnitude and direction that are independent of one another. The phrase also refers to a quantity's mathematical or geometrical representation.

If no vector can be written as a linear combination of the others, a set of vectors is said to be linearly independent.

The vector representation for the forces F and F are:

\(\rm \vec F_1 = 20 COS 60^0 \vec i + 20 SIN 60^0 \vec j\\\\ F_1 =20 \times \frac{1}{2} \vec i+20 \times \frac{\sqrt{3} }{2} \vec j \\\\ \vec F_1 = 10 \vec i+ 10 \sqrt{3} \vec J\)

\(\rm F_2 = 20 cos 60^0 \vec i+20 sin(-60) \vec j \\\\ F_2 = 20 \times \frac{1}{2} \times \vec i+20 \times \frac{\sqrt{3} }{2} \vec j \\\\ \vec F_2 = 10 \vec I -10\sqrt{3} \vec J\)

The vector sum of the two forces are;

\(\rm \vec R = \vec F_1+\vec F_2\\\\ \vec R = 10 \vec i+ 10 \sqrt{3} \vec J+10 \vec i-10\sqrt{3} \vec J\\\\ \vec R =20 i\)

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The modulus of elasticity, E, is a measure of a material's stiffness and ability to resist deformation when a force is applied. It is defined as the ratio of stress to strain within the elastic range of the material. In other words, it describes how much a material will stretch or compress under a given force.

The modulus of elasticity is important because it allows engineers to predict how materials will behave under different conditions, such as temperature changes, loading conditions, and other factors. It also helps to determine the maximum load a material can withstand before it starts to deform or break.

In detail, the modulus of elasticity is a fundamental property of a material that describes its ability to resist deformation when subjected to external forces. It is calculated by measuring the stress and strain of the material and using the equation E = σ/ε, where σ is stress and ε is strain.

The modulus of elasticity is important in many areas of engineering, such as structural design, materials science, and mechanics. It helps to ensure that structures and materials are designed and tested to withstand the loads and stresses they will be subjected to, and it provides a basis for comparing different materials and choosing the best one for a particular application.

In summary, the modulus of elasticity, E, is a material property that describes its stiffness and resistance to deformation. It is correctly determined using Hooke's Law and is crucial for predicting the mechanical behavior of materials when subjected to stress.

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I think its "a dropped penny sinks at the bottom of a pond". Because, non-contact force is a force that you don't touch, like gravity or weight, that falls but you didn't drop it on purpose nature did or gravity itself did.

The question addresses the stability of the atmosphere and the factors that determine convective stability or instability. It also explains the difference between the adiabatic lapse rate of dry air and wet saturated air.

a) The stability of the atmosphere is determined by the temperature profile and relative densities of the air cell and atmosphere. If the temperature of the surrounding atmosphere decreases with altitude at a rate greater than the adiabatic lapse rate of the air cell, the atmosphere is considered convectively stable.

In this case, the air cell will return to its original position. Conversely, if the temperature of the surrounding atmosphere decreases slower than the adiabatic lapse rate of the air cell, the atmosphere is convectively unstable. The air cell will continue moving in the same direction.

b) The adiabatic lapse rate refers to the rate at which temperature decreases with altitude for a parcel of air lifted or descending adiabatically (without exchanging heat with its surroundings). The adiabatic lapse rate of dry air is higher (around \(9.8^0C\) per kilometer) compared to the adiabatic lapse rate of wet saturated air (around 5°C per kilometer).

This difference arises because when water vapor condenses during the ascent of saturated air, latent heat is released, reducing the rate of temperature decrease. A diagram can illustrate the difference between the two lapse rates, showcasing their respective slopes.

c) When wet unsaturated air rises from the ocean surface, its temperature decreases at a rate equal to the dry adiabatic lapse rate. However, if the ambient lapse rate (temperature decrease with altitude) is higher than the adiabatic lapse rate for dry air, a temperature inversion layer forms at higher altitudes.

In this inversion layer, the temperature increases with altitude instead of decreasing. A schematic diagram can depict the temperature changes of the wet air in comparison to the ambient temperature, showing the inversion layer.

Cumulus clouds form at the altitude where the rising moist air reaches the level of the temperature inversion layer. These clouds are formed due to the condensation of water vapor as the air parcel cools to its dew point temperature.

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Answer:

the formula v = f×lambda.

v= 4.25× 5.6

therefore speed is

23.8 meters per second

Answer:

5 i think

Explanation:

Answer:

what is the question.

Explanation:

El valor de L del tramo rugoso B a C con coeficiente de fricción igual a 0,6, recorrido por el cuerpo de 2 kg cuando se suelta del punto A es 5.00 m.  

El valor de L se puede calcular a partir de la definición de trabajo:

\(W = F_{\mu}*d\)  (1)

En donde:

\(F_{\mu}\): es la fuerza aplicada sobre el cuerpo en el tramo de B a C = fuerza de roce = -μN (el signo menos se debe a que está en dirección opuesta a la del movimiento)

μ: es el coeficiente de roce = 0,6

N: es la normal = mg

m: es la masa del cuerpo = 2 kg

g: es la aceleración debida a la gravedad = 9,81 m/s²

d: es la distancia = L =?

Por otra parte, el trabajo también se define como la diferencia de energía mecánica entre los puntos B y C.

\( W = E_{C} - E_{B} \)   (2)

Al igualar la ecuación (1) con la (2) tenemos:

\(E_{C} - E_{B} = F_{\mu}*d\)   (3)

En el punto C, la energía es cero (0) dado que el cuerpo se detiene y en el punto B la energía que tiene el objeto es la cinética:  

\( E_{B} = \frac{1}{2}mv_{B}^{2} \)      

En donde:  

\(v_{B}\): es la velocidad del cuerpo en el punto B

La velocidad del cuerpo en el punto B se puede calcular mediante conservación de energía entre los puntos A y B:

\( E_{A} = E_{B} \)          

En el punto A, el cuerpo tiene energía potencial gravitacional, por lo tanto:

\( mgh = \frac{1}{2}mv_{B}^{2} \)    (4)

En donde:

h: es la altura = 3 m

Entonces, la velocidad en el punto B es (eq 4):

\( v_{B} = \sqrt{\frac{2mgh}{m}} = \sqrt{2*9,81 m/s^{2}*3 m} = 7,67 m/s \)

Ahora, la ecuación (3) queda como sigue:  

\( 0 - \frac{1}{2}mv_{B}^{2} = -\mu N*L \)  

\( \frac{1}{2}2 kg*(7.67 m/s)^{2} = 0,6*2 kg*9,81 m/s^{2}*L \)  

Resolviendo para L, tenemos:

\( L = \frac{\frac{1}{2}2 kg*(7.67 m/s)^{2}}{0,6*2 kg*9,81 m/s^{2}} = 5.00 m \)

Por lo tanto, el valor de L es 5.00 m.

Encuentra más sobre trabajo aqui:

Espero que te sea de utilidad!  

To determine the final equilibrium temperature, we use the principle of conservation of energy, equating the heat lost by the aluminum to the heat gained by the water, resulting in a final temperature of 24.6°C.

When two substances with different temperatures come into contact, heat transfer occurs until they reach thermal equilibrium, where their temperatures are equal. To determine the final equilibrium temperature, we can use the principle of conservation of energy, which states that the heat lost by one substance is equal to the heat gained by the other.

First, we calculate the heat lost by the aluminum using the formula:

Q = m * c * ΔT

Where:

Q is the heat lost

m is the mass of aluminum

c is the specific heat of aluminum

ΔT is the change in temperature

Substituting the given values:

Q_aluminum = 80.0 g * 0.90 J/g°C * (5.0°C - final temperature)

Next, we calculate the heat gained by the water using the same formula:

Q = m * c * ΔT

Where:

Q is the heat gained

m is the mass of water

c is the specific heat of water

ΔT is the change in temperature

Substituting the given values:

Q_water = 100.0 g * 4.18 J/g°C * (final temperature - 60.0°C)

Since the total heat lost by the aluminum is equal to the total heat gained by the water, we can set up an equation:

Q_aluminum = Q_water

80.0 g * 0.90 J/g°C * (5.0°C - final temperature) = 100.0 g * 4.18 J/g°C * (final temperature - 60.0°C)

Simplifying and solving the equation gives us the final equilibrium temperature of 24.6°C.

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Removing bulb A from the circuit does not have any effect on the brightness of bulb B.

If bulb A is removed from the circuit, the potential difference across bulb B remains the same. Since the power dissipated by the resistance of the bulb is given by P = \(V^{2}\)/R and its resistance remains unchanged, the brightness of bulb B will stay the same.

When bulbs are connected in parallel, they experience the same potential difference across them. Therefore, removing bulb A does not affect the potential difference across bulb B.

The power dissipated by a resistance is given by the equation  P = \(V^{2}\)/R, where P is the power, V is the potential difference, and R is the resistance. Since the resistance of bulb B remains the same, the power dissipated by bulb B remains constant. The brightness of a bulb is directly proportional to the power dissipated, so if the power remains constant, the brightness of bulb B will also remain unchanged.

Therefore, removing bulb A from the circuit does not have any effect on the brightness of bulb B.

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If pressure has to be decreased the height of the piston needs to be increased which will increase volume of gas eventually decreasing the pressure.

The thrust (perpendicular force on a surface) acting per unit area of a body is referred to as pressure. It can be stated mathematically as follows: Pascal is the SI unit of pressure (Pa). One Pascal is the amount of pressure one Newton of force applies to a square inch of space. Additionally, 1 P a = 1 N / m 2. In the International System of Units, pressure or stress is measured in pascals (Pa) (SI). It bears Blaise Pascal's name, a mathematician and physicist. Applied force of one newton (N) per square metre is equal to one pascal (P) (m2).

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Answer:

The net strong force on each proton due to all the nucleons is stronger than the net repulsive force.

Explanation:

The strong nuclear force pulls together protons and neutrons in the nucleus. At very small distances only, such as those inside the nucleus, this strong force overcomes the electromagnetic force, and prevents the electrical repulsion of protons from blowing the nucleus apart.

The resulting equation of motion for the system is given by m × x''(t) + k × x(t) = f(t), which is 2 × x''(t) + 18 * x(t) = 2 * sin(2t).

What is  equation of motion?

The equations of motion are a set of mathematical relationships that describe the motion of objects under the influence of forces. There are different sets of equations of motion, depending on the specific scenario and the type of motion being considered (linear motion, projectile motion, circular motion, etc.). The equations of motion for linear motion, also known as the equations of uniformly accelerated motion.

To find the equation of motion for the system, we start with Newton's second law of motion, which states that the sum of forces acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, the object is the 2-kg mass attached to the spring.

The force exerted by the spring is proportional to the displacement of the mass from its equilibrium position, and it can be expressed as F_spring = -k× x(t), where k is the spring constant and x(t) is the displacement of the mass at time t.

In addition to the force exerted by the spring, there is an external force f(t) = 2 ×sin(2t) acting on the mass.

Applying Newton's second law, we have the equation of motion: m ×x''(t) + k ×x(t) = f(t).

Substituting the given values, m = 2 kg and k = 18 N/m, we obtain 2 ×x''(t) + 18 × x(t) = 2 ×sin(2t).

Therefore, the resulting equation of motion for the system is 2 × x''(t) + 18 × x(t) = 2 × sin(2t).

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Answer:

The eight Moon phases:

Waxing Crescent: In the Northern Hemisphere, we see the waxing crescent phase as a thin crescent of light on the right. First Quarter: We see the first quarter phase as a half moon. Waxing Gibbous: The waxing gibbous phase is between a half moon and full moon.

The phases of the Moon are the different ways the Moon looks from Earth over about a month. As the Moon orbits around the Earth, the half of the Moon that faces the Sun will be lit up. The different shapes of the lit portion of the Moon that can be seen from Earth are known as phases of the Moon.

Explanation:

Hope it is helpful....

Answer: i think u can put this The phases of the Moon are the different ways the Moon looks from Earth over about a month. As the Moon orbits around the Earth, the half of the Moon that faces the Sun will be lit up. The different shapes of the lit portion of the Moon that can be seen from Earth are known as phases of the Moon

Don't forget to drop a heart have a happy friday

Answer:   Eat only when you're truly hungry instead of when you are tired, anxious, or feeling an emotion besides hunger.

Plan meals ahead of time to ensure that you eat a healthy well-balanced meal.

Keep more fruits, low-fat dairy products (low-fat milk and low-fat yogurt), vegetables, and whole-grain foods at home and at work.

Explanation:

Answer:

I know that some foods have a lot of sugar. I read online that I don’t need any more than 25 grams of added sugar a day. One kind of pop that I like to drink has 40 grams of sugar per can. I can start by drinking less pop. Next, I learned that some food makers are now putting nutrition keys on the front of their boxes. I love all kinds of breakfast cereal, so I can use the nutrition key to compare brands. Cereal high in fiber is good, but cereal high in sugar isn’t. I’ll be more careful, too, when ordering fast food. Sometimes fast-food places want to change the size of my order from medium to large for a higher price. From now on, I won’t pick the bigger meal. Picking the medium-sized meal should be better for me and can even save me money.

Explanation: Plato

Ability of the joints and muscle to move through in full range of motion?

answer : flexibility......

Using trigonometry, the scalar components of vector a and b along the x axis are 3.0 m and 5.2 m, respectively.

Based on the drawing, we can see that the x axis is horizontal and that vector a makes an angle of 60 degrees with the x axis, while vector b makes an angle of 30 degrees with the x axis. To find the scalar component of each vector along the x axis, we need to use trigonometry.

For vector a:
- The magnitude of a is 6.0 m, so we can use the cosine of 60 degrees (adjacent side over hypotenuse) to find the scalar component ax:
ax = a*cos(60) = 6.0 m * 0.5 = 3.0 m

For vector b:
- Again, the magnitude of b is 6.0 m, so we can use the cosine of 30 degrees to find the scalar component bx:
bx = b*cos(30) = 6.0 m * √(3)/2 ≈ 5.2 m

Therefore, the scalar components of vector a and b along the x axis are 3.0 m and 5.2 m, respectively.

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Answer:

0.893 rad/s in the clockwise direction

Explanation:

From the law of conservation of angular momentum,

angular momentum before impact = angular momentum after impact

L₁ = L₂

L₁ = angular momentum of bullet = + 9 kgm²/s (it is positive since the bullet tends to rotate in a clockwise direction from left to right)

L₂ = angular momentum of cylinder and angular momentum of bullet after collision.

L₂ = (I₁ + I₂)ω where I₁ = rotational inertia of cylinder = 1/2MR² where M = mass of cylinder = 5 kg and R = radius of cylinder = 2 m, I₂ = rotational inertia of bullet about axis of cylinder after collision = mR² where m = mass of bullet = 0.02 kg and R = radius of cylinder = 2m and ω = angular velocity of system after collision

So,

L₁ = L₂

L₁ = (I₁ + I₂)ω

ω = L₁/(I₁ + I₂)

ω = L₁/(1/2MR² + mR²)

ω = L₁/(1/2M + m)R²

substituting the values of the variables into the equation, we have

ω = L₁/(1/2M + m)R²

ω = + 9 kgm²/s/(1/2 × 5 kg + 0.02 kg)(2 m)²

ω = + 9 kgm²/s/(2.5 kg + 0.02 kg)(4 m²)

ω = + 9 kgm²/s/(2.52 kg)(4 m²)

ω = +9 kgm²/s/10.08 kgm²

ω = + 0.893 rad/s

The angular velocity of the cylinder bullet system is 0.893 rad/s in the clockwise direction-since it is positive.

Answer:

the filling stops when the pressure of the pump equals the pressure of the interior air plus the pressure of the walls.

Explanation:

This exercise asks to describe the inflation situation of a spherical fultball.

Initially the balloon is deflated, therefore the internal pressure is equal to the pressure of the air outside, atmospheric pressure, when it begins to inflate the balloon with a pump this creates a pressure in the inlet valve and as it is greater than the pressure inside, the air enters it, this is repeated in each filling cycle, manual pump.

When the ball is full we have two forces, the one created by the external walls and the one aired by the pressure of the pump, these forces are directed towards the inside, but the air molecules exert a pressure towards the outside, which translates into a force. When these two forces are equal, the pump is no longer able to continue introducing air into the balloon.

Consequently the filling stops when the pressure of the pump equals the pressure of the interior air plus the pressure of the walls.