GUYSSSSS PLS HELP I HAVE SCHOOL IN AN HOUR

To find the area bounded by the given curve y = x^2 - (1/x) - 72x - 13, the lines x = 3, x = 4, and the x-axis (y = 0), we need to evaluate the definite integral of the curve between the limits x = 3 and x = 4.

To find the area bounded by the curve y = x^2 - (1/x) - 72x - 13, x = 3, x = 4, and the x-axis (y = 0), we integrate the function with respect to x from x = 3 to x = 4:

Area = ∫[3 to 4] (x^2 - (1/x) - 72x - 13) dx

By evaluating this definite integral, we can find the area bounded by the curve.

To calculate the integral, we can break it down into simpler integrals, applying the power rule and the rule for integrating 1/x:

Area = ∫[3 to 4] (x^2 - (1/x) - 72x - 13) dx

= [(x^3/3) - ln|x| - 36x^2 - 13x] from 3 to 4

Evaluating the integral at the limits, we subtract the value at x = 3 from the value at x = 4:

Area = [(4^3/3) - ln|4| - 36(4^2) - 13(4)] - [(3^3/3) - ln|3| - 36(3^2) - 13(3)]

Calculating this expression, we can determine the area bounded by the given curve, lines, and the x-axis.

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Answer:

I feel the answer is:  "But we do believe that we should promise to do our best and do something good for somebody every day."

Step-by-step explanation:

I know this is right because I am currently learning about it in Edmentum and I took the test and got it right!

I hope this helps!  Please make brainliest!

Answer:

5 nickles in a quator.

Step-by-step explanation:

Answer:

5 nickels

Step-by-step explanation:

The value of a nickel is 5 cents and the value of a quarter is 25 cents.

The equation we can use for this is 5 times x = 25

From here, you can divide 25 By 5 and get 5 as your final answer.

Hope this helps, have a good day!

Answer:

\( (0, 8\sqrt{3}) \)  and  \( (0, -8\sqrt{3}) \) are both 14 units from points (-2, 0) and (2, 0).

Step-by-step explanation:

distance formula

\( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \)

We want the distance, d, from points (-2, 0) and (2, 0) to be 14.

Point (-2, 0):

\( 14 = \sqrt{(x - (-2))^2 + (y - 0)^2} \)

\( \sqrt{(x + 2)^2 + y^2} = 14 \)

Point (2, 0):

\( 14 = \sqrt{(x - 2)^2 + (y - 0)^2} \)

\( \sqrt{(x - 2)^2 + y^2} = 14 \)

We have a system of equations:

\( \sqrt{(x + 2)^2 + y^2} = 14 \)

\( \sqrt{(x - 2)^2 + y^2} = 14 \)

Since the right sides of both equations are equal, we set the left sides equal.

\( \sqrt{(x + 2)^2 + y^2} = \sqrt{(x - 2)^2 + y^2} \)

Square both sides:

\( (x + 2)^2 + y^2 = (x - 2)^2 + y^2 \)

Square the binomials and combine like terms.

\( x^2 + 4x + 4 + y^2 = x^2 - 4x + 4 + y^2 \)

\( 4x = -4x \)

\( 8x = 0 \)

\( x = 0 \)

Now we substitute x = 0 in the first equation of the system of equations:

\( \sqrt{(x + 2)^2 + y^2} = 14 \)

\( \sqrt{(0 + 2)^2 + y^2} = 14 \)

\( \sqrt{4 + y^2} = 14 \)

Square both sides.

\( y^2 + 4 = 196 \)

\( y^2 = 192 \)

\( y = \pm \sqrt{192} \)

\( y = \pm \sqrt{64 \times 3} \)

\( y = \pm 8\sqrt{3} \)

The points are:

\( (0, 8\sqrt{3}) \)  and  \( (0, -8\sqrt{3}) \)

Number of hours she needs to work to make $1500 in her first paycheck is; 117 hours.

She saw one that is offering a $100 signing bonus and a wage of $12 per hour.

A(x) = 12x + 100

To find the Number of hours she needs to work to make $1500 in her first paycheck, we put 1500 for A(x) to get;

1500 = 12x + 100

12x = 1500 - 100

12x = 1400

x = 1400/12

x = 116.67

Approximating to the nearest hours gives;

x = 117 hours

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To find the area of the surface that lies within the cylinder x² + y² = 9, we need to find the limits of integration for x and y.

Since the surface is defined as z = xy, we can rewrite the equation of the cylinder as y = √(9 - x²).
To find the limits of integration for x, we need to determine the range of x-values for which y is defined. From the equation y = √(9 - x²), we can see that y is defined as long as 9 - x² ≥ 0. Solving this inequality, we have x² ≤ 9, which means -3 ≤ x ≤ 3.
Now, to find the limits of integration for y, we need to determine the range of y-values for which x is defined. From the equation x² + y² = 9, we can see that y is defined as long as x² + y² ≤ 9. Therefore, -√(9 - x²) ≤ y ≤ √(9 - x²).
Using these limits of integration, we can set up the double integral to find the area of the surface:
A = ∬(R) √(1 + (∂z/∂x)² + (∂z/∂y)²) dA
where R is the region defined by -3 ≤ x ≤ 3 and -√(9 - x²) ≤ y ≤ √(9 - x²).
Unfortunately, it is not possible to calculate the exact value of this integral without further information. However, you can use numerical integration methods or software to approximate the area.

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Answer: B 10 Times large

Step-by-step explanation:The first 5 is 500,000 And the second 5 is 50,000

500,000÷ 50,000= 10

Answer:

a) 39

b) 4

Step-by-step explanation:

\( {7}^{2} = 7 \times 7 = 49\)

Answer:

(4,4)

Step-by-step explanation:

The solution set of the system of equations can be found by setting the two equations equal to each other and solving for x.

x^2 - 6x + 12 = 2x - 4

x^2 - 8x + 16 = 0

(x - 4)^2 = 0

x = 4

Since both equations in the system are equal to y, we can substitute x = 4 into either equation to find the corresponding value of y.

y = 2x - 4 = 2(4) - 4 = 4

Therefore, the solution of this system of equations is (4, 4).

Therefore, the correct answer is (4, 4).

Answer:5.7ft

Step-by-step explanation:

sin = opposite/adjacent

sin 35 = x/10

10 * sin 35 = x

x=5.7

The parametric representation for the part of the sphere x² + y² + z² = 4 that lies above the cone defined by z = √(x² + y²) is given by x = u, y = v, and z = √(4 - u² - v²), where u and v range over appropriate intervals. The value of z can be greater than, equal to, or less than 2 depending on the values of u and v.

To find the parametric representation, we can assign u and v as parameters. Considering the equations x = u and y = v, we can substitute these values into the equation of the sphere to solve for z. Substituting x = u and y = v into x² + y² + z² = 4 yields u² + v² + z² = 4. Rearranging the equation, we have z² = 4 - u² - v², which gives us z = ±√(4 - u² - v²). However, since we are interested in the upper part of the sphere, we take the positive square root.

Therefore, the parametric representation for the part of the sphere that lies above the given cone is x = u, y = v, and z = √(4 - u² - v²). The values of u and v can vary within appropriate intervals that satisfy the given conditions. As for the value of z, it can be greater than 2, equal to 2, or less than 2 depending on the specific values of u and v.

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A paired-test can be used to check if the two blood pressure taken from 2 groups,one group having normal blood pressure another having white coat hypertension differ or not.

A paired t-test is used to determine whether two sample means are equal or not. White coat hypertension occurs when a person's blood pressure rises when they are in a medical setting.

To assess whether the two blood pressure measurements differ, a paired t-test should be used. The paired t-test is used to compare two dependent samples that are connected in some manner. A random sample of 50 patients should be taken to see if the two blood pressures differ. Here are the steps for conducting a paired t-test:

- State the null and alternative hypotheses.
- Calculate the difference between the two groups of data.
- Calculate the sample mean, sample standard deviation, and sample size.
- Use the t-distribution to determine the critical value.
- Compute the test statistic.
- Determine the p-value.
- Make a decision.

It is worth noting that in order to use the paired t-test, the data must be normally distributed. Additionally, this test can be performed on a one-tailed or two-tailed basis, depending on the hypothesis test. F-distribution is not used in a paired t-test.

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Answer:

It's c :]

Step-by-step explanation:

Answer: 11/25

Step-by-step explanation:

I got the answers at the end of a near-pod but if you need to show your work

The measure of arc BC is 720 times the measure of angle BAC.

Given that AC is the diameter of the circle and AB is a chord with a length of 16 units, we need to find BC (the length of the other chord) and mBC (the measure of angle BAC).

To find BC, we can use the property of chords in a circle. If two chords intersect within a circle, the products of their segments are equal. In this case, since AB = BC = 16 units, the product of their segments will be:

AB * BC = AC * CE

16 * BC = 2 * r * CE (AC is the diameter, so its length is twice the radius)

Since the area of the circle is given as 289 square units, we can find the radius (r) using the formula for the area of a circle:

Area = π * r^2

289 = π * r^2

r^2 = 289 / π

r = √(289 / π)

Now, we can substitute the known values into the equation for the product of the segments:

16 * BC = 2 * √(289 / π) * CEBC = (√(289 / π) * CE) / 8

To find mBC, we can use the properties of angles in a circle. The angle subtended by an arc at the center of a circle is double the angle subtended by the same arc at any point on the circumference. Since AC is a diameter, angle BAC is a right angle. Therefore, mBC will be half the measure of the arc BC.

mBC = 0.5 * m(arc BC)

To find the measure of the arc BC, we need to find its length. The length of an arc is determined by the ratio of the arc angle to the total angle of the circle (360 degrees). Since mBC is half the arc angle, we can write:

arc BC = (mBC / 0.5) * 360

arc BC = 720 * mBC

Therefore, the length of the arc BC equals 720 times the length of the angle BAC.

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In a tumor sample with a mutated fumarate dehydrogenase (FH) that is less active than the normal isoform, the expected consequence would be an increased accumulation of fumarate.

This accumulation of fumarate leads to several downstream effects, including epigenetic changes, activation of hypoxia-inducible factor (HIF) pathways, and altered metabolism. However, one consequence that would not be expected is a decreased expression of hypoxia-inducible factor 1-alpha (HIF-1α). Fumarate dehydrogenase (FH) is an enzyme involved in the tricarboxylic acid (TCA) cycle, also known as the Krebs cycle. It catalyzes the conversion of fumarate to malate, contributing to the production of energy in the form of ATP. In a tumor sample with a mutated FH that is less active, there would be a reduced conversion of fumarate to malate. As a result, fumarate would accumulate in the cell.

The accumulation of fumarate has several consequences. Firstly, it can lead to epigenetic changes by inhibiting enzymes called alpha-ketoglutarate-dependent dioxygenases, which are involved in DNA and histone demethylation. This alteration in epigenetic regulation can contribute to tumorigenesis. Secondly, fumarate accumulation can stabilize and activate hypoxia-inducible factor (HIF) pathways. HIF-1α, a subunit of HIF, is normally regulated by oxygen levels and degraded under normoxic conditions. However, in the presence of accumulated fumarate, HIF-1α stabilization can occur even in the presence of oxygen, leading to the activation of HIF target genes involved in angiogenesis, glucose metabolism, and cell proliferation.

Given these effects, it is unlikely that a decreased expression of HIF-1α would be observed in a tumor sample with a mutated FH and fumarate accumulation. On the contrary, HIF-1α expression would be expected to increase due to its stabilization in response to fumarate accumulation.

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Answer:

(0, 12)

Step-by-step explanation:

To find the y-intercept of the quadratic function f(x) = (x - 6)(x - 2), we need to substitute x = 0 in the equation and solve for f(0).

f(x) = (x - 6)(x - 2)

f(0) = (0 - 6)(0 - 2) // Substitute x = 0

f(0) = 12

Therefore, the y-intercept of the quadratic function f(x) = (x - 6)(x - 2) is 12, which means the graph of the function intersects the y-axis at the point (0, 12).

The inverses modulo m for the given pairs of relatively prime integers are:

a) Inverse of 4 modulo 9 is 1.

b) Inverse of 19 modulo 141 is 1.

c) Inverse of 55 modulo 89 is 1.

d) Inverse of 89 modulo 232 is 1.

To find the inverse of a modulo m for each pair of relatively prime integers, we can use the Extended Euclidean Algorithm. The inverse of a modulo m is a number x such that (a * x) mod m = 1.

a) For a = 4 and m = 9:

We need to find the inverse of 4 modulo 9.

Using the Extended Euclidean Algorithm, we have:

9 = 2 * 4 + 1

4 = 4 * 1 + 0

The last nonzero remainder in the algorithm is 1. So, the inverse of 4 modulo 9 is 1.

b) For a = 19 and m = 141:

We need to find the inverse of 19 modulo 141.

Using the Extended Euclidean Algorithm, we have:

141 = 7 * 19 + 8

19 = 2 * 8 + 3

8 = 2 * 3 + 2

3 = 1 * 2 + 1

2 = 2 * 1 + 0

The last nonzero remainder in the algorithm is 1. So, the inverse of 19 modulo 141 is 1.

c) For a = 55 and m = 89:

We need to find the inverse of 55 modulo 89.

Using the Extended Euclidean Algorithm, we have:

89 = 1 * 55 + 34

55 = 1 * 34 + 21

34 = 1 * 21 + 13

21 = 1 * 13 + 8

13 = 1 * 8 + 5

8 = 1 * 5 + 3

5 = 1 * 3 + 2

3 = 1 * 2 + 1

2 = 2 * 1 + 0

The last nonzero remainder in the algorithm is 1. So, the inverse of 55 modulo 89 is 1.

d) For a = 89 and m = 232:

We need to find the inverse of 89 modulo 232.

Using the Extended Euclidean Algorithm, we have:

232 = 2 * 89 + 54

89 = 1 * 54 + 35

54 = 1 * 35 + 19

35 = 1 * 19 + 16

19 = 1 * 16 + 3

16 = 5 * 3 + 1

3 = 3 * 1 + 0

The last nonzero remainder in the algorithm is 1. So, the inverse of 89 modulo 232 is 1.

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Answer:

5/9

Step-by-step explanation:

we add all of the values and divide by the total number in this case 9, all of them add to make 5 so we do 5÷9 to get 5/9

Proof of the statement AB + CD = AD + BC is shown below.

We have,

Quadrilateral A B C D is circumscribed about P.

     Statements                                                        Reasons

1. Quadrilateral ABCD is circumscribed              Given

about circle P

2. AB and CD are opposite sides of ABCD Definition of opposite sides

3. AD and BC are opposite sides of ABCD      Definition of opposite sides

4. AB + CD = AP + BP + CP + DP         Definition of a circumscribed  

                                                                  quadrilateral

5. AD + BC = AP + DP + BP + CP Definition of a circumscribed

                                                          quadrilateral

6. AP + BP + CP + DP = AP + DP + BP + CP Addition property of

                                                                          equality

7. AB + CD = AD + BC               Substitution property of equality

In this proof, we start by stating the given information in line 1. In lines 2 and 3, we use the definition of opposite sides to identify AB and CD, and AD and BC.

In lines 4 and 5, we use the definition of a circumscribed quadrilateral to express AB+CD and AD+BC in terms of the lengths of the four sides of the quadrilateral and the radius of the circle.

In line 6, we use the addition property of equality to show that the expressions in lines 4 and 5 are equal to each other.

Finally, in line 7, we use the substitution property of equality to substitute the expressions from lines 4 and 5 with each other and conclude that AB+CD = AD+BC.

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Answer

Solved Calculus AB, Semester 2 Assignment: Applications of ...

The population of a bacteria culture increases at the rate of 3 times the square root of the present population.

Answer:

neither

Step-by-step explanation:      

Answer:

C (rad 2 x rad 5 x rad 2 x rad 5)

Step-by-step explanation:

rad 2 times rad 5 = rad 10

rad 10 times 2 = rad 20

rad 20 times rad 5 = rad 100

rad 100 = 10

10 is rational

Answer:

4

Step-by-step explanation:

because The square root of 16 is 4, which is a rational number.

Answer:

4

Step-by-step explanation:

The amount that Bert should deposit to earn $192 interest is $4,000 (option C).

When an account earns a simple interest, the account increases linearly. It means that the value of the account increases at a constant rate.

The rate of increase is determined by the amount deposited, the interest rate and the number of years the money was deposited for.

Amount to be deposited = simple interest / (years x interest rate)

$192 / (0.016 x 3) $192 / 0.048 = $4,000

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The probability of out of any two students chosen at random, one student will be absent while the other is present is 29/450 or approximately 0.064.

Let's denote the event that a student is absent as A and the event that a student is present as P.

The probability of a student being absent is P(A) = 1/30, which means the probability of a student being present is P(P) = 29/30.

We want to find the probability that out of any two students chosen at random, one student will be absent while the other is present.

There are two possible cases for this event:

The first student is absent and the second student is present

The first student is present and the second student is absent

Let's calculate the probability of each case separately:

Case 1: The probability of the first student being absent is P(A) = 1/30. The probability of the second student being present is P(P) = 29/30. Therefore, the probability of the first student being absent and the second student being present is:

P(A and P) = P(A) × P(P) = (1/30) × (29/30) = 29/900

Case 2: The probability of the first student being present is P(P) = 29/30. The probability of the second student being absent is P(A) = 1/30. Therefore, the probability of the first student being present and the second student being absent is:

P(P and A) = P(P) × P(A) = (29/30) × (1/30) = 29/900

The total probability of one student being absent and the other being present is the sum of the probabilities of the two cases:

P = P(A and P) + P(P and A) = (29/900) + (29/900) = 58/900

Simplifying the fraction by dividing both the numerator and denominator by 2, we get:

P = 29/450

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Answer:

58\(\sqrt{65}\)

Step-by-step explanation:

you can find the height of this trapezoid by using the pythagorean theorem where the hypotenuse is 18 and one leg is 8 (33-25)

let x = height

\(8^{2}\) + \(x^{2}\) = \(18^{2}\)

\(x^{2}\) = 324 - 64

\(x^{2}\) = 260     therefore, x = \(\sqrt{260}\)

\(\sqrt{260}\) = \(\sqrt{4}\)· \(\sqrt{65}\)  or  2\(\sqrt{65}\)

A = \(\frac{1}{2}\)h x (sum of the bases)        

bases are 25 and 33

A = (2\(\sqrt{65}\)) ÷ 2)58

Answer:

square root of 25

Step-by-step explanation:

Answer:

Square foot of 25

Step-by-step explanation:

I took the test and got it right!

Answer: Yes it is rational number because it has a terminating decimal expansion

Step-by-step explanation:

Define Rational number:

rational number, in arithmetic, a number that can be represented as the quotient p/q of two integers such that q ≠ 0. In addition to all the fractions, the set of rational numbers includes all the integers, each of which can be written as a quotient with the integer as the numerator and 1 as the denominator.

Yes it is rational number because it has a terminating decimal expansion.

7/2=3.5

Define Integer:

An integer is a whole number (not a fractional number) that can be positive, negative, or zero. Examples of integers are: -5, 1, 5, 8, 97, and 3,043. Examples of numbers that are not integers are: -1.43, 1 3/4, 3.14.

all integers between -7 and 2 in increasing order are:

-6,-5,-4,-3,-2,-1,0 and 1.

since, it has to be in increasing order -6 will come first and 1 at the last.

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X: -4. Y: -3

Step-by-step explanation: