A sample of carbon dioxide gas trapped by a moveable piston has a volume of 23.5 L at 23°C and standard pressure. Assuming the pressure does not change, what would the volume be if the temperature were increased to 53°C?

In \(\rm 4\;NH_3\), the 4 has been the coefficient of the compound and represents the number of molecules of ammonia.

\(\rm NH_3\) has been a compound of nitrogen and hydrogen. The compound has been a covalent compound, formed by the sharing of electrons in between nitrogen and hydrogen.

The compound has been consisted of 1 nitrogen atom and 3 hydrogen atoms. The hydrogen atoms bonding results in the completion of the octet of the nitrogen and provides stability to the compound.

While writing the chemical equation, the coefficient of the compound has been describing the number of molecules present in the reaction. In \(\rm 4\;NH_3\), the 4 has been the coefficient of the compound and represents the number of molecules of ammonia.

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Answer:

B

Explanation:

neutrons + atomic number/proton/electron for a neutral atom = mass number

e.g

mass number of Chlorine 35.5

proton number 17

neutron number will be 35.5-17 = 18.5

Therefore.....

your question deduced says

atomic number is 5

mass number is 11

neutron number is however mass number minus atomic number 11-5 =6

Answer:

Mercury has a relatively high vapour pressure and the highest volatility of any metal, vapourizing to become a colourless, odourless gas. The metal is a fair conductor of electricity, but a poor conductor of heat. Mercury's atomic number is 8.

Answer:

The combustion of diborane (B2H6) is as follows:

2B2H6(g) + 6O2(g) → 4H2O(g) + B4O(g)

The balanced chemical equation shows that 2 moles of B2H6 react with 6 moles of O2 to produce 4 moles of H2O and 1 mole of B4O. We can use this information to calculate the amount of heat released by the combustion of 0.491 g of B2H6:

0.491 g B2H6 × (1 mol B2H6/27.67 g B2H6) × (1 mole B4O/2 moles B2H6) × (-2037 kJ/mol B4O) = -7.89 kJ

The negative sign indicates that the reaction releases heat.

The heat released by the reaction is absorbed by the calorimeter, which causes its temperature to increase. We can use the equation:

q = Ccalorimeter × ΔT

where q is the amount of heat absorbed by the calorimeter, Ccalorimeter is the heat capacity of the calorimeter, and ΔT is the change in temperature of the calorimeter.

Rearranging the equation, we get:

ΔT = q/Ccalorimeter

Substituting the values we obtained, we get:

ΔT = (-7.89 kJ)/(7.854 kJ/°C) = -1.005°C

The negative sign indicates that the temperature of the calorimeter decreases by 1.005°C. Therefore, the final temperature of the calorimeter is:

19.63°C - 1.005°C = 18.625°C

Rounding to the appropriate number of significant figures, the final temperature of the calorimeter is 18.6°C.

Hope this is what you are looking for.

The molarity of the oxalic acid solution titrated with the potassium permanganate solution is 0.053 M

To determine the molarity of the solution, stoichiometric relationships and rules of three are used.

2 KMnO4 + H2C2O4 → 2 CO2 + K2O + 2 MnO3 + H2O

If there are 0.09113 mol of KMnO4 in 1 liter of solution then in 0.2324 liters there are:

X moles of KMnO4 = 0.02324 x 0.09113 x 1

X moles of KMnO4 = 0.0021 mole

If 2 mol KMnO4 combines with 1 mol H2C2O4 then 0.0021 mol KMnO4 combines with:

X mol H2C2O4 = 0.0021 mol KMnO4 x 1 mol / 2 mol KMnO4

X mol H2C2O4 = 0.0021 x 1 / 2 = 0.001 mol

If there are 0.001 mol H2C2O4 in 0.02 liters of solution then in 1 liter there are:

X mol H2C2O4 = 1 x 0.001 / 0.02 = 0.053

Therefore, the molarity of H2C2O4 is 0.053M

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This extremely high temperature indicates that under normal conditions, you do not need to worry about your car tire bursting from overheating as it is unlikely to reach such extreme temperatures.

To determine the temperature at which the tire will burst, we can use the ideal gas law equation:

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

Rearranging the equation to solve for temperature, we have:

T = PV / (nR)

Given that the pressure threshold for bursting is 1.4 x 10^3 kPa, the volume is 30 L, and the number of moles of air is 2.5 mol, we can substitute these values along with the ideal gas constant R = 8.314 J/(mol K) into the equation.

T = (1.4 x 10^3 kPa) * (30 L) / (2.5 mol * 8.314 J/(mol K))

Converting kPa to Pa and L to m^3, and simplifying the equation, we find:

T ≈ 20,993 K

This extremely high temperature indicates that under normal conditions, you do not need to worry about your car tire bursting from overheating as it is unlikely to reach such extreme temperatures.

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The student needs to add approximately 83.3 mL of 12 M HCl solution to the existing 1 L of 2 M HCl solution to increase the concentration to 3 M. It is important to handle concentrated acids with caution and follow proper safety procedures.

To increase the concentration of a 1 L solution of 2 M HCl to 3 M, the student needs to calculate the volume of concentrated HCl needed and add it to the existing solution. Here's how the calculation can be done:

Given:

Initial concentration of HCl solution = 2 M

Final concentration desired = 3 M

Initial volume of HCl solution = 1 L

Step 1: Calculate the moles of HCl in the initial solution.

Moles of HCl = Initial concentration × Initial volume = 2 M × 1 L = 2 moles

Step 2: Calculate the moles of HCl needed for the desired concentration.

Moles of HCl needed = Final concentration × Final volume = 3 M × 1 L = 3 moles

Step 3: Calculate the moles of HCl to be added.

Moles of HCl to be added = Moles needed - Moles present = 3 moles - 2 moles = 1 mole

Step 4: Convert the moles of HCl to the required volume of concentrated HCl.

To calculate the volume, we need to know the concentration of the concentrated HCl solution. Assuming it is 12 M, we can use the following formula:

Volume of concentrated HCl = Moles of HCl to be added / Concentration of concentrated HCl

Volume of concentrated HCl = 1 mole / 12 M = 0.0833 L or 83.3 mL

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Answer:

smoking- mouth cancer

anorexia -brittle hair

bulimia torn- esophagus

4-cirrhois

This is right I took the test.

Explanation:

you need to add 1.79 mL of 3.0 M HCl to react with 0.45 g of NaHCO3 and produce the most NaCl.

To determine how much 3.0 M HCl is needed to react with 0.45 g of sodium hydrogen carbonate (NaHCO3) and get the most NaCl, you need to first calculate the number of moles of NaHCO3 that you have:

molar mass of NaHCO3 = 84.01 g/mol

moles of NaHCO3 = mass / molar mass = 0.45 g / 84.01 g/mol = 0.00536 mol

Next, you need to determine the stoichiometry of the reaction between NaHCO3 and HCl. The balanced chemical equation for this reaction is:

NaHCO3 + HCl → NaCl + H2O + CO2

From this equation, you can see that one mole of NaHCO3 reacts with one mole of HCl to produce one mole of NaCl. Therefore, you need 0.00536 moles of HCl to react with 0.00536 moles of NaHCO3.

To calculate the volume of 3.0 M HCl needed to provide 0.00536 moles of HCl, you can use the following equation:

moles of solute = concentration x volume of solution (in liters)

Rearranging this equation to solve for the volume of solution gives:

the volume of solution = moles of solute/concentration

Plugging in the values gives:

volume of solution = 0.00536 mol / 3.0 mol/L = 0.00179 L or 1.79 mL

Therefore, you need to add 1.79 mL of 3.0 M HCl to react with 0.45 g of NaHCO3 and produce the most NaCl.

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To solve this question we have to apply Charles Law, that states that:

Where V1 is the initial volume, T1 is the initial temperature, V2 is the final volume and T2 is the final temperature.

Before using the given values, we have to convert the given temperatures to Kelvin degrees:

Now, we can replace these values for T1 and T2 respectively. Also replace V1 for 1L and solve for V2 to find the volume of the balloon inside the freezer:

It means that the volume of the balloon in the freezer is 0.86L.

Answer:

0.0289 kg of CO2 will be formed

Explanation:

Step 1: Data given

Mass of iron produced = 24.42 grams

Atomic mass iron = 55.845 g/mol

Molar mass CO2 = 44.01 g/mol

Step 2: The balanced equation

Fe2O3 + 3CO → 2Fe + 3CO2

Step 3: Calculate moles iron

Moles iron = mass iron / molar mass iron

Moles iron = 24.42 grams / 55.845 g/mol

Moles iron = 0.437 moles

Step 4: Calculate moles CO2

For 1 mol Fe2O3 we need 3 moles CO to produce 2 moles Fe and 3 moles CO2

For 0.437 moles Fe we'll have 3/2 * 0.437 = 0.6555 moles CO2

Step 5: Calculate mass CO2

Mass CO2 = moles CO2 * molar mass CO2

Mass CO2 = 0.6555 moles * 44.01 g/mol

Mass CO2 = 28.85 grams = 0.0289 kg

0.0289 kg of CO2 will be formed

The correct categorization of the solutions is:a. KCl - Neutral

b. ZnCl2 - Acidic

c. Ba(C2H3O2)2 - Basic

d. NH4I - Acidic

e. NaNO3 - Neutral

To determine whether a 0.5M solution of each salt is acidic, basic, or neutral, we need to analyze the nature of the ions present in the solution.

a. KCl: When KCl is dissolved in water, it dissociates into K+ and Cl- ions. Both K+ and Cl- are spectator ions and do not contribute to the acidity or basicity of the solution. Therefore, the solution is neutral.

b. ZnCl2: When ZnCl2 is dissolved in water, it dissociates into Zn2+ and 2Cl- ions. The presence of Zn2+ ions in the solution can hydrolyze water molecules, resulting in the formation of H+ ions. Therefore, the solution is acidic.

c. Ba(C2H3O2)2: When Ba(C2H3O2)2 is dissolved in water, it dissociates into Ba2+ and 2C2H3O2- ions. The acetate ions (C2H3O2-) can hydrolyze water, leading to the formation of OH- ions. Therefore, the solution is basic.

d. NH4I: When NH4I is dissolved in water, it dissociates into NH4+ and I- ions. The presence of NH4+ ions in the solution can undergo a weak hydrolysis, resulting in the formation of H+ ions. Therefore, the solution is acidic.

e. NaNO3: When NaNO3 is dissolved in water, it dissociates into Na+ and NO3- ions. Both Na+ and NO3- ions are spectator ions and do not contribute to the acidity or basicity of the solution. Therefore, the solution is neutral.

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Answer: Clouds need two things to form: cool air and particles on which water vapor can condense. Clouds form as air cools. Cold air cannot hold as much water vapor, so the water vapor condenses. Water vapor condenses on small particles in the atmosphere, such as smoke, salt, and dust. As a result, clouds form.

Explanation: correct on edge

Answer: 404.71 ML

Explanation:

We can use Boyle's Law to solve this problem, which states that the pressure and volume of a gas are inversely proportional at a constant temperature.

Boyle's Law equation: P1V1 = P2V2

Where:

P1 = initial pressure

V1 = initial volume

P2 = final pressure

V2 = final volume

Given:

P1 = 3.6 atm

V1 = 95 mL

P2 = 0.85 atm

We can rearrange the equation to solve for V2:

V2 = (P1V1)/P2

V2 = (3.6 atm * 95 mL)/(0.85 atm)

V2 = 404.71 mL

Therefore, the final volume of the gas is approximately 404.71 mL. Hopefully this helps gang fasho

We can use Boyle's law to solve this problem, which states that the pressure of a gas is inversely proportional to its volume when temperature and amount are held constant. The formula is:

P1V1 = P2V2

Where:

P1 = 3.6 atm (initial pressure)

V1 = 95 mL (initial volume)

P2 = 0.85 atm (final pressure)

V2 = ? (final volume)

Substituting the given values, we get:

(3.6 atm)(95 mL) = (0.85 atm)(V2)

Simplifying, we get:

V2 = (3.6 atm)(95 mL) / (0.85 atm)

V2 = 404.7 mL

Therefore, the final volume of the gas is 404.7 mL.

The heat change of the process is 7.67 kJ which means that 7.76 kJ of energy will be lost during the process of freezing the water.

To calculate the heat change when freezing water, we need to determine the amount of heat transferred during the phase change from liquid to solid.

This is given by:

Q = m * deltaHf

where;

Q is the amount of heat transferred, m is the mass of water, and deltaHf is the enthalpy of fusion of water, which is 6.01 kJ/mol.

To convert the mass of water from grams to moles, we need to divide by the molar mass of water:

moles = mass / molar mass

moles = 23 g / 18.015 g/mol

moles = 1.277 mol

Now we can calculate the amount of heat transferred:

Q = m * deltaHf

Q = 1.277 mol * 6.01 kJ/mol

Q = 7.67 kJ

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In order to promote a healthy environment, the piece of trash should be matched to the best method of disposing them as follows:

Compost rotting can be defined as a chemical change that involves the mixture of decayed organic substances such as dead leaves, vegetables, manure, or egg shells, that are added to the soil, in order to fertilize it.

Recycling can be defined as a waste (trash) management technique that involves the process of converting a raw material that has reached the end of its life cycle into new and reusable items.

In order to promote a healthy environment, the piece of trash should be matched to the best method of disposing them as follows:

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Answer:

Recycling - television set, plastic milk bottle, and soup can.

Compost - egg shell, vegetable peel, and grass clippings.

Explanation:

Plato

Un metal pintado corre menos que uno expuesto al aire porque no sufre la acción del oxígeno.

El oxígeno es un elemento extremadamente electronegativo presente en el aire, este elemento tiende a capturar electrones fácilmente.

Un metal es un elemento que pierde fácilmente electrones debido a su configuración electrónica.

Así, un metal expuesto al aire, al contacto con oxígeno, tiende a corroerse más fácilmente que un metal que tiene una capa protectora (pintura).

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Answer:

the electron will be drawn more toward the atom with the higher e lectronegativity resulting in a polar covalent bond.

Explanation:

When atoms of different elements share electrons through covalent bonding, the electron will be drawn more toward the atom with the higher e lectronegativity resulting in a polar covalent bond. When compared to ionic compounds, covalent compounds usually have a lower melting and boiling point, and have less of a tendency to dissolve in water.

Answer:

a

Explanation:

Answer:

cyclopentane cyclobutene cyclohexane cycloheptane

An electron has a negative charge.

The charge of an electron is a fundamental property of the particle, and it is denoted by the symbol "e." The magnitude of the charge of an electron is approximately 1.602 × 10^-19 coulombs (C). This value is considered the elementary charge and is used as a reference for other charges. The charge of an electron plays a significant role in determining the behavior and interactions of atoms and molecules. It is opposite in sign to the charge of a proton, which is positive. The electron's charge allows it to interact with other charged particles, such as protons and ions, through electrostatic forces. Electrons are subatomic particles that orbit the nucleus of an atom in specific energy levels or orbitals. They contribute to the overall stability and chemical properties of atoms and participate in chemical bonding and reactions. The movement of electrons between atoms is what enables the formation of chemical bonds and the sharing or transfer of electrons to create ions. In summary, the charge of an electron is negative, and it plays a fundamental role in the structure and behavior of atoms and molecules.

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Answer:

answer is B

Explanation:

hope I helped

The number of moles of O₃ required to react with 0.54 mole of NH₃ is 0.36 mole

First, let us let us consider the balanced equation, to obtain usefull information as regarding the question.

6NH₃ + 4O₃ -> 3N₂O + 9H₂O

From the balanced equation above,

6 moles of NH₃ reacted with 4 moles of O₃

With the information obtained from the balanced equation, we can succefully determine the number of mole of O₃ required to react with 0.54 mole of NH₃. Details below

From the balanced equation above,

6 moles of NH₃ reacted with 4 moles of O₃

Therefore,

0.54 moles of NH₃ will react with = (0.54 × 4) / 6 = 0.36 mole of O₃

Therefore, we can conclude that the number of mole of O₃ required is 0.36 mole

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Answer:

Explanation:

Aniline is an organic compound with the formula C6H5NH2. Consisting of a phenyl group attached to an amino group, aniline is the simplest aromatic amine.

Taking into account the reaction stoichiometry, 380.12 grams of O₂ are produced as the result of the decomposition of 843 g of NaClO₃.

In first place, the balanced reaction iS:

2 NaClO₃ → 2 NaCl + 3 O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: if by reaction stoichiometry 212.9 grams of NaClO₃ form 96 grams of O₂, 843 grams of NaClO₃ form how much mass of O₂?

mass of O₂= (843 grams of NaClO₃× 96 grams of O₂) ÷212.9 grams of NaClO₃

mass of O₂= 380.12 grams

Finally, 380.12 grams of O₂ are formed.

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Answer:

22.52g of hydrogen chloride will be produced.

Explanation:

1st) From the balanced reaction we know that 1 mole of PCl5 reacts with 1 mole of water to produce 1 mole of POCl3 and two moles of hydrogen chloride. Using the molar mass of PCl5 (208.24g/mol) and HCl (36.5g/mol) we can convert the moles to grams:

- 1 mole of PCl5 weighs 208.24g.

- 2 moles of HCl weigh 73g

2nd) With the grams of PCl5 and HCl from the stoichiometry, and the given value of 64.23g of PCl5, we can calculate the mass of HCl that will be produced:

Finally, 22.52g of hydrogen chloride will be produced.

According to the Bohr effect, an increase in the supply of oxygen (O2) to muscles will result from a drop in carbon dioxide (CO2) levels.

The reason for this is that a decrease in CO2 weakens the T state of haemoglobin, which is the type of haemoglobin that binds oxygen. The P50 level (the partial pressure of oxygen at which haemoglobin is half-saturated with oxygen) decreases and the release of O2 from haemoglobin increases due to the T state's poorer stability. Enhanced O2 supply to muscles is the effect of this increased O2 release. The Bohr effect is a phenomena wherein when the pH of the immediate environment falls, hemoglobin's affinity for oxygen also diminishes.

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