Which reaction taking place inside an internal combustion engine appreciably leads to the formation of acid deposition?N2(g) + O2(g) → 2NO(g)C8H18(g) + 11O2(g) → 3CO(g) + 5CO2(g) + 9H2O2C8H18(g) + 25O2(g) → 16CO2(g) + 18H2O2SO2(g) + O2(g) → 2SO3

Answers

Answer 1

The reaction that takes place inside an internal combustion engine that appreciably leads to the formation of acid deposition is the combustion of sulfur-containing fuels, which produces sulfur dioxide (SO2).

This gas can react with oxygen (O2) to form sulfur trioxide (SO3), which then reacts with water (H2O) to form sulfuric acid (H2SO4). This acid can then fall to the ground as acid deposition, which can harm plants, animals, and humans.
Therefore, the correct answer from the given reactions is 2SO2(g) + O2(g) → 2SO3(g). This reaction occurs when fuels containing sulfur, such as diesel or coal, are burned. In modern engines, however, measures such as sulfur dioxide scrubbers are employed to remove the sulfur dioxide from the exhaust gases, thereby reducing acid deposition.

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Related Questions

what color is used to represent crust that is 135 million years old

Answers

orange i believe so or if not blue

Sonam has a tank that holds 0.5L of air at a temperature of 300K and a pressure

of 880kPa.

What volume would the air occupy if it were released into the atmosphere, where

the pressure is 102kPa and the temperature is 327K?​

Answers

Answer:

4.70 L

Explanation:

Use the basic relationship:

P1V1/T1 = P2V2/T2

Re-arrange to:

P1V1 T2 / (T1P2) = V2   To find the new volume

Sub in the values:

880 * .5 * 327 / ( 300*102) = 4.70 L

What changes have occurred in the last 20-50 years in the temperate deciduous forest in the united kingdom

Answers

There have been several changes that have occurred in the temperate deciduous forest of the United Kingdom over the last 20-50 years. Some of these changes include:

1. Increase in temperature: The average temperature in the UK has increased over the last few decades, which has resulted in changes in the timing of seasonal events in the forest. For example, the leafing-out of trees has advanced by several days.

2. Changes in vegetation: There has been a shift in the composition of the forest towards more shade-tolerant species, which has led to changes in the understory vegetation.

3. Changes in wildlife: Changes in the forest structure and composition have led to changes in the wildlife that inhabit the forest. For example, some bird species have increased in abundance, while others have declined.

4. Increase in invasive species: The UK has seen an increase in invasive plant species, such as Japanese knotweed, which can outcompete native species and alter the composition of the forest.

5. Changes in land use: Forests in the UK are increasingly being managed for multiple uses, such as recreation and timber production. This has led to changes in forest structure and composition.

hydrophobic interactions may occur between the r-groups of which of the following pairs of amino acids:

Answers

Hydrophobic interactions may occur between the R-groups of non-polar amino acids such as alanine (Ala), valine (Val), leucine (Leu), isoleucine (Ile), phenylalanine (Phe), tryptophan (Trp), and methionine (Met). These interactions can play a critical role in the folding and stability of proteins.

Hydrophobic interactions may occur between the R-groups of the following pairs of amino acids:

The pairs of amino acids that can experience hydrophobic interactions are those with non-polar, hydrophobic R-groups. Some examples of these amino acids include:

1. Alanine (Ala)
2. Valine (Val)
3. Leucine (Leu)
4. Isoleucine (Ile)
5. Phenylalanine (Phe)
6. Methionine (Met)
7. Proline (Pro)
8. Tryptophan (Trp)

Any combination of these amino acids can result in hydrophobic interactions between their R-groups due to their non-polar nature.

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pleas answer this, it’s due tomorrow. I will give brainliest.

pleas answer this, its due tomorrow. I will give brainliest.

Answers

Answer:

just the second

Explanation:

Answer:

both are changes in state, and both conserve mass. Hope it helps and please have a good day or night

Which of the following is the empirical formula for C4H8?
A. CH4
B. C6H6
C. C2H2
D. CH2

Answers

it would be CH2! you’re just simplifying C4H8, 4 can go into C4 1 time (so we just say C) and 4 can go into H8 2 times (H2)

A machine increase the rate of doing ______.
Sharp instruments are called ______.
help me and I will make you brianlist ​

Answers

Doing work “easier “
Called “ fingerstick”

A certain decomposition reaction is first order with a rate constant of 6.85 * 10^-4.1 at 25°C. What is the half-life of the reaction in minutes? Report your answer to one decimal place. Do not input a unit.

Answers

The half-life of the reaction is approximately 16.9 minutes at 25°C.

Chemical reactions can be classified based on their reaction rate, which can be determined experimentally by measuring how quickly the reactants are consumed or how quickly the products are formed. The rate of a chemical reaction is typically described by a rate law, which relates the rate of the reaction to the concentrations of the reactants.

One common type of rate law is the first-order rate law, which describes a reaction that depends on the concentration of a single reactant raised to the power of 1. The rate constant for a first-order reaction is a measure of how quickly the reaction proceeds and is typically denoted by the symbol k.

The half-life of a reaction is the time it takes for the concentration of the reactant to decrease by half. For a first-order reaction, the half-life is related to the rate constant by the following equation:

t1/2 = ln(2) / k

where t1/2 is the half-life of the reaction, ln(2) is the natural logarithm of 2, and k is the rate constant.

Given a first-order reaction with a rate constant of 6.85 * 10^-4.1 at 25°C, we can use the above equation to calculate the half-life of the reaction:

t1/2 = ln(2) / (6.85 * 10^-4.1)

t1/2 = 1014.4 seconds

Converting the answer to minutes gives:

t1/2 = 16.9 minutes (rounded to one decimal place)

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What are the main differences in the synthesis of purine and pyrimidine nucleotides?

Answers

The main differences in the synthesis of purine and pyrimidine nucleotides -

The key difference between purine and pyrimidine synthesis is that purine synthesis occurs mainly via salvage pathway while pyrimidine synthesis occurs mainly via De novo pathway.Purine and pyrimidine are nitrogen-containing bases.

What are 2 differences between purine and pyrimidine?

The purines, adenine and thymine, are smaller two-ringed bases, while the pyrimidines, cytosine and uracil, are larger and have a single ring. The pyrimidines, cytosine and uracil, are smaller and have a single ring, while the purines, adenine and guanine, are larger and have two rings.

What are the structural differences among purines and pyrimidines in DNA and RNA?

Purines and Pyrimidines are nitrogenous bases that make up the two different kinds of nucleotide bases in DNA and RNA. The two-carbon nitrogen ring bases (adenine and guanine) are purines, while the one-carbon nitrogen ring bases (thymine and cytosine) are pyrimidines.

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What would happen to the food chain, if all the plants were removed?

Answers

Answer: chain reaction there will be no carbon and animals who eat plants will die off

Explanation:

Convert 0.0009 Mm to millimeters.


A. 900 mm
B. 900000 mm
C. 9 x 10^-13 mm
D. 900000000 mm
E. 90 mm
F.9 x 10-7 mm
G. 9000 mm
H. 9 x 10-10 mm

Answers

Answer:

0.0009 Meters =

0.9 Millimeters

how many hydrogen atoms are in 3Fe(OH)2

Answers

Answer:

six

Explanation:

This is kinda like      3  * (Fe + 2O + 2H)      which would be SIX hydrogen atoms  ( or 3 hydrogen molecules)

How many oxygen atoms are in 15 molecules of tetraphosphorus decoxide (also known as phosphorus pentoxide), p₄o₁₀?

Answers

There are 150 oxygen atoms in 15 molecules of tetraphosphorus decoxide (P₄O₁₀).

Tetraphosphorus decoxide (P₄O₁₀) consists of four phosphorus atoms and ten oxygen atoms. To determine the number of oxygen atoms in 15 molecules of P₄O₁₀, we can first calculate the total number of oxygen atoms in one molecule and then multiply by 15.

The subscript "10" in P₄O₁₀ indicates that there are ten oxygen atoms. Therefore, in one molecule of P₄O₁₀, we have:

10 oxygen atoms

To find the number of oxygen atoms in 15 molecules of P₄O₁₀, we multiply the number of oxygen atoms per molecule by the number of molecules:

Number of oxygen atoms = 10 oxygen atoms/molecule × 15 molecules

Number of oxygen atoms = 150 oxygen atoms

So, there are 150 oxygen atoms in 15 molecules of tetraphosphorus decoxide (P₄O₁₀).

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How many grams of sulfur are in 3.54 g of H2S?

Answers

Answer:

3.329 g

Explanation:

First you need to determine the molar mass of H2S which is 34.1 g/mol.

With that we know that to find the moles of H2S we just divide the mass of sample with the molar mass.

3.54 g / 34.1 g/mol = 0.103812317  mol of H2S

This means that there is also 0.103812317  mol of sulfur since there is 1 mole of sulfur per 1 mole of H2S.

The molar mass of sulfur is 32.065 g/mol and to find the mass of sulfur you need to multiply the molar mass with the moles of the compound.  

0.103812317  mol * 32.065 g/mol = 3.329 g of sulfur

Let me know if you get something else or if something is unclear in the comments so that we can figure it out.

Consider a galvanic cell with a beaker of sulfuric acid and a beaker of nitric acid. The sulfuric acid beaker contains a strip of tin, and the nitric acid cell contains a strip of platinum. A wire runs between the strips. The reaction that occurs is as follows:

3Sn(s) + 2NO3–(aq) + 8H+(aq) → 3Sn2+(aq) + 2NO(g) + 4H2O(l)

In three to five sentences, list which electrode is the anode and which is the cathode and the half reactions that occur at each electrode.

Answers

I wrote, The platinum electrode is the cathode in this reaction. The tin electrode is the anode in this reaction. In the half reactions that occur the nitrate is reduced to nitric oxide(NO) while the tin electrode is oxidized to Sn2+.

Oxidation occurs at the tin half cell(anode) while reduction occurs at the nitrate half cell(cathode).

A galvanic cell refers to a cell that produces electrical energy spontaneously by redox reaction. Oxidation occurs at the anode while reduction occurs at the cathode in a galvanic cell.

The oxidation half equation at the anode occurs as follows;

3Sn(s) → 3Sn^2+(aq) + 6e

The reduction half equation that occurs at the cathode is;

2NO3–(aq) + 8H+(aq) + 6e→  2NO(g) + 4H2O(l)

We can see that electron loss occurs at the cathode while electron gain occurs at the anode as we can see in the equations above.

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Prepare a project report on various samples of
a) a mixture
b) a compound
c) an element ( metal or non metal)
( 2 from each ) highlighting the main characteristics features of elements, compounds and mixtures.

detailed answer plsss

Answers

Project Reports

A) Mixture

This refers to the material that is made when different substances mix up physically and causes a reaction.

You can make on the project of Mixture -

1) Alloys2)Colloids3) Suspension4) Solution

B) Compound

This refers to the chemical bond that holds different atoms tightly

You can make on the project of Compound -

1)Water2)Methane3)Carbon Dioxide4) Sulfuric Acid

C) Elements

Based on the fact that the atom is the smallest indivisible part of an element, elements like phosphorous cannot be further broken down.

You can make on the project of Elements -

1) Mercury2) Iron3) Copper4)Carbon

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I need help answering these

I need help answering these

Answers

U has a total of six electrons. This corresponds to carbon (C). A is the second most common element in the atmosphere.

How to explain the information

The second most common element in the atmosphere is oxygen (O). E is a noble gas.

Noble gases include helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and radon (Rn). Based on the given options, E could be xenon (Xe).

S is an alkali metal.

Alkali metals include lithium (Li), sodium (Na), potassium (K), rubidium (Rb), cesium (Cs), and francium (Fr). Based on the given options, S could be sodium (Na).

O is a halogen.

Halogens include fluorine (F), chlorine (Cl), bromine (Br), iodine (I), and astatine (At). Based on the given options, O could be bromine (Br).

O has an atomic number larger than V but smaller than W.

Based on the periodic table, the atomic number of oxygen (O) is 8, which is larger than the atomic number of vanadium (V) (23) and smaller than the atomic number of tungsten (W) (74).

The charge on an L ion is +2.

The charge of +2 indicates that L must lose two electrons to form the ion. Based on the given options, L could be calcium (Ca).

C has five electrons in its outer energy fever.

Carbon (C) has four valence electrons, not five. This contradicts the given statement, so we need to revisit the deductions.

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14.
Unlike addition polymers, condensation polymers form from _____.

monomers that have only one functional group
the head-to-tail joining of monomer units
the joining of unsaturated monomers
monomers that have at most three carbon atoms

Answers

Answer:

Addition polymers are formed when monomer units join each other in a process that involves the rearranging of electrons in double or triple bonds in the monomer. The polymer is the ONLY product formed.

EX:C=C + C=C + C=C - ·C-C-C-C-C-C·

Ethene(ethylene) monomers -> part of polyethene

Explanation:

What is the density of mas that is 3.1
The choices
A)0.94 /
B)0.79/
C)1.26/
D)1.38

Answers

Do you have the volume of this mass? To be able to find the density of a mass, you need 2 factors. Mass(m) and Volume(V). I also need to know if the volume is measured in cubic meters (m³) or gallons or cubic foot. If you can provide these i can gladly comment the answer down.

Explain the correlation between the number of valence electrons an atom has a number of other atoms can bond with? give an example

Answers

The number of valence electrons an atom has determines how many other atoms it can bond with. For example carbon has 4 valence electrons, so it can form 4 covalent bonds with other atoms.

which three human body systems coordinate to cause the arm to move

Answers

Answer:

Nervous system, Cardiac system, and the muscluar system

Explanation:

Heat Shield Rock 5. How did Heat Shield Rock get its name?​

Answers

Answer:

Heat Shield Rock is a basketball-sized iron-nickel meteorite found on the Meridiani Planum plain of Mars by the Mars rover Opportunity in January 2005.

Heat Shield Rock

Aluminum, sulfur, and chorine are elements found on the periodic table. Tests
involving these three elements would show that at normal room temperature -
F Sulfur is malleable and aluminum conducts electricity
G Chlorine is malleable and conducts electricity
H Aluminum is malleable and conducts electricity
J All three elements are malleable and conduct electricity

Answers

Aluminum is malleable and conducts Electricity

why do minerals only form in certain areas?

Answers

Answer:

Often, chemical changes in the water might result in the release of different minerals such as salt or calcium carbonate. Pressure and heat in the process of creating metamorphic rock can also result in the formation or transformation of minerals.  Minerals in igneous rocks often form where magma has cooled over time.

Explanation:

Minerals only form in certain areas due to presence of specific environment.

Minerals only form in certain areas because of the presence of suitable environmental condition for it. Every mineral needs specific environment for its formation. Without that specific temperature, pressure and some other factors, the mineral can't formed.

Every mineral needs specific environment for its formation which is different from one another so we can conclude that mineral formation needs particular environmental conditions.

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V7
Which of the following is a MIXTURE. Select ALL that apply.
(0/1 Point) a:brass
b:calcium
c:sodium chloride
d:apple juice​

Answers

Answer:

sodium chloride

Explanation:

A 75.0 mL portion of a 1.60 M solution is diluted to a total volume of 278 mL. A 139 mL portion of that solution is diluted by adding 193 mL of water. What is the final concentration? Assume the volumes are additive.

Answers

In this question we have two dilutions occurring, for both cases we will use the dilution formula, which says that the initial concentration and volume of a solution must be equal to the final concentration and volume of the solution, we can better understand that formula presenting it to the question:

M1 * V1 = M2 * V2

where:

M1 = initial molar concentration

V1 = initial volume in liters

M2 = final molar concentration

V2 = final volume in liters

Now let's see what happens in our first dilution:

1.60 M * 0.075 L = M2 * 0.278 L

M2 = 0.43 M, this is the first final concentration

Now we have a solution with 0.43M and 278 mL

In the question we take 139 mL of the 0.43 M solution and add 193 mL, therefore having 332 mL as final volume, let's use the formula again

0.43 M * 0.139 L = M2 * 0.332 L

M2 = 0.180 M as final concentration

the instructor reveals that the weak acid is hypochlorous acid, hocl. the known ka for hocl is 4.0×10-8. what is the percent error in the experiment?

Answers

The percent error in the experiment is 12.5%

What is a Percentage Error?

When comparing the estimated value to the actual value, the percent error is the difference, and it is given as a percentage.

How to find the percent error,

Let us find the % error in the experiment:

Given \(K_a = 4.0 * 10^-^8\)

Original; Ka= 3.5 x 10^-8

Percent error = accepted value - experimental value/accepted value x 100

= 4.0 x 10^-8 - 3.5 x 10^-8/4.0 x10^10^-8 x 100

= 12.5%

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There is a total of seventeen constitutional isomers for the molecular formula C5H13N. Draw the skeletal formula of all eight constitutional isomers that are primary amines.

Answers

There are seven structural isomers of 3-amines given the chemical formula C6H15N.

How many constitutional isomers may a molecule with the chemical formula C 2h 4cl 2 have?

It might be put on the same carbon as the first chlorine atom, or it could be placed on the other carbon atom. As a result, the chemical formula C2H4Cl2 can have two isomers. Create and compare models of both isomers. It is vital to note that this molecule can only have two isomers.

This is sometimes referred to as 2° amine. C5H13N secondary amine has six isomers. Isomers are compounds that have the same molecular formula but a distinct structural formula.

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Describe the scale used to measure the basicity of a substance. Demonstrate how you could differentiate a weak base from a strong one. (10
points)

Answers

Answer:

The pH scale is used to measure the acidity or basicity of a substance.

Explanation:

pH stands for potential hydrogen. It ranges from 0 to 14, 7 being neutral. The pH of water is 7 i.e. it is neither acidic nor basic. 0 to 7 shows acidic behavior while 7 to 14 shows basic behavior.

Experiment:

Dip the pH paper in the liquid and wait for ten seconds. The pH strip starts to discolor.

For a strong acid the strip will turn red.

For a weak acid the strip will become pale red.

To find the correct pH value we can compare it with the indicator scale present on the pH scale box.

The scale used to measure the basicity of a substance is called the pH scale.

What is the pH scale?

The pH scale is a logarithmic scale that ranges from 0 to 14 and is used to determine the acidity or basicity of a solution. A pH value of 7 is considered neutral, values below 7 are acidic, and values above 7 are basic.

To differentiate a weak base from a strong one, you can perform the following experiments:

pH Measurement: Measure the pH of the solution containing the base using a pH meter or pH indicator paper. A strong base will have a higher pH value, typically around 12-14, indicating a highly basic solution. A weak base will have a lower pH value, closer to 7, indicating a less basic or slightly basic solution.

Conductivity Test: Dissolve a small amount of the base in water and measure its electrical conductivity using a conductivity meter. Strong bases are good electrolytes and will conduct electricity well, resulting in a high conductivity. Weak bases, on the other hand, are poor electrolytes and will exhibit lower conductivity.

Reaction with Acids: Add a few drops of a strong acid, such as hydrochloric acid (HCl), to a solution containing the base. Strong bases will rapidly and completely neutralize the acid, resulting in a significant increase in pH. Weak bases, however, will only partially neutralize the acid, leading to a smaller increase in pH.

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. How many kilograms of iron can be recovered from 639 kilograms of the ore Feo ?

Answers

MW Fe2O3 = 55.8*2 + 16.0*3 = 159.6 g

Moles = mass /MW
=639 kg / 159.6
= 639,000g / 159.6
=4003.8 moles

Each mole of Fe203 yields 2 moles of Fe.

4003.8 moles Fe203 = 2*4003.8 = 8007.5 moles of Fe.

mass = moles x MW = 8007.5 * 55.8 = 446,812 g = 446.8 kg

There are 446.8 kg of iron in 639 kg of iron ore.

Can be recovered 496.7 kilograms of iron from 639 kilograms of the ore FeO.

To find the mass of Fe in the ore FeO, we need to calculate the number of moles of the ore.

\( n_{FeO} = \frac{m_{FeO}}{M_{FeO}} \)

Where:

\( m_{FeO}\): is the mass of FeO = 639 kg = 639000 g

\( M_{FeO}\): is the molar mass of FeO = 71.844 g/mol

The number of moles of FeO is:

\( n_{FeO} = \frac{m_{FeO}}{M_{FeO}} = \frac{639000 g}{71.844 g/mol} = 8894.3 \:moles \)

Now, in 1 mol of FeO we have 1 mol of Fe, so the number of moles of Fe is:

\( n_{Fe} = n_{FeO} = 8894.3 \:moles \)

Then, the mass of Fe is:

\( m_{Fe} = n_{Fe}*A_{Fe} = 8894.3 \:moles*55.84 g/mol = 496657.7 g = 496.7 kg \)

Therefore, 496.7 kilograms of iron can be recovered.

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. How many kilograms of iron can be recovered from 639 kilograms of the ore Feo ?
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